Question

Na₂O₂¼¸ºõÄÜÓëËùÓг£¼ûµÄÆø̬·Ç½ðÊôÑõ»¯ÎïÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦£¬È磺2Na₂O₂+2CO₂=2Na₂CO₃+O₂£¬Na₂O₂+CO=Na₂CO₃£®
£¨1£©ÊÔ·Ö±ðд³öNa₂O₂ÓëSO₂¡¢SO₃·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º

 

£¬

 

£®
£¨2£©Í¨¹ý±È½Ï¿ÉÖª£¬µ±·Ç½ðÊôÔªËØ´¦ÓÚ

 

¼Û̬ʱ£¬ÓëNa₂O₂·´Ó¦ÓÐO₂Éú³É£®
£¨3£©µÈÎïÖʵÄÁ¿µÄN₂¡¢O₂¡¢CO₂µÄ»ìºÏÆøÌåͨ¹ýNa₂O₂ºó£¬Ìå»ý±äΪԭÌå»ýµÄ

8

9

£¨Í¬ÎÂͬѹÏ£©£¬Õâʱ»ìºÏÆøÌåÖÐN₂¡¢O₂¡¢CO₂ÎïÖʵÄÁ¿Ö®±ÈΪ

 

£®

Answer 1

¿¼µã£ºÎïÖʵÄÁ¿µÄÏà¹Ø¼ÆËã,ÄƵÄÖØÒª»¯ºÏÎï

רÌ⣺¼ÆËãÌâ,ÔªËؼ°Æ仯ºÏÎï

·ÖÎö£ºÓÉÌâ¸øÐÅÏ¢¿ÉÖª£¬¹ýÑõ»¯ÄÆÓëµÍ¼Û̬µÄ·Ç½ðÊôÑõ»¯Îï·¢Éú»¯ºÏ·´Ó¦£¬Éú³É¸Ã·Ç½ðÊôµÄ×î¸ß¼Û̬µÄº¬ÑõËáÑΣ¬´ËʱûÓÐÑõÆø²úÉú£»µ±·Ç½ðÊôÑõ»¯ÎïÓиߵͼÛ̬ʱ£¬¹ýÑõ»¯ÄÆÓë×î¸ß¼Û̬µÄ·Ç½ðÊôÑõ»¯Îï·´Ó¦Éú³É¸Ã·Ç½ðÊôµÄ×î¸ß¼Û̬µÄº¬ÑõËáÑκÍÑõÆø£»»ìºÏÆøÌåͨ¹ý×ãÁ¿µÄNa₂O₂ºó£¬CO₂ÓëNa₂O₂·´Ó¦£¬N₂ºÍO₂ÓëNa₂O₂²»·´Ó¦£¬¾ÝÆøÌåµÄÌå»ýÖ®±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È£¬¼ÆËã³ö»ìºÏÆøÌåÖÐN₂¡¢O₂ÆøÌåµÄÌå»ýÓëCO₂µÄÌå»ý¹Øϵ£¬ÒԴ˽â´ð¸ÃÌ⣮

½â´ð£º ½â£º£¨1£©¸ù¾Ý¸ù¾Ý¹ýÑõ»¯ÄƺͶþÑõ»¯Ì¼µÄ·´Ó¦£¬¿ÉÒÔÍÆÖª¹ýÑõ»¯ÄƺͶþÑõ»¯Áò·´Ó¦Éú³ÉÑÇÁòËáÄƺÍÑõÆø£¬ÑÇÁòËáÄÆÒ×±»ÑõÆøÑõ»¯ÎªÁòËáÄÆ£¬¼´SO₂+Na₂O₂=Na₂SO₄£¬ÈýÑõ»¯ÁòºÍ¹ýÑõ»¯ÄÆ·´Ó¦Éú³ÉÁòËáÄƺÍÑõÆø£¬¼´2Na₂O₂+2SO₃¨T2Na₂SO₄+O₂£¬
¹Ê´ð°¸Îª£º2Na₂O₂+2SO₂¨T2Na₂SO₄£»2Na₂O₂+2SO₃¨T2Na₂SO₄+O₂£»
£¨2£©¸ù¾Ý·´Ó¦2Na₂O+2CO₂¨T2Na₂CO₃+O₂£¬Na₂O₂+CO¨TNa₂CO₃ºÍ2Na₂O₂+2SO₂¨T2Na₂SO₄£¬2Na₂O₂+2SO₃¨T2Na₂SO₄+O₂£¬±È½Ï¿ÉÖª£ºÔÚÑõ»¯ÎïÖУ¬µ±·Ç½ðÊôÔªËØ´¦ÓÚ×î¸ß¼Ûʱ£¬ÆäÑõ»¯ÎïÓë¹ýÑõ»¯ÄÆ·´Ó¦¾ÍÓÐO₂Éú³É£¬¹Ê´ð°¸Îª£º×î¸ß£»
£¨3£©Ò»¶¨Ìå»ýµÄN₂¡¢O₂¡¢CO₂»ìºÏÆøÌåͨ¹ý×ãÁ¿µÄNa₂O₂ºó£¬CO₂ÓëNa₂O₂·´Ó¦£¬N₂ºÍO₂ÓëNa₂O₂²»·´Ó¦£¬ÉèN₂ºÍO₂ÎïÖʵÄÁ¿Îªxmol£¬CO₂µÄÎïÖʵÄÁ¿Îªymol£¬
·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2CO₂+2Na₂O₂¨T2Na₂CO₃+O₂£¬
¸ù¾ÝÆøÌåµÄÌå»ýÖ®±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È¿ÉÖª£¬

x+0.5y

x+y

=

8

9

£¬
½âÖ®µÃ£ºx=3.5y£¬
N₂¡¢O₂¡¢CO₂ÎïÖʵÄÁ¿Ö®±ÈΪ1.75£º1.75£º1£¬
¹Ê´ð°¸Îª£º1.75£º1.75£º1£®

µãÆÀ£º±¾Ì⿼²é¹ýÑõ»¯ÄÆ֪ʶ£¬²àÖØÓÚѧÉúµÄ·ÖÎöÄÜÁ¦ºÍ×ÔѧÄÜÁ¦µÄ¿¼²é£¬×¢Òâ°ÑÎÕÌâ¸øÐÅÏ¢£¬¾ßÓзÖÎöºÍ½â¾öÎÊÌâµÄÄÜÁ¦£¬ÄѶȲ»´ó£®