(8·Ö)ijÄðÔ쳧ÒÔµí·ÛΪÖ÷ÒªÔ­ÁÏ£¬ÖÆÈ¡ÆÏÌÑÌÇ¡¢¾Æ¾«ºÍ´×Ëᣬ²¢ÇÒ´×ËáºÍÒ춡´¼[(CH3)2CHCH2OH]·´Ó¦ÖÆÈ¡ÒÒËáÒ춡õ¥¡£ÒÒËáÒ춡õ¥Ö÷ÒªÓÃÓÚÅäÖÆÏ㽶¡¢²ÝÝ®ºÍÄÌÓ͵ÈÏãÐ͵ÄÏ㾫¡£Æä·´Ó¦¹ý³ÌÈçÏ£º
µí·Û¢ÙÆÏÌÑÌÇ¢ÚÒÒ´¼¢ÛÒÒÈ©¢ÜÒÒËá¢ÝÒÒËáÒ춡õ¥
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)д³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
¢Ù________________________________________________________________________£»
¢Ú________________________________________________________________________£»
¢Ý________________________________________________________________________¡£
(2)ÆÏÌÑÌÇÊÇÒ»ÖÖÖØÒªµÄÓªÑøÎïÖÊ£¬ËüÊÇÈËÀàÉúÃü»î¶¯ËùÐèÄÜÔ´µÄÖØÒªÀ´Ô´Ö®Ò»¡£ÒÑÖªÆÏÌÑÌǵÄȼÉÕÈÈÊÇ2840 kJ¡¤mol£­1£¬Ð´³öÆÏÌÑÌÇÍêÈ«Ñõ»¯µÄÈÈ»¯Ñ§·½³Ìʽ£º
________________________________________________________________________¡£

(1)¢Ù(C6H£«nH2OnC6H
¢ÚC6H2C2H5OH£«2CO2¡ü
¢ÝCH3COOH£«(CH3)2CHCH2OHŨH2SO4¡÷CH3COOCH2CH(CH3)2£«H2O
(2)C6H12O6(s)£«6O2(g)===6CO2(g)£«6H2O(l)£»¦¤H£½£­2840 kJ¡¤mol£­1

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(8·Ö)ijÄðÔ쳧ÒÔµí·ÛΪÖ÷ÒªÔ­ÁÏ£¬ÖÆÈ¡ÆÏÌÑÌÇ¡¢¾Æ¾«ºÍ´×Ëᣬ²¢ÇÒ´×ËáºÍÒ춡´¼[(CH3)2CHCH2OH]·´Ó¦ÖÆÈ¡ÒÒËáÒ춡õ¥¡£ÒÒËáÒ춡õ¥Ö÷ÒªÓÃÓÚÅäÖÆÏ㽶¡¢²ÝÝ®ºÍÄÌÓ͵ÈÏãÐ͵ÄÏ㾫¡£Æä·´Ó¦¹ý³ÌÈçÏ£º

µí·Û¢ÙÆÏÌÑÌÇ¢ÚÒÒ´¼¢ÛÒÒÈ©¢ÜÒÒËá¢ÝÒÒËáÒ춡õ¥

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)д³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ£º

¢Ù________________________________________________________________________£»

¢Ú________________________________________________________________________£»

¢Ý________________________________________________________________________¡£

(2)ÆÏÌÑÌÇÊÇÒ»ÖÖÖØÒªµÄÓªÑøÎïÖÊ£¬ËüÊÇÈËÀàÉúÃü»î¶¯ËùÐèÄÜÔ´µÄÖØÒªÀ´Ô´Ö®Ò»¡£ÒÑÖªÆÏÌÑÌǵÄȼÉÕÈÈÊÇ2840kJ¡¤mol£­1£¬Ð´³öÆÏÌÑÌÇÍêÈ«Ñõ»¯µÄÈÈ»¯Ñ§·½³Ìʽ£º

________________________________________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(10·Ö)ijÖÆÌdz§ÒÔ¸ÊÕáΪԭÁÏÖÆÌÇ£¬Í¬Ê±µÃµ½´óÁ¿µÄ¸ÊÕáÔü£¬¶Ô¸ÊÕáÔü½øÐÐ×ÛºÏÀûÓò»½ö¿ÉÒÔÌá¸ß¾­¼ÃЧÒ棬¶øÇÒ»¹ÄÜ·ÀÖ¹»·¾³ÎÛȾ£¬ÏÖ°´ÒÔÏ·½Ê½½øÐУº

 

£¨1£©Ð´³öA¡¢B¡¢FµÄÃû³Æ·Ö±ðΪ          ¡¢          ¡¢            ¡£

£¨2£©EµÄ½á¹¹¼òʽΪ            ¡£

£¨3£©Ð´³ö·´Ó¦¢ÛºÍ·´Ó¦¢ÝµÄ»¯Ñ§·½³Ìʽ¡£

·´Ó¦¢Û                                             ¡£

·´Ó¦¢Ý                                             ¡£

£¨4£©Ð´³ö±ÈE¶àÒ»¸ö̼µÄͬϵÎï·¢Éú¼Ó¾Û·´Ó¦µÄ»¯Ñ§·½³Ìʽ                 ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêºÚÁú½­Ê¡Äµµ¤½­Ò»ÖиßÒ»ÏÂѧÆÚÆÚÄ©²âÊÔ»¯Ñ§ ÌâÐÍ£º¼ÆËãÌâ

(10·Ö)ijÖÆÌdz§ÒÔ¸ÊÕáΪԭÁÏÖÆÌÇ£¬Í¬Ê±µÃµ½´óÁ¿µÄ¸ÊÕáÔü£¬¶Ô¸ÊÕáÔü½øÐÐ×ÛºÏÀûÓò»½ö¿ÉÒÔÌá¸ß¾­¼ÃЧÒ棬¶øÇÒ»¹ÄÜ·ÀÖ¹»·¾³ÎÛȾ£¬ÏÖ°´ÒÔÏ·½Ê½½øÐУº

£¨1£©Ð´³öA¡¢B¡¢FµÄÃû³Æ·Ö±ðΪ          ¡¢          ¡¢            ¡£
£¨2£©EµÄ½á¹¹¼òʽΪ            ¡£
£¨3£©Ð´³ö·´Ó¦¢ÛºÍ·´Ó¦¢ÝµÄ»¯Ñ§·½³Ìʽ¡£
·´Ó¦¢Û                                             ¡£
·´Ó¦¢Ý                                             ¡£
£¨4£©Ð´³ö±ÈE¶àÒ»¸ö̼µÄͬϵÎï·¢Éú¼Ó¾Û·´Ó¦µÄ»¯Ñ§·½³Ìʽ                 ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê¸ß¿¼»¯Ñ§Ò»ÂÖ¸´Ï°¡¶ÉúÃü»î¶¯µÄÎïÖÊ»ù´¡¡¢È˹¤ºÏ³ÉÓлú»¯ºÏÎרÌâ×ۺϲâÊÔ ÌâÐÍ£ºÌî¿ÕÌâ

(8·Ö)ijÄðÔ쳧ÒÔµí·ÛΪÖ÷ÒªÔ­ÁÏ£¬ÖÆÈ¡ÆÏÌÑÌÇ¡¢¾Æ¾«ºÍ´×Ëᣬ²¢ÇÒ´×ËáºÍÒ춡´¼[(CH3)2CHCH2OH]·´Ó¦ÖÆÈ¡ÒÒËáÒ춡õ¥¡£ÒÒËáÒ춡õ¥Ö÷ÒªÓÃÓÚÅäÖÆÏ㽶¡¢²ÝÝ®ºÍÄÌÓ͵ÈÏãÐ͵ÄÏ㾫¡£Æä·´Ó¦¹ý³ÌÈçÏ£º

µí·Û¢ÙÆÏÌÑÌÇ¢ÚÒÒ´¼¢ÛÒÒÈ©¢ÜÒÒËá¢ÝÒÒËáÒ춡õ¥

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)д³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ£º

¢Ù________________________________________________________________________£»

¢Ú________________________________________________________________________£»

¢Ý________________________________________________________________________¡£

(2)ÆÏÌÑÌÇÊÇÒ»ÖÖÖØÒªµÄÓªÑøÎïÖÊ£¬ËüÊÇÈËÀàÉúÃü»î¶¯ËùÐèÄÜÔ´µÄÖØÒªÀ´Ô´Ö®Ò»¡£ÒÑÖªÆÏÌÑÌǵÄȼÉÕÈÈÊÇ2840 kJ¡¤mol£­1£¬Ð´³öÆÏÌÑÌÇÍêÈ«Ñõ»¯µÄÈÈ»¯Ñ§·½³Ìʽ£º

________________________________________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸