分析:(1)先算小括号里面的减法,再算括号外的除法,然后算乘法,最后算加法;
(2)先算小括号里面的减法,再根据乘法结合律简算;
(3)先同时运算乘法,然后再算减法,最后算加法.
(4)先把(2890+
+
+
)÷(
+
+
)分成2890÷(
+
+
)+(
+
+
)÷(
+
+
),然后在根据商不变规律简算.
(5)前面每个分母都是后面的两倍,如果加多一个
,分数部分就等于1.
+
+
+…+
=1-
;
如果1+2+4+8+…+512加多一个1,后面整数部分就等于2×512,1+2+4+8+…+512=2×512-1=1023;再把这两部分加在一起即可;
解答:解:(1)490+6510÷(101-98)×217,
=490+6510÷3×217,
=490+2170×217,
=490+470890,
=471380;
(2)3
×(7
-1
)×0.3÷1
,
=3
×
×0.3÷1
,
=
×
×
×
,
=(
×
)×(
×
),
=1×
,
=
;
(3)41.2×8.1-11×9
+53.7×1.9,
=333.72-101.75+102.03,
=231.97+102.03,
=334;
(4)(2890+
+
+
)÷(
+
+
),
=2890÷(
+
+
)+(
+
+
)÷(
+
+
),
=2890÷(
+
+
)+1,
=(2890×120)÷[120×(
+
+
)]+1,
=(2890×120)÷[120×
+120×
+120×
]+1,
=(2890×120)÷[100+105+84]+1,
=2890×120÷289+1,
=2890÷289×120+1,
=10×120+1,
=1200,
=1201;
(5)
+
+
+…+
+1+2+4+8+…+512,
=(
+
+
+…+
+
-
)+(1+2+4+8+…+512+1-1);
=(1-
)+(512×2-1),
=
+1023,
=1023
.
点评:本题考查了较复杂的简便运算,注意找清楚规律,再根据规律化简.