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    【题目】设复数z＝2m＋（4－m2）i，当实数m取何值时，复数z对应的点：

    （1）位于虚轴上？

    （2）位于一、三象限？

    （3）位于以原点为圆心，以4为半径的圆上？

    【答案】（1）m＝0（2）m＜－2或0＜m＜2（3）m＝0或m＝±2

    【解析】（1）复数z对应的点位于虚轴上，则m＝0.

    ∴m＝0时，复数z对应的点位于虚轴上.

    （2）复数z对应的点位于一、三象限，则2m·（4－m2）＞0m（m－2）（m＋2）＜0m＜－2或0＜m＜2.

    ∴m＜－2或0＜m＜2时，复数z对应的点位于一、三象限.

    （3）复数z对应的点位于以原点为圆心，以4为半径的圆上，则|z|＝＝4m＝0或m＝±2.

    ∴m＝0或m＝±2时，复数z对应的点位于以原点为圆心，以4为半径的圆上.

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