(3·Ö) ÐÇÆÚÌ죬СǿµÄÂèÂèÒª±ºÖÆÃæ°ü£¬½ÐСǿȥÉ̵êÂò»ØÒ»°ü´¿¼î£¬Ð¡Ç¿×Ðϸ¿´ÁË°üװ˵Ã÷(ÈçÏÂͼ)£¬²¢²úÉúÒÉÎÊ£º´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊÇ·ñ´ï±êÄØ£¿

»Øµ½Ñ§Ð££¬ËûÈ¡³ö´Ó¼ÒÀï´øÀ´µÄһС°ü´¿¼îÑùÆ·ºÍСÃ÷Ò»Æð½øÐÐʵÑ飬СÃ÷ºÍСǿ·Ö±ðÉè¼ÆÁËÒÔÏÂÁ½ÖÖ²»Í¬µÄʵÑé·½°¸£º
 
ʵÑé·½°¸
Сǿ
׼ȷ³ÆÈ¡5.5 g´¿¼îÑùÆ··ÅÈëÉÕ±­ÖУ¬ÓÖÈ¡À´50¿Ë¡¢14.6%µÄÏ¡ÑÎËáÖðµÎ¼ÓÈ룬ÖÁ¸ÕºÃ²»ÔÙ²úÉúÆøÅÝÍ£Ö¹µÎ¼ÓÏ¡ÑÎËᣬ»¹Ê£ÓàÏ¡ÑÎËá25¿Ë¡£
СÃ÷
׼ȷ³ÆÈ¡5.5 g´¿¼îÑùÆ··ÅÈë׶ÐÎÆ¿ÖУ¬¼ÓÈëÒ»¶¨ÖÊÁ¿·ÖÊý¡¢×ãÁ¿µÄÏ¡ÑÎËᣬ²¢½«²úÉúµÄÆøÌå¸ÉÔïºóͨÈë×ãÁ¿µÄÇâÑõ»¯ÄÆÈÜÒºÖУ¨ÈçÏÂͼËùʾ£© £¬³ä·ÖÎüÊպ󣬳ÆÁ¿ÇâÑõ»¯ÄÆÈÜÒºÖÊÁ¿Ôö¼ÓÁË2.0¿Ë¡£

£¨1£©Ð¡Ç¿²âµÃµÄ´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿£¨Ð´³ö¼ÆËã¹ý³Ì£©
£¨2£©Ð¡Ã÷²âµÃµÄ´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿£¨Ð´³ö¼ÆËã¹ý³Ì£©
£¨3£©Á½Î»Í¬Ñ§ÓÖÇëÀ´ÀÏʦ°ï棬ÀÏʦѡȡÁíÍâÒ»Öֲⶨ·½·¨¾­·´¸´²â¶¨½á¹û¶¼ÊÇ96.3%£¬ÇëÄã½áºÏʵÑé¹ý³Ì·ÖÎöÒ»ÏÂÁ½Î»Í¬Ñ§Ë­µÄ²â¶¨½á¹û²»×¼È·£¬ÎªÊ²Ã´£¿
(1)96.4%     £¨2£©87.6%
£¨3£©Ð¡Ã÷µÄʵÑéÖвúÉúµÄÆøÌå²»ÄÜÈ«²¿±»ÇâÑõ»¯ÄÆÈÜÒºÎüÊÕ£¬²ÐÁôÔÚÒÇÆ÷ÖÐÒ»²¿·Ö£¬Ê¹µÃ²â¶¨½á¹û²»×¼È·¡£

ÊÔÌâ·ÖÎö£º¸ù¾Ý»¯Ñ§·½³Ìʽ¼ÆËã¼´¿É¡£
£¨1£©½â£ºÉè´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿Îªx¡£
+2HCl="2NaCl+" H2O+ CO2¡ü
106         73
x         25g¡Á14.6%
106:73=x£º25g¡Á14.6%
x=5.3g
´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊÇ=96.4%¡£
´ð£º´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊÇ96.4%¡£
£¨2£©½â£ºÉè´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿Îªy¡£
+2HCl="2NaCl+" H2O+ CO2¡ü
106                                 44
y                         2.0g
106:44=y£º2.0g
y=4.8g
´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊÇ=87.6%¡£
´ð£º´¿¼îÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊÇ87.6%¡£
£¨3£©ÒòΪСÃ÷µÄʵÑéÖвúÉúµÄÆøÌå²»ÄÜÈ«²¿±»ÇâÑõ»¯ÄÆÈÜÒºÎüÊÕ£¬²ÐÁôÔÚÒÇÆ÷ÖÐÒ»²¿·Ö£¬Ê¹µÃ²â¶¨½á¹û²»×¼È·¡£
µãÆÀ£º¸ù¾Ý»¯Ñ§·½³Ìʽ¼ÆË㣬ҪעÒâ½âÌâµÄ²½Ö裬É衢д¡¢ÕÒ¡¢ÁС¢½â¡¢´ð¡£
ÒªÏëʵÑéµÄ½á¹û׼ȷ£¬Éè¼Æ¿ÆѧºÏÀíµÄʵÑéºÜÖØÒª¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

ΪÁ˲ⶨº¬ÔÓÖʵÄÑõ»¯Ìú£¨ÔÓÖʲ»²Î¼Ó·´Ó¦£©ÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý£¬Ä³Í¬Ñ§³ÆÈ¡¸ÃÑùÆ·10 g£¬²¢ÓÃÏÂͼËùʾµÄ×°ÖýøÐÐʵÑ飬

µÃµ½ÈçÏÂÁ½×éÊý¾Ý£º
 
·´Ó¦Ç°
Ñõ»¯ÌúÍêÈ«·´Ó¦ºó
A×é 
²£Á§¹ÜºÍÑùÆ·µÄÖÊÁ¿43.7 g 
²£Á§¹ÜºÍ¹ÌÌåÎïÖʵÄÖÊÁ¿41.3 g 
B×é 
¹ã¿ÚÆ¿ºÍ³ÎÇåʯ»ÒË®µÄÖÊÁ¿180 g 
¹ã¿ÚÆ¿ºÍÆ¿ÄÚÎïÖʵÄÖÊÁ¿186.2 g 
 
ÊԻشð£º
£¨1£©¢ÙÄãÈÏΪ£¬Ó¦µ±Ñ¡Ôñ        ×éµÄÊý¾ÝÀ´¼ÆËãÑùÆ·ÖеÄÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý£¬Çëд³ö¾ßÌå½âÌâ¹ý³Ì¡£
¢ÚÇë½âÊÍÄ㲻ѡÁíÒ»×éÊý¾Ý½øÐмÆËãµÄÔ­Òò                                            
                                                                         ¡£
£¨2£©ÕâλͬѧËùÓÃ×°ÖõIJ»×ãÖ®´¦ÊÇ                           ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

£¨3·Ö£©¼ÓÈÈ·Ö½â15.8g¸ßÃÌËá¼Ø£¬¿ÉÒԵõ½ÑõÆøµÄÖÊÁ¿ÊǶàÉÙ£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÖÓÐÏõËá¼ØÑùÆ·£¨ÔÓÖʲ»ÈÜÓÚË®£©¡£È¡15g¸ÃÑùÆ··ÅÈëÉÕ±­ÖУ¬ÔÙ¼ÓÈë50gˮʹÆäÖеÄÏõËá¼ØÈ«²¿Èܽ⣬Ȼºó¾²ÖᢹýÂË£¬È¡15.5gÂËÒº£¬²âµÃº¬ÓÐÏõËá¼Ø3g£¬ÔòÔ­ÑùÆ·ÖÐÏõËá¼ØµÄÖÊÁ¿·ÖÊýÊÇ
A£®14.9%B£®65%C£®75%D£®80%

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

£¨6·Ö£©Ð¡Ã÷¼Ò¹ºÂòÁËһƿ°×´×£¬±êÇ©ÉÏ×¢Ã÷´×ËáµÄÖÊÁ¿·ÖÊý¡Ý5%¡£Ð¡Ã÷Ï룺ÕâÆ¿°×´×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±êÇ©µÄ±ê×¢Ïà·û£¿ÇëÄãÓÃÓйØËá¼îµÄ֪ʶ£¬¶¨Á¿²â¶¨°×´×Öд×ËáµÄº¬Á¿¡£
¡¾ÊµÑéÔ­Àí¡¿
¢ÅÓÃÒÑ֪Ũ¶ÈµÄÇâÑõ»¯ÄÆÈÜÒººÍ´×Ëá·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
CH3COOH + NaOH = CH3COONa + H2O
¢ÆÔÚ»ìºÏÈÜÒºÖУ¬µ±´×ËáºÍÇâÑõ»¯ÄÆÍêÈ«ÖкÍʱ£¬ÔÙÔö¼Ó1µÎÇâÑõ»¯ÄÆÈÜÒº£¬ÈÜÒº¾Í³Ê¼îÐÔ£¬¶ø1µÎÇâÑõ»¯ÄÆÈÜҺԼΪ0.05 ml£¬¶Ô²â¶¨½á¹ûµÄÓ°ÏìºÜС£¬¿ÉºöÂÔ²»¼Æ¡£
¡¾ÊµÑé²½Öè¡¿
¢ÅÓà         È¡12.0 mL°×´×£¨ÃܶȽüËÆΪ1.0g/ ml£©£¬µ¹ÈëÉÕ±­ÖУ¬¼ÓÈë20 mlÕôÁóˮϡÊÍ£¬ÔÙµÎÈ뼸µÎ·Ó̪ÊÔÒº¡£
¢ÆÁ¿È¡45.0 mlÈÜÖÊÖÊÁ¿·ÖÊýΪ1.0%µÄÇâÑõ»¯ÄÆÈÜÒº£¨ÃܶȽüËÆΪ1.0 g/ ml£©£¬ÓýºÍ·µÎ¹ÜÈ¡¸ÃÇâÑõ»¯ÄÆÈÜÒº£¬ÖðµÎµØµÎ¼Óµ½Ï¡ÊͺóµÄ°×´×ÖУ¬Í¬Ê±²»¶ÏµØ½Á°èÉÕ±­ÖеÄÈÜÒº¡£µÎÖÁÇ¡ºÃÍêÈ«·´Ó¦£¬Ê£ÓàÇâÑõ»¯ÄÆÈÜÒº5.0 ml¡£
¡¾½»Á÷·´Ë¼¡¿¢ÅÔÚʵÑé²½Öè¢ÙÖУ¬¼ÓÊÊÁ¿Ë®Ï¡ÊÍ°×´×£¬¶ÔʵÑé½á¹ûÓÐÎÞÓ°Ï죿Ϊʲô£¿
¢ÆÔÚʵÑé²½Öè¢ÚÖУ¬Ð¡Ã÷ÈçºÎÈ·¶¨´×ËáºÍÇâÑõ»¯ÄÆÒÑÍêÈ«Öкͣ¿
¡¾Êý¾Ý´¦Àí¡¿¸ù¾ÝʵÑéÊý¾Ý£¬Í¨¹ý¼ÆËãÅжϰ״×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±êÇ©µÄ±ê×¢Ïà·û£¿£¨3·Ö£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

£¨3·Ö£©¸ß´¿µÄµ¥¾§¹èÊÇÖØÒªµÄ°ëµ¼Ìå²ÄÁÏ¡£ÖƱ¸¸ß´¿¹èµÄ»¯Ñ§·½³ÌʽΪ£º
SiCl4 +2H2Si+ 4HCl¡£Çë¼ÆËãÒª»ñµÃ56g¹è£¨Si£©£¬ÖÁÉÙÐèÒªÇâÆø¶àÉÙ¿Ë£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

£¨3·Ö£©³¤¾ÃʹÓõÄÈÈË®ºøÄÚ¶¼»áÓÐÒ»²ãË®¹¸£¬ÒÑÖªÆäÖ÷Òª³É·ÖÊÇ̼Ëá¸ÆºÍÇâÑõ»¯Ã¾£¬ÓÃÏ¡ÑÎËá¿ÉÒÔÇå³ýÕâЩˮ¹¸¡£Ä³Ð£»¯Ñ§¿ÎÍâ»î¶¯Ð¡×éͬѧÔڲⶨˮ¹¸ÖÐ̼Ëá¸ÆµÄº¬Á¿Ê±£¬ÔÚ200gË®¹¸ÖмÓÈë×ãÁ¿µÄÏ¡ÑÎËᣬ²¢Í¬Ê±²âÁ¿ÁË3·ÖÖÓÄÚ²úÉúÆøÌåµÄÖÊÁ¿£¬ÓйØÊý¾ÝÈçÏ£º
ʱ¼ä/s
0
30
50
90
120
150
180
ÆøÌåÖÊÁ¿/g
0
30
50
60
80
66
66
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©±íÖÐÓÐÒ»Ïî²âÁ¿½á¹ûÓнϴóµÄÎó²î£¬Æä¶ÔÓ¦µÄʱ¼äÊÇ      ¡£
£¨2£©Ë®¹¸ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿              

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

£¨3·Ö£©ÔÚÒ»ÉÕ±­ÖÐÊ¢ÓÐ42.2g̼Ëá¸ÆºÍÂÈ»¯¸ÆµÄ·Ûĩ״»ìºÏÎÏòÆäÖмÓÈë116.6gË®£¬Ê¹ÂÈ»¯¸ÆÍêÈ«Èܽ⡣ȻºóÏòÆäÖÐÖðµÎ¼ÓÈë10%µÄÏ¡ÑÎËᣬÉÕ±­ÖÐÊ£Óà¹ÌÌåµÄÖÊÁ¿Óë¼ÓÈëÏ¡ÑÎËáµÄÖÊÁ¿¹ØϵÇúÏßÈçͼËùʾ£¬Çë¸ù¾ÝÌâÒâ»Ø´ðÎÊÌ⣺

£¨1£©µ±µÎÈëÏ¡ÑÎËáÖÊÁ¿ÖÁͼÖÐAµãʱ£¬ÇóËùµÃÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý¡£
£¨2£©µ±µÎÈëÏ¡ÑÎËáÖÊÁ¿ÖÁͼÖÐBµãʱ£¬¼ÌÐøÏòÉÕ±­ÖмÓÈëÉÏÊö·Ûĩ״»ìºÏÎïÖÁ¸Õ¸ÕÎÞÆøÅݲúÉú£¬Çó´ËʱÉÕ±­ÖиÆÔªËØÖÊÁ¿¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

£¨6·Ö£©Ä³Ê¯»Ò³§Ðµ½Ò»Åúʯ»Òʯ£¬ÆäÖк¬ÓÐÔÓÖʶþÑõ»¯¹è£¨¶þÑõ»¯¹è²»ÈÜÓÚË®£¬²»ÓëÑÎËá·´Ó¦£¬¸ßβ»·Ö½â£©Îª²â¶¨Ê¯»ÒʯÑùÆ·µÄ´¿¶È£¬Ä³»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧ·Ö³ÉÈý×éʵÑé²âµÃÊý¾ÝÈçÏÂ±í£º
ʵÑé´ÎÊý
1
2
3
Ï¡ÑÎËáÖÊÁ¿£¨g£©
50
50
100
ÑùÆ·ÖÊÁ¿£¨g£©
20
30
20
²úÉúÆøÌåµÄÖÊÁ¿£¨g£©
6.6
6.6
6.6
£¨1£©¸ÃʵÑéÖеڠ    ´ÎÏ¡ÑÎËáºÍÑùÆ·Ç¡ºÃÍêÈ«·´Ó¦£»  
£¨2£©Çó³ö¸Ãʯ»ÒʯÑùÆ·µÄ´¿¶È¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸