Question

已知：如图，AB⊥BE于点B，DE⊥BE于点E，F、C在BE上，AC、DF相交于点G，且AB＝DE，BF＝CE．

求证： GF＝GC．

 

Answer 1

证明: ∵AB⊥BE，DE⊥BE

∴ÐABC=ÐDEF=90°                         

∵BF＝CE

∴BC=EF                                   

又∵AB＝DE                                

∴△ABC≌△DEF                              

 ∴ÐACB=ÐDFE                                

∴GF＝GC   

解析:略