| 1 | µÚ1·Ý | µÚ2·Ý | µÚ3·Ý | µÚ4·Ý |
| ¼ÓÈëBaCl2ÈÜÒºµÄÖÊÁ¿/g | 15 | 20 | 25 | 30 |
| ·´Ó¦µÃµ½µÄ³ÁµíµÄÖÊÁ¿/g | 1.398 | 1.864 | 2.330 | 2.330 |
·ÖÎö ¿ÉÒÔ¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉÕýÈ·Êéд»¯Ñ§·½³Ìʽ£®¸ù¾ÝÏà¹Ø¼ÆËã·½·¨½øÐÐÓйصļÆË㣮ÀýÈ磬ÇóÁòËáµÄÖÊÁ¿·ÖÊýʱ£¬¿ÉÒÔ¸ù¾Ý»¯Ñ§·½³ÌʽÇó³öÁòËáµÄÖÊÁ¿£¬ÔÙÓÃÁòËáµÄÖÊÁ¿³ýÒÔ»ìºÏÈÜÒºµÄÖÊÁ¿¾ÍÊÇÁòËáµÄÖÊÁ¿·ÖÊý
½â´ð ½â£º£¨1£©½â£ºÉèÁòËáµÄÖÊÁ¿·ÖÊýΪX£¬Éú³ÉµÄÂÈ»¯ÇâµÄÖÊÁ¿Îªy£¬
BaCl2+H2SO4=2HCl+BaSO4¡ý
98 233
5gX 2.330g
$\frac{98}{233}=\frac{5gx}{2.330g}$
X=19.6%
´ð£ºÁòËáµÄÖÊÁ¿·ÖÊýÊÇ19.6%£®
£¨2£©É裬»ìºÏËáÖÐHClµÄÖÊÁ¿·ÖÊýΪz£¬
NaOH+HCl=NaCl+H2O
40 36.5
10g¡Á10% 5gz
$\frac{40}{10g¡Á10%}=\frac{36.5}{5gz}$
z=18.25%
´ð°¸£º18.25%£®
µãÆÀ ±¾ÌâÖ÷Òª¿¼²éÁËÈÜÒºµÄÖÊÁ¿·ÖÊýÇ󷨡¢Êéд»¯Ñ§·½³ÌʽµÈ·½ÃæµÄÎÊÌ⣮
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | Óþƾ«µÆµÄÍâÑæ¸øÊԹܼÓÈÈ | B£® | ¼ÓÈÈǰûÓвÁ¸ÉÊÔ¹ÜÍâ±ÚµÄË® | ||
| C£® | ±»¼ÓÈȵÄÒºÌ峬¹ýÊÔ¹ÜÈÝ»ýµÄ$\frac{1}{3}$ | D£® | ûÓеæÊ¯ÃÞÍø |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ¸ÉÔï¼Á£¨Éúʯ»Ò£©ÎüË® | B£® | º£Ë®†ðÑÎ | ||
| C£® | Ï¡ÊÍŨËá | D£® | ÓÃʳÑÎÅäÖÆÑÎË® |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | HNO3 | B£® | NO | C£® | H2S | D£® | HClO |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ÓÃÀäµú×Ó·ÅÔÚÀ¯Öò»ðÑæÉÏ·½ÖÆÈ¡Ì¿ºÚ | |
| B£® | ÓÃʳ´×ºÍСËÕ´òÖÆÈ¡¶þÑõ»¯Ì¼ | |
| C£® | Óû¨°êÖÆ×÷ָʾ¼Á£¬¼ìÑé´¿¼îÈÜÒºµÄËá¼îÐÔ | |
| D£® | Óûƶ¹ºÍÂ̶¹Ö¤Ã÷·Ö×ÓÖ®¼äÓмä¸ô |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| ÐòºÅ | ÐèÇø·ÖÎïÖÊ | ·½·¨Ò» | ·½·¨¶þ |
| A | ¿ÕÆøºÍÑõÆø | Óôø»ðÐÇľÌõ¼ìÑé | ÎÅÆøÎ¶ |
| B | ӲˮºÍÈíË® | ¹Û²ìÑÕÉ« | ¼Ó·ÊÔíË®½Á°è |
| C | Ìú·ÛºÍÌ¿·Û | ÓôÅÌúÎüÒý | ¼ÓÏ¡ÁòËá |
| D | ÇâÑõ»¯ÄÆÈÜÒººÍ̼ËáÄÆÈÜÒº | ÓÃÎÞÉ«·Ó̪ÈÜÒºÊÔÒº | ¼ÓÏ¡ÑÎËá |
| A£® | A | B£® | B | C£® | C | D£® | D |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | 1mol¶þÑõ»¯Ì¼Ô¼º¬ÓÐ6.02¡Á1023¸ö¶þÑõ»¯Ì¼·Ö×Ó | |
| B£® | 1mol¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª44g | |
| C£® | 1mol¶þÑõ»¯Ì¼Öк¬ÓÐ1mol̼Ô×Ó | |
| D£® | 1mol¶þÑõ»¯Ì¼º¬ÓÐ1molÑõÔ×Ó |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com