ijÐËȤС×éΪ²â¶¨ÊµÑéÊÒÖÐһƿ¾ÃÖõĹýÑõ»¯ÇâÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£¬ÊµÑé²âµÃÏà¹ØÊý¾ÝÈçͼËùʾ£º
¹ýÑõ»¯ÇâÈÜÒº68.0g+¶þÑõ»¯ÃÌ1.0g
ÖÁÖÊÁ¿²»ÔÙ¼õÇá
Ê£ÓàµÄ»ìºÏÎï67.4g
£¨1£©Ê£ÓàµÄ»ìºÏÎïÖжþÑõ»¯Ã̵ÄÖÊÁ¿Îª
1.0
1.0
g£¬¶þÑõ»¯ÃÌÔÚ·´Ó¦ÖеÄ×÷ÓÃÊÇ
´ß»¯×÷ÓÃ
´ß»¯×÷ÓÃ
£¬·´Ó¦Éú³ÉÑõÆøµÄÖÊÁ¿Îª
1.6
1.6
g£®
£¨2£©¼ÆËã¸Ã¹ýÑõ»¯ÇâÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿£®
£¨3£©¼ÆËã¸Ã¹ýÑõ»¯ÇâÈÜÒºÖÐÈÜÖÊÖÊÁ¿·ÖÊý£®
·ÖÎö£º£¨1£©¶þÑõ»¯ÃÌÊǹýÑõ»¯Çâ·Ö½âµÄ´ß»¯¼Á£¬´ß»¯¼ÁÔÚ»¯Ñ§·´Ó¦Ç°ºóÖÊÁ¿²»±ä£»¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬ÔÚ»¯Ñ§·´Ó¦ÖУ¬²Î¼Ó·´Ó¦Ç°¸÷ÎïÖʵÄÖÊÁ¿×ܺ͵ÈÓÚ·´Ó¦ºóÉú³É¸÷ÎïÖʵÄÖÊÁ¿×ܺͣ®Òò´ËÍêÈ«·´Ó¦ºó£¬ÎïÖʼõÉÙµÄÖÊÁ¿¾ÍÊÇÉú³ÉµÄÆøÌåÖÊÁ¿£»
£¨2£©¸ù¾Ý¹ýÑõ»¯Çâ·Ö½âµÄ»¯Ñ§·½³ÌʽºÍ£¨1£©ÖмÆËã³öµÄÑõÆøµÄÖÊÁ¿£¬¾Í¿É¼ÆËã³ö²ÎÓë·´Ó¦µÄ¹ýÑõ»¯ÇâµÄÖÊÁ¿£»£¨3£©¸ù¾ÝÖÊÁ¿·ÖÊý¹«Ê½¼ÆËã¼´¿É£®
½â´ð£º½â£º£¨1£©ÒòΪ´ß»¯¼ÁÔÚ»¯Ñ§·´Ó¦Ç°ºóÖÊÁ¿²»±ä£¬¹Ê»ìºÏÎïÖжþÑõ»¯Ã̵ÄÖÊÁ¿Îª1.0g£»¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬·´Ó¦Éú³ÉÑõÆøµÄÖÊÁ¿=68g+1.0g-67.4g=1.6g£»¹Ê´ð°¸Îª£º1.0£¬´ß»¯×÷Óà 1.6
£¨2£©Éè68.0 g¹ýÑõ»¯ÇâÈÜÒºÖк¬ÓйýÑõ»¯ÇâµÄÖÊÁ¿Îªx£®
2H2O2
 MnO2 
.
 
2H2O+O2¡ü
68               32
x               1.6g           
68
x
=
32
1.6g

x=3.4g
´ð£º¹ýÑõ»¯ÇâÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿Îª3.4g
£¨3£©¹ýÑõ»¯ÇâÈÜÒºµÄÈÜÖʵÄÖÊÁ¿·ÖÊý=
3.4g
68.0g
¡Á100%=5.0%
´ð£º¹ýÑõ»¯ÇâÈÜÒºÖÐÈÜÖÊÖÊÁ¿·ÖÊýΪ5.0%
µãÆÀ£º±¾ÌâÖ÷Òª¿¼²éѧÉú¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£»ÔËÓû¯Ñ§·½³ÌʽºÍÖÊÁ¿·ÖÊý¹«Ê½½øÐмÆËãµÄÄÜÁ¦£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¹ýÑõ»¯Çâ²»Îȶ¨»á×ÔÈ»·Ö½â£¬¾ÃÖõĹýÑõ»¯ÇâÈÜÒº£¬ÆäÈÜÖʵÄÖÊÁ¿·ÖÊý»á±äС£®Ä³ÐËȤС×éΪ²â¶¨ÊµÑéÊÒÖÐһƿ¾ÃÖõĹýÑõ»¯ÇâÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£¬½øÐÐʵÑ飮²âµÃÏà¹ØÊý¾ÝÈçͼËùʾ£º
¾«Ó¢¼Ò½ÌÍø
£¨1£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬·´Ó¦Éú³ÉÑõÆøµÄÖÊÁ¿Îª
 
£®
£¨2£©¼ÆËã¸Ã¹ýÑõ»¯ÇâÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£®£¨Ð´³ö¼ÆËã¹ý³Ì£©
ÓÑÇéÌáʾ£ºÊµÑéÖйýÑõ»¯Çâ·Ö½âµÄ»¯Ñ§·½³ÌʽΪ2H2O2
 MnO2 
.
 
2H2+2O2£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¹ýÑõ»¯Ç⣨H2O2£©²»Îȶ¨»á×ÔÈ»·Ö½â£¬¾ÃÖõĹýÑõ»¯ÇâÈÜÒº£¬ÆäÈÜÖÊÖÊÁ¿·ÖÊý»á±äС£®Ä³ÐËȤС×éΪ²â¶¨ÊµÑéÊÒÖÐһƿ¾ÃÖõĹýÑõ»¯ÇâÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£¬½øÐÐʵÑ飮²âµÃÏà¹ØÊý¾ÝÈçͼËùʾ£º
£¨1£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬·´Ó¦Éú³ÉÑõÆøµÄÖÊÁ¿Îª
0.8
0.8
g£»
£¨2£©¹ýÑõ»¯ÇâÖÐÇâÔªËغÍÑõÔªËصÄÖÊÁ¿±ÈΪ
1£º16
1£º16
£»
£¨3£©¸Ã¹ýÑõ»¯ÇâÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ
5%£®
5%£®
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijÐËȤС×éΪ²â¶¨ÊµÑéÊÒÖÐһƿ¾ÃÖõĹýÑõ»¯ÇâÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£¬ÊµÑé²âµÃÏà¹ØÊý¾ÝÈçͼËùʾ£º

£¨1£©Ê£ÓàµÄ»ìºÏÎïÖжþÑõ»¯Ã̵ÄÖÊÁ¿Îª
2.0
2.0
g£¬·´Ó¦Éú³ÉÑõÆøµÄÖÊÁ¿Îª
1.6
1.6
g£®
£¨2£©¸Ã¹ýÑõ»¯ÇâÈÜÒºÖÐÈÜÖÊÖÊÁ¿·ÖÊýΪ¶àÉÙ£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijÐËȤС×éΪ²â¶¨Ò»Æ¿¹ýÑõ»¯ÇâÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£¬ÊµÑé²âµÃÏà¹ØÊý¾ÝÈçͼËùʾ£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¾«Ó¢¼Ò½ÌÍø
£¨1£©·´Ó¦Éú³ÉÑõÆøµÄÖÊÁ¿Îª
 
g£®
£¨2£©¼ÆËã¸Ã¹ýÑõ»¯ÇâÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¹ú¼Ò¹æ¶¨£¬ÄðÔìʳ´×µÄ×ÜËẬÁ¿±ê׼Ϊ3.5¡«5.0g/100mL¡²×ÜËẬÁ¿¼´100mLʳ´×Öк¬´×Ëᣨ»¯Ñ§Ê½Îª£ºCH3COOH£©µÄÖÊÁ¿¡³£®Ä³ÐËȤС×éΪ²â¶¨Ò»ÊÐÊÛʳ´×µÄ×ÜËẬÁ¿£¬½øÐÐÁËʵÑ飮ʵÑéºó£¬µÃÖª10.0mL¸Ãʳ´×ÑùÆ·Óë7.5gÈÜÖʵÄÖÊÁ¿·ÖÊýΪ4%µÄÇâÑõ»¯ÄÆÈÜҺǡºÃÍêÈ«·´Ó¦£®
£¨1£©´×ËáÊôÓÚ
 
£¨Ìî¡°ÓлúÎ»ò¡°ÎÞ»úÎ£©£®
£¨2£©´×ËáÖÐÑõÔªËصÄÖÊÁ¿·ÖÊýΪ
 
£¨½á¹û¾«È·µ½0.1%£©£®
£¨3£©¼ÆËã¸ÃÊÐÊÛʳ´×ÑùÆ·ÖеÄ×ÜËẬÁ¿£¬²¢ËµÃ÷ÊÇ·ñ·ûºÏ¹ú¼Ò±ê×¼£®£¨Ê³´×ºÍÇâÑõ»¯ÄÆ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£ºCH3COOH+NaOH¨TCH3COONa+H2O£¬¼ÙÉè¸ÃÊÐÊÛʳ´×ÑùÆ·ÖÐÆäËüÎïÖʲ»ÓëÇâÑõ»¯ÄÆ·¢Éú·´Ó¦£©£¨¼ÆËã¹ý³ÌÌîдÔÚ´ðÌâÖ½ÉÏ£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸