ºãÎÂÏ£¬½«16 mol N2Óë24 mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýΪ4LµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2£¨g£©+3H2£¨g£©2NH3£¨g£©£¬10·ÖÖÓºó·´Ó¦´ïƽºâʱ£¬NH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£¬ÏÂÁеĹØ˵·¨ÕýÈ·µÄÊÇ           £¨    £©

      A£®´ïµ½Æ½ºâʱ£¬N2ºÍH2µÄת»¯ÂÊÖ®±ÈΪ1£º1

      B£®10·ÖÖÓÄÚv(H2)=0.35mol/(L¡¤min)

      C£®Æ½ºâ»ìºÏÆøÌåµÄÃܶÈΪ128g/L

      D£®Æ½ºâ»ìºÏÆøÌåÖУ¬n£¨N2£©£ºn£¨H2£©£ºn£¨NH3£©=1£º3£º2

C


½âÎö:

N2£¨g£©+3H2£¨g£©2NH3£¨g£©

           Æðµã£º 16       24            0

          ±ä»¯Á¿£ºx        3x           2x

          ƽºâʱ£º16-x     24-3x         2x

ÓÉƽºâʱ£¬NH3µÄº¬Á¿Îª25%£¬Öªx=4mol.£¬½øÒ»²½¼ÆËãÖª£¬Ö»ÓÐCÕýÈ·

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚºãÎÂÏ£¬½«a mol N2Óëb mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©
£¨1£©·´Ó¦½øÐе½Ä³Ê±¿Ìtʱ£¬nt£¨N2£©=13mol£¬nt£¨NH3£©=6mol£¬¼ÆËãaµÄÖµ
16
16
£®
£¨2£©·´Ó¦´ïƽºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8L£¨ÕÛËã³É±ê¿öÏ£©£¬ÆäÖÐNH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£®¼ÆËãƽºâʱNH3µÄÎïÖʵÄÁ¿
8mol
8mol
£®
£¨3£©Ô­»ìºÏÆøÌåÓëƽºâ»ìºÏÆøÌå×ÜÎïÖʵÄÁ¿Ö®±È£¨Ð´³ö×î¼ò±È£¬ÏÂͬ£©n£¨Ê¼£©£ºn£¨Æ½£©=
5£º4
5£º4
£®
£¨4£©Ô­»ìºÏÆøÌåÖÐa£ºb=
2£º3
2£º3
£®
£¨5£©´ïµ½Æ½ºâʱ£¬N2ºÍH2µÄת»¯ÂÊÖ®±È¦Á£¨N2£©£º¦Á£¨H2£©=
1£º2
1£º2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ºãÎÂÏ£¬½«a mol N2Óëb mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©£¬·´Ó¦´ïƽºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8L£¨±ê×¼×´¿öÏ£©£¬ÆäÖÐNH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£®¼ÆË㣺
£¨1£©´ïµ½Æ½ºâʱ£¬ÏûºÄN2µÄÎïÖʵÄÁ¿£¬n£¨N2£©=
16mol
16mol

£¨2£©Ô­»ìºÏÆøÌåÓëƽºâ»ìºÏÆøÌåµÄѹǿ֮±È£¨Ð´³ö×î¼òÕûÊý±È£©£¬p£¨Ê¼£©£ºp£¨Æ½£©=
5£º4
5£º4
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ºãÎÂÏ£¬½«a mol N2Óëb mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©
£¨1£©Èô·´Ó¦½øÐе½Ä³Ê±¿Ìtʱ£¬nt£¨N2£©=13mol£¬nt£¨NH3£©=6mol£¬Ôòa=
16
16

£¨2£©·´Ó¦´ïƽºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8L£¨±ê¿öÏ£©£¬ÆäÖÐNH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£®ÔòƽºâʱNH3µÄÎïÖʵÄÁ¿Îª
8mol
8mol
£®
£¨3£©Ô­»ìºÏÆøÌåÓëƽºâ»ìºÏÆøÌåµÄ×ÜÎïÖʵÄÁ¿Ö®±ÈΪ
5£º4
5£º4
£®
£¨4£©Æ½ºâ»ìºÏÆøÌåÖУ¬n£¨N2£©£ºn£¨H2£©£ºn£¨NH3£©µÈÓÚ
3£º3£º2
3£º3£º2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÄ£ÄâÌâ ÌâÐÍ£ºµ¥Ñ¡Ìâ

ºãÎÂÏ£¬½«16 mol N2Óë24 mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýΪ4LµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2£¨g£©+3H2£¨g£©2NH3£¨g£©£¬10·ÖÖÓºó·´Ó¦´ïƽºâʱ£¬NH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£¬ÏÂÁеĹØ˵·¨ÕýÈ·µÄÊÇ     
[     ]
A£®´ïµ½Æ½ºâʱ£¬N2ºÍH2µÄת»¯ÂÊÖ®±ÈΪ1£º1   
B£®10·ÖÖÓÄÚv(H2)=0.35mol/(L¡¤min)   
C£®Æ½ºâ»ìºÏÆøÌåµÄÃܶÈΪ128g/L   
D£®Æ½ºâ»ìºÏÆøÌåÖУ¬n£¨N2£©£ºn£¨H2£©£ºn£¨NH3£©=1£º3£º2

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸