Question

18£®Ôڲⶨһ½Ú¸Éµç³ØµÄµç¶¯ÊƺÍÄÚ×èµÄʵÑéÖУ¬±¸ÓÐÏÂÁÐÆ÷²Ä£º
A£®µç³ØE£¨µç¶¯ÊÆԼΪ1.5V¡¢ÄÚ×èԼΪ1.0¦¸£©
B£®µçÁ÷±íA₁£¨ÂúÆ«µçÁ÷3mA£¬ÄÚ×èR₄=10¦¸£©
C£®µçÁ÷±íA£¨0¡«0.6A£¬ÄÚ×è0.1¦¸£©
D£®¶¨Öµµç×èÆ÷R₃=990¦¸
E£®»¬Ïß±ä×èÆ÷R₁£¨0-10¦¸¡¢10A£©
F£®»¬¶¯±ä×èÆ÷R₂£¨0-100¦¸¡¢10A£©
G£®¿ª¹Ø£¬µ¼ÏßÈô¸É
£¨1£©Îª·½±ãÇÒÄܽÏ׼ȷµØ½øÐвâÁ¿£¬ÆäÖÐӦѡÓõĻ¬Ïß±ä×èÆ÷ÊÇR₁£®£¨Ñ¡Ìî¡°R₁¡±»ò¡°R₂¡±£©
£¨2£©Éè¼ÆµÄʵÑéµç·Èçͼ£¬²¢ÒÑÔÚͼÖбêÉÏËùÑ¡ÓÃÆ÷²ÄµÄ·ûºÅ£»µ±Á÷¹ýµçÁ÷±íGµÄµçÁ÷ΪI₁=1.25mAʱ£¬µçÔ´Á½¶ËµÄµçѹU=1.25V
£¨3£©Èçͼ2Ϊijһͬѧ¸ù¾ÝËûËùÉè¼ÆµÄʵÑé¸ø³öµÄI₁-I₂ͼÏߣ¨I₁ΪµçÁ÷±íGµÄʾÊý£¬I₂ΪµçÁ÷±íAµÄʾÊý£©£¬ÓÉͼÏß¿ÉÇóµÃ±»²âµç³ØµÄµç¶¯ÊÆE=1.46V£¬ÄÚ×èr=0.84¦¸£®

Answer 1

·ÖÎö £¨1£©Îª·½±ãʵÑé²Ù×÷£¬Ó¦Ñ¡×î´ó×èÖµ½ÏСµÄ»¬¶¯±ä×èÆ÷£®
£¨2£©¸ù¾ÝµçÁ÷±íʾÊýÓ¦Óô®Áªµç·ÌصãÓëÅ·Ä·¶¨ÂÉÇó³öµçѹ£®
£¨3£©¸ù¾ÝʵÑéµç·Çó³öͼÏóµÄº¯Êý±í´ïʽ£¬È»ºó¸ù¾ÝͼÏóÇó³öµçÔ´µç¶¯ÊÆÓëÄÚ×裮

½â´ð ½â£º£¨1£©Îª·½±ãʵÑé²Ù×÷£¬»¬¶¯±ä×èÆ÷ӦѡÔñR₁£®
£¨2£©ÓÉͼʾµç·ͼ¿ÉÖª£¬µçÁ÷±íGÓëµç×èR₃´®Áª×é³Éµçѹ±í£¬µçѹ±í²â·¶Ëµçѹ£¬µçÔ´Á½¶ËµçѹΪ£º
U=I₁£¨R₄+R₃£©=0.00125¡Á£¨10+990£©=1.25V£»
£¨3£©ÓÉͼÒÒËùʾʵÑéµç·¿ÉÖª£¬Ôڱպϵç·ÖÐÓУº
E=I₁£¨R₄+R₃£©+I₂r£¬I₁=$\frac{E}{{R}_{4}+{R}_{3}}$-$\frac{r}{{R}_{4}+{R}_{3}}$I₂£¬
ÓÉͼÏó¿ÉÖª£¬Í¼ÏóµÄ½Ø¾àΪ£ºb=1.46¡Á10^-3=$\frac{E}{{R}_{4}+{R}_{3}}$=$\frac{E}{10+990}$=$\frac{E}{1000}$£¬
ÔòµçÔ´µç¶¯ÊÆΪ£ºE=1.46V£»
ͼÏóбÂÊΪ£ºk=$\frac{r}{{R}_{4}+{R}_{3}}$=$\frac{r}{1000}$=$\frac{¡÷{I}_{1}}{¡÷{I}_{2}}$=$\frac{1.46¡Á1{0}^{-3}-1.0¡Á1{0}^{-3}}{0.55}$¡Ö0.84£¬
µçÔ´ÄÚ×èΪ£ºr=0.84¦¸£»
¹Ê´ð°¸Îª£º£¨1£©R₁£»£¨2£©1.25£»£¨3£©1.46£»0.84£®

µãÆÀ ÔÚÓ¦ÓÃͼÏó·¨´¦ÀíʵÑéÊý¾ÝÇóµçÔ´µç¶¯ÊÆÓëÄÚ×èʱ£¬Òª¸ù¾ÝʵÑéµç·ÓëʵÑéÔ­ÀíÇó³öͼÏóµÄº¯Êý±í´ïʽ£¬È»ºóÇó³öµçÔ´µç¶¯ÊÆÓëÄÚ×裮