CO¿ÉÓÃÓںϳɼ״¼£¬Ò»¶¨Î¶ÈÏ£¬ÏòÌå»ýΪ2LµÄÃܱÕÈÝÆ÷ÖмÓÈëCOºÍH2£¬·¢Éú·´Ó¦

CO£¨g£©+2H2£¨g£© CH3OH£¨g£©£¬´ïƽºâºó²âµÃ¸÷×é·ÖŨ¶ÈÈçÏ£º

ÎïÖÊ

CO

H2

CH3OH

Ũ¶È(mol•L£­1)

0.9

1.0

0.6

¢Ù»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿__________________________¡£

¢ÚÁÐʽ²¢¼ÆËãÆ½ºâ³£ÊýK=__________________________¡£

¢ÛÈô½«ÈÝÆ÷Ìå»ýѹËõΪ1L,²»¾­¼ÆË㣬Ԥ²âÐÂÆ½ºâÖÐc(H2)µÄȡֵ·¶Î§ÊÇ__________¡£

¢ÜÈô±£³ÖÌå»ý²»±ä£¬ÔÙ³äÈë0.6molCOºÍ0.4molCH3OH,´ËʱvÕý___vÄæ(Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±)¡£


¢Ù18.56£¨2·Ö£© 

¢Ú0.6/(0.9¡Á1.02)=2/3 L2• moL2 (»ò0.67 L2• moL2)     £¨2·Ö£© 

 ¢Û1 mol•L1<c(H2)<2 mol•L1£¨2·Ö£©  

¢Ü=£¨2·Ö£©


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¸ß´¿MnCO3ÊÇÖÆ±¸¸ßÐÔÄÜ´ÅÐÔ²ÄÁϵÄÖ÷ÒªÔ­ÁÏ¡£ÊµÑéÊÒÒÔMnO2ΪԭÁÏÖÆ±¸ÉÙÁ¿¸ß´¿MnCO3µÄ²Ù×÷²½ÖèÈçÏ£º

²éÔÄ×ÊÁÏ£º¢ÙMnCO3ÄÑÈÜÓÚË®£¬³±ÊªÊ±Ò×±»¿ÕÆøÑõ»¯£¬100¡æ¿ªÊ¼·Ö½â¡£

¢ÚMn£¨OH£©2¿ªÊ¼³ÁµíʱpH=7.7¡£

ʵÑé¹ý³Ì£º

¢ñ. ÓÃͼ1ËùʾװÖÃÖÆ±¸MnSO4ÈÜÒº¡£

¢ò. ±ß½Á°è±ßÏòMnSO4ÈÜÒºÖмÓÈëÉÔ¹ýÁ¿NaHCO3ÈÜÒº£¬¹ýÂË¡£

¢ó. Ï´µÓ³Áµí¡£

¢ô. Ï´µÓºóµÄ³ÁµíÔÚζȵÍÓÚ100¡æµÄÌõ¼þϸÉÔï£¬ÖÆµÃ¸ß´¿MnCO3¹ÌÌå¡£

£¨1£©Í¼1ÖÐʯ»ÒÈéµÄ×÷ÓÃÊÇ__________£¬ÉÕÆ¿Öз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ__________¡£

£¨2£©¸ù¾Ýͼ2¡°½þÃÌ¡±µÄ·´Ó¦ÊÊÒËʱ¼äÊÇ____________________¡£ÈôʵÑéÖн«N2»»³É¿ÕÆø£¬²âµÃ·´Ó¦ÒºÖÐMn2+¡¢SO42-µÄŨ¶ÈËæ·´Ó¦Ê±¼ät±ä»¯Èçͼ3¡£µ¼ÖÂÈÜÒºÖÐMn2+¡¢SO42-Ũ¶È±ä»¯²úÉúÃ÷ÏÔ²îÒìµÄÔ­ÒòÊÇ______________________________¡£

ͼ2                                             ͼ3

£¨3£©¢òÖмÓÈëÉÔ¹ýÁ¿NaHCO3ÈÜÒº£¬¿ØÖÆÈÜÒºpHÔÚ__________·¶Î§£¬Ð´³ö¼ÓÈëNaHCO3£¬ºó·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ____________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


»¯Ñ§ÓëÉú»î¡¢Éç»áÃÜÇÐÏà¹Ø¡£ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ£¨   £©

A£®ÀûÓÃÌ«ÑôÄܵÈÇå½àÄÜÔ´´úÌæ»¯Ê¯È¼ÁÏ£¬ÓÐÀûÓÚ½ÚÔ¼×ÊÔ´¡¢±£»¤»·¾³

B£®·²º¬ÓÐʳƷÌí¼Ó¼ÁµÄʳÎï¶ÔÈËÌ彡¿µ¾ùÓк¦£¬²»¿ÉʳÓÃ

C£®Îª·ÀÖ¹µç³ØÖеÄÖØ½ðÊôµÈÎÛȾÍÁÈÀºÍË®Ì壬Ӧ»ý¼«¿ª·¢·Ïµç³ØµÄ×ÛºÏÀûÓü¼Êõ

D£®ÌᳫÈËÃǹºÎïʱ²»ÓÃËÜÁÏ´ü£¬ÊÇΪÁË·ÀÖ¹°×É«ÎÛȾ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏòºãΡ¢ºãÈÝ£¨2L£©µÄÃܱÕÈÝÆ÷ÖгäÈë2molXºÍÒ»¶¨Á¿µÄY£¬·¢Éú·´Ó¦£º2X(g)£«Y(g)2Z(g)

¦¤H£¼0£¬4minºó´ïµ½Æ½ºâc(X)£½0.2mol·L-1£¬ÇÒXÓëYµÄת»¯ÂÊÏàµÈ¡£ÏÂÁÐ˵·¨Öв»ÕýÈ·µÄÊÇ£¨   £©

A£®´ïµ½Æ½ºâʱ£¬ÔÙ³äÈë1molX£¬·´Ó¦µÄìʱ䱣³Ö²»±ä

B£®ÓÃY±íʾ4minÄڵķ´Ó¦ËÙÂÊΪ0.1 mol·L-1·min-1

C£®ÔÙÏòÈÝÆ÷ÖгäÈë1molZ£¬´ïµ½ÐÂÆ½ºâ£¬c(X)¡Ãc(Y)£½2¡Ã1

D£®4minºó£¬ÈôÉý¸ßζȣ¬Æ½ºâ³£ÊýKÔö´ó

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


³£ÎÂÏ£¬0.1mol·L£­1ijһԪËá(HA)ÈÜÒºÖÐc(OH£­)/c(H£«)£½1¡Á10£­8£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨   £©

A£®ÓÉpH£½3µÄHAÓëpH£½11µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ÈÜÒºÖÐc(Na£«)£¾c(Ac)£¾c(OH¡ª)£¾c(H£«)

B£®0.1mol·L£­1HAÈÜÒºÓë0.05mol·L£­1NaOHÈÜÒºµÈÌå»ý»ìºÏºóËùµÃÈÜÒºÖУ¬

2c(H£«)£«c(HA)£½c(A£­)£«c(OH£­)

C£®¸ÃÈÜÒºÖÐÓÉË®µçÀë³öµÄc(H£«)£½1¡Á10£­11 mol·L£­1

D£®Å¨¶È¾ùΪ0.1mol/LµÄHAºÍNaAÈÜÒºµÈÌå»ý»ìºÏºó£¬ÈôÈÜÒº³ÊËáÐÔ£¬Ôò

c(A£­)£¾c(HA)£¾c(Na£«)£¾c(H£«)£¾c(OH£­)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


²ÝËáÊǶþÔªÈõËᣬ²ÝËáÇâ¼ØÈÜÒº³ÊËáÐÔ¡£ÔÚ0.1mol·L£­1 KHC2O4ÈÜÒºÖУ¬ÏÂÁйØÏµÕýÈ·µÄÊÇ                                  (    )                                            

A£®c(K+)+c(H+) = c(HC2O4£­)+c(OH£­)+c(C2O42£­

B£®c(HC2O4£­)+c (C2O42£­) = 0.1 mol·L£­1   

C£®c(C2O42£­) < c(H2C2O4)                  

D£®c(K+) = c(H2C2O4)+c(HC2O4£­)+c(C2O42£­)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÒÑÖª£º(NH4)2CO3(s)=NH4HCO3(s)+NH3(g)  ¡÷= + 74.9 kJ·mol-1£¬ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ       £¨    £©

A£®¸Ã·´Ó¦ÖÐìØ±ä¡¢ìʱä½Ô´óÓÚ0                          
B£®¸Ã·´Ó¦ÊÇÎüÈÈ·´Ó¦£¬Òò´ËÒ»¶¨²»ÄÜ×Ô·¢½øÐÐ

  C£®Ì¼ËáÑηֽⷴӦÖÐìØÔö¼Ó£¬Òò´ËÈκÎÌõ¼þÏÂËùÓÐ̼ËáÑηֽâÒ»¶¨×Ô·¢½øÐÐ
D£®ÄÜ×Ô·¢½øÐеķ´Ó¦Ò»¶¨ÊÇ·ÅÈÈ·´Ó¦£¬²»ÄÜ×Ô·¢½øÐеķ´Ó¦Ò»¶¨ÊÇÎüÈÈ·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


²ÝËáÊǶþÔªÈõËᣬ²ÝËáÇâ¼ØÈÜÒº³ÊËáÐÔ¡£ÔÚ0.1mol·L£­1 KHC2O4ÈÜÒºÖУ¬ÏÂÁйØÏµÕýÈ·µÄÊÇ                                  (    )                                            

A£®c(K+)+c(H+) = c(HC2O4£­)+c(OH£­)+c(C2O42£­

B£®c(HC2O4£­)+c (C2O42£­) = 0.1 mol·L£­1   

C£®c(C2O42£­) < c(H2C2O4)                  

D£®c(K+) = c(H2C2O4)+c(HC2O4£­)+c(C2O42£­)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÓÒͼÊÇijѧУʵÑéÊÒ´Ó»¯Ñ§ÊÔ¼ÁÉ̵êÂò»ØµÄÁòËáÊÔ¼Á±êÇ©ÉϵIJ¿·ÖÄÚÈÝ¡£ÏÖÓøÃŨÁòËáÅäÖÆ100 mL¡¡1 mol/LµÄÏ¡ÁòËá¡£¿É¹©Ñ¡ÓõÄÒÇÆ÷ÓУº

¢Ù½ºÍ·µÎ¹Ü£»¢ÚÉÕÆ¿£»¢ÛÉÕ±­£»¢Ü Ò©³×£»¢ÝÁ¿Í²£»¢ÞÍÐÅÌÌìÆ½¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)ÅäÖÆÏ¡ÁòËáʱ£¬ÉÏÊöÒÇÆ÷Öв»ÐèҪʹÓõÄÓР         £¨Ñ¡ÌîÐòºÅ£©£¬

»¹È±ÉÙµÄÒÇÆ÷ÓР            ¡¡¡¡         £¨Ð´ÒÇÆ÷Ãû³Æ£©£»

(2)¾­¼ÆË㣬ÅäÖÆ100mL1mol/LµÄÏ¡ÁòËáÐèÒªÓÃÁ¿Í²Á¿È¡ÉÏÊöŨÁòËáµÄÌå»ýΪ   ¡¡    mL£¨±£ÁôһλСÊý£©£¬Á¿È¡Å¨ÁòËáʱӦѡÓà         £¨Ñ¡Ìî¢Ù10mL¡¢¢Ú50mL ¡¢¢Û100mL£©¹æ¸ñµÄÁ¿Í²£»

(3)¢ÙÅäÖÆ¹ý³ÌÖУ¬Èô½«Ï´µÓÉÕ±­ËùµÃµÄÈÜÒºÖ±½Óµ¹Èë·ÏÒº¸×ÖУ¬Ôòµ¼ÖÂ×îºóËùµÃÈÜÒºµÄŨ¶È

___ _____      (Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°Îޱ仯¡±£¬ÏÂͬ)¡£

 ¢Ú¶¨ÈÝʱ¸©ÊÓÈÝÁ¿Æ¿µÄ¿Ì¶ÈÏߣ¬ÔòËùÅäµÃµÄÈÜҺŨ¶È_____         __¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸