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【题目】如图所示为电动机提升重物的装置,电动机线圈的电阻为r=1 Ω,电动机两端电压为5 V,电路中的电流为1 A,物体A重20 N。忽略一切摩擦,求:

1电动机线圈电阻消耗的热功率为多少?

2电动机输入功率和输出功率各是多少?

310 s内电动机可以把重物匀速提升多高?

4这台电动机的机械效率是多少?

【答案】11 W 25 W4 W 32 m 480%

【解析】电动机工作时,其电路为非纯电阻电路,它从电源获取的功率一部分转化为线圈的热功率,另一部分转化为电动机的机械功率。

1电动机线圈上消耗的热功率为

P=I2r=1 W

2电动机的输入功率就是电流通过电动机做功的功率,即

P=UI=5×1 W=5 W

电动机的输出功率就是电动机对外做机械功的功率,根据P=P+P

得P=P-P=5 W-1 W=4 W

3设物体A的重力为G,t=10s内物体上升的高度为h,根据能量守恒定律得Pt=Gh

h=m=2 m

4这台电动机的机械效率为

η=×100%=×100%=80%

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