25 ¡æ£¬101 k Paʱ£¬Ç¿ËáÓëÇ¿¼îµÄÏ¡ÈÜÒº·¢ÉúÖкͷ´Ó¦Éú³É1molˮʱËù·Å³öµÄÈÈÁ¿Ô¼Îª57.3 kJ/mol£»ÐÁÍéµÄȼÉÕÈÈΪ5518 kJ/mol¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ£¨ £©
A£®CH3COOH(aq)+NaOH(aq)===
CH3COONa(aq)+H2O(l)
H=
57.3kJ/mol
B£®KOH(aq)+
H2SO4(aq)=
K2SO4(aq)+H2O(l)
H=
57.3kJ/mol
C£®2C8H18(g)+25O2
(g)=16CO2 (g)+18H2O(1)
H=
11036
kJ/mol
D£®C8H18(l)+
O2 (g)=8CO2 (g)+
9H2O(g)
H=
5518 kJ/mol
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25 ¡æ£¬101 k Paʱ£¬Ç¿ËáÓëÇ¿¼îµÄÏ¡ÈÜÒº·¢ÉúÖкͷ´Ó¦µÄÖкÍÈÈΪ-57.3 kJ/mol£¬ÐÁÍéµÄȼÉÕÈÈΪ-5518 kJ/mol¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ£¨ £©
A£®2H+(aq)
+
(aq)+
(aq)+2
(aq) = BaSO4(s)+2H
O(l);
H =
57.3 kJ/mol
B£®KOH(aq)+
H
SO4(aq) =
K
SO4(aq)+H
O(l);
H=
57.3kJ/mol
C£®C8H18(l)+
O
(g)=8CO
(g)+ 9H
O(g);
H=
5518 kJ/mol
D£®2C8H18(g)+25O
(g)=16CO
(g)+18H
O(1);
H=
5518 kJ/mol
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25 ¡æ£¬101 k Paʱ£¬Ç¿ËáÓëÇ¿¼îµÄÏ¡ÈÜÒº·¢ÉúÖкͷ´Ó¦µÄÖкÍÈÈΪ57.3 kJ/mol£¬ÐÁÍéµÄȼÉÕÈÈΪ5518 kJ/mol¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ ( )
A£®2H+(aq)+SO42£(aq)+Ba2£«(aq)+2OH-(aq)=BaSO4(s)+2H2O(1)
¡÷H=
57.3 kJ/mol
B£®KOH(aq)+
H2 SO4(aq)=
K2SO4(aq)+H2O(l) ¡÷H=
57.3kJ/mol
C£®C8H18(I)+
O2(g)=8CO2(g)+9H2O ¡÷H=
5518 kJ/mol
D£®2C8H18(g)+25O2(g)=16CO2(g)+18H2O(1)
¡÷H=
5518 kJ/mol
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25¡æ£¬101 k Paʱ£¬Ç¿ËáÓëÇ¿¼îµÄÏ¡ÈÜÒº·¢ÉúÖкͷ´Ó¦µÄÖкÍÈÈΪ57.3 kJ/mol£¬ÐÁÍéµÄȼÉÕÈÈΪ5518 kJ/mol¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ£¨ £©
A£®2H+(aq) +SO42£(aq)+Ba2+(aq)+2OH£(aq)=BaSO4(s)+2H2O(1)£»¦¤H=£57.3 kJ/mol
B£®KOH(aq)+ H2 SO4(aq)=K2SO4(aq)+H2O(l)£»¦¤H=£57.3kJ/mol
C£®2C8H18(g)+25O2(g)=16CO2(g)+18H2O(1)£»¦¤H=£5518 kJ/mol
D£®C8H18(l)+ 25/2 O2(g)=8CO2(g)+ 9H2O(1)£»¦¤H=£5518 kJ/mol
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25 ¡æ£¬101 k Paʱ£¬Ç¿ËáÓëÇ¿¼îµÄÏ¡ÈÜÒº·¢ÉúÖкͷ´Ó¦µÄÖкÍÈÈΪ57.3 kJ/mol£¬ÐÁÍéµÄȼÉÕÈÈΪ5518 kJ/mol¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ
A.2H+(aq) +
(aq)+
(aq)+2OH
(aq)=BaSO4(s)+2H
O(1);
H=
57.3
kJ/mol
B.KOH(aq)+
H
SO4(aq)=
K
SO4(aq)+H
O(I);
H=
57.3kJ/mol
C.C8H18(I)+
O
(g)=8CO
(g)+ 9H
O;
H=
5518 kJ/mol
D.2C8H18(g)+25O
(g)=16CO
(g)+18H
O(1);
H=
5518 kJ/mol![]()
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