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 如图,四棱锥的底面是正方形,⊥平面

(1)求证:

(2)求二面角的大小.


解:(1)连接BD,∵⊥平面

平面

∴AC⊥SD    又四边形ABCD是正方形,∴AC⊥BD

∴AC ⊥平面SBD

∴AC⊥SB.                     

(2)设的中点为,连接

∵SD=AD,CS=CA,

∴DE⊥SA, CE⊥SA.

是二面角的平面角.

计算得:DE=,CE=,CD=2,则CD⊥DE.

,

所以所求二面角的大小为 .


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