9.(09四川) -May I open the window to let in some fresh air?
-___________
A. Come on B. Take care C. Go ahead! D. Hold on!
[答案]C 根据语境可以知道:去开吧,去做吧。所以答案为:C。容易误选A。come on 的意思是“算了吧!加油!”
8.(09江西) ----Thank you for your MP4 player. I’ll get Mary to take it to you soon.
----___________.
I’ve bought a new one.
A. No
sense B. No
hurry C. No
way D. No
use
[答案]B 考查交际用语。由“我已经买了一个”,便知是NO hurry, 不着急。
7.(09湖南) ______ the police thought he was the most likely one, since they had no exact proof about it, they could not arrest him.
A. Although B. As long as C. If only D. As soon as
[答案]A
[解析]考查从属连词的用法。根据句意,引导让步状语从句。故选A。
6.(09福建) –Bruce, I really appreciate your handwriting.
- .
A. I
practice every day
B. Thank you very much
C.
No, I don’t think so
D. Well, it’s not good enough
[答案]B 考查交际用语。前一句表示赞扬,应答句应表示感谢,故选B。
5.(09北京) At first he hated the new job but decided to give himself a few months to see___ it got any better.
A. when B. how C. why D. if
[答案]A
4.(09北京) You may use room as you like ____ you clean it up afterwards
A. so
far as B. so long
as C. in case D. even if
[答案]C
3.(09北京) John plays basketball well, _____his favorite sport is badminton.
A.
so B.
or C. yet D. for
[答案]D
1.(09安徽) – I wonder how much you charge for your services.
-- The
first two are free the
third costs $30.
A.
while
B. until
C.
when
D. before
[答案]A
(09安徽)2 -- Could you be so kind as to close the window?
-- .
A. With
pleasure
B. Go ahead
C. Yes,
please
D. That's OK
[答案]A
31.(2009重庆卷文)(本小题满分13分,(Ⅰ)问7分,(Ⅱ)问6分)
某单位为绿化环境,移栽了甲、乙两种大树各2株.设甲、乙两种大树移栽的成活率分别为
和
,且各株大树是否成活互不影响.求移栽的4株大树中:21世纪教育网
![]()
(Ⅰ)至少有1株成活的概率;
(Ⅱ)两种大树各成活1株的概率.
解: 设
表示第
株甲种大树成活,
; 设
表示第
株乙种大树成活, ![]()
则
独立,且![]()
(Ⅰ)至少有1株成活的概率为:
![]()
(Ⅱ)由独立重复试验中事件发生的概率公式知,两种大树各成活1株的概率为:
21世纪教育网
![]()
30.(2009重庆卷理)(本小题满分13分,(Ⅰ)问7分,(Ⅱ)问6分)
某单位为绿化环境,移栽了甲、乙两种大树各2株.设甲、乙两种大树移栽的成活率分别为
和
,且各株大树是否成活互不影响.求移栽的4株大树中:
(Ⅰ)两种大树各成活1株的概率;
(Ⅱ)成活的株数
的分布列与期望.
![]()
解:设
表示甲种大树成活k株,k=0,1,2
表示乙种大树成活l株,l=0,1,2
则
,
独立. 由独立重复试验中事件发生的概率公式有
,
.
据此算得
,
,
.
21世纪教育网
![]()
,
,
.
(Ⅰ) 所求概率为
.
(Ⅱ) 解法一:
的所有可能值为0,1,2,3,4,且21世纪教育网
![]()
,
,
![]()
=
,
.
.
综上知
有分布列
|
|
0 |
1 |
2 |
3 |
4 |
|
P |
1/36 |
1/6 |
13/36 |
1/3 |
1/9 |
从而,
的期望为
![]()
(株)
解法二:
分布列的求法同上
令
分别表示甲乙两种树成活的株数,则
![]()
![]()
故有
21世纪教育网
![]()
从而知![]()
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