»¯Ñ§ÓëÉú»îÃÜÇÐÏà¹Ø£®
£¨1£©ÏÂÁÐÉú»îÎïÆ·ÖУ¬ËùʹÓõÄÖ÷Òª²ÄÁÏÊôÓںϳÉÓлú¸ß·Ö×Ó²ÄÁϵÄÊÇ________£¨Ìî×ÖĸÐòºÅ£©£®

£¨2£©ÎªÁ˼õÉÙ¡°°×É«ÎÛȾ¡±£¬ÔÚ³¬ÊйºÎïʱ£¬¹ú¼ÒÌᳫ________£®
£¨3£©ÈËÀàÉãÈ¡µÄʳÎïÖУ¬º¬ÓеÄÓªÑøËØÓÐÌÇÀà¡¢ÓÍÖ¬¡¢Î¬ÉúËØ¡¢ÎÞ»úÑΡ¢Ë®ºÍ________£®µ±ÈËÌåȱ________ʱ£¬»á·¢Éú¹ÇÖÊÊèËÉ£¬ÈÝÒ×¹ÇÕÛ£®
£¨4£©¼ÒÍ¥Éú»îÖг£¼ûµÄÀ¬»øÓУº¢Ù¼¦µ°Æ¤£¬¢Ú·ÏÖ½£¬¢ÛÀòËÒ¶£¬¢ÜÅ£ÄÌ´ü£¬ÆäÖÐÊôÓÚ³øÓàÀ¬»øµÄÊÇ________£¨ÌîÊý×ÖÐòºÅ£©£®

½â£º£¨1£©ËÜÁϺÐÊôÓںϳÉÓлú¸ß·Ö×Ó²ÄÁÏ£¬ÃÞ²¼´ü¡¢ÑòÈÞΧ½íÊôÓÚÌìÈ»²ÄÁÏ£¬îѺϽ𾵼ÜÊôÓÚ½ðÊô²ÄÁÏ£»
£¨2£©ÎªÁ˼õÉÙ¡°°×É«ÎÛȾ¡±£¬ÔÚ³¬ÊйºÎïʱ£¬¹ú¼ÒÌᳫ£ºÓò¼´ü´úÌæËÜÁÏ´ø»òÖظ´Ê¹ÓÃËÜÁÏ´ü£»
£¨3£©ÈËÀàÉãÈ¡µÄʳÎïÖУ¬º¬ÓеÄÓªÑøËØÓÐÌÇÀà¡¢ÓÍÖ¬¡¢Î¬ÉúËØ¡¢ÎÞ»úÑΡ¢Ë®ºÍµ°°×ÖÊ£¬µ±ÈËÌåȱ¸Æʱ£¬»á·¢Éú¹ÇÖÊÊèËÉ£¬ÈÝÒ×¹ÇÕÛ£»
£¨4£©¼ÒÍ¥Éú»îÖг£¼ûµÄÀ¬»øÓУº¢Ù¼¦µ°Æ¤£¬¢Ú·ÏÖ½£¬¢ÛÀòËÒ¶£¬¢ÜÅ£ÄÌ´ü£¬ÆäÖÐÊôÓÚ³øÓàÀ¬»øµÄÊǼ¦µ°Æ¤ºÍÀòËÒ¶£®
¹Ê´ð°¸Îª£º
£¨1£©A£»
£¨2£©Óò¼´ü´úÌæËÜÁÏ´ø»òÖظ´Ê¹ÓÃËÜÁÏ´ü£»
£¨3£©µ°°×ÖÊ£»¸Æ£»
£¨4£©¢Ù¢Û£®
·ÖÎö£º£¨1£©¸ù¾Ý²ÄÁϵķÖÀà½øÐнâ´ð£»
£¨2£©¸ù¾Ý°×É«ÎÛȾµÄ·ÀÖδëÊ©½øÐнâ´ð£»
£¨3£©¸ù¾ÝÈËÌåÖк¬ÓеÄÓªÑøËؽøÐнâ´ð£»
£¨4£©¸ù¾ÝÀ¬»øµÄ·ÖÀà½øÐнâ´ð£®
µãÆÀ£º±¾Ìâ´ÓÉú»îµÄʵ¼Ê³ö·¢ÁªÏµËùѧ»¯Ñ§ÖªÊ¶£¬Ê¹ÎÒÃÇÃ÷°×»¯Ñ§ÎïÖʶÔÈËÌ彡¿µµÄÓ°ÏìÒÔ¼°²ÄÁϵķÖÀ࣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

12¡¢»¯Ñ§ÓëÉú»îÃÜÇÐÏà¹Ø
£¨1£©ÉÅʳºÏÀí¡¢ÓªÑø¾ùºâÊǽ¡¿µµÄ»ù±¾±£Ö¤£®ÏÂÁÐʳÎïÖУ¬¸»º¬ÌÇÀàµÄÊÇ
C
£¨Ìî×ÖĸÐòºÅ£¬ÏÂͬ£©£¬ÄÜÌṩ´óÁ¿µ°°×ÖʵÄÊÇ
D
£®
A£®Ê³ÓÃÓÍ      B£®´ó°×²Ë     C£®Ã×·¹     D£®ÓãÈâ
£¨2£©ÈÕ³£Éú»îÖеÄÏÂÁÐ×ö·¨£¬·ûºÏ¡°µÍ̼Éú»î¡±ÀíÄîµÄÊÇ
ABCD

A£®½ÚԼʹÓÃÖ½ÕÅ            B£®·ÖÀà»ØÊÕ´¦ÀíÀ¬»ø
C£®¼õÉÙʹÓÃËÜÁÏ´ü          D£®¼õÉÙʹÓÃÒ»´ÎÐÔÖ½±­
£¨3£©ÉϺ£ÊÀ²©»áÓÐÐí¶àLEDµÆ£¬ÎªÆ乩µçµÄ×°ÖýÓÊÜÑô¹âÕÕÉäºó£¬±ã¿É½«
¹â
ÄÜת±äΪµçÄÜ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?ÑÓÇìÏØһģ£©»¯Ñ§ÓëÉú»îÃÜÇÐÏà¹Ø£®
£¨1£©ÈÕ³£Éú»îÖÐʳÓõļ¦µ°¡¢ÍÑÖ¬ÄÌÖи»º¬µÄÓªÑøËØÊÇ
µ°°×ÖÊ
µ°°×ÖÊ
£®ÎªÁË·ÀÖ¹ØþÙͲ¡¼°·¢Óý²»Á¼£¬Ó׶ùÇàÉÙÄê¿ÉÒÔ²¹³äһЩº¬
¸Æ
¸Æ
ÔªËصÄʳƷ£®
£¨2£©ÏÂÁÐÎïÆ·ËùʹÓõÄÖ÷Òª²ÄÁÏÊôÓÚÌìÈ»ÏËάµÄÊÇ
C
C
£¨ÌîÐòºÅ£¬ÏÂͬ£©£®

£¨3£©Ï´µÓ¼Á¿ÉÇåÏ´²Í¾ßÉϵÄÓÍÎÛ£¬ÕâÊÇÒòΪϴµÓ¼Á¾ßÓÐ
È黯
È黯
¹¦ÄÜ£®
£¨4£©ÌìÈ»Æø£¨Ö÷Òª³É·ÖΪ¼×Í飩ÊǼÒÓÃȼÁÏ£®¼×ÍéÔÚ¿ÕÆøÖÐȼÉյĻ¯Ñ§·½³ÌʽΪ
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
£®
¸ù¾ÝϱíÊý¾Ý·ÖÎö£¬Óëú£¨°´C¼Æ£©Ïà±È£¬ÓÃÌìÈ»Æø×öȼÁϵÄÓŵãÊÇ£º
ȼÉÕÏàͬÖÊÁ¿µÄÁ½ÖÖÎïÖÊ£¬¼×Íé²úÉúµÄ¶þÑõ»¯Ì¼ÉÙ£¬¶Ô»·¾³ÎÛȾС¡¢·Å³öµÄÈÈÁ¿¶à£®
ȼÉÕÏàͬÖÊÁ¿µÄÁ½ÖÖÎïÖÊ£¬¼×Íé²úÉúµÄ¶þÑõ»¯Ì¼ÉÙ£¬¶Ô»·¾³ÎÛȾС¡¢·Å³öµÄÈÈÁ¿¶à£®
£®
1gÎïÖÊÍêȫȼÉÕ²úÉúCO2µÄÖÊÁ¿ 1gÎïÖÊÍêȫȼÉշųöµÄÈÈÁ¿
CH4 2.75g 56kJ
C 3.67g 32kJ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?ºÚÁú½­£©»¯Ñ§ÓëÉú»îÃÜÇÐÏà¹Ø£¬ÏÂÁÐʳÎïÖÐÖ÷ҪΪÈËÌåÌṩµ°°×ÖʵÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?ÑγǶþÄ££©»¯Ñ§ÓëÉú»îÃÜÇÐÏà¹Ø£¬Éú»îÖеÄÏÂÁÐ×ö·¨²»ºÏÀíµÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?ÆÜϼÇø¶þÄ££©»¯Ñ§ÓëÉú»îÃÜÇÐÏà¹Ø£¬ÔÚ³ø·¿ÀïÔ̲Ø×ÅÐí¶à»¯Ñ§ÖªÊ¶£®
£¨1£©ÏÂÁÐʳÎïÖУ¬Î¬ÉúËغ¬Á¿±È½Ï·á¸»µÄÊÇ
A
A
£¨Ìî×ÖĸÐòºÅ£©£®

£¨2£©½´ÓÍÊÇÖØÒªµÄµ÷ζƷ£¬½´ÓÍÊÊÁ¿¼ÓÌú¿ÉÒÔÓÐЧԤ·ÀȱÌúÐÔƶѪ£®ÌúÊÇÈËÌå±ØÐëµÄ
΢Á¿
΢Á¿
£¨Ñ¡Ìî¡°³£Á¿¡±¡¢¡°Î¢Á¿¡±£©ÔªËØ£®
£¨3£©ÎªÁËÓÐЧ·ÀÖ¹²Ëµ¶ÉúÐ⣬¿ÉÒÔ²ÉÈ¡µÄÒ»ÖÖ×ö·¨ÊÇ
±£³Ö²Ëµ¶µÄ¸ÉÔï
±£³Ö²Ëµ¶µÄ¸ÉÔï
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸