ʵÑéÊÒ¿ÉÓÃNH4HCO3ºÍNaClΪԭÁÏÖƱ¸´¿¼î£®Çë¸ù¾ÝϱíÊý¾ÝºÍʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣮

¡¡¡¡30¡æʱ¼¸ÖÖÑεÄÈܽâ¶È(g/100 gË®)(¼ûϱí)

¡¡¡¡ÖƱ¸´¿¼îµÄÖ÷Òª²½ÖèÈçÏ£º

¡¡¡¡¢ÙÅäÖÆ50 mLÖÊÁ¿·ÖÊýԼΪ25£¥µÄ´ÖʳÑÎË®ÈÜÒº(ÃܶȽüËÆ1 g¡¤cm£­3)£®

¡¡¡¡¢Ú¾«ÖÆʳÑÎË®(´ÖʳÑÎÖк¬ÓÐÉÙÁ¿Ca2+¡¢Mg2+¡¢µÈÔÓÖÊ)ÓÃÑÎËὫÂËÒºpHµ÷ÖÁ7£®

¡¡¡¡¢Û¼ÓÈÈʳÑÎË®£¬½«ÈÜҺζȿØÖÆÔÚ30¡«35¡æ£®

¡¡¡¡¢ÜÔÚ²»¶Ï½Á°èÏ£¬·Ö´Î½«ÑÐϸµÄNH4HCO3¼ÓÈëʳÑÎË®ÖУ¬¼ÓÍêÁϺ󣬼ÌÐø±£Î£¬½Á°è°ëСʱ£®

¡¡¡¡¢Ý¾²Ö㬳ÃÈȹýÂË£¬»ØÊÕĸҺ£®¾§ÌåÓÃÕôÁóˮϴµÓÁ½´Î£®

¡¡¡¡¢Þ½«¾§Ìå×ÆÉÕ£¬µÃµ½´¿¼î£®

(1)

²½Öè¢ÙÖУ¬ÅäÖÆÈÜÒºµÄ×îºóÒ»²½²Ù×÷ÊÇ________£®

(2)

²½Öè¢ÚÖУ¬ÊÇ·ñÐèÒª³ýÈ¥£¿________£¬ÀíÓÉÊÇ________£®

(3)

²½Öè¢ÜÖÐËùÓвÙ×÷µÄ¹²Í¬Ä¿µÄÊÇ________£®

(4)

²½Öè¢ÝÖо§ÌåµÄÏ´µÓÒºÖÐÖ÷Òªº¬ÓеÄÔÓÖÊÑôÀë×ÓÊÇ________£¬Í¨³£Çé¿öÏ£¬¼ìÑéÕâÖÖÑôÀë×ӵķ½·¨ÊÇ________£®

´ð°¸£º
½âÎö£º

(1)

Óò£Á§°ô½Á°è

(2)

²»ÐèÒª,³ýÈ¥Ca2+¡¢Mg2+ºó£¬ÔÚÈÜÒºËù¿ØÖƵÄζÈÏ£¬¿ÉÄÜ´æÔÚµÄÁòËáÑεÄÈܽâ¶È±ÈNaHCO3´ó£¬Çҵĺ¬Á¿ÉÙ£¬¹ýÂ˺ó»áÁôÔÚĸҺÖÐ

(3)

ʹÉú³ÉNaHCO3µÄ·´Ó¦³ä·Ö½øÐÐ

(4)

NH4+,È¡ÉÙÐíÑùÆ·£¬¼ÓÈëÇâÑõ»¯ÄÆ£¬¼ÓÈÈ£¬²úÉúµÄÆøÌåÄÜʹºìɫʯÈïÊÔÖ½±äÀ¶(»òÓÃÕºÓÐŨÑÎËáµÄ²£Á§°ô¼ìÑéÆøÌ壬Óа×Ñ̲úÉú)£¬Ö¤Ã÷º¬ÓÐNH4+


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÉ½¶«Ê¡ÇàÖÝÒ»ÖÐ2012½ì¸ßÈý»¯Ñ§Ò»ÂÖ¸ú×ÙѵÁ·£ºµÚ10ÕµÚ2½²ÎïÖʵķÖÀëºÍÌá´¿(³¿Æ°æ) ³¿Æ°æ ÌâÐÍ£º058

ʵÑéÊÒ¿ÉÓÃNH4HCO3ºÍNaClΪԭÁÏÖƱ¸´¿¼î£®Çë¸ù¾ÝϱíÊý¾ÝºÍʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣺

ÖƱ¸´¿¼îµÄ²½ÖèÈçÏ£º

¢ÙÅäÖÆ50 mLÔ¼25£¥µÄ´ÖʳÑÎË®ÈÜÒº(ÃܶȽüËÆΪ1 g/cm3)£®

¢Ú¾«ÖÆʳÑÎË®(´ÖʳÑÎÖк¬ÓÐÉÙÁ¿Ca2+¡¢Mg2+¡¢SOµÈÔÓÖÊ)ÓÃÑÎËὫÂËÒºµÄpHÖµµ÷ÖÁ7£®

¢Û¼ÓÈÈʳÑÎË®£¬½«ÈÜҺζȿØÖÆÔÚ30¡æ¡«35¡æ£®

¢ÜÔÚ²»¶Ï½Á°èÏ£¬·Ö´Î½«ÑÐϸµÄNH4HCO3¼ÓÈëʳÑÎË®ÖУ¬¼ÓÍêÁϺ󣬼ÌÐø±£Î¡¢½Á°è°ëСʱ£®

¢Ý¾²Ö㬳ÃÈȹýÂË£¬»ØÊÕĸҺ£®¾§ÌåÓÃÕôÁóˮϴµÓÁ½´Î£®

¢Þ½«¾§Ìå×ÆÉÕ£¬µÃµ½´¿¼î£®

(1)²½Öè¢ÙÖУ¬ÅäÖÆÈÜÒºµÄ×îºóÒ»²½²Ù×÷ÊÇ________£»

(2)²½Öè¢ÚÖУ¬SOÊÇ·ñÐèÒª³ýÈ¥£¿________£¬ÀíÓÉÊÇ________£®

(3)²½Öè¢ÜÖÐËùÓвÙ×÷µÄ¹²Í¬Ä¿µÄÊÇ________£»

(4)²½Öè¢ÝÖо§ÌåµÄÏ´µÓÒºÖÐÖ÷Òªº¬ÓеÄÔÓÖÊÑôÀë×ÓÊÇ________£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÕã½­Ê¡Äþ²¨ËÄÖи߶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

£¨8·Ö£©ÊµÑéÊÒ¿ÉÓÃNH4HCO3ºÍNaClΪԭÁÏÖƱ¸´¿¼î¡£Çë¸ù¾ÝϱíÊý¾ÝºÍʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣺ 30¡æʱ¼¸ÖÖÑεÄÈܽâ¶È£¯g

NaCl
NH4HCO3
NaHCO3
NH4Cl
Na2SO4
£¨NH4£©2SO4
CaCl2
MgCl2
CaSO4
36.3
27.0
11.1
41.4
40.8
78
51.7
26.2
0.165
ÖƱ¸´¿¼îµÄ²½ÖèÈçÏ£º
¢ÙÅäÖÆ50 mLÔ¼25£¥µÄ´ÖʳÑÎË®ÈÜÒº£¨ÃܶȽüËÆΪ1 g£¯mL£©¡£
¢Ú¾«ÖÆʳÑÎË®£¨´ÖʳÑÎÖк¬ÓÐÉÙÁ¿Ca2+¡¢Mg2+¡¢SO42-µÈÔÓÖÊ£©£¬ÓÃÑÎËὫÂËÒºµÄpHÖµµ÷ÖÁ7¡£
¢Û¼ÓÈÈʳÑÎË®£¬½«ÈÜҺζȿØÖÆÔÚ30 ©¤ 35¡æ¡£
¢ÜÔÚ²»¶Ï½Á°èÏ£¬·Ö´Î½«ÑÐϸµÄNH4HCO3¼ÓÈëʳÑÎË®ÖУ¬¼ÓÍêÁϺ󣬼ÌÐø±£Î¡¢½Á°è°ëСʱ¡£
¢Ý¾²Ö㬳ÃÈȹýÂË£¬»ØÊÕĸҺ¡£¾§ÌåÓÃÕôÁóˮϴµÓÁ½´Î¡£
¢Þ½«¾§Ìå×ÆÉÕ£¬µÃµ½´¿¼î¡£
£¨1£©²½Öè¢ÙÖУ¬ÅäÖÆÈÜÒºµÄ×îºóÒ»²½²Ù×÷ÊÇ               £»
£¨2£©²½Öè¢ÚÖУ¬SO42-ÊÇ·ñÐèÒª¼ÓÈëijÖÖÊÔ¼Á³ýÈ¥£¿   £¬ÀíÓÉÊÇ             
£¨3£©²½Öè¢ÜÖÐËùÓвÙ×÷µÄ¹²Í¬Ä¿µÄÊÇ             £»
£¨4£©²½Öè¢ÝÖо§ÌåµÄÏ´µÓÒºÖÐÖ÷Òªº¬ÓеÄÔÓÖÊÑôÀë×ÓÊÇ   £¬ÔÚͨ³£Çé¿öÏ£¬¼ìÑéÕâÖÖÑôÀë×ÓµÄʵÑé²Ù×÷Ϊ             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012ÄêÈ˽̰æ¸ßÖл¯Ñ§Ñ¡ÐÞ6 2.1 ÎïÖʵķÖÀëºÍÌá´¿Á·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

ʵÑéÊÒ¿ÉÓÃNH4HCO3ºÍNaClΪԭÁÏÖƱ¸´¿¼î¡£Çë¸ù¾ÝϱíÊý¾ÝºÍʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣺                 30¡æʱ¼¸ÖÖÑεÄÈܽâ¶È£¯g

NaCl

NH4HCO3

NaHCO3

NH4Cl

Na2SO4

CaCl2

MgCl2

CaSO4

36.3

27.0

11.1

41.4

40.8

78

51.7

26.2

0.165

ÖƱ¸´¿¼îµÄ²½ÖèÈçÏ£º

¢Ù ÅäÖÆ50 mLÔ¼25£¥µÄ´ÖʳÑÎË®ÈÜÒº£¨ÃܶȽüËÆΪ1 g£¯cm3£©¡£

¢Ú ¾«ÖÆʳÑÎË®£¨´ÖʳÑÎÖк¬ÓÐÉÙÁ¿Ca2+¡¢Mg2+¡¢µÈÔÓÖÊ£©ÓÃÑÎËὫÂËÒºµÄpHÖµµ÷ÖÁ7¡£

¢Û ¼ÓÈÈʳÑÎË®£¬½«ÈÜҺζȿØÖÆÔÚ30 ©¤ 35¡æ¡£

¢Ü ÔÚ²»¶Ï½Á°èÏ£¬·Ö´Î½«ÑÐϸµÄNH4HCO3¼ÓÈëʳÑÎË®ÖУ¬¼ÓÍêÁϺ󣬼ÌÐø±£Î¡¢ ½Á°è°ëСʱ¡£

¢Ý ¾²Ö㬳ÃÈȹýÂË£¬»ØÊÕĸҺ¡£¾§ÌåÓÃÕôÁóˮϴµÓÁ½´Î¡£

¢Þ ½«¾§Ìå×ÆÉÕ£¬µÃµ½´¿¼î¡£

£¨1£©²½Öè¢ÙÖУ¬ÅäÖÆÈÜÒºµÄ×îºóÒ»²½²Ù×÷ÊÇ______________________£»

£¨2£©²½Öè¢ÚÖУ¬SO42-ÊÇ·ñÐèÒª³ýÈ¥£¿_________£¬ÀíÓÉÊÇ________________

£¨3£©²½Öè¢ÜÖÐËùÓвÙ×÷µÄ¹²Í¬Ä¿µÄÊÇ_____________£»

£¨4£©²½Öè¢ÝÖо§ÌåµÄÏ´µÓÒºÖÐÖ÷Òªº¬ÓеÄÔÓÖÊÑôÀë×ÓÊÇ____________£¬ÔÚͨ³£Çé¿öÏ£¬¼ìÑéÕâÖÖÑôÀë×ӵķ½·¨_______________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìÕã½­Ê¡¸ß¶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

£¨8·Ö£©ÊµÑéÊÒ¿ÉÓÃNH4HCO3ºÍNaClΪԭÁÏÖƱ¸´¿¼î¡£Çë¸ù¾ÝϱíÊý¾ÝºÍʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣺ 30¡æʱ¼¸ÖÖÑεÄÈܽâ¶È£¯g

NaCl

NH4HCO3

NaHCO3

NH4Cl

Na2SO4

£¨NH4£©2SO4

CaCl2

MgCl2

CaSO4

36.3

27.0

11.1

41.4

40.8

78

51.7

26.2

0.165

ÖƱ¸´¿¼îµÄ²½ÖèÈçÏ£º

¢Ù ÅäÖÆ50 mLÔ¼25£¥µÄ´ÖʳÑÎË®ÈÜÒº£¨ÃܶȽüËÆΪ1 g£¯mL£©¡£

¢Ú ¾«ÖÆʳÑÎË®£¨´ÖʳÑÎÖк¬ÓÐÉÙÁ¿Ca2+¡¢Mg2+¡¢SO42-µÈÔÓÖÊ£©£¬ÓÃÑÎËὫÂËÒºµÄpHÖµµ÷ÖÁ7¡£

¢Û ¼ÓÈÈʳÑÎË®£¬½«ÈÜҺζȿØÖÆÔÚ30 ©¤ 35¡æ¡£

¢Ü ÔÚ²»¶Ï½Á°èÏ£¬·Ö´Î½«ÑÐϸµÄNH4HCO3¼ÓÈëʳÑÎË®ÖУ¬¼ÓÍêÁϺ󣬼ÌÐø±£Î¡¢ ½Á°è°ëСʱ¡£

¢Ý ¾²Ö㬳ÃÈȹýÂË£¬»ØÊÕĸҺ¡£¾§ÌåÓÃÕôÁóˮϴµÓÁ½´Î¡£

¢Þ ½«¾§Ìå×ÆÉÕ£¬µÃµ½´¿¼î¡£

£¨1£©²½Öè¢ÙÖУ¬ÅäÖÆÈÜÒºµÄ×îºóÒ»²½²Ù×÷ÊÇ                £»

£¨2£©²½Öè¢ÚÖУ¬SO42-ÊÇ·ñÐèÒª¼ÓÈëijÖÖÊÔ¼Á³ýÈ¥£¿    £¬ÀíÓÉÊÇ             

£¨3£©²½Öè¢ÜÖÐËùÓвÙ×÷µÄ¹²Í¬Ä¿µÄÊÇ              £»

£¨4£©²½Öè¢ÝÖо§ÌåµÄÏ´µÓÒºÖÐÖ÷Òªº¬ÓеÄÔÓÖÊÑôÀë×ÓÊÇ    £¬ÔÚͨ³£Çé¿öÏ£¬¼ìÑéÕâÖÖÑôÀë×ÓµÄʵÑé²Ù×÷Ϊ              ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸