(12·Ö) ʵÑéÊÒÖÐÒÔÂÁÍÁ¿ó(Ö÷Òª³É·ÖÊÇAl2O3ºÍÉÙÁ¿µÄSiO2ºÍFe2O3ÔÓÖÊ)ΪԭÁÏÖÆÈ¡Al2(SO4)3ºÍï§Ã÷·¯¾§Ìå[NH4Al(SO4)2¡¤12H2O]µÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

ÊԻشðÏÂÁÐÎÊÌ⣺

¢Å¹ÌÌåaµÄ»¯Ñ§Ê½Îª_____£¬IIIÖÐͨÈë¹ýÁ¿CO2ÆøÌåµÄÀë×Ó·½³ÌʽΪ                    ¡£

¢ÆÓÉVÖÆÈ¡ï§Ã÷·¯ÈÜÒºµÄ»¯Ñ§·½³ÌʽΪ__________________________£¬´Óï§Ã÷·¯ÈÜÒºÖлñµÃï§Ã÷·¯¾§ÌåµÄʵÑé²Ù×÷ÒÀ´ÎΪ£¨Ìî²Ù×÷Ãû³Æ£©           ¡¢ÀäÈ´½á¾§¡¢¹ýÂËÏ´µÓ¡£

¢ÇÒÔ1000kgº¬Ñõ»¯ÂÁ36%µÄÂÁÍÁ¿óΪԭÁÏÖÆÈ¡Al2(SO4)3£¬ÐèÏûºÄÖÊÁ¿·ÖÊý98%µÄÁòËᣨÃܶÈ1.84g/cm3£©___________L£¨±£ÁôһλСÊý£©¡£

¢ÈÈôͬʱÖÆÈ¡ï§Ã÷·¯ºÍÁòËáÂÁ£¬Í¨¹ý¿ØÖÆÁòËáµÄÓÃÁ¿µ÷½ÚÁ½ÖÖ²úÆ·µÄ²úÁ¿¡£ÈôÓûʹÖƵõÄï§Ã÷·¯ºÍÁòËáÂÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ1:1£¬ÔòͶÁÏʱÂÁÍÁ¿óÖÐAl2O3ºÍH2SO4µÄÎïÖʵÄÁ¿Ö®±ÈΪ___________¡£

 

£¨12·Ö£©

¢ÅSiO2£¨2·Ö£©    AlO2-+CO2+2H2O==HCO3-+Al(OH)3¡ý£¨2·Ö£©

¢ÆAl2(SO4)3+ H2SO4 + 2NH3 ==2NH4Al(SO4)2£¨2·Ö£©   Õô·¢Å¨Ëõ£¨2·Ö£©

¢Ç575.4L£¨2·Ö£©  ¢È3:10£¨2·Ö£©

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ì½­ËÕÊ¡Æô¶«ÖÐѧ¸ßÈýÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

(12·Ö) ʵÑéÊÒÖÐÒÔÂÁÍÁ¿ó(Ö÷Òª³É·ÖÊÇAl2O3ºÍÉÙÁ¿µÄSiO2ºÍFe2O3ÔÓÖÊ)ΪԭÁÏÖÆÈ¡Al2(SO4)3ºÍï§Ã÷·¯¾§Ìå[NH4Al(SO4)2¡¤12H2O]µÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

ÊԻشðÏÂÁÐÎÊÌ⣺
¢Å¹ÌÌåaµÄ»¯Ñ§Ê½Îª_____£¬IIIÖÐͨÈë¹ýÁ¿CO2ÆøÌåµÄÀë×Ó·½³ÌʽΪ                    ¡£
¢ÆÓÉVÖÆÈ¡ï§Ã÷·¯ÈÜÒºµÄ»¯Ñ§·½³ÌʽΪ__________________________£¬´Óï§Ã÷·¯ÈÜÒºÖлñµÃï§Ã÷·¯¾§ÌåµÄʵÑé²Ù×÷ÒÀ´ÎΪ£¨Ìî²Ù×÷Ãû³Æ£©           ¡¢ÀäÈ´½á¾§¡¢¹ýÂËÏ´µÓ¡£
¢ÇÒÔ1000kgº¬Ñõ»¯ÂÁ36%µÄÂÁÍÁ¿óΪԭÁÏÖÆÈ¡Al2(SO4)3£¬ÐèÏûºÄÖÊÁ¿·ÖÊý98%µÄÁòËᣨÃܶÈ1.84g/cm3£©___________L£¨±£ÁôһλСÊý£©¡£
¢ÈÈôͬʱÖÆÈ¡ï§Ã÷·¯ºÍÁòËáÂÁ£¬Í¨¹ý¿ØÖÆÁòËáµÄÓÃÁ¿µ÷½ÚÁ½ÖÖ²úÆ·µÄ²úÁ¿¡£ÈôÓûʹÖƵõÄï§Ã÷·¯ºÍÁòËáÂÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ1:1£¬ÔòͶÁÏʱÂÁÍÁ¿óÖÐAl2O3ºÍH2SO4µÄÎïÖʵÄÁ¿Ö®±ÈΪ___________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê°²»ÕÊ¡Êæ³ÇÏþÌìÖÐѧ¸ß¶þÏÂѧÆÚÖÊÁ¿²âÊÔ5»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

(12·Ö)ʵÑéÊÒ³£ÀûÓü×È©·¨²â¶¨(NH4)2SO4ÑùÆ·ÖеªµÄÖÊÁ¿·ÖÊý£¬Æä·´Ó¦Ô­ÀíΪ£º
4NH4£«£«6HCHO??3H£«£«6H2O£«(CH2)6N4H£«[µÎ¶¨Ê±£¬1 mol(CH2)6N4H£«Óë1 mol H£«Ï൱]£¬È»ºóÓÃNaOH±ê×¼ÈÜÒºµÎ¶¨·´Ó¦Éú³ÉµÄËᡣijÐËȤС×éÓü×È©·¨½øÐÐÁËÈçÏÂʵÑ飺
²½Öè¢ñ¡¡³ÆÈ¡ÑùÆ·1.500 g¡£
²½Öè¢ò¡¡½«ÑùÆ·Èܽâºó£¬ÍêȫתÒƵ½250 mLÈÝÁ¿Æ¿ÖУ¬¶¨ÈÝ¡¢³ä·ÖÒ¡ÔÈ¡£
²½Öè¢ó¡¡ÒÆÈ¡25.00 mLÑùÆ·ÈÜÒºÓÚ250 mL׶ÐÎÆ¿ÖУ¬¼ÓÈë10 mL 20%µÄÖÐÐÔ¼×È©ÈÜÒº£¬Ò¡ÔÈ¡¢¾²ÖÃ5 minºó£¬¼ÓÈë1¡«2µÎ·Ó̪ÊÔÒº£¬ÓÃNaOH±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㡣°´ÉÏÊö²Ù×÷·½·¨ÔÙÖظ´2´Î¡£
(1)¸ù¾Ý²½Öè¢óÌî¿Õ£º
¢Ù¼îʽµÎ¶¨¹ÜÓÃÕôÁóˮϴµÓºó£¬Ö±½Ó¼ÓÈëNaOH±ê×¼ÈÜÒº½øÐе樣¬Ôò²âµÃÑùÆ·ÖеªµÄÖÊÁ¿·ÖÊý________(Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족)¡£
¢Ú׶ÐÎÆ¿ÓÃÕôÁóˮϴµÓºó£¬Ë®Î´µ¹¾¡£¬ÔòµÎ¶¨Ê±ÓÃÈ¥NaOH±ê×¼ÈÜÒºµÄÌå»ý________(Ìî¡°Æ«´ó¡±¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족)¡£
¢ÛµÎ¶¨Ê±±ßµÎ±ßÒ¡¶¯×¶ÐÎÆ¿£¬ÑÛ¾¦Ó¦¹Û²ì________¡£
A£®µÎ¶¨¹ÜÄÚÒºÃæµÄ±ä»¯
B£®×¶ÐÎÆ¿ÄÚÈÜÒºÑÕÉ«µÄ±ä»¯
¢ÜµÎ¶¨´ïµ½ÖÕµãʱ£¬·Óָ̪ʾ¼ÁÓÉ________É«±ä³É______É«¡£
(2)µÎ¶¨½á¹ûÈçϱíËùʾ£º
µÎ¶¨´ÎÊý      ´ý²âÈÜÒºµÄÌå»ý/mL    ±ê×¼ÈÜÒºµÄÌå»ý/mL
µÎ¶¨Ç°¿Ì¶È   µÎ¶¨ºó¿Ì¶È
1     25.00      1.02 21.03
2     25.00      2.00 21.99
3     25.00      0.20 20.20
ÈôNaOH±ê×¼ÈÜÒºµÄŨ¶ÈΪ0.101 0 mol¡¤L£­1£¬Ôò¸ÃÑùÆ·ÖеªµÄÖÊÁ¿·ÖÊýΪ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÕã½­Ê¡ºþÖÝÊиßÈýÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

(12·Ö) ʵÑéÊÒ¿ÉÓÉÈíÃÌ¿ó(Ö÷Òª³É·ÖΪ MnO2)ÖƱ¸ KMnO4£¬·½·¨ÈçÏ£ºÈíÃÌ¿óÓë¹ýÁ¿¹ÌÌå KOH ºÍ KClO3 ÔÚ¸ßÎÂÏ·´Ó¦£¬Éú³ÉÃÌËá¼Ø(K2MnO4)ºÍ KCl£»ÓÃË®Èܽ⣬ÂËÈ¥²ÐÔü£¬ÂËÒºËữºó£¬K2MnO4ת±äΪMnO2ºÍ KMnO4£»ÂËÈ¥MnO2³Áµí£¬Å¨ËõÂËÒº£¬½á¾§µÃµ½Éî×ÏÉ«µÄÕë×´KMnO4Çë»Ø´ð£º

£¨1£©ÈíÃÌ¿óÖƱ¸K2MnO4µÄ»¯Ñ§·½³ÌʽÊÇ                                   ¡£

£¨2£©K2MnO4ÖƱ¸KMnO4µÄÀë×Ó·½³ÌʽÊÇ                                   ¡£

£¨3£©ÅäƽÑõ»¯»¹Ô­·´Ó¦·½³Ìʽ£º

£ß£ß C2O42-+£ß£ßMnO4-+£ß£ßH+£½£ß£ßCO2+£ß£ßMn2++£ß£ßH2O

£¨4£©³ÆÈ¡6.0 gº¬H2C2O4¡¤2H2O¡¢KHC2O4ºÍK2SO4µÄÊÔÑù£¬¼ÓË®Èܽ⣬Åä³É250mLÈÜÒº¡£Á¿È¡Á½·Ý´ËÈÜÒº¸÷25.00 mL£¬·Ö±ðÖÃÓÚÁ½¸ö׶ÐÎÆ¿ÖС£

¢ÙµÚÒ»·ÝÈÜÒºÖмÓÈë·Ó̪ÊÔÒº£¬µÎ¼Ó0.25 mol¡¤L£­1NaOHÈÜÒºÖÁ20.00 mLʱ£¬ÈÜÒºÓÉÎÞÉ«±äΪdzºìÉ«¡£¸ÃÈÜÒº±»Öк͵ÄH£«µÄÎïÖʵÄÁ¿Îª£ß£ß£ßmol¡£

¢ÚµÚ¶þ·ÝÈÜÒºÖеμÓ0.10 mol¡¤L£­1µÄËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖÁ16.00 mLʱ·´Ó¦ÍêÈ«£¬´ËʱÈÜÒºÑÕÉ«Óɣߣ߱äΪ£ß£ß¡£¸ÃÈÜÒºÖл¹Ô­¼ÁµÄÎïÖʵÄÁ¿Îª£ß£ß£ßmol¡£

¢ÛÔ­ÊÔÑùÖÐH2C2O4¡¤2H2OµÄÖÊÁ¿·ÖÊýΪ£ß£ß£ß£ß£ß¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê½­ËÕÊ¡¸ßÈýÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

(12·Ö) ʵÑéÊÒÖÐÒÔÂÁÍÁ¿ó(Ö÷Òª³É·ÖÊÇAl2O3ºÍÉÙÁ¿µÄSiO2ºÍFe2O3ÔÓÖÊ)ΪԭÁÏÖÆÈ¡Al2(SO4)3ºÍï§Ã÷·¯¾§Ìå[NH4Al(SO4)2¡¤12H2O]µÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

ÊԻشðÏÂÁÐÎÊÌ⣺

¢Å¹ÌÌåaµÄ»¯Ñ§Ê½Îª_____£¬IIIÖÐͨÈë¹ýÁ¿CO2ÆøÌåµÄÀë×Ó·½³ÌʽΪ                     ¡£

¢ÆÓÉVÖÆÈ¡ï§Ã÷·¯ÈÜÒºµÄ»¯Ñ§·½³ÌʽΪ__________________________£¬´Óï§Ã÷·¯ÈÜÒºÖлñµÃï§Ã÷·¯¾§ÌåµÄʵÑé²Ù×÷ÒÀ´ÎΪ£¨Ìî²Ù×÷Ãû³Æ£©            ¡¢ÀäÈ´½á¾§¡¢¹ýÂËÏ´µÓ¡£

¢ÇÒÔ1000kgº¬Ñõ»¯ÂÁ36%µÄÂÁÍÁ¿óΪԭÁÏÖÆÈ¡Al2(SO4)3£¬ÐèÏûºÄÖÊÁ¿·ÖÊý98%µÄÁòËᣨÃܶÈ1.84g/cm3£©___________L£¨±£ÁôһλСÊý£©¡£

¢ÈÈôͬʱÖÆÈ¡ï§Ã÷·¯ºÍÁòËáÂÁ£¬Í¨¹ý¿ØÖÆÁòËáµÄÓÃÁ¿µ÷½ÚÁ½ÖÖ²úÆ·µÄ²úÁ¿¡£ÈôÓûʹÖƵõÄï§Ã÷·¯ºÍÁòËáÂÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ1:1£¬ÔòͶÁÏʱÂÁÍÁ¿óÖÐAl2O3ºÍH2SO4µÄÎïÖʵÄÁ¿Ö®±ÈΪ___________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸