¸ù¾ÝÒÔÏÂʵÑéÄÚÈݻشðÎÊÌ⣺
¢ÙÉúÎï×éÖ¯Öл¹Ô­Ìǵļø¶¨           ¢ÚÉúÎï×éÖ¯ÖÐÖ¬·¾µÄ¼ø¶¨
¢ÛÉúÎï×éÖ¯Öе°°×Öʵļø¶¨           ¢Ü¹Û²ìÖ²Îïϸ°ûµÄÖʱڷÖÀëºÍ¸´Ô­
¢ÝÒ¶ÂÌÌåÖÐÉ«ËصÄÌáÈ¡ºÍ·ÖÀë         ¢ÞDNAµÄ´ÖÌáÈ¡Óë¼ø¶¨
¢ß¹Û²ì¸ù¼â·ÖÉú×é֯ϸ°ûµÄÓÐË¿·ÖÁÑ   ¢à̽¾¿½Íĸ¾úϸ°ûºôÎüµÄ·½Ê½
£¨1£©ÔÚÉÏÊöʵÑé¹ý³ÌÖУ¬±ØÐë½èÖúÏÔ΢¾µ²ÅÄÜÍê³ÉµÄÊǣߣߣߣߣ¨ÐòºÅ£©£¬ÊµÑéÖÐÐèҪˮԡ¼ÓÈȵÄÓУߣߣߣߣ¨ÐòºÅ£©
£¨2£©ÔÚÉÏÊöʵÑéÖУ¬³£Óõ½¾Æ¾«µÄʵÑéÓТڢݢޢߣ¬ÆäÖоƾ«ËùÆðµÄ×÷Ó÷ֱðÊÇ¢ÚÏ´È¥¸¡É«¡¢£ß£ß£ß£ß¡¢£ß£ß£ß£ß¡¢£ß£ß£ß£ß¡£
£¨3£©ÓÉÓÚʵÑé²ÄÁÏÓÃÆ·»òÊÔ¼ÁËùÏÞ£¬ÓÐʱºòÐèÒªÉè·¨Ìæ´ú¡£ÏÂÁи÷Ïî´¦ÀíÖÐÕýÈ·µÄÊÇ£¨   £©

A£®×ö¢ßʵÑéʱ£¬¿ÉÓÃËâÒ¶´úÌæÑó´Ð¸ù¼â
B£®×ö¢ÜʵÑéʱ£¬¿ÉÓü¦Ñªºìϸ°û´úÌæ×ÏÉ«Ñó´Ð±íƤϸ°û
C£®×ö¢ÝʵÑéʱ£¬¿ÉÓøɾ»µÄϸɳ´úÌæ¶þÑõ»¯¹è
D£®×ö¢ÚʵÑéʱ£¬¿ÉÓÃÁúµ¨×Ï´úÌæËÕµ¤IIIȾҺ

£¨1£©¢Ú¢Ü¢ß  ¢Ù¢Þ
£¨2£©¢ÝÈܽâÒ¶ÂÌÌåÉ«ËØ ¢Þ½«DNAÓëµ°°×ÖÊ·ÖÀ렢߹̶¨Ö²Îïϸ°û £¨3£©C

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2012-2013ѧÄê½­Î÷¹ã²ýÒ»ÖС¢³çÈÊÒ»Öи߶þÉÏѧÆÚÆÚÖÐÁª¿¼ÉúÎïÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£º×ÛºÏÌâ

¸ù¾ÝÒÔÏÂʵÑéÄÚÈݻشðÎÊÌ⣺
¢ÙÉúÎï×éÖ¯Öл¹Ô­Ìǵļø¶¨
¢ÚÉúÎï×éÖ¯ÖÐÖ¬·¾µÄ¼ø¶¨
¢ÛÉúÎï×éÖ¯Öе°°×Öʵļø¶¨
¢Ü¹Û²ìÖ²Îïϸ°ûµÄÖʱڷÖÀëºÍ¸´Ô­
¢ÝÂÌÒ¶ÖÐÉ«ËصÄÌáÈ¡ºÍ·ÖÀë
¢Þ¹Û²ìDNAºÍRNAÔÚϸ°ûÖеķֲ¼
¢ß¹Û²ì¸ù¼â·ÖÉú×é֯ϸ°ûµÄÓÐË¿·ÖÁÑ
¢à̽¾¿½Íĸ¾úϸ°ûºôÎüµÄ·½Ê½
¢áÌåÑéÖƱ¸Ï¸°ûĤµÄ·½·¨
£¨1£©ÔÚÉÏÊöʵÑé¹ý³ÌÖУ¬±ØÐë½èÖúÏÔ΢¾µ²ÅÄÜÍê³ÉµÄÊÇ                   £¨ÌîÐòºÅ£©£¬ÊµÑéÖÐÐèҪˮԡ¼ÓÈȵÄÓР                 £¨ÌîÐòºÅ£©¡£
£¨2£©ÔÚÉÏÊöʵÑéÖУ¬ÐèÒªÓõ½¾Æ¾«µÄʵÑéÓТڡ¢¢Ý£»ÐèÒªÓõ½ÑÎËáµÄÓТޡ¢¢ß£¬ÆäÖоƾ«ËùÆðµÄ×÷Ó÷ֱðÊÇ¢Ú                          ¡£ ¢Ý                              ¡£ÆäÖÐÑÎËáËùÆðµÄ×÷Ó÷ֱðÊÇ¢Þ                                  ¡£¢ß                               ¡£
£¨3£©ÓÉÓÚʵÑé²ÄÁÏÓÃÆ·»òÊÔ¼ÁËùÏÞ£¬ÓÐʱºòÐèÒªÉè·¨Ìæ´ú¡£ÏÂÁи÷Ïî´¦ÀíÖÐÕýÈ·µÄÓУ¨   £©
£¨ÓÐÒ»¸ö»ò¶à¸ö´ð°¸£©

A£®×ö¢ßʵÑéʱ£¬¿ÉÓÃÑó´ÐÁÛƬҶ´úÌæÑó´Ð¸ù¼â
B£®×ö¢áʵÑéʱ£¬¿ÉÓü¦Ñªºìϸ°û´úÌ沸È鶯ÎïѪºìϸ°û
C£®×ö¢ÙʵÑéʱ£¬¿ÉÓðàÊÏÊÔ¼Á´úÌæì³ÁÖÊÔ¼Á
D£®×ö¢àʵÑéʱ£¬¿ÉÓÃäå÷êÏã²Ý·ÓÀ¶Ë®ÈÜÒº´úÌæ³ÎÇåʯ»ÒË®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2011-2012ѧÄ꺣ÄÏÊ¡º£ÄÏÖÐѧ¸ßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔÉúÎïÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£º×ÛºÏÌâ

£¨16·Ö£© ¸ù¾ÝÒÔÏÂʵÑéÄÚÈݻشðÎÊÌ⣺

£¨1£©ÔÚÉÏÊöʵÑé¹ý³ÌÖУ¬±ØÐë½èÖúÏÔ΢¾µ²ÅÄÜÍê³ÉµÄÊÇ            £¨ÌîÐòºÅ£©£»±ØÐ뾭ˮԡ¼ÓÈȵÄÊÇ            £¨ÌîÐòºÅ£©¡£
£¨2£©Çë·Ö±ðÑ¡ÔñÔÚÉÏÊöʵÑéÖÐËùÓõÄÒ©Æ·ºÍ·½·¨£º
ʵÑé¢Ù              £¨ÌîÐòºÅ£©£¬ÊµÑé¢Û           £¨ÌîÐòºÅ£©
¢Ù0.1g/mLNaOH       ¢Ú0.1g/mLNaCl       ¢Û0.01g/mLCuSO4  
¢Ü0.05g/mLCuSO4      ¢Ý·Ö±ðʹÓà         ¢Þ»ìºÏºóÔÙʹÓà     
£¨3£©ÊµÑé¢ÚÖÐËùÓþƾ«µÄ×÷ÓÃÊÇ              £»ÊµÑé¢Þ¹Û²ìµ½RNA¡¢DNAÒÀ´Î±»È¾³É                 ¡£
£¨4£©Ä³¿ÆÑÐС×éÔÚ½øÐÐÁËʵÑé¢ÝµÄ»ù´¡ÉÏ£¬·ÖÀë³öÁËÍêÕûµÄÒ¶Èâϸ°û£¬ÕâЩϸ°ûÒ»²¿·Ö·ÅÔÚÊÊÒËÌõ¼þÏÂÅàÑø£¬ÄÜͨ¹ý¹âºÏ×÷ÓòúÉúµí·Û£¬ÁíÒ»²¿·Ö½ÁËéºó·ÅÔÚͬÑùÌõ¼þÏÂÅàÑø£¬·¢ÏÖûÓвúÉúµí·Û¡£´Ë¿ÆÑÐС×éÑо¿µÄÄÚÈÝÊôÓÚÉúÃüϵͳÖеĠ     ²ã´Î£¬´ËʵÑéµÄʵÑé½áÂÛÊÇ                                                         ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2011-2012ѧÄê¹ã¶«Ê¡Ã·Ïض«É½ÖÐѧ¸ßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔÉúÎïÊÔ¾í ÌâÐÍ£º×ÛºÏÌâ

¸ù¾ÝÒÔÏÂʵÑéÄÚÈݻشðÎÊÌ⣺

£¨1£©ÔÚÉÏÊöʵÑé¹ý³ÌÖУ¬±ØÐë½èÖúÏÔ΢¾µ²ÅÄÜÍê³ÉµÄÊÇ            £¨ÌîÐòºÅ£©£»±ØÐ뾭ˮԡ¼ÓÈȵÄÊÇ            £¨ÌîÐòºÅ£©¡£
£¨2£©Çë·Ö±ðÑ¡ÔñÔÚÉÏÊöʵÑéÖÐËùÓõÄÒ©Æ·ºÍ·½·¨£º
ʵÑé¢Ù              £¨ÌîÐòºÅ£©£¬ÊµÑé¢Û           £¨ÌîÐòºÅ£©
¢Ù0.1g/mLNaOH       ¢Ú0.1g/mLNaCl       ¢Û0.01g/mLCuSO4  
¢Ü0.05g/mLCuSO4      ¢Ý·Ö±ðʹÓà         ¢Þ»ìºÏºóÔÙʹÓà     
£¨3£©ÊµÑé¢ÚÖÐËùÓþƾ«µÄ×÷ÓÃÊÇ              £»ÊµÑé¢Þ¹Û²ìµ½RNA¡¢DNAÒÀ´Î±»È¾³É                 ¡£
£¨4£©Ä³¿ÆÑÐС×éÔÚ½øÐÐÁËʵÑé¢ÝµÄ»ù´¡ÉÏ£¬·ÖÀë³öÁËÍêÕûµÄÒ¶Èâϸ°û£¬ÕâЩϸ°ûÒ»²¿·Ö·ÅÔÚÊÊÒËÌõ¼þÏÂÅàÑø£¬ÄÜͨ¹ý¹âºÏ×÷ÓòúÉúµí·Û£¬ÁíÒ»²¿·Ö½ÁËéºó·ÅÔÚͬÑùÌõ¼þÏÂÅàÑø£¬·¢ÏÖûÓвúÉúµí·Û¡£´Ë¿ÆÑÐС×éÑо¿µÄÄÚÈÝÊôÓÚÉúÃüϵͳÖеĠ     ²ã´Î£¬´ËʵÑéµÄʵÑé½áÂÛÊÇ                                                         ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2014½ì½­ËÕÊ¡³£ÖÝÊиßÈý10Ô½ÌѧÖÊÁ¿µ÷ÑÐÉúÎïÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º×ÛºÏÌâ

£¨6·Ö£©¸ù¾ÝÒÔÏÂʵÑéÄÚÈݻشðÎÊÌ⣺

£¨1£©ÔÚÉÏÊöʵÑé¹ý³ÌÖУ¬±ØÐë½èÖúÏÔ΢¾µ²ÅÄÜÍê³ÉµÄÊÇ              £¨ÐòºÅ£©£¬ÊµÑéÖÐӦʼÖÕ±£³ÖÉúÎï»îÐÔµÄÊÇ              £¨ÐòºÅ£©¡£

£¨2£©ÓÉÓÚʵÑé²ÄÁÏÓÃÆ·»òÊÔ¼ÁËùÏÞ£¬ÓÐʱºòÐèÒªÉè·¨Ìæ´ú¡£ÏÂÁи÷Ïî´¦ÀíÖÐÕýÈ·µÄÊÇ               ¡£

A£®×ö¢ßʵÑéʱ£¬¿ÉÓÃÑó´Ð±íƤ´úÌæÑó´Ð¸ù¼â

B£®×ö¢ÙʵÑéʱ£¬¿ÉÓøÊÕá´úÌæÆ»¹û

C£®×ö¢ÝʵÑéʱ£¬¿ÉÓøɾ»µÄϸɳ´úÌæ¶þÑõ»¯¹è

D£®×ö¢ÚʵÑéʱ£¬¿ÉÓÃËÕµ¤¢ô´úÌæËÕµ¤¢óȾҺ

£¨3£©ÔÚÉÏÊöʵÑéÖУ¬³£Óõ½¾Æ¾«µÄʵÑéÓТڢݢߣ¬ÆäÖоƾ«ËùÆðµÄ×÷Ó÷ֱðÊÇ       ¡¢     ¡¢      ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2014½ì¹ã¶«Ê¡¸ßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔÉúÎïÊÔ¾í ÌâÐÍ£º×ÛºÏÌâ

¸ù¾ÝÒÔÏÂʵÑéÄÚÈݻشðÎÊÌ⣺

 

 

 

 

£¨1£©ÔÚÉÏÊöʵÑé¹ý³ÌÖУ¬±ØÐë½èÖúÏÔ΢¾µ²ÅÄÜÍê³ÉµÄÊÇ             £¨ÌîÐòºÅ£©£»±ØÐ뾭ˮԡ¼ÓÈȵÄÊÇ             £¨ÌîÐòºÅ£©¡£

£¨2£©Çë·Ö±ðÑ¡ÔñÔÚÉÏÊöʵÑéÖÐËùÓõÄÒ©Æ·ºÍ·½·¨£º

ʵÑé¢Ù               £¨ÌîÐòºÅ£©£¬ÊµÑé¢Û            £¨ÌîÐòºÅ£©

¢Ù0.1g/mLNaOH        ¢Ú0.1g/mLNaCl        ¢Û0.01g/mLCuSO4   

¢Ü0.05g/mLCuSO4       ¢Ý·Ö±ðʹÓà          ¢Þ»ìºÏºóÔÙʹÓà     

£¨3£©ÊµÑé¢ÚÖÐËùÓþƾ«µÄ×÷ÓÃÊÇ               £»ÊµÑé¢Þ¹Û²ìµ½RNA¡¢DNAÒÀ´Î±»È¾³É                  ¡£

£¨4£©Ä³¿ÆÑÐС×éÔÚ½øÐÐÁËʵÑé¢ÝµÄ»ù´¡ÉÏ£¬·ÖÀë³öÁËÍêÕûµÄÒ¶Èâϸ°û£¬ÕâЩϸ°ûÒ»²¿·Ö·ÅÔÚÊÊÒËÌõ¼þÏÂÅàÑø£¬ÄÜͨ¹ý¹âºÏ×÷ÓòúÉúµí·Û£¬ÁíÒ»²¿·Ö½ÁËéºó·ÅÔÚͬÑùÌõ¼þÏÂÅàÑø£¬·¢ÏÖûÓвúÉúµí·Û¡£´Ë¿ÆÑÐС×éÑо¿µÄÄÚÈÝÊôÓÚÉúÃüϵͳÖеĠ      ²ã´Î£¬´ËʵÑéµÄʵÑé½áÂÛÊÇ                                                          ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸