п·Û¿É½«Ë®ÌåÖеÄÏõËáÑλ¹Ô­£¬Æä·´Ó¦Ô­Àí¿ÉÒÔÓÃÒÔÏÂÀë×Ó·½³Ìʽ±íʾ
______NO3-+______OH-+______Zn+______H2O¡ú______NH3+______Zn£¨OH£©42-
£¨1£©Å䯽ÉÏÊöÀë×Ó·´Ó¦·½³Ìʽ£¬±ê³öµç×Ó×ªÒÆµÄ·½ÏòºÍÊýÄ¿£»
£¨2£©Ä³ºÓ¶ÎͬʱÊÜËáÐÔÎïÖÊÎÛȾ£¬Èôп·ÛÓëÆä»¹Ô­µÄÏõËá¸ùÀë×ÓµÄÎïÖʵÄÁ¿Ö®±ÈΪ4£º1£¬Ôòп·Û±»Ñõ»¯Îª______Àë×Ó£¬ÏõËá¸ùÀë×Ó±»»¹Ô­Îª______£¨¾ùÓû¯Ñ§·ûºÅ±íʾ£©£»
£¨3£©½«Ð¿·Û¸ÄΪÂÁ·ÛÔÚÉÏÊöËáÐÔÌõ¼þÏ»¹Ô­ÏõËáÑΣ¬Èô»¹Ô­µÈÎïÖʵÄÁ¿µÄÏõËá¸ùÀë×Ó£¬Ð¿ÓëÂÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ______£»
£¨4£©ÏÖÒѺϳÉÁËÓÐZn-Zn¹²¼Û¼üµÄ»¯ºÏÎÓÉZn2OÖÆZn2Cl2¿ÉÑ¡ÓõÄÊÔ¼ÁÊÇ______£®
a£®ÑÎËá         b£®ÂÈÆø          c£®KClO3£®
£¨1£©µªÔªËØ»¯ºÏ¼Û´Ó+5¼Û±ä»¯Îª-3¼Û£¬Ð¿ÔªËØ»¯ºÏ¼Û´Ó0¼Û±ä»¯Îª+2¼Û£¬ÏÈÇó×îС¹«±¶ÊýΪ8£¬Ð¿ºÍпÀë×Óǰ³Ë4£¬¹Û²ìÅ䯽£¬µÃµ½Àë×Ó·½³ÌʽΪ£ºNO3-+7OH-+4Zn+6H2O=NH3+4Zn£¨OH£©4-£»µç×Ó×ªÒÆ×ÜÊýΪ8£¬±ê×¢µç×Ó×ªÒÆÎª£º

¾«Ó¢¼Ò½ÌÍø

£¬
¹Ê´ð°¸Îª£º1£»7£»4£»6£»1£»4£»

¾«Ó¢¼Ò½ÌÍø

£»
£¨2£©Èôп·ÛÓëÆä»¹Ô­µÄÏõËá¸ùÀë×ÓµÄÎïÖʵÄÁ¿Ö®±ÈΪ4£º1£¬ÒÀ¾Ýµç×ÓÊØºã£¬Zn¡«Zn2+¡«2e-£»ÉèÏõËá¸ùÖеªÔªËØ»¯ºÏ¼Û±ä»¯Îªx£¬NO3-¡«N¡«£¨5-x£©£¬ÒÀ¾Ýµç×ÓÊØºãµÃµ½4¡Á2=1¡Á£¨5-x£©£¬x=-3£¬»¹Ô­²úÎïΪNH4+£¬¹Ê´ð°¸Îª£ºZn2+£»NH4+£»
£¨3£©»¹Ô­µÈÁ¿ÏõËá¸ùÀë×Ó£¬Ð¿ºÍÂÁʧµç×ÓÏàͬÎïÖʵÄÁ¿Ö®±ÈΪ3£º2£¬¹Ê´ð°¸Îª£º3£º2£»
£¨4£©b£®ÂÈÆø c£®KClO3 £¬¶¼ÊÇÇ¿Ñõ»¯¼ÁÄÜÑõ»¯Zn2OΪ¸ß¼Û̬²»ÄÜÖÆ±¸Zn2Cl2 £¬ÓÉZn2OÖÆZn2Cl2¿ÉÑ¡ÓõÄÊÔ¼ÁÑ¡ÓÃa£¨HCl£©£¬¹Ê´ð°¸Îª£ºa£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?Õ¢±±ÇøÒ»Ä££©Ð¿·Û¿É½«Ë®ÌåÖеÄÏõËáÑλ¹Ô­£¬Æä·´Ó¦Ô­Àí¿ÉÒÔÓÃÒÔÏÂÀë×Ó·½³Ìʽ±íʾ
1
1
NO3-+
7
7
OH-+
4
4
Zn+
6
6
H2O¡ú
1
1
NH3+
4
4
Zn£¨OH£©42-
£¨1£©Å䯽ÉÏÊöÀë×Ó·´Ó¦·½³Ìʽ£¬±ê³öµç×Ó×ªÒÆµÄ·½ÏòºÍÊýÄ¿£»
£¨2£©Ä³ºÓ¶ÎͬʱÊÜËáÐÔÎïÖÊÎÛȾ£¬Èôп·ÛÓëÆä»¹Ô­µÄÏõËá¸ùÀë×ÓµÄÎïÖʵÄÁ¿Ö®±ÈΪ4£º1£¬Ôòп·Û±»Ñõ»¯Îª
Zn2+
Zn2+
Àë×Ó£¬ÏõËá¸ùÀë×Ó±»»¹Ô­Îª
NH4+
NH4+
£¨¾ùÓû¯Ñ§·ûºÅ±íʾ£©£»
£¨3£©½«Ð¿·Û¸ÄΪÂÁ·ÛÔÚÉÏÊöËáÐÔÌõ¼þÏ»¹Ô­ÏõËáÑΣ¬Èô»¹Ô­µÈÎïÖʵÄÁ¿µÄÏõËá¸ùÀë×Ó£¬Ð¿ÓëÂÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ
3£º2
3£º2
£»
£¨4£©ÏÖÒѺϳÉÁËÓÐZn-Zn¹²¼Û¼üµÄ»¯ºÏÎÓÉZn2OÖÆZn2Cl2¿ÉÑ¡ÓõÄÊÔ¼ÁÊÇ
a
a
£®
a£®ÑÎËá         b£®ÂÈÆø          c£®KClO3£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

п·Û¿É½«Ë®ÌåÖеÄÏõËáÑλ¹Ô­£¬Æä·´Ó¦Ô­Àí¿ÉÒÔÓÃÒÔÏÂÀë×Ó·½³Ìʽ±íʾ
______NO3-+______OH-+______Zn+______H2O¡ú______NH3+______Zn£¨OH£©42-
£¨1£©Å䯽ÉÏÊöÀë×Ó·´Ó¦·½³Ìʽ£¬±ê³öµç×Ó×ªÒÆµÄ·½ÏòºÍÊýÄ¿£»
£¨2£©Ä³ºÓ¶ÎͬʱÊÜËáÐÔÎïÖÊÎÛȾ£¬Èôп·ÛÓëÆä»¹Ô­µÄÏõËá¸ùÀë×ÓµÄÎïÖʵÄÁ¿Ö®±ÈΪ4£º1£¬Ôòп·Û±»Ñõ»¯Îª______Àë×Ó£¬ÏõËá¸ùÀë×Ó±»»¹Ô­Îª______£¨¾ùÓû¯Ñ§·ûºÅ±íʾ£©£»
£¨3£©½«Ð¿·Û¸ÄΪÂÁ·ÛÔÚÉÏÊöËáÐÔÌõ¼þÏ»¹Ô­ÏõËáÑΣ¬Èô»¹Ô­µÈÎïÖʵÄÁ¿µÄÏõËá¸ùÀë×Ó£¬Ð¿ÓëÂÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ______£»
£¨4£©ÏÖÒѺϳÉÁËÓÐZn-Zn¹²¼Û¼üµÄ»¯ºÏÎÓÉZn2OÖÆZn2Cl2¿ÉÑ¡ÓõÄÊÔ¼ÁÊÇ______£®
a£®ÑÎËá¡¡¡¡¡¡¡¡ b£®ÂÈÆø¡¡¡¡¡¡¡¡¡¡c£®KClO3£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012ÄêÉϺ£ÊÐÕ¢±±Çø¸ß¿¼»¯Ñ§Ò»Ä£ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

п·Û¿É½«Ë®ÌåÖеÄÏõËáÑλ¹Ô­£¬Æä·´Ó¦Ô­Àí¿ÉÒÔÓÃÒÔÏÂÀë×Ó·½³Ìʽ±íʾ
______NO3-+______OH-+______Zn+______H2O¡ú______NH3+______Zn£¨OH£©42-
£¨1£©Å䯽ÉÏÊöÀë×Ó·´Ó¦·½³Ìʽ£¬±ê³öµç×Ó×ªÒÆµÄ·½ÏòºÍÊýÄ¿£»
£¨2£©Ä³ºÓ¶ÎͬʱÊÜËáÐÔÎïÖÊÎÛȾ£¬Èôп·ÛÓëÆä»¹Ô­µÄÏõËá¸ùÀë×ÓµÄÎïÖʵÄÁ¿Ö®±ÈΪ4£º1£¬Ôòп·Û±»Ñõ»¯Îª______Àë×Ó£¬ÏõËá¸ùÀë×Ó±»»¹Ô­Îª______£¨¾ùÓû¯Ñ§·ûºÅ±íʾ£©£»
£¨3£©½«Ð¿·Û¸ÄΪÂÁ·ÛÔÚÉÏÊöËáÐÔÌõ¼þÏ»¹Ô­ÏõËáÑΣ¬Èô»¹Ô­µÈÎïÖʵÄÁ¿µÄÏõËá¸ùÀë×Ó£¬Ð¿ÓëÂÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ______£»
£¨4£©ÏÖÒѺϳÉÁËÓÐZn-Zn¹²¼Û¼üµÄ»¯ºÏÎÓÉZn2OÖÆZn2Cl2¿ÉÑ¡ÓõÄÊÔ¼ÁÊÇ______£®
a£®ÑÎËá         b£®ÂÈÆø          c£®KClO3£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸