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【题目】为了验证木炭可被浓H2SO4氧化成CO2,选用如图所示仪器(内含物质)组装成实验装置:

(1)如按气流由左向右流向,连接上述装置的正确顺序是(填各接口字母):________接________,________接________,________接________。

(2)仪器乙、丙应有怎样的实验现象才表明已检验出CO2?

乙中________________________,丙中________________________。

(3)丁中酸性KMnO4溶液的作用是__________________________________________。

(4)写出甲中反应的化学方程式____________________________________________。

【答案】(1)A F E C D B

(2)澄清石灰水变浑浊 品红溶液未褪色

(3)吸收SO2

(4)C+2H2SO4(浓)CO2↑+2SO2↑+2H2O

【解析】木炭与浓硫酸加热反应生成CO2、SO2和H2O。其中CO2、SO2在化学性质上的相同点都是酸性氧化物,都跟澄清石灰水中的Ca(OH)2反应,使澄清石灰水变浑浊,这会干扰CO2的鉴别。SO2和CO2在化学性质上的明显不同点是SO2有漂白性和强的还原性,而CO2都没有。所以,在鉴别CO2时,首先用酸性KMnO4溶液将SO2氧化除去,再用品红溶液检验是否被完全除去,最后用澄清石灰水检验CO2的存在,是一种确认CO2存在的好方案。

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