Èçͼ£¬ÔÚ·½¸ñÖ½ÖУ¬¡÷ABCµÄÈý¸ö¶¥µã¼°D£¬E£¬F£¬G£¬

HÎå¸öµã·Ö±ðλÓÚСÕý·½ÐεĶ¥µãÉÏ£®

£¨1£©ÏÖÒÔD£¬E£¬F£¬G£¬HÖеÄÈý¸öµãΪ¶¥µã»­Èý½ÇÐΣ¬ÔÚËù»­µÄÈý½ÇÐÎÖÐÓë¡÷ABC

   ²»È«µÈµ«Ãæ»ýÏàµÈµÄÈý½ÇÐÎÊÇ¡¡      ¡¡£¨Ö»ÐèÒªÌîÒ»¸öÈý½ÇÐΣ©

£¨2£©ÏÈ´ÓD£¬EÁ½¸öµãÖÐÈÎÒâȡһ¸öµã£¬ÔÙ´ÓF£¬G£¬HÈý¸öµãÖÐÈÎÒâÈ¡Á½¸ö²»Í¬µÄµã£¬ÒÔËùÈ¡µÃÕâÈý¸öµãΪ¶¥µã»­Èý½ÇÐΣ¬ÇóËù»­Èý½ÇÐÎÓë¡÷ABCÃæ»ýÏàµÈµÄ¸ÅÂÊ£¨Óû­Ê÷״ͼ»òÁбí¸ñÇó½â£©£®

                        


£¨1£©£¨3·Ö£©   ¡÷DFG»ò¡÷DHF

£¨2£©£¨5·Ö£©   »­Ê÷״ͼµÃ³ö£º

ÓÉÊ÷״ͼ¿ÉÖª¹²ÓÐ6ÖÖ¿ÉÄܵĽá¹û£¬ÆäÖÐÓë¡÷ABCÃæ»ýÏàµÈµÄÓÐ3ÖÖ£¬¼´¡÷DHF£¬¡÷DGF£¬¡÷EGF£¬¹ÊËù»­Èý½ÇÐÎÓë¡÷ABCÃæ»ýÏàµÈµÄ¸ÅÂÊP=  = £¬

´ð£ºËù»­Èý½ÇÐÎÓë¡÷ABCÃæ»ýÏàµÈµÄ¸ÅÂÊΪ£®


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º


¶þ´Îº¯Êýy=+x+cµÄͼÏóÓëxÖáÓÐÁ½¸ö½»µãA£¨£¬0£©£¬A£¨£¬0£©£¬ÇÒ£¬µãP(m£¬n)ÊÇͼÏóÉÏÒ»µã£¬ÄÇôÏÂÁÐÅжÏÕýÈ·µÄÊÇ£¨¡¡¡¡£©

A.µ±n0ʱ£¬m0                                    B.µ±nʱ£¬m£¾

C.µ±n0ʱ£¬                        D.µ±nʱ£¬m£¾

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º


°ÑÏÂÁи÷ÊýÌîÈëÏàÓ¦µÄ¼¯ºÏÖÐ

£¬£¬£«13.5£¬£¬3.14£¬£¬£¬£¬0£¬£«5£¬

2.1010010001¡­, £¬  

¢ÙÕýÊý¼¯ºÏ         {                                                                                                ¡­}

¢Ú¸ºÊý¼¯ºÏ         {                                                                                                ¡­}

¢ÛÎÞÀíÊý¼¯ºÏ     {                                                                                                ¡­}

¢ÜÕûÊý¼¯ºÏ       {                                                                                                ¡­}

¢Ý·ÖÊý¼¯ºÏ      {                                                                                                ¡­}

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º


Èçͼ£¬ÒÑÖªµãA£¬B£¬C£¬D£¬E£¬FÊDZ߳¤Îª1µÄÕýÁù±ßÐεĶ¥µã£¬

Á¬½ÓÈÎÒâÁ½µã¾ù¿ÉµÃµ½Ò»ÌõÏ߶Σ¬ÔÚÁ¬½ÓÁ½µãËùµÃµÄËùÓÐÏß¶ÎÖÐÈÎÈ¡

Ò»ÌõÏ߶Σ¬È¡µ½³¤¶ÈΪ´íÎó£¡Î´ÕÒµ½ÒýÓÃÔ´¡£µÄÏ߶εĸÅÂÊΪ( )

A. B. C. D.



²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º


¼×¡¢ÒÒ¡¢±ûÈýÈËÕ¾³ÉÒ»ÅźÏÓ°ÁôÄÔò¼×¡¢ÒÒ¶þÈËÏà  ÁڵĸÅÂÊÊÇ        £®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º


Èçͼ£¬ÔÚÆ½ÃæÖ±½Ç×ø±êϵxOyÖУ¬A¡¢BΪxÖáÉÏÁ½µã£¬C¡¢DΪyÖáÉϵÄÁ½µã£¬¾­¹ýµãA¡¢C¡¢BµÄÅ×ÎïÏßµÄÒ»²¿·ÖC1Óë¾­¹ýµãA¡¢D¡¢BµÄÅ×ÎïÏßµÄÒ»²¿·ÖC2×éºÏ³ÉÒ»Ìõ·â±ÕÇúÏߣ¬ÎÒÃǰÑÕâÌõ·â±ÕÇúÏß³ÉΪ¡°µ°Ïß¡±£®ÒÑÖªµãCµÄ×ø±êΪ

  £¨0£¬﹣1.5 £©£¬µãMÊÇÅ×ÎïÏßC2£ºy=mx2﹣2mx﹣3m£¨m£¼0£©µÄ¶¥µã£®

£¨1£©ÇóA¡¢BÁ½µãµÄ×ø±ê£»

£¨2£©¡°µ°Ïß¡±ÔÚµÚËÄÏóÏÞÉÏÊÇ·ñ´æÔÚÒ»µãP£¬Ê¹µÃ¡÷PBCµÄ

Ãæ»ý×î´ó£¿Èô´æÔÚ£¬Çó³ö¡÷PBCÃæ»ýµÄ×î´óÖµ£»Èô²»´æÔÚ£¬

Çë˵Ã÷ÀíÓÉ£»

£¨3£©µ±¡÷BDMΪֱ½ÇÈý½ÇÐÎʱ£¬ÇómµÄÖµ£®


²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º


¹ØÓÚµÄÒ»Ôª¶þ´Î·½³ÌûÓÐʵÊý¸ù£¬ÔòÅ×ÎïÏߵĶ¥µãÔÚ£¨  £©          

 A£®µÚÒ»ÏóÏÞ        B£®µÚ¶þÏóÏÞ              C£®µÚÈýÏóÏÞ             D£®µÚËÄÏóÏÞ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º


 º¯ÊýµÄͼÏóÓëyÖáµÄ½»µã×ø±êÊÇ   (    )

A. (2,0)          B. (-2,0)            C. (0,4)             D. (0,-4)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º


ÔÚ²»Í¸Ã÷µÄÏä×ÓÀï·ÅÓÐ4¸öƹÅÒÇò£¬Ã¿¸öƹÅÒÇòÉÏ·Ö±ðдÓÐÊý×Ö1¡¢2¡¢3¡¢4£¬´ÓÏäÖÐÃþ³öÒ»¸öÇò¼ÇÏÂÊý×Öºó·Å»ØÏäÖУ¬Ò¡ÔȺóÔÙÃþ³öÒ»¸öÇò¼ÇÏÂÊý×Ö£®Èô½«µÚÒ»´ÎÃþ³öµÄÇòÉÏÊý×Ö¼ÇΪµãµÄºá×ø±ê£¬µÚ¶þ´ÎÃþ³öµÄÇòÉÏÊý×Ö¼ÇΪµãµÄ×Ý×ø±ê£®
£¨1£©Çëд³öÁ½´ÎÃþÇòºóËùÓпÉÄܵĵãµÄ×ø±ê£¬²¢ÓÃÁÐ±í·¨»òÊ÷״ͼ·¨ËµÃ÷£»
£¨2£©ÇóÕâÑùµÄµãÂäÔÚÒÔM£¨2,2£©ÎªÔ²ÐÄ£¬°ë¾¶Îª2µÄÔ²ÄڵĸÅÂÊ.

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸