Question

15£®½â·½³Ì£®
£¨1£©x¡Á$\frac{3}{5}$=20¡Á$\frac{1}{4}$£»      
£¨2£©$\frac{1}{3}$+10x=$\frac{4}{5}$£»      
£¨3£©$\frac{3}{5}$x+25=40£»   
£¨4£©x-$\frac{1}{5}$x=68£»     
£¨5£©19-$\frac{3}{25}$x=7£»   
£¨6£©$\frac{2}{9}$x+$\frac{1}{6}$=$\frac{7}{9}$£®

Answer 1

·ÖÎö £¨1£©ÏȽ«Ô­·½³Ì»¯¼ò£¬ÔÙ¸ù¾ÝµÈʽµÄÐÔÖÊ£¬ÔÚ·½³ÌÁ½±ßͬʱ³ýÒÔ$\frac{3}{5}$µÃ½â£»
£¨2£©¸ù¾ÝµÈʽµÄÐÔÖÊ£¬ÔÚ·½³ÌÁ½±ßÏÈͬʱ¼õÈ¥$\frac{1}{3}$£¬ÔÙͬʱ³ýÒÔ10µÃ½â£»
£¨3£©¸ù¾ÝµÈʽµÄÐÔÖÊ£¬ÔÚ·½³ÌÁ½±ßÏÈͬʱ¼õÈ¥25£¬ÔÙͬʱ³ýÒÔ$\frac{3}{5}$µÃ½â£»
£¨4£©¸ù¾Ý³Ë·¨·ÖÅäÂÉ»¯¼ò£¬ÔÙ¸ù¾ÝµÈʽµÄÐÔÖÊ£¬ÔÚ·½³ÌÁ½±ßͬʱ³ýÒÔ$\frac{4}{5}$µÃ½â£»
£¨5£©¸ù¾ÝµÈʽµÄÐÔÖÊ£¬ÔÚ·½³ÌÁ½±ßÏÈͬʱ¼ÓÉÏ$\frac{3}{25}$x£¬ÔÙͬʱ¼õÈ¥7£¬×îºóͬʱ³ýÒÔ$\frac{3}{25}$µÃ½â£»
£¨6£©¸ù¾ÝµÈʽµÄÐÔÖÊ£¬ÔÚ·½³ÌÁ½±ßÏÈͬʱ¼õÈ¥$\frac{1}{6}$£¬ÔÙͬʱ³ýÒÔ$\frac{2}{9}$µÃ½â£»

½â´ð ½â£º
£¨1£©x¡Á$\frac{3}{5}$=20¡Á$\frac{1}{4}$
       $\frac{3}{5}$x=5
    $\frac{3}{5}$x¡Â$\frac{3}{5}$=5¡Â$\frac{3}{5}$
         x=5¡Á$\frac{5}{3}$
         x=$\frac{25}{3}$

£¨2£©$\frac{1}{3}$+10x=$\frac{4}{5}$
  $\frac{1}{3}$+10x-$\frac{1}{3}$=$\frac{4}{5}$-$\frac{1}{3}$
       10x=$\frac{7}{15}$
   10x¡Â10=$\frac{7}{15}$¡Â10
         x=$\frac{7}{15}$¡Á$\frac{1}{10}$
         x=$\frac{7}{150}$  
 
£¨3£©$\frac{3}{5}$x+25=40
  $\frac{3}{5}$x+25-25=40-25
        $\frac{3}{5}$x=15
     $\frac{3}{5}$x¡Â$\frac{3}{5}$=15¡Â$\frac{3}{5}$
          x=15¡Á$\frac{5}{3}$
          x=25

£¨4£©x-$\frac{1}{5}$x=68
 £¨1-$\frac{1}{5}$£©x=68
       $\frac{4}{5}$x=68
    $\frac{4}{5}$x¡Â$\frac{4}{5}$=68¡Â$\frac{4}{5}$
         x=68¡Á$\frac{5}{4}$
         x=85  
 
£¨5£©19-$\frac{3}{25}$x=7
19-$\frac{3}{25}$x+$\frac{3}{25}$x=7+$\frac{3}{25}$x
         19=7+$\frac{3}{25}$x
       19-7=7+$\frac{3}{25}$x-7
         12=$\frac{3}{25}$x
     12¡Â$\frac{3}{25}$=$\frac{3}{25}$x¡Â$\frac{3}{25}$
     12¡Á$\frac{25}{3}$=x
        100=x
          x=100 

£¨6£©$\frac{2}{9}$x+$\frac{1}{6}$=$\frac{7}{9}$
  $\frac{2}{9}$x+$\frac{1}{6}$-$\frac{1}{6}$=$\frac{7}{9}$-$\frac{1}{6}$
       $\frac{2}{9}$x=$\frac{22}{36}$
    $\frac{2}{9}$x¡Â$\frac{2}{9}$=$\frac{22}{36}$¡Â$\frac{2}{9}$
         x=$\frac{22}{36}$¡Á$\frac{9}{2}$
         x=$\frac{11}{4}$

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