[题目]昆仑玉的成分为钙镁硅酸盐.可简单看成是Ca2Mg5Si8O22(OH)2.则其用二氧化硅和金属氧化物的形式可表示为．题目和参考答案——青夏教育精英家教网—

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【题目】昆仑玉的成分为钙镁硅酸盐，可简单看成是Ca2Mg5Si8O22（OH）2，则其用二氧化硅和金属氧化物的形式可表示为．

【答案】2CaO5MgO8SiO2H2O．

【解析】根据硅酸盐改写成氧化物的形式为：活泼金属氧化物较活泼金属氧化物二氧化硅水，同时要遵循原子守恒，Ca2Mg5Si8O22（OH）2可表示为：2CaO5MgO8SiO2H2O，故答案为2CaO5MgO8SiO2H2O。

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