£¨2007?Ìì½ò£©U¡¢V¡¢W¡¢X¡¢Y¡¢ZÊÇÔ­×ÓÐòÊýÒÀ´ÎÔö´óµÄÁùÖÖ³£¼ûÔªËØ£®YµÄµ¥ÖÊÔÚW2ÖÐȼÉյIJúÎï¿ÉʹƷºìÈÜÒºÍÊÉ«£®ZºÍWÔªËØÐγɵĻ¯ºÏÎïZ3W4¾ßÓдÅÐÔ£®UµÄµ¥ÖÊÔÚW2ÖÐȼÉÕ¿ÉÉú³ÉUWºÍUW2Á½ÖÖÆøÌ壮XµÄµ¥ÖÊÊÇÒ»ÖÖ½ðÊô£¬¸Ã½ðÊôÔÚUW2ÖоçÁÒȼÉÕÉú³ÉºÚ¡¢°×Á½ÖÖ¹ÌÌ壮
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©VµÄµ¥ÖÊ·Ö×ӵĽṹʽΪ
N¡ÔN
N¡ÔN
£»XWµÄµç×ÓʽΪ
£»ZÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ
µÚËÄÖÜÆÚ£¬µÚVIII×å
µÚËÄÖÜÆÚ£¬µÚVIII×å
£®
£¨2£©UÔªËØÐγɵÄͬËØÒìÐÎÌåµÄ¾§ÌåÀàÐÍ¿ÉÄÜÊÇ£¨ÌîÐòºÅ£©
¢Ù¢Û
¢Ù¢Û
£®
¢ÙÔ­×Ó¾§Ìå    ¢ÚÀë×Ó¾§Ìå    ¢Û·Ö×Ó¾§Ìå    ¢Ü½ðÊô¾§Ìå
£¨3£©U¡¢V¡¢WÐγɵÄ10µç×ÓÇ⻯ÎïÖУ¬U¡¢VµÄÇ⻯Îï·Ðµã½ÏµÍµÄÊÇ£¨Ð´»¯Ñ§Ê½£©
CH4
CH4
£»V¡¢WµÄÇ⻯Îï·Ö×Ó½áºÏH+ÄÜÁ¦½ÏÇ¿µÄÊÇ£¨Ð´»¯Ñ§Ê½£©
NH3
NH3
£¬ÓÃÒ»¸öÀë×Ó·½³Ìʽ¼ÓÒÔÖ¤Ã÷
NH3+H3O+¨TNH4++H2O
NH3+H3O+¨TNH4++H2O
£®
£¨4£©YW2ÆøÌåͨÈëBaCl2ºÍHNO3µÄ»ìºÏÈÜÒº£¬Éú³É°×É«³ÁµíºÍÎÞÉ«ÆøÌåVW£¬Óйط´Ó¦µÄÀë×Ó·½³ÌʽΪ
3SO2+2NO3-+3Ba2++2H2O¨T3BaSO4¡ý+2NO+4H+
3SO2+2NO3-+3Ba2++2H2O¨T3BaSO4¡ý+2NO+4H+
£¬ÓÉ´Ë¿ÉÖªVWºÍYW2»¹Ô­ÐÔ½ÏÇ¿µÄÊÇ£¨Ð´»¯Ñ§Ê½£©
SO2
SO2
£®
·ÖÎö£ºYµÄµ¥ÖÊÔÚW2ÖÐȼÉյIJúÎï¿ÉʹƷºìÈÜÒºÍÊÉ«£®¸ÃÆøÌåΪSO2£¬ÔòYΪSÔªËØ£¬WΪOÔªËØ£¬ZºÍWÔªËØÐγɵĻ¯ºÏÎïZ3W4¾ßÓдÅÐÔ£¬ÔòZ3W4ΪFe3O4£¬ZΪFeÔªËØ£¬UµÄµ¥ÖÊÔÚW2ÖÐȼÉÕ¿ÉÉú³ÉUWºÍUW2Á½ÖÖÆøÌ壬ӦΪCOºÍCO2ÆøÌ壬UΪCÔªËØ£¬XµÄµ¥ÖÊÊÇÒ»ÖÖ½ðÊô£¬¸Ã½ðÊôÔÚUW2ÖоçÁÒȼÉÕÉú³ÉºÚ¡¢°×Á½ÖÖ¹ÌÌ壬ӦΪMgºÍCO2µÄ·´Ó¦£¬ÔòXΪMgÔªËØ£¬¸ù¾ÝU¡¢V¡¢W¡¢X¡¢Y¡¢ZÊÇÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¿ÉÖªVΪNÔªËØ£¬ÒԴ˽â´ðÌâÖи÷ÎÊ£®
£¨1£©VΪNÔªËØ£¬Æäµ¥ÖÊΪN2£¬½á¹¹ÎªN¡ÔN£¬£»XWΪMgO£¬ÎªÀë×Ó»¯ºÏÎZΪFeÔªËØ£¬Ô­×ÓÐòÊýΪ26£¬ÒԴ˽â´ð£»
£¨2£©UΪCÔªËØ£¬Ðγɵĵ¥ÖÊÓнð¸Õʯ¡¢Ê¯Ä«ºÍC60µÈ£»
£¨3£©U¡¢V¡¢WÐγɵÄ10µç×ÓÇ⻯Îï·Ö±ðÊÇCH4¡¢NH3¡¢H2O£¬NH3º¬ÓÐÇâ¼ü£¬·Ðµã±È¼×ÍéµÄ·Ðµã¸ß£¬NH3µÄË®ÈÜÒº³Ê¼îÐÔ£¬ÓëË®±È½Ï¸üÒ×½áºÏH+£»
£¨4£©SO2¾ßÓнÏÇ¿»¹Ô­ÐÔ£¬¿ÉÓÃÇ¿Ñõ»¯ÐÔÎïÖÊHNO3·¢ÉúÑõ»¯»¹Ô­·´Ó¦£¬Éú³ÉÁòËᣬ¼ÓÈëÂÈ»¯±µÉú³ÉÁòËá±µ³Áµí£»ÒÀ¾ÝÑõ»¯»¹Ô­·´Ó¦ÖÐ »¹Ô­¼ÁµÄ»¹Ô­ÐÔ´óÓÚ»¹Ô­²úÎïÅжϣ®
½â´ð£º½â£ºYµÄµ¥ÖÊÔÚW2ÖÐȼÉյIJúÎï¿ÉʹƷºìÈÜÒºÍÊÉ«£®¸ÃÆøÌåΪSO2£¬ÔòYΪSÔªËØ£¬WΪOÔªËØ£¬ZºÍWÔªËØÐγɵĻ¯ºÏÎïZ3W4¾ßÓдÅÐÔ£¬ÔòZ3W4ΪFe3O4£¬ZΪFeÔªËØ£¬UµÄµ¥ÖÊÔÚW2ÖÐȼÉÕ¿ÉÉú³ÉUWºÍUW2Á½ÖÖÆøÌ壬ӦΪCOºÍCO2ÆøÌ壬UΪCÔªËØ£¬XµÄµ¥ÖÊÊÇÒ»ÖÖ½ðÊô£¬¸Ã½ðÊôÔÚUW2ÖоçÁÒȼÉÕÉú³ÉºÚ¡¢°×Á½ÖÖ¹ÌÌ壬ӦΪMgºÍCO2µÄ·´Ó¦£¬ÔòXΪMgÔªËØ£¬¸ù¾ÝU¡¢V¡¢W¡¢X¡¢Y¡¢ZÊÇÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¿ÉÖªVΪNÔªËØ£¬
£¨1£©VΪNÔªËØ£¬Æäµ¥ÖÊΪN2£¬½á¹¹ÎªN¡ÔN£¬£»XWΪMgO£¬ÎªÀë×Ó»¯ºÏÎµç×ÓʽΪ£¬ZΪFeÔªËØ£¬Ô­×ÓÐòÊýΪ26£¬Î»ÓÚÔªËØÖÜÆÚ±íÖеÚËÄÖÜÆÚ£¬µÚVIII×壬
¹Ê´ð°¸Îª£ºN¡ÔN£»£»µÚËÄÖÜÆÚ£¬µÚVIII×壻
£¨2£©UΪCÔªËØ£¬Ðγɵĵ¥ÖÊÓнð¸Õʯ¡¢Ê¯Ä«ºÍC60µÈ£¬·Ö±ðÊôÓÚÔ­×Ó¾§Ìå¡¢»ìºÏ¾§Ìå¡¢·Ö×Ó¾§Ì壬¹Ê´ð°¸Îª£º¢Ù¢Û£»
£¨3£©U¡¢V¡¢WÐγɵÄ10µç×ÓÇ⻯Îï·Ö±ðÊÇCH4¡¢NH3¡¢H2O£¬NH3º¬ÓÐÇâ¼ü£¬·Ðµã±È¼×ÍéµÄ·Ðµã¸ß£¬NH3µÄË®ÈÜÒº³Ê¼îÐÔ£¬ÓëË®±È½Ï¸üÒ×½áºÏH+£¬¿ÉÓÃNH3+H3O+=NH4++H2OµÄ·´Ó¦À´Ö¤Ã÷£¬
¹Ê´ð°¸Îª£ºCH4£»NH3£»NH3+H3O+=NH4++H2O£»
£¨4£©SO2¾ßÓнÏÇ¿»¹Ô­ÐÔ£¬¿ÉÓÃÇ¿Ñõ»¯ÐÔÎïÖÊHNO3·¢ÉúÑõ»¯»¹Ô­·´Ó¦£¬Éú³ÉÁòËᣬ¼ÓÈëÂÈ»¯±µÉú³ÉÁòËá±µ³Áµí£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º3SO2+3Ba2++2H2O+2NO3-=3BaSO4¡ý+2NO¡ü+4H+£¬·´Ó¦ÖжþÑõ»¯Áò×ö»¹Ô­¼Á»¹Ô­ÐÔ´óÓÚ»¹Ô­²úÎïNO£¬
¹Ê´ð°¸Îª£º3SO2+3Ba2++2H2O+2NO3-=3BaSO4¡ý+2NO¡ü+4H+£»SO2£®
µãÆÀ£º±¾Ì⿼²éÔªËØÍƶÏÌ⣬ÌâÄ¿½ÏΪ×ۺϣ¬Éæ¼°µç×Óʽ¡¢¾§ÌåÀàÐÍ¡¢Çâ¼üÒÔ¼°Ñõ»¯»¹Ô­·´Ó¦µÈÎÊÌ⣬±¾ÌâµÄ¹Ø¼üÊÇÕýÈ·ÍƶÏÔªËصÄÖÖÀ࣬עÒâ°ÑÎձȽÏÎÊÌâµÄ½Ç¶È£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

ͬ²½Á·Ï°²á´ð°¸