I£®Ò»¿óÇøµÄÖØÁ¦¼ÓËÙ¶ÈÆ«´ó£¬Ä³Í¬Ñ§¡°Óõ¥°Ú²â¶¨ÖØÁ¦¼ÓËٶȡ±ÊµÑé̽¾¿¸ÃÎÊÌ⣮]
£¨1£©ÓÃ×îС·Ö¶ÈΪºÁÃ×µÄÃ׳߲âµÃ°ÚÏߵij¤¶ÈΪ990.8mm£¬ÓÃ10·Ö¶ÈµÄÓα꿨³ß²âµÃ°ÚÇòµÄÖ±¾¶Èçͼ1Ëùʾ£¬°ÚÇòµÄÖ±¾¶Îª______mm£®
£¨2£©°Ñ°ÚÇò´ÓƽºâλÖÃÀ­¿ªÒ»¸öС½Ç¶ÈÓɾ²Ö¹ÊÍ·Å£¬Ê¹µ¥°ÚÔÚÊúֱƽÃæÄÚ°Ú¶¯£¬ÓÃÃë±í²â³öµ¥°Ú×ö50´ÎÈ«Õñ¶¯ËùÓõÄʱ¼ä£¬Ãë±í¶ÁÊýÈçͼ2Ëùʾ£¬¶Á³öËù¾­ÀúµÄʱ¼ä£¬µ¥°ÚµÄÖÜÆÚΪ______s£®
£¨3£©²âµÃµ±µØµÄÖØÁ¦¼ÓËÙ¶ÈΪ______m/s2£®£¨±£Áô3λÓÐЧÊý×Ö£©
II£®Ò»¿éµçÁ÷±íµÄÄÚ×è´óÔ¼ÊǼ¸°ÙÅ·£¬Ä³Í¬Ñ§ÓÃÈçͼ3µç·²âÁ¿ÆäÄÚ×èºÍÂúÆ«µçÁ÷£¬²¿·ÖʵÑé²½ÖèÈçÏ£º
¢ÙÑ¡ÔñÆ÷²Ä£ºÁ½¸öµç×èÏä¡¢2½Ú¸Éµç³Ø£¨Ã¿½Úµç¶¯ÊÆΪ1.5V£¬ÄÚ×è²»¼Æ£©¡¢2¸öµ¥µ¶µ¥ÖÀ¿ª¹ØºÍÈô¸Éµ¼Ïߣ»
¢Ú°´Èçͼ3ËùʾµÄµç·ͼÁ¬½ÓºÃÆ÷²Ä£¬¶Ï¿ª¿ª¹ØS1¡¢S2£¬½«µç×èÏä1µÄµç×èµ÷ÖÁ×î´ó£»
¢Û±ÕºÏ¿ª¹ØS1£¬µ÷½Úµç×èÏä1£¬²¢Í¬Ê±¹Û²ìµçÁ÷±íÖ¸Õ룬µ±Ö¸Õë´¦ÓÚÂúÆ«¿Ì¶Èʱ£¬¶ÁÈ¡µç×èÏä1µÄ×èֵΪ500¦¸£»
¢Ü±£³Öµç×èÏä1µÄµç×è²»±ä£¬ÔٱպϿª¹ØS2£¬Ö»µ÷½Úµç×èÏä2£¬²¢Í¬Ê±¹Û²âµçÁ÷±íÖ¸Õ룬µ±Ö¸Õë´¦ÓÚ°ëÆ«¿Ì¶Èʱ£¬¶ÁÈ¡µç×èÏä2µÄ×èֵΪ250¦¸£®
ͨ¹ý·ÖÎöÓë¼ÆËã¿ÉÖª£º
£¨1£©µçÁ÷±íÄÚ×èµÄ²âÁ¿Öµ RA=______£»µçÁ÷±íµÄÂúÆ«µçÁ÷Öµ Ig=______£»
£¨2£©¸Ãͬѧ·¢ÏÖµçÁ÷±íÂúÆ«¿Ì¶ÈµÄ±ê³ÆֵΪ¡°3A¡±£¬Óë²âÁ¿ÖµÍêÈ«²»·û£®ÓÚÊǽ«Ò»¸öµç×èÏäÓëµçÁ÷±í²¢Áª½øÐиÄ×°£¬Ê¹¸Ä×°ºóµÄµçÁ÷±íÁ¿³ÌÓëÂúÆ«¿Ì¶ÈµÄ±ê³ÆÖµÏà·û£¬Ôò¸Ä×°ºóµÄµçÁ÷±íµÄÄÚ×è
R/A
=_______£®
¾«Ó¢¼Ò½ÌÍø
¢ñ£¨1£©ÓÉͼ1ËùʾÓα꿨³ß¿ÉÖª£¬Ö÷³ßʾÊýÊÇ1.8cm=18mm£¬
Óαê³ßʾÊýÊÇ4¡Á0.1mm=0.4mm£¬Óα꿨³ßʾÊý£¬¼´°ÚÇòµÄÖ±¾¶Îª18mm+0.4mm=18.4mm£»
£¨2£©ÓÉͼ2ËùʾÃë±í¿ÉÖª£¬·ÖÕëʾÊýÊÇ1min=60s£¬ÃëÕëʾÊýÊÇ40s£¬ÔòÃë±íʾÊýÊÇ60s+40s=100s£¬
µ¥°ÚÖÜÆÚT=
t
n
=
100s
50
=2s£»
£¨3£©µ¥°Ú°Ú³¤L=l+
d
2
=990.8mm+
18.4mm
2
=1000mm=1m£»
Óɵ¥°ÚÖÜÆÚ¹«Ê½T=2¦Ð
L
g
£¬¿ÉÖªÖØÁ¦¼ÓËٶȣºg=
4¦Ð2L
T2
=
4¡Á(3.14)2¡Á1m
(2s)2
¡Ö9.86m/s2£»
¢ò£¨1£©ÓÉÌâÒâÖªµçÔ´µç¶¯ÊÆE=1.5V¡Á2=3V£»
±ÕºÏ¿ª¹ØS1£¬¶Ï¿ªS2ʱ£¬µç×èÏä1ÓëµçÁ÷±í´®Á¬½ÓÈëµç·£¬
µ±Ö¸Õë´¦ÓÚÂúÆ«¿Ì¶Èʱ£¬¶ÁÈ¡µç×èÏä1µÄ×èֵΪ500¦¸£¬
ÓÉ´®Áªµç·Ìص㼰ŷķ¶¨ÂɿɵãºE=Ig£¨RA+R1£©£¬¼´£º3V=Ig£¨RA+500¦¸£©  ¢Ù£¬
±ÕºÏ¿ª¹ØS1¡¢S2ʱ£¬µçÁ÷±íÓëµç×èÏä2²¢Áª£¬È»ºóÓëµç×èÏä1´®Áª£¬
µç×èÏä1×èÖµ²»±ä£¬µçÁ÷±íÖ¸Õë´¦ÓÚ°ëÆ«¿Ì¶È£¬µç×èÏä2µÄ×èֵΪ250¦¸£¬
´ËʱµçÁ÷±íÁ½¶ËµçѹΪ£ºUA=IARA=
Ig
2
¡ÁRA£¬Á÷¹ýµç×èÏä2µÄµçÁ÷£º
I2=
U2
R2
=
UA
R2
=
IgRA
2
R2
=
IgRA
2¡Á250¦¸
=
IgRA
500¦¸
£¬¸É·µçÁ÷I=IA+I2=
Ig
2
+
IgRA
500¦¸
£¬
ÓÉ´®Áªµç·Ìص㼰ŷķ¶¨ÂɿɵãºE=+UA+U1=
IgRA
2
+IR1¨T
IgRA
2
+£¨
Ig
2
+
IgRA
500¦¸
£©R1£¬
¼´3V¨T
IgRA
2
+£¨
Ig
2
+
IgRA
500¦¸
£©¡Á500¦¸    ¢Ú£¬
ÓÉ¢Ù¢Ú½âµÃ£ºRA=500¦¸£¬Ig=0.003A=3mA£»
£¨2£©µçÁ÷±íµÄÂúÆ«µçѹUA=IgRA=0.003A¡Á500¦¸=1.5V£¬
¸Ä×°ºóµçÁ÷±íµÄÄÚ×èRA¡ä=
UA
Ig¡ä
=
1.5V
3A
=0.5¦¸£®
¹Ê´ð°¸Îª£ºI¡¢£¨1£©18.4£»£¨2£©2.0£»£¨3£©9.86£»
II¡¢£¨1£©500¦¸£»£¨2£©3mA£»£¨3£©0.5¦¸£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

I£®Ò»¿óÇøµÄÖØÁ¦¼ÓËÙ¶ÈÆ«´ó£¬Ä³Í¬Ñ§¡°Óõ¥°Ú²â¶¨ÖØÁ¦¼ÓËٶȡ±ÊµÑé̽¾¿¸ÃÎÊÌ⣮]
£¨1£©ÓÃ×îС·Ö¶ÈΪºÁÃ×µÄÃ׳߲âµÃ°ÚÏߵij¤¶ÈΪ990.8mm£¬ÓÃ10·Ö¶ÈµÄÓα꿨³ß²âµÃ°ÚÇòµÄÖ±¾¶Èçͼ1Ëùʾ£¬°ÚÇòµÄÖ±¾¶Îª
 
mm£®
£¨2£©°Ñ°ÚÇò´ÓƽºâλÖÃÀ­¿ªÒ»¸öС½Ç¶ÈÓɾ²Ö¹ÊÍ·Å£¬Ê¹µ¥°ÚÔÚÊúֱƽÃæÄÚ°Ú¶¯£¬ÓÃÃë±í²â³öµ¥°Ú×ö50´ÎÈ«Õñ¶¯ËùÓõÄʱ¼ä£¬Ãë±í¶ÁÊýÈçͼ2Ëùʾ£¬¶Á³öËù¾­ÀúµÄʱ¼ä£¬µ¥°ÚµÄÖÜÆÚΪ
 
s£®
£¨3£©²âµÃµ±µØµÄÖØÁ¦¼ÓËÙ¶ÈΪ
 
m/s2£®£¨±£Áô3λÓÐЧÊý×Ö£©
II£®Ò»¿éµçÁ÷±íµÄÄÚ×è´óÔ¼ÊǼ¸°ÙÅ·£¬Ä³Í¬Ñ§ÓÃÈçͼ3µç·²âÁ¿ÆäÄÚ×èºÍÂúÆ«µçÁ÷£¬²¿·ÖʵÑé²½ÖèÈçÏ£º
¢ÙÑ¡ÔñÆ÷²Ä£ºÁ½¸öµç×èÏä¡¢2½Ú¸Éµç³Ø£¨Ã¿½Úµç¶¯ÊÆΪ1.5V£¬ÄÚ×è²»¼Æ£©¡¢2¸öµ¥µ¶µ¥ÖÀ¿ª¹ØºÍÈô¸Éµ¼Ïߣ»
¢Ú°´Èçͼ3ËùʾµÄµç·ͼÁ¬½ÓºÃÆ÷²Ä£¬¶Ï¿ª¿ª¹ØS1¡¢S2£¬½«µç×èÏä1µÄµç×èµ÷ÖÁ×î´ó£»
¢Û±ÕºÏ¿ª¹ØS1£¬µ÷½Úµç×èÏä1£¬²¢Í¬Ê±¹Û²ìµçÁ÷±íÖ¸Õ룬µ±Ö¸Õë´¦ÓÚÂúÆ«¿Ì¶Èʱ£¬¶ÁÈ¡µç×èÏä1µÄ×èֵΪ500¦¸£»
¢Ü±£³Öµç×èÏä1µÄµç×è²»±ä£¬ÔٱպϿª¹ØS2£¬Ö»µ÷½Úµç×èÏä2£¬²¢Í¬Ê±¹Û²âµçÁ÷±íÖ¸Õ룬µ±Ö¸Õë´¦ÓÚ°ëÆ«¿Ì¶Èʱ£¬¶ÁÈ¡µç×èÏä2µÄ×èֵΪ250¦¸£®
ͨ¹ý·ÖÎöÓë¼ÆËã¿ÉÖª£º
£¨1£©µçÁ÷±íÄÚ×èµÄ²âÁ¿Öµ RA=
 
£»µçÁ÷±íµÄÂúÆ«µçÁ÷Öµ Ig=
 
£»
£¨2£©¸Ãͬѧ·¢ÏÖµçÁ÷±íÂúÆ«¿Ì¶ÈµÄ±ê³ÆֵΪ¡°3A¡±£¬Óë²âÁ¿ÖµÍêÈ«²»·û£®ÓÚÊǽ«Ò»¸öµç×èÏäÓëµçÁ÷±í²¢Áª½øÐиÄ×°£¬Ê¹¸Ä×°ºóµÄµçÁ÷±íÁ¿³ÌÓëÂúÆ«¿Ì¶ÈµÄ±ê³ÆÖµÏà·û£¬Ôò¸Ä×°ºóµÄµçÁ÷±íµÄÄÚ×è
R
/
A
=_
 
£®¾«Ó¢¼Ò½ÌÍø

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º2011Äê4ÔÂÀí¿Æ×ÛºÏÎïÀíʵÑéÊÔ¾í£¨¶þ£©£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

I£®Ò»¿óÇøµÄÖØÁ¦¼ÓËÙ¶ÈÆ«´ó£¬Ä³Í¬Ñ§¡°Óõ¥°Ú²â¶¨ÖØÁ¦¼ÓËٶȡ±ÊµÑé̽¾¿¸ÃÎÊÌ⣮]
£¨1£©ÓÃ×îС·Ö¶ÈΪºÁÃ×µÄÃ׳߲âµÃ°ÚÏߵij¤¶ÈΪ990.8mm£¬ÓÃ10·Ö¶ÈµÄÓα꿨³ß²âµÃ°ÚÇòµÄÖ±¾¶Èçͼ1Ëùʾ£¬°ÚÇòµÄÖ±¾¶Îª______mm£®
£¨2£©°Ñ°ÚÇò´ÓƽºâλÖÃÀ­¿ªÒ»¸öС½Ç¶ÈÓɾ²Ö¹ÊÍ·Å£¬Ê¹µ¥°ÚÔÚÊúֱƽÃæÄÚ°Ú¶¯£¬ÓÃÃë±í²â³öµ¥°Ú×ö50´ÎÈ«Õñ¶¯ËùÓõÄʱ¼ä£¬Ãë±í¶ÁÊýÈçͼ2Ëùʾ£¬¶Á³öËù¾­ÀúµÄʱ¼ä£¬µ¥°ÚµÄÖÜÆÚΪ______s£®
£¨3£©²âµÃµ±µØµÄÖØÁ¦¼ÓËÙ¶ÈΪ______m/s2£®£¨±£Áô3λÓÐЧÊý×Ö£©
II£®Ò»¿éµçÁ÷±íµÄÄÚ×è´óÔ¼ÊǼ¸°ÙÅ·£¬Ä³Í¬Ñ§ÓÃÈçͼ3µç·²âÁ¿ÆäÄÚ×èºÍÂúÆ«µçÁ÷£¬²¿·ÖʵÑé²½ÖèÈçÏ£º
¢ÙÑ¡ÔñÆ÷²Ä£ºÁ½¸öµç×èÏä¡¢2½Ú¸Éµç³Ø£¨Ã¿½Úµç¶¯ÊÆΪ1.5V£¬ÄÚ×è²»¼Æ£©¡¢2¸öµ¥µ¶µ¥ÖÀ¿ª¹ØºÍÈô¸Éµ¼Ïߣ»
¢Ú°´Èçͼ3ËùʾµÄµç·ͼÁ¬½ÓºÃÆ÷²Ä£¬¶Ï¿ª¿ª¹ØS1¡¢S2£¬½«µç×èÏä1µÄµç×èµ÷ÖÁ×î´ó£»
¢Û±ÕºÏ¿ª¹ØS1£¬µ÷½Úµç×èÏä1£¬²¢Í¬Ê±¹Û²ìµçÁ÷±íÖ¸Õ룬µ±Ö¸Õë´¦ÓÚÂúÆ«¿Ì¶Èʱ£¬¶ÁÈ¡µç×èÏä1µÄ×èֵΪ500¦¸£»
¢Ü±£³Öµç×èÏä1µÄµç×è²»±ä£¬ÔٱպϿª¹ØS2£¬Ö»µ÷½Úµç×èÏä2£¬²¢Í¬Ê±¹Û²âµçÁ÷±íÖ¸Õ룬µ±Ö¸Õë´¦ÓÚ°ëÆ«¿Ì¶Èʱ£¬¶ÁÈ¡µç×èÏä2µÄ×èֵΪ250¦¸£®
ͨ¹ý·ÖÎöÓë¼ÆËã¿ÉÖª£º
£¨1£©µçÁ÷±íÄÚ×èµÄ²âÁ¿Öµ RA=______£»µçÁ÷±íµÄÂúÆ«µçÁ÷Öµ Ig=______£»
£¨2£©¸Ãͬѧ·¢ÏÖµçÁ÷±íÂúÆ«¿Ì¶ÈµÄ±ê³ÆֵΪ¡°3A¡±£¬Óë²âÁ¿ÖµÍêÈ«²»·û£®ÓÚÊǽ«Ò»¸öµç×èÏäÓëµçÁ÷±í²¢Áª½øÐиÄ×°£¬Ê¹¸Ä×°ºóµÄµçÁ÷±íÁ¿³ÌÓëÂúÆ«¿Ì¶ÈµÄ±ê³ÆÖµÏà·û£¬Ôò¸Ä×°ºóµÄµçÁ÷±íµÄÄÚ×è=_______£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸