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    (14分)某中学课外兴趣小组用惰性电极电解饱和食盐水（含少量Ca2+、Mg2+)作系列探究，装置如下图所示：

    (1)电解时，甲同学发现电极a附近溶液出现浑浊,请用离子方程式表示原因____________

    (2)一段时间后，你认为C中溶液可能出现的现象是______，请用离子方程式表示原因________________________

    (3) 实验结束后，乙同学将A中的物质冷却后加入到H2S溶液中发现有气泡出现，但加人到稀盐酸中却没有任何现象。请用化学方程式和简要的文字解释原因____________

    (4) 随着反应的进行，兴趣小组的同学们都特别注意到D中溶液红色逐渐褪去。他们对溶液红色褪去主要原因提出了如下假设，请你完成假设二。

    假设一:B中逸出气体与水反应生成的物质有强氧化性，使红色逐渐褪去；

    假设二 ：__________________________________________。

    (5) 请你设计实验验证上述假设一，写出实验步骤及结论___________________________________________________________________________

     

    【答案】

    （共 14 分）

    （1）2H+ + 2e-=H2↑,Mg2+ + 2OH-=Mg（OH）2↓（2分）

    （2）有淡黄色沉淀（2分）   Cl2+S2-=2Cl-+S↓（2分）

    （3）Ag置换H2S的反应式为：2Ag+H2S=Ag2S+H2,表明Ag2S的溶解度比AgCl小很多（3分）

    （4）可能是H+中和了OH-造成褪色（2分）

    （5）1.取少量D中褪色后的溶液于试管中

    2.滴加1-2滴酚酞溶液,如果又显红色,则假设一正确（3分）

    【解析】略

     

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