已知:① C(s)+O2(g)=CO2(g), DH=-393.5 kJ?mol-1 ② 2CO(g)+O2(g)=2CO2(g), DH=-566 kJ?mol-1 ③ TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g), DH=+141 kJ?mol-1 则TiO2(s)+2Cl2(g)+2C(s)=TiCl4的DH= .答案:-80 kJ?mol-1 查看更多

 

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已知:① C(s)+O2(g)=CO2(g);          DH=—393.5 kJ·mol-1

② 2CO(g)+O2(g)=2CO2(g);                DH=-566 kJ·mol-1

③ TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g);       DH=+141 kJ·mol-1

则TiO2(s)+2Cl2(g)+2C(s)=TiCl4(s)+2CO(g)的DH=                

 

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已知:① C(s)+O2(g)=CO2(g);           DH=—393.5 kJ·mol-1

② 2CO(g)+O2(g)=2CO2(g);                 DH=-566 kJ·mol-1

③ TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g);        DH=+141 kJ·mol-1

则TiO2(s)+2Cl2(g)+2C(s)=TiCl4(s)+2CO(g)的DH=                

 

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由金红石(TiO2)制取单质Ti,涉及到的步骤为::

TiO2TiCl4Ti

    已知:① C(s)+O2(g)=CO2(g);         DH=-393.5 kJ?mol-1

    ② 2CO(g)+O2(g)=2CO2(g);           DH=-566 kJ?mol-1

    ③ TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g);    DH=+141 kJ?mol-1

    则TiO2(s)+2Cl2(g)+2C(s)=TiCl4(s)+2CO(g)的DH                

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(5分)把煤作为燃料可通过下列两种途径:
途径Ⅰ  C(s)+O2(g)=====CO2(g);ΔH1<0    ①
途径Ⅱ 先制成水煤气:
C(s)+H2O(g)=====CO(g)+H2(g);ΔH2>0    ②
再燃烧水煤气:
2CO(g)+O2(g)=====2CO2(g);ΔH3<0            ③
2H2(g)+O2(g)=====2H2O(g);ΔH4<0       ④
请回答下列问题:
(1)途径Ⅰ放出的热量理论上_________(填“大于”“等于”或“小于”)途径Ⅱ放出的热量。
(2)ΔH1、ΔH2、ΔH3、ΔH4的数学关系式是_______________。
(3).已知:① C(s)+O2(g)=CO2(g);        DH=—393.5 kJ·mol-1
② 2CO(g)+O2(g)=2CO2(g);        DH=-566 kJ·mol-1
③ TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g);   DH=+141 kJ·mol-1
则TiO2(s)+2Cl2(g)+2C(s)=TiCl4(s)+2CO(g)的DH=                

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(5分)把煤作为燃料可通过下列两种途径:

途径Ⅰ  C(s)+O2(g)=====CO2(g);ΔH1<0   ①

途径Ⅱ  先制成水煤气:

C(s)+H2O(g)=====CO(g)+H2(g);ΔH2>0            ②

再燃烧水煤气:

2CO(g)+O2(g)=====2CO2(g);ΔH3<0              ③

2H2(g)+O2(g)=====2H2O(g); ΔH4<0       ④

请回答下列问题:

(1)途径Ⅰ放出的热量理论上_________(填“大于”“等于”或“小于”)途径Ⅱ放出的热量。

(2)ΔH1、ΔH2、ΔH3、ΔH4的数学关系式是_______________。

(3).已知:① C(s)+O2(g)=CO2(g);         DH=—393.5 kJ·mol-1

② 2CO(g)+O2(g)=2CO2(g);         DH=-566 kJ·mol-1

③ TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g);    DH=+141 kJ·mol-1

则TiO2(s)+2Cl2(g)+2C(s)=TiCl4(s)+2CO(g)的DH=                

 

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