£¨2011?µÂÖÝÄ£Ä⣩¸ÖÌú¹¤ÒµÊǹú¼Ò¹¤ÒµµÄ»ù´¡£¬¸ÖÌúÉúÐâÏÖÏóÈ´Ëæ´¦¿É¼û£¬Îª´ËÿÄê¹ú¼ÒËðʧ´óÁ¿×ʽð£®Çë»Ø´ð¸ÖÌú¸¯Ê´Óë·À»¤¹ý³ÌÖеÄÓйØÎÊÌ⣮
£¨1£©¸ÖÌúµÄµç»¯Ñ§¸¯Ê´ÔÀíÈçͼ1Ëùʾ£º
¢Ùд³öʯīµç¼«µÄµç¼«·´Ó¦Ê½
O2+4e-+2H2O¨T4OH-
O2+4e-+2H2O¨T4OH-
£»
¢Ú½«¸Ã×°ÖÃ×÷¼òµ¥Ð޸ļ´¿É³ÉΪ¸ÖÌúµç»¯Ñ§·À»¤µÄ×°Öã¬ÇëÔÚͼ1ÐéÏß¿òÄÚËùʾλÖÃ×÷³öÐ޸ģ¬²¢ÓüýÍ·±ê³öµ¼ÏßÖеç×ÓÁ÷¶¯·½Ïò£®
¢Ûд³öÐ޸ĺóʯīµç¼«µÄµç¼«·´Ó¦Ê½
2Cl--2e-¨TCl2¡ü
2Cl--2e-¨TCl2¡ü
£®
£¨2£©Éú²úÖпÉÓÃÑÎËáÀ´³ýÌúÐ⣮ÏÖ½«Ò»ÉúÐâµÄÌúƬ·ÅÈëÑÎËáÖУ¬µ±ÌúÐâ±»³ý¾¡ºó£¬ÈÜÒºÖз¢ÉúµÄ»¯ºÏ·´Ó¦µÄ»¯Ñ§·½³Ìʽ
2FeCl3+Fe¨T3FeCl2
2FeCl3+Fe¨T3FeCl2
£®
£¨3£©ÔÚʵ¼ÊÉú²úÖУ¬¿ÉÔÚÌú¼þµÄ±íÃæ¶ÆÍ·ÀÖ¹Ìú±»¸¯Ê´£®×°ÖÃʾÒâÈçͼ2£º
¢ÙAµç¼«¶ÔÓ¦µÄ½ðÊôÊÇ
Í
Í
£¨Ð´ÔªËØÃû³Æ£©£¬Bµç¼«µÄµç¼«·´Ó¦Ê½ÊÇ
Cu2++2e-¨TCu
Cu2++2e-¨TCu
£®
¢ÚÈôµç¶ÆÇ°Ìú¡¢ÍÁ½Æ¬½ðÊôÖÊÁ¿Ïàͬ£¬µç¶ÆÍê³Éºó½«ËüÃÇÈ¡³öÏ´¾»¡¢ºæ¸É¡¢³ÆÁ¿£¬¶þÕßÖÊÁ¿²îΪ5.12g£¬Ôòµç¶Æʱµç·ÖÐͨ¹ýµÄµç×ÓΪ
0.08
0.08
mol£®
¢Û¶Æ²ãÆÆËðºó£¬¶ÆÍÌú±È¶ÆпÌú¸üÈÝÒ×±»¸¯Ê´£¬Çë¼òҪ˵Ã÷ÔÒò
Ìú±ÈÍ»îÆ㬶ƲãÆÆ»µºó£¬ÔÚ³±Êª»·¾³ÖÐÐγÉÔµç³Ø£¬ÌúΪ¸º¼«£¬¼ÓËÙÌúµÄ¸¯Ê´
Ìú±ÈÍ»îÆ㬶ƲãÆÆ»µºó£¬ÔÚ³±Êª»·¾³ÖÐÐγÉÔµç³Ø£¬ÌúΪ¸º¼«£¬¼ÓËÙÌúµÄ¸¯Ê´
£®