ʵÑéÊÒÖÐ×îÐÂÑÐÖƳöÒ»ÖÖ½ðÊôÑõ»¯ÎïвÄÁÏ.´óÁ¿ÊµÑé±íÃ÷£¬Í¨¹ýÕâÖÖвÄÁÏÖƳɵľùÔÈ°ôÖеĵçÁ÷ I ×ñÑ­I=KU3µÄ¹æÂÉ£¨ÆäÖÐU±íʾ°ôÁ½¶ËµÄµçÊƲʽÖÐK£½0.02A/V3 £©.ÏÖ½«¸Ã°ôÓëÒ»¸ö×ñÑ­Å·Ä·¶¨Âɵĵç×è´®ÁªÔÚÒ»Æðºó½ÓÔÚÒ»¸öÄÚ×è¿ÉÒÔºöÂÔ£¬µç¶¯ÊÆΪ6VµÄµçÔ´ÉÏ.
£¨1£©µ±´®ÁªµÄµç×èÆ÷µÄ×èÖµR1£½_____¦¸Ê±£¬µç·ÖеĵçÁ÷Ϊ0.16A.
£¨2£©µ±´®ÁªµÄµç×èÆ÷µÄ×èÖµR2£½_____¦¸Ê±£¬°ôÉÏÏûºÄµÄµç¹¦ÂÊÊǵç×èÉÏÏûºÄµÄµç¹¦ÂʵÄ2±¶.

25¦¸£»1.56¦¸

¡¾ÊÔÌâ·ÖÎö¡¿

£¨1£©µ±µç·ÖеçÁ÷I=0.16Aʱ£¬°ôÁ½¶ËµÄµçѹ
U=V=2V
µç×èR1Á½¶Ëµçѹ      U¡ä£½E£­U£½4V
                                  R1£½U¡ä/I=4/0.16¦¸=25¦¸
£¨2£©°ôÉÏÏûºÄµÄµç¹¦ÂÊUIÊǵç×èÉÏÏûºÄµÄµç¹¦ÂÊ£¨E£­U£©IµÄ2±¶£¬¼´
UI=2£¨E£­U£©I
½âµÃ°ôÁ½¶ËµÄµçѹ  U=2E¡®3=4V
µç·ÖеçÁ÷  I=KU3=0.02¡Á43A=1.28A

µç×è  R2=£¨E-U£©/2=¦¸=1.56¦¸

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

ͬ²½Á·Ï°²á´ð°¸