Èçͼ8-3-7£¬Ò»Çᵯ»É×ó¶Ë¹Ì¶¨ÔÚ³¤Îï¿éMµÄ×ó¶Ë£¬ÓÒ¶ËÓëСľ¿émÁ¬½Ó£¬ÇÒm¡¢M¼°MÓëµØÃæ¼ä½Ó´¥¹â»¬.¿ªÊ¼Ê±£¬mºÍMͬʱ¾²Ö¹£¬ÏÖͬʱ¶Ôm¡¢MÊ©¼ÓµÈ´ó·´ÏòµÄˮƽºãÁ¦F1ºÍF2£¬´ÓÁ½ÎïÌ忪ʼÔ˶¯ÒÔºóµÄÕû¸öÔ˶¯¹ý³ÌÖУ¬¶Ôm¡¢MºÍµ¯»É×é³ÉµÄϵͳ£¨Õû¸ö¹ý³ÌÖе¯»ÉÐα䲻³¬¹ýÆäµ¯ÐÔÏÞ¶È£©£¬ÕýÈ·µÄ˵·¨ÊÇ£¨ £©
![]()
ͼ8-3-7
A.ÓÉÓÚF1¡¢F2µÈ´ó·´Ïò£¬¹Êϵͳ»úеÄÜÊØºã
B.F1¡¢F2·Ö±ð¶Ôm¡¢M×öÕý¹¦£¬¹Êϵͳ¶¯Á¿²»¶ÏÔö¼Ó
C.F1¡¢F2·Ö±ð¶Ôm¡¢M×öÕý¹¦£¬¹Êϵͳ»úеÄܲ»¶ÏÔö¼Ó
D.µ±µ¯»Éµ¯Á¦´óСÓëF1¡¢F2´óСÏàµÈʱ£¬m¡¢MµÄ¶¯ÄÜ×î´ó
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º
![]()
ͼ8-3-7
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º2013½ìºþ±±Ê¡¸ßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔÎïÀí¾í ÌâÐÍ£ºÑ¡ÔñÌâ
Èçͼ 7 Ëùʾ£¬Ò»Çᵯ»ÉµÄÁ½¶ËÓëÖÊÁ¿·Ö±ðΪ m1 ºÍ m2 µÄÁ½Îï¿é A ¡¢B ÏàÁ¬½Ó£¬²¢¾²Ö¹Ôڹ⻬µÄË®Æ½ÃæÉÏ£¬ ÏÖʹ A ˲ʱ»ñµÃˮƽÏòÓÒµÄËÙ¶È 3 m/s£¬ÒÔ´Ë¿ÌΪ¼ÆÊ±Æðµã£¬Á½Îï¿éµÄËÙ¶ÈËæÊ±¼ä±ä»¯µÄ¹æÂÉÈçͼ 8 Ëùʾ£¬´ÓͼÏñÐÅÏ¢¿ÉµÃ£¨ £©
![]()
A£®ÔÚ t1 ¡¢t3 ʱ¿ÌÁ½Îï¿é´ïµ½¹²Í¬ËÙ¶È 1 m/s£¬ÇÒµ¯»É¶¼ÊÇ´¦ÓÚѹËõ״̬
B£®´Ó t3 µ½ t4 ʱ¿Ìµ¯»ÉÓÉѹËõ״̬»Ö¸´µ½Ô³¤
C£®Á½ÎïÌåµÄÖÊÁ¿Ö®±ÈΪ m1¡Ãm2 = 1¡Ã2
D£®ÔÚ t2 ʱ¿Ì A Óë B µÄ¶¯ÄÜÖ®±ÈΪ Ek1¡ÃEk2 = 1¡Ã8
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º
¡°Ì½¾¿ÎïÌåÔ˶¯ÓëÊÜÁ¦µÄ¹ØÏµ¡±ÊµÑé×°ÖÃÈçͼ8£¨a£©Ëùʾ£¬Ò»Ä¾¿é A·ÅÔÚˮƽ³¤Ä¾°åBÉÏ£¬Ä¾¿éA×ó¶Ë˩һÇáÉþ£¬¿ç¹ý¹Ì¶¨ÔÚľ°åB±ßÔµµÄ»¬ÂÖÓëһɰͰCÏàÁ¬£¬Ä¾¿éAÓÒ²àÓë´òµã¼ÆÊ±Æ÷µÄÖ½´øÏàÁ¬.ÒÑ֪ľ¿éAµÄÖÊÁ¿ÎªM£¬²»¼ÆÖ½´øµÄĦ²ÁÁ¦¼°ÇáÉþºÍ»¬ÂÖ¼äµÄĦ²Á.
![]()
£¨1£©µ÷½ÚɰͰCÖÐɰµÄÖÊÁ¿£¬Ê¹Ä¾¿éAÔÈËÙÏò×óÔ˶¯£¬²â³öɰͰºÍɰµÄ×ÜÖÊÁ¿Îªm1£¬Ôòľ¿éAÓëľ°åBÖ®¼äµÄ¶¯Ä¦²ÁÒòÊýΪ_______£»
£¨2£©¸Ä±äɰͰCÖÐɰµÄÖÊÁ¿£¬Ê¹Ä¾¿éÏò×ó×öÔȼÓËÙÖ±ÏßÔ˶¯£¬²â³öɰͰºÍɰµÄ×ÜÖÊÁ¿Îªm2£¬Ôòľ¿éAÓëľ°åBÖ®¼äµÄ¶¯Ä¦²ÁÒòÊýΪ______£¨Óú¬M¡¢m2¡¢a¡¢gµÄ´úÊýʽ±íʾ£©£»
£¨3£©Í¼8£¨b£©ÊÇijͬѧʵÑéÖвâµÃµÄÖ½´ø£¬Í¼ÖÐÿÁ½¸ö¼ÇÊýµã¼äµÄʱ¼ä¼ä¸ôΪ0.1s£¬ÓÉͼÖиø³öµÄÊý¾Ý£¬¿ÉÇó³öľ¿éAÔ˶¯µÄ¼ÓËÙ¶ÈΪa=______£»
Èô´Ëʱ²âµÃɰͰºÍɰµÄ×ÜÖÊÁ¿Îª1kg£¬²âµÃľ¿éAµÄÖÊÁ¿Îª4kg£¬Ôòľ¿éAÓëľ°åBÖ®¼äµÄ¶¯Ä¦²ÁÒòÊý´óСÊÇ_________.£¨gÈ¡10m/s2£©
ÏÂͼÒÑÖª£ºAB=5.31cm¡¢BC=5.71cm¡¢CD=6.10cm¡¢ DE=6.52cm¡¢ EF=6.93cm¡¢ FG=7.32cm.![]()
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º
Èçͼ 7 Ëùʾ£¬Ò»Çᵯ»ÉµÄÁ½¶ËÓëÖÊÁ¿·Ö±ðΪ m1 ºÍ m2 µÄÁ½Îï¿é A ¡¢B ÏàÁ¬½Ó£¬²¢¾²Ö¹Ôڹ⻬µÄË®Æ½ÃæÉÏ£¬ÏÖʹ A ˲ʱ»ñµÃˮƽÏòÓÒµÄËÙ¶È 3 m/s£¬ÒÔ´Ë¿ÌΪ¼ÆÊ±Æðµã£¬Á½Îï¿éµÄËÙ¶ÈËæÊ±¼ä±ä»¯µÄ¹æÂÉÈçͼ 8 Ëùʾ£¬´ÓͼÏñÐÅÏ¢¿ÉµÃ£¨ £©
![]()
A£®ÔÚ t1 ¡¢t3 ʱ¿ÌÁ½Îï¿é´ïµ½¹²Í¬ËÙ¶È 1 m/s£¬ÇÒµ¯»É¶¼ÊÇ´¦ÓÚѹËõ״̬
B£®´Ó t3 µ½ t4 ʱ¿Ìµ¯»ÉÓÉѹËõ״̬»Ö¸´µ½Ô³¤
C£®Á½ÎïÌåµÄÖÊÁ¿Ö®±ÈΪ m1¡Ãm2 = 1¡Ã2
D£®ÔÚ t2 ʱ¿Ì A ÓëB µÄ¶¯ÄÜÖ®±ÈΪ Ek1¡ÃEk2 = 1¡Ã8
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com