£¨5·Ö£©Ï¸°ûÔÚ´úл¹ý³ÌÖУ¬»á²úÉú¹ýÑõ»¯Ç⣬Ëü¶Ôϸ°ûÓж¾º¦×÷Ó㬵«ÌåÄÚÓйýÑõ»¯ÇâøµÄ´æÔÚ¿ÉÒÔ½«Æä·Ö½âΪÎÞ¶¾µÄÎïÖÊ¡£Çë·ÖÎöÏÂÁÐÒ»×éʵÑ飬²¢»Ø´ðÓйØÎÊÌ⣺

ÊԹܱàºÅ
¼ÓÈëÎï
Ìõ¼þ
ÏÖÏó
A
2mL H2O2+2µÎFeCl3
30¡æ
·Å³öÉÙÁ¿ÆøÅÝ
B
2mL H2O2+2µÎ¸ÎÔàÑÐÄ¥Òº
30¡æ
·Å³ö´óÁ¿ÆøÅÝ
C
2mL H2O2+2µÎÖó¹ýµÄ¸ÎÔàÑÐÄ¥Òº
Öó·ÐºóÀäÈ´ÖÁ30¡æ
ÎÞÆøÅÝ
D
2mL H2O2+2µÎÀ䶳µÄ¸ÎÔàÑÐÄ¥Òº
0¡æ
ÎÞÆøÅÝ
E
2mL H2O2+2µÎÈ˵ÄÐÂÏÊÍÙÒº
30¡æ
ÎÞÆøÅÝ
  £¨1£©ÊµÑéB£®EÏÖÏó˵Ã÷øµÄ´ß»¯×÷ÓþßÓÐ_______________Ìص㡣
£¨2£©ÊµÑéBºÍCÏÖÏó²»Í¬µÄÔ­ÒòÊÇ_______________________________________¡£
£¨3£©ÊµÑéB³ÖÐøÒ»¶Îʱ¼äºó£¬²»ÔÙ²úÉúÆøÅÝ£¬£¨¢ñ£©¿ÉÄÜÊÇÆäÖеÄøʧȥ»îÐÔ£¬£¨¢ò£©¿ÉÄÜÊǹýÑõ»¯ÇâÒѾ­±»³¹µ×·Ö½â£¬¾¿¾¹ÊÇÄĸöÔ­Òò£¬ÇëÍê³ÉÏÂÁÐʵÑéÉè¼Æ¡£ÏòBÊÔ¹ÜÖмÓÈëÊÊÁ¿µÄ                   £¬¹Û²ìÓÐÎÞÆøÅÝ¡£Èç¹ûÓУ¬Ôò˵Ã÷ÊÇÔ­ÒòΪ      £¬Èç¹ûÎÞ£¬Ôò˵Ã÷ÊÇÔ­ÒòΪ            ¡£

£¨1£©×¨Ò»ÐÔ£¨2£©¸ßÎÂʹøʧ»î£¨3£©¹ýÑõ»¯Çâ ¢ò¢ñ£¨»ò¸ÎÔàÑÐÄ¥Òº¢ñ ¢ò£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º ÌâÐÍ£º

ϸ°ûÔÚ´úл¹ý³ÌÖУ¬»á²úÉú¹ýÑõ»¯Ç⣬Ëü¶Ôϸ°ûÓж¾º¦×÷Ó㬵«ÌåÄÚÓйýÑõ»¯ÇâøµÄ´æÔÚ¿ÉÒÔ½«Æä·Ö½âΪˮºÍÑõÆø£¬Æä´ß»¯»îÐÔ¿ÉÓÃÈçÏ·½·¨²â¶¨£ºÓôò¿×Æ÷½«ÂËÈÆÖƳÉСԲƬ£¬½þÅÝÔÚº¬Ã¸µÄ¹ýÑõ»¯Ç⻺³åÒºÖУ¬ÊµÑ鿪ʼʱ£¬Ð¡Ô²Æ¬³Á½µÔÚÈÜÒºµÄµ×²¿£¬µ«ºóÀ´»á¸¡³öÒºÃ棬¼Ç¼СԲƬÉϸ¡µÄʱ¼ä£¬ÓÃʱ¼äµÄµ¹ÊýÀ´±íʾ¹ýÑõ»¯ÇâµÄ´ß»¯»îÐÔ¡£ÎªÑо¿·´Ó¦ÎïŨ¶È¶Ôø´ß»¯»îÐÔµÄÓ°Ï죬ʵÑéÔÚ²»Í¬Å¨¶ÈµÄ¹ýÑõ»¯ÇâÈÜÒºÖÐÖظ´½øÐУ¬ÊµÑé½á¹ûÈçͼËùʾ£¬·ÖÎö²¢»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ð¡Ô²ÂËֽƬ½øÐе½Ò»¶¨Ê±¼äºó¿ªÊ¼Éϸ¡µÄÔ­ÒòÊÇ                         ¡£

£¨2£©ÊµÑéÖйýÑõ»¯ÇâÈÜÒºÓûº³åÒºµÄÄ¿µÄÊÇ                                ¡£

£¨3£©¸ù¾ÝͼÖеÄÇúÏßÃèÊö·´Ó¦ÎïŨ¶ÈÓë¹ýÑõ»¯Çâø´ß»¯ËÙÂʼäµÄ¹Øϵ                 

                                                 ¡£

£¨4£©µ±µ×ÎïŨ¶È³¬¹ý140mol¡¤L£­1ʱ£¬·´Ó¦ËÙÂʲ»ÔÙ¼Ó¿ìµÄÔ­ÒòÊÇ                 ¡£

£¨5£©Ä³Í¬Ñ§Ïë½øÒ»²½Ì½¾¿²»Í¬Î¶ȶԹýÑõ»¯Çâø»îÐÔµÄÓ°Ï죬Éè¼ÆÁËÒÔʵÑ飬£º£º

¢ÙÈ¡6Ö§ÊԹֱܷð±àºÅΪA1¡¢A2¡¢B1¡¢B??2¡¢C1¡¢C2£¬ÔÚA1¡¢B1¡¢C1ÖмÓÈëµÈÁ¿µÄ¹ýÑõ»¯Çâ¡¢»º³åÒººÍСԲÂËֽƬ£¬ÔÚA2¡¢B2¡¢C2ÖмÓÈëÊÊÁ¿µÈÁ¿µÄ¹ýÑõ»¯ÇâøÈÜÒº¡£ÇëÍê³ÉÒÔϲ½Ö裺

¢Ú                                                                             

                                                                      ¡£

¢Û                                                                  ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º ÌâÐÍ£º

ϸ°ûÔÚ´úл¹ý³ÌÖУ¬»á²úÉú¹ýÑõ»¯Ç⣬Ëü¶Ôϸ°ûÓж¾º¦×÷Ó㬵«ÌåÄÚÓйýÑõ»¯ÇâøµÄ´æÔÚ¿ÉÒÔ½«Æä·Ö½âΪˮºÍÑõÆø£¬Æä´ß»¯»îÐÔ¿ÉÓÃÈçÏ·½·¨²â¶¨£ºÓôò¿×Æ÷½«ÂËÈÆÖƳÉСԲƬ£¬½þÅÝÔÚº¬Ã¸µÄ¹ýÑõ»¯Ç⻺³åÒºÖУ¬ÊµÑ鿪ʼʱ£¬Ð¡Ô²Æ¬³Á½µÔÚÈÜÒºµÄµ×²¿£¬µ«ºóÀ´»á¸¡³öÒºÃ棬¼Ç¼СԲƬÉϸ¡µÄʱ¼ä£¬ÓÃʱ¼äµÄµ¹ÊýÀ´±íʾ¹ýÑõ»¯ÇâµÄ´ß»¯»îÐÔ¡£ÎªÑо¿·´Ó¦ÎïŨ¶È¶Ôø´ß»¯»îÐÔµÄÓ°Ï죬ʵÑéÔÚ²»Í¬Å¨¶ÈµÄ¹ýÑõ»¯ÇâÈÜÒºÖÐÖظ´½øÐУ¬ÊµÑé½á¹ûÈçͼËùʾ£¬·ÖÎö²¢»Ø´ðÏÂÁÐÎÊÌ⣺

 
 

 

 

 

 

 

 

 

 

 


£¨1£©Ð¡Ô²ÂËֽƬ½øÐе½Ò»¶¨Ê±¼äºó¿ªÊ¼Éϸ¡µÄÔ­ÒòÊÇ                         ¡£

£¨2£©ÊµÑéÖйýÑõ»¯ÇâÈÜÒºÓûº³åÒºµÄÄ¿µÄÊÇ                                ¡£

£¨3£©¸ù¾ÝͼÖеÄÇúÏßÃèÊö·´Ó¦ÎïŨ¶ÈÓë¹ýÑõ»¯Çâø´ß»¯ËÙÂʼäµÄ¹Øϵ                               

                                                         ¡£

£¨4£©µ±µ×ÎïŨ¶È³¬¹ý140mol?L£­1ʱ£¬·´Ó¦ËÙÂʲ»ÔÙ¼Ó¿ìµÄÔ­ÒòÊÇ                 ¡£

   £¨5£©Ä³Í¬Ñ§Ïë½øÒ»²½Ì½¾¿²»Í¬Î¶ȶԹýÑõ»¯Çâø»îÐÔµÄÓ°Ï죬Éè¼ÆÁËÒÔʵÑ飬£º£¨4·Ö£©£º

¢ÙÈ¡6Ö§ÊԹֱܷð±àºÅΪA1¡¢A2¡¢B1¡¢B­2¡¢C1¡¢C2£¬ÔÚA1¡¢B1¡¢C1ÖмÓÈëµÈÁ¿µÄ¹ýÑõ»¯Çâ¡¢»º³åÒººÍСԲÂËֽƬ£¬ÔÚA2¡¢B2¡¢C2ÖмÓÈëÊÊÁ¿µÈÁ¿µÄ¹ýÑõ»¯ÇâøÈÜÒº¡£ÇëÍê³ÉÒÔϲ½Ö裺

¢Ú                                                                             

                                                                      ¡£

¢Û                                                                  ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2012-2013Ä긣½¨ÂÞÔ´µÚÒ»ÖÐѧ¸ßÒ»µÚ¶þ´ÎÔ¿¼ÉúÎïÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£º×ÛºÏÌâ

H2O2³£ÓÃÓÚƯ°×£¬Ò²ÓÃÓÚÇåϴСµÄÉË¿Ú£»Ï¸°ûÔÚ´úл¹ý³ÌÖÐÒ²»á²úÉúH2O2£¬Ëü¶Ôϸ°ûÓж¾º¦×÷Ó㬵«ÌåÄÚÓйýÑõ»¯Çâø£¬ÄÜʹÆä·Ö½âΪÎÞ¶¾ÎïÖÊ¡£
Çë·ÖÎöÏÂͼÖеÄʵÑ飬²¢»Ø´ðÓйØÎÊÌ⣺£¨14·Ö£©

£¨1£©ÔÚ¢Ù¡«¢ÞºÅÊÔ¹ÜÖУ¬×îÏȲúÉúÆøÅݵÄÊÇÊԹܠ      £¬µ¥Î»Ê±¼äÄÚ²úÉúÆøÅÝ×î¶àµÄÊÇÊԹܠ                   £»
£¨2£©ÔÚÊԹܢÚÖУ¬Ñ¡ÓÃÐÂÏʸÎÔà×öʵÑ飬ÊÇÒòΪÐÂÏʸÎÔàÖУ¨¡¡¡¡£©¡£
A.º¬¹ýÑõ»¯Çâ¶à¡¡B.¹ýÑõ»¯ÇâøÒ×»Ó·¢    C.º¬Ã¸µÄÖÖÀà¶à¡¡D.¹ýÑõ»¯Çâø¶àÇÒ»îÐÔÇ¿
(3)ÔÚʵÑéÖÐÈ¡ÐÂÏʸÎÔà,ѸËÙ¼ôËéͶÈëÊԹܢÚÖÐ,¼ôËéµÄÄ¿µÄÊÇ£¨¡¡£©¡£
A.·ÀÖ¹¹ýÑõ»¯Çâø»Ó·¢¡¡¡¡¡¡¡¡¡¡B.·ÀÖ¹¹ýÑõ»¯Çâø·Ö½â
C.·Àֹϸ°ûÖйýÑõ»¯ÇâøµÄÊÍ·Å¡¡D.ʹ¹ýÑõ»¯ÇâøÓëH2O2³ä·Ö½Ó´¥
£¨4£©±È½Ï¢ÙºÍ¢ÚºÅÊԹܣ¬ËµÃ÷ø¾ß                                     ¡£
£¨5£©±È½Ï¢ÚºÍ¢Û¢Ü¢Ý¢ÞºÅÊԹܣ¬ËµÃ÷ø                                       ¡£
£¨6£©ÔÚ¢Û¡¢¢Ü¡¢¢Ý¡¢¢ÞÊÔ¹ÜÖУ¬         ºÅÊÔ¹ÜÖÐËù¸øµÄÌõ¼þÓпÉÄÜÆÆ»µH2O2øµÄ·Ö×ӽṹ£¬´Ó¶øʹÆäʧȥ»îÐÔ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2015½ì¸£½¨ÂÞÔ´µÚÒ»ÖÐѧ¸ßÒ»µÚ¶þ´ÎÔ¿¼ÉúÎïÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º×ÛºÏÌâ

H2O2³£ÓÃÓÚƯ°×£¬Ò²ÓÃÓÚÇåϴСµÄÉË¿Ú£»Ï¸°ûÔÚ´úл¹ý³ÌÖÐÒ²»á²úÉúH2O2£¬Ëü¶Ôϸ°ûÓж¾º¦×÷Ó㬵«ÌåÄÚÓйýÑõ»¯Çâø£¬ÄÜʹÆä·Ö½âΪÎÞ¶¾ÎïÖÊ¡£

Çë·ÖÎöÏÂͼÖеÄʵÑ飬²¢»Ø´ðÓйØÎÊÌ⣺£¨14·Ö£©

£¨1£©ÔÚ¢Ù¡«¢ÞºÅÊÔ¹ÜÖУ¬×îÏȲúÉúÆøÅݵÄÊÇÊԹܠ      £¬µ¥Î»Ê±¼äÄÚ²úÉúÆøÅÝ×î¶àµÄÊÇÊԹܠ                   £»

£¨2£©ÔÚÊԹܢÚÖУ¬Ñ¡ÓÃÐÂÏʸÎÔà×öʵÑ飬ÊÇÒòΪÐÂÏʸÎÔàÖУ¨¡¡¡¡£©¡£

A.º¬¹ýÑõ»¯Çâ¶à¡¡B.¹ýÑõ»¯ÇâøÒ×»Ó·¢    C.º¬Ã¸µÄÖÖÀà¶à¡¡D.¹ýÑõ»¯Çâø¶àÇÒ»îÐÔÇ¿

(3)ÔÚʵÑéÖÐÈ¡ÐÂÏʸÎÔà,ѸËÙ¼ôËéͶÈëÊԹܢÚÖÐ,¼ôËéµÄÄ¿µÄÊÇ£¨¡¡£©¡£

A.·ÀÖ¹¹ýÑõ»¯Çâø»Ó·¢¡¡¡¡¡¡¡¡¡¡B.·ÀÖ¹¹ýÑõ»¯Çâø·Ö½â

C.·Àֹϸ°ûÖйýÑõ»¯ÇâøµÄÊÍ·Å¡¡D.ʹ¹ýÑõ»¯ÇâøÓëH2O2³ä·Ö½Ó´¥

£¨4£©±È½Ï¢ÙºÍ¢ÚºÅÊԹܣ¬ËµÃ÷ø¾ß                                     ¡£

£¨5£©±È½Ï¢ÚºÍ¢Û¢Ü¢Ý¢ÞºÅÊԹܣ¬ËµÃ÷ø                                       ¡£

£¨6£©ÔÚ¢Û¡¢¢Ü¡¢¢Ý¡¢¢ÞÊÔ¹ÜÖУ¬         ºÅÊÔ¹ÜÖÐËù¸øµÄÌõ¼þÓпÉÄÜÆÆ»µH2O2øµÄ·Ö×ӽṹ£¬´Ó¶øʹÆäʧȥ»îÐÔ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2011-2012ѧÄ긣½¨Ê¡¸ßÈý11ÔÂÔ¿¼ÊÔÉúÎïÊÔ¾í ÌâÐÍ£º×ÛºÏÌâ

£¨5·Ö£©Ï¸°ûÔÚ´úл¹ý³ÌÖУ¬»á²úÉú¹ýÑõ»¯Ç⣬Ëü¶Ôϸ°ûÓж¾º¦×÷Ó㬵«ÌåÄÚÓйýÑõ»¯ÇâøµÄ´æÔÚ¿ÉÒÔ½«Æä·Ö½âΪÎÞ¶¾µÄÎïÖÊ¡£Çë·ÖÎöÏÂÁÐÒ»×éʵÑ飬²¢»Ø´ðÓйØÎÊÌ⣺

ÊԹܱàºÅ

¼ÓÈëÎï

Ìõ¼þ

ÏÖÏó

A

2mL H2O2+2µÎFeCl3

30¡æ

·Å³öÉÙÁ¿ÆøÅÝ

B

2mL H2O2+2µÎ¸ÎÔàÑÐÄ¥Òº

30¡æ

·Å³ö´óÁ¿ÆøÅÝ

C

2mL H2O2+2µÎÖó¹ýµÄ¸ÎÔàÑÐÄ¥Òº

Öó·ÐºóÀäÈ´ÖÁ30¡æ

ÎÞÆøÅÝ

D

2mL H2O2+2µÎÀ䶳µÄ¸ÎÔàÑÐÄ¥Òº

0¡æ

ÎÞÆøÅÝ

E

2mL H2O2+2µÎÈ˵ÄÐÂÏÊÍÙÒº

30¡æ

ÎÞÆøÅÝ

   £¨1£©ÊµÑéB£®EÏÖÏó˵Ã÷øµÄ´ß»¯×÷ÓþßÓÐ_______________Ìص㡣

   £¨2£©ÊµÑéBºÍCÏÖÏó²»Í¬µÄÔ­ÒòÊÇ_______________________________________¡£

   £¨3£©ÊµÑéB³ÖÐøÒ»¶Îʱ¼äºó£¬²»ÔÙ²úÉúÆøÅÝ£¬£¨¢ñ£©¿ÉÄÜÊÇÆäÖеÄøʧȥ»îÐÔ£¬£¨¢ò£©¿ÉÄÜÊǹýÑõ»¯ÇâÒѾ­±»³¹µ×·Ö½â£¬¾¿¾¹ÊÇÄĸöÔ­Òò£¬ÇëÍê³ÉÏÂÁÐʵÑéÉè¼Æ¡£ÏòBÊÔ¹ÜÖмÓÈëÊÊÁ¿µÄ                    £¬¹Û²ìÓÐÎÞÆøÅÝ¡£Èç¹ûÓУ¬Ôò˵Ã÷ÊÇÔ­ÒòΪ       £¬Èç¹ûÎÞ£¬Ôò˵Ã÷ÊÇÔ­Òò Ϊ             ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸