¶þÑõ»¯îæ(CeO2)ÊÇÒ»ÖÖÖØÒªµÄÏ¡ÍÁÑõ»¯Îƽ°åµçÊÓÏÔʾÆÁÉú²ú¹ý³ÌÖвúÉú´óÁ¿µÄ·Ï²£Á§·ÛÄ©(º¬SiO2¡¢Fe2O3¡¢CeO2ÒÔ¼°ÆäËûÉÙÁ¿¿ÉÈÜÓÚÏ¡ËáµÄÎïÖÊ)¡£Ä³¿ÎÌâ×éÒÔ´Ë·ÛĩΪԭÁÏ»ØÊÕî棬Éè¼ÆʵÑéÁ÷³ÌÈçÏ£º

(1)Ï´µÓÂËÔüAµÄÄ¿µÄÊÇΪÁËÈ¥³ý________(ÌîÀë×Ó·ûºÅ)£¬¼ìÑé¸ÃÀë×ÓÊÇ·ñÏ´¾»µÄ·½·¨ÊÇ___________________________________________________¡£
(2)µÚ¢Ú²½·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ__________________________________£¬ÂËÔüBµÄÖ÷Òª³É·ÖÊÇ________¡£
(3)ÝÍÈ¡ÊÇ·ÖÀëÏ¡ÍÁÔªËصij£Ó÷½·¨¡£ÒÑÖª»¯ºÏÎïTBP×÷ΪÝÍÈ¡¼ÁÄܽ«îæÀë×Ó´ÓË®ÈÜÒºÖÐÝÍÈ¡³öÀ´£¬TBP________(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)ÓëË®»¥ÈÜ¡£ÊµÑéÊÒ½øÐÐÝÍÈ¡²Ù×÷ʱÓõ½µÄÖ÷Òª²£Á§ÒÇÆ÷ÓÐ________¡¢ÉÕ±­¡¢²£Á§°ô¡¢Á¿Í²µÈ¡£
(4)È¡ÉÏÊöÁ÷³ÌÖеõ½µÄCe(OH)4²úÆ·0.536 g£¬¼ÓÁòËáÈܽâºó£¬ÓÃ0.100 0 mol¡¤L£­1 FeSO4±ê×¼ÈÜÒºµÎ¶¨ÖÕµã(îæ±»»¹Ô­ÎªCe3£«)£¬ÏûºÄ25.00 mL±ê×¼ÈÜÒº£¬¸Ã²úÆ·ÖÐCe(OH)4µÄÖÊÁ¿·ÖÊýΪ________¡£

¡¡(1)Fe3£«¡¡È¡×îºóÒ»´ÎÏ´µÓÒº£¬¼ÓÈëKSCNÈÜÒº£¬Èô²»³öÏÖºìÉ«£¬ÔòÒÑÏ´¾»£»·´Ö®£¬Î´Ï´¾»(ÆäËûºÏÀí´ð°¸¾ù¿É)
(2)2CeO2£«H2O2£«6H£«=2Ce3£«£«4H2O£«O2¡ü¡¡SiO2(ÆäËûºÏÀí´ð°¸¾ù¿É)
(3)²»ÄÜ¡¡·ÖҺ©¶·
(4)97.0%

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

¿ÕÆø´µ³ö·¨¹¤ÒÕ£¬ÊÇÄ¿Ç°¡°º£Ë®Ìáä塱µÄ×îÖ÷Òª·½·¨Ö®Ò»¡£Æ乤ÒÕÁ÷³ÌÈçÏ£º

(1)²½Öè¢ÛµÄÀë×Ó·½³Ìʽ£º                               ¡£
(2)²½Öè¢ÝÖÐäåÕôÆøÀäÄýºóµÃµ½ÒºäåÓëäåË®µÄ»ìºÏÎ¿ÉÀûÓÃËüÃǵÄÏà¶ÔÃܶÈÏà²îºÜ´óµÄÌصã½øÐзÖÀë¡£·ÖÀëÒÇÆ÷µÄÃû³ÆÊÇ       ¡£
(3)äåË®»ìºÏÎï¢òÖÐÈÜÓÐÒ»¶¨Á¿µÄÂÈÆø£¬Òò´ËÔÚ²½Öè¢ÝÖпɽ«ÕôÁó²úÉúµÄÆøÌåͨ¹ý       (ÌîÊÔ¼ÁÃû³Æ)ÈÜÒº£¬ÒÔ³ýÈ¥ÂÈÆø¡£
(4)²½Öè¢ÝµÄÕôÁó¹ý³ÌÖУ¬Î¶ÈÓ¦¿ØÖÆÔÚ80¡«90 ¡æ¡£Î¶ȹý¸ß»ò¹ýµÍ¶¼²»ÀûÓÚÉú²ú£¬Çë½âÊÍÔ­Òò£º                                                               ¡£
(5)²½Öè¢ÙÖÐÓÃÁòËáËữ¿ÉÌá¸ßCl2µÄÀûÓÃÂÊ£¬ÀíÓÉÊÇ                           ¡£
(6)ÌáÈ¡äåµ¥ÖÊ£¬²ÉÓÃÕôÁó¡°äåË®»ìºÏÎï¢ò¡±¶ø²»ÊÇÕôÁó¡°äåË®»ìºÏÎï¢ñ¡±£¬Çë˵Ã÷Ô­Òò£º                                          ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

º£Ë®µÄ×ÛºÏÀûÓÿÉÒÔÖƱ¸½ðÊôþ£¬ÆäÁ÷³ÌÈçÏÂͼËùʾ£º

(1)Mg(OH)2³ÁµíÖлìÓеÄCa(OH)2Ó¦ÔõÑù³ýÈ¥£¿Ð´³öʵÑé²½Öè¡£__________________________
(2)ʵÑéÊÒ½«´ÖÑÎÖƳɾ«ÑεĹý³ÌÖУ¬Èܽ⡢¹ýÂË¡¢Õô·¢Èý¸ö²½ÖèµÄ²Ù×÷¶¼ÒªÓõ½²£Á§°ô£¬·Ö±ð˵Ã÷ÔÚÕâÈýÖÖÇé¿öÏÂʹÓò£Á§°ôµÄÄ¿µÄ£º
¢ÙÈܽ⣺________________¡£
¢Ú¹ýÂË£º__________________________¡£
¢ÛÕô·¢£º________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

Òø°±ÈÜÒº·Å¾Ãºó»á²úÉúµþµª»¯Òø£¨AgN3£©¶øÒýÆð±¬Õ¨£¬Ö±½ÓÅÅ·Å»áÎÛȾ»·¾³£¬ÇÒÔì³ÉÒø×ÊÔ´µÄÀË·Ñ¡£Ä³Ñо¿Ð¡×éÉè¼ÆÁË´ÓÒø¾µ·´Ó¦ºóµÄ·ÏÒºÖУ¨º¬¹ýÁ¿µÄÒø°±ÈÜÒº£¬¼ÙÉè²»º¬µ¥ÖÊÒø£©»ØÊÕÒøµÄÈçÏÂÁ½ÖÖʵÑéÁ÷³Ì£º
£¨ÒÑÖª£º[Ag£¨NH3£©2]£«ÔÚÈÜÒºÖдæÔÚƽºâ£º[Ag£¨NH3£©2]£«??Ag£«£«2NH3£©

£¨1£©Ð´³ö¼×·½°¸µÚ¢Ù²½·ÏÒºÓëÏ¡HNO3·´Ó¦µÄÀë×Ó·½³Ìʽ                                                                       ¡£
£¨2£©¼×·½°¸µÚ¢Ú²½¼ÓÈëµÄÌú·ÛÒª¹ýÁ¿µÄÄ¿µÄÊÇ                                                                                                                                               ¡£
¼×·½°¸Á÷³Ì¿ÉÄܲúÉúµÄ´óÆøÎÛȾÎïÊÇ                                                                       ¡£
£¨3£©ÒÒ·½°¸Èô×îÖյõ½Òø·ÛµÄÖÊÁ¿Æ«´ó£¬ÅųýδϴµÓ¸É¾»µÄÒòËØ£¬¿ÉÄܵÄÔ­ÒòÊÇ                                                                       ¡£
£¨4£©ÊµÑéÊÒÅäÖÆÒø°±ÈÜÒºµÄ²Ù×÷¹ý³ÌÊÇ                                                                                                                                                                                                                       ¡£
£¨5£©ÒÑÖªÒÒ·½°¸µÚ¢Û²½·´Ó¦ÓÐH2SÆøÌå²úÉú£¬Èô×îÖյõ½Òø·Û21.6 g£¬²»¿¼ÂÇÆäËûËðʧ£¬ÀíÂÛÉϸò½ÐèÒª¼ÓÈëÌú·Û       g¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÀûÓÃÁòËáÔü(Ö÷Òªº¬Fe2O3¡¢SiO2¡¢Al2O3¡¢MgOµÈÔÓÖÊ)ÖƱ¸Ñõ»¯ÌúµÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

(1)¡°Ëá½þ¡±ÖÐÁòËáÒªÊʵ±¹ýÁ¿£¬Ä¿µÄÊÇ£º¢ÙÌá¸ßÌúµÄ½þ³öÂÊ£»¢Ú________¡£
(2)¡°»¹Ô­¡±Êǽ«Fe3£«×ª»¯ÎªFe2£«£¬Í¬Ê±FeS2±»Ñõ»¯ÎªSO42¡ª£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________________________________________________________¡£
(3)Ϊ²â¶¨¡°Ëá½þ¡±²½ÖèºóÈÜÒºÖÐFe3£«µÄÁ¿ÒÔ¿ØÖƼÓÈëFeS2µÄÁ¿¡£ÊµÑé²½ÖèΪ£º×¼È·Á¿È¡Ò»¶¨Ìå»ýµÄËá½þºóµÄÈÜÒºÓÚ׶ÐÎÆ¿ÖУ¬¼ÓÈëÏ¡ÑÎËá¡¢ÉÔ¹ýÁ¿SnCl2£¬ÔÙ¼ÓHgCl2³ýÈ¥¹ýÁ¿µÄSnCl2£¬ÒÔ¶þ±½°·»ÇËáÄÆΪָʾ¼Á£¬ÓÃK2Cr2O7±ê×¼ÈÜÒºµÎ¶¨£¬Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽÈçÏ£º
2Fe3£«£«Sn2£«£«6Cl£­=2Fe2£«£«SnCl62¡ª
Sn2£«£«4Cl£­£«2HgCl2=SnCl62¡ª£«Hg2Cl2¡ý
6Fe2£«£«Cr2O72¡ª£«14H£«=6Fe3£«£«2Cr3£«£«7H2O
¢ÙÈôSnCl2²»×ãÁ¿£¬Ôò²â¶¨µÄFe3£«Á¿________(Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°²»±ä¡±£¬ÏÂͬ)£»
¢ÚÈô²»¼ÓHgCl2£¬Ôò²â¶¨µÄFe3£«Á¿________¡£
(4)¢Ù¿ÉÑ¡ÓÃ________(ÌîÊÔ¼Á)¼ìÑéÂËÒºÖк¬ÓÐFe3£«¡£²úÉúFe3£«µÄÔ­ÒòÊÇ________________________________________________________________________(ÓÃÀë×Ó·½³Ìʽ±íʾ)¡£
¢ÚÒÑÖª²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïÐÎʽ³ÁµíʱÈÜÒºµÄpH¼ûÏÂ±í£º

³ÁµíÎï
Fe(OH)3
Al(OH)3
Fe(OH)2
Mg(OH)2
Mn(OH)2
¿ªÊ¼³Áµí
2.7
3.8
7.5
9.4
8.3
ÍêÈ«³Áµí
3.2
5.2
9.7
12.4
9.8
 
ʵÑé¿ÉÑ¡ÓõÄÊÔ¼ÁÓУºÏ¡ÏõËá¡¢Ba(NO3)2ÈÜÒº¡¢ËáÐÔKMnO4ÈÜÒº¡¢NaOHÈÜÒº£¬ÒªÇóÖƱ¸¹ý³ÌÖв»²úÉúÓж¾ÆøÌå¡£
ÇëÍê³ÉÓÉ¡°¹ýÂË¡±ºóµÄÈÜҺģÄâÖƱ¸Ñõ»¯ÌúµÄʵÑé²½Ö裺
a£®Ñõ»¯£º________________________________________________________£»
b£®³Áµí£º__________________________________________________________£»
c£®·ÖÀ룬ϴµÓ£»
d£®ºæ¸É£¬ÑÐÄ¥¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

º£ÑóÊÇÉúÃüµÄÒ¡Àº¡¢×ÊÔ´µÄ±¦¿â¡£ÖйúҪʵʩº£ÑóÇ¿¹úÕ½ÂÔ£¬ÊµÏÖÓɺ£Ñó´ó¹úÏòº£ÑóÇ¿¹úÂõ½øµÄÃÎÏë¡£º£Ñó¾­¼ÃÒѾ­³ÉΪÀ­¶¯ÎÒ¹ú¹úÃñ¾­¼Ã·¢Õ¹µÄÖØÒªÒýÇ棬º£Ë®µÄ×ۺϿª·¢¡¢ÀûÓÃÊǺ£Ñ󾭼õÄÒ»²¿·Ö£¬º£Ë®ÖпÉÌáÈ¡¶àÖÖ»¯¹¤Ô­ÁÏ£¬ÏÂÃæÊǹ¤ÒµÉ϶Ժ£Ë®µÄ¼¸Ïî×ÛºÏÀûÓõÄʾÒâͼ¡£ÆäÁ÷³ÌÈçÏÂͼËùʾ£º

£¨1£©Ð´³ö¢Ù¡¢¢Ú·´Ó¦µÄÀë×Ó·½³Ìʽ£º
¢Ù______________________£¬¢Ú______________________¡£
£¨2£©¹¤ÒµÉÏÀûÓõç½â±¥ºÍʳÑÎË®²úÉúµÄÇâÆøºÍÂÈÆøÖÆÈ¡ÑÎËᣬΪÁËÌåÏÖÂÌÉ«»¯Ñ§ÀíÄʹÂÈÆø³ä·Ö·´Ó¦£¬²ÉÈ¡½«ÂÈÆøÔÚÇâÆøÖÐȼÉյİ취£¬¿É±ÜÃâÂÈÆøȼÉÕ²»ÍêÈ«ÎÛȾ¿ÕÆø£¬Çëд³öÂÈÆøÔÚÇâÆøÖÐȼÉÕµÄʵÑéÏÖÏó£º______________________¡£
£¨3£©´ÖÑÎÖк¬ÓÐCa£²£«¡¢Mg£²£«¡¢SO4£²£­µÈÔÓÖÊ£¬¾«Öƺó¿ÉµÃµ½±¥ºÍNaC1ÈÜÒº¡£ÏÖÓÐÏÂÁгýÔÓÊÔ¼Á£ºA£®ÑÎËá   B£®ÇâÑõ»¯±µÈÜÒº   C£®Ì¼ËáÄÆÈÜÒº¡£¾«ÖÆʱ¼ÓÈë¹ýÁ¿³ýÔÓÊÔ¼ÁµÄÕýȷ˳ÐòÊÇ______________¡££¨ÌîÐòºÅ£©
£¨4£©½ðÊôþÔÚ¿ÕÆøÖÐȼÉÕʱ£¬³ýÉú³ÉMgOÍ⣬»¹ÓÐÉÙÁ¿Mg3N2Éú³É¡£°ÑµÈÎïÖʵÄÁ¿µÄ½ðÊôþ·Ö±ð·ÅÔÚ£ºA£®´¿ÑõÆø£¨O2£©ÖУ»B£®¶þÑõ»¯Ì¼ÆøÌåÖУ»C£®¿ÕÆøÖС£ÍêȫȼÉպ󣬵õ½µÄ¹ÌÌåÎïÖʵÄÖÊÁ¿ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ______________¡££¨ÌîÐòºÅ£©
£¨5£©½«µç½â±¥ºÍNaClÈÜÒºÉú³ÉµÄÂÈÆøͨÈëÇâÑõ»¯ÄÆÈÜÒºÖпÉÒԵõ½NaClO¡£Ä³»¯Ñ§ÐËȤС×é̽¾¿NaClOÓëÄòËØCO(NH2)2µÄ·´Ó¦²úÎͨ¹ýʵÑé·¢ÏÖ²úÎï³ýijÖÖÑÎÍ⣬ÆäÓà²úÎﶼÊÇÄܲÎÓë´óÆøÑ­»·µÄÎïÖÊ£¬Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÓÃʯ»ÒÈ顢ʯ»Òµª(CaCN2)ºÍÁ¶³§Æø(º¬H2S)·´Ó¦£¬¼ÈÄܾ»»¯Î²Æø£¬ÓÖÄÜ»ñµÃÓ¦Óù㷺µÄCS(NH2)2(Áòëå)£¬Æ䲿·Ö¹¤ÒÕÁ÷³ÌÈçÏ£º

(1)¸ßÎÂÏ£¬H2S´æÔÚÏÂÁз´Ó¦£º2H2S(g)??2H2(g)£«S2(g)£¬Æäƽºâ³£Êý±í´ïʽΪK£½________________¡£
(2)ÓÃʯ»ÒÈéÎüÊÕH2SÖÆÈ¡Ca(HS)2ÐèÒªÔÚµÍÎÂϽøÐУ¬ÆäÔ­ÒòÊÇ_____________________________________________________£»
¹ýÂ˵õ½µÄÂËÔü¿ÉÔÙÀûÓã¬ÂËÔüµÄÖ÷Òª³É·ÖÊÇ________(Ìѧʽ)¡£
(3)ºÏ³ÉÁòëåÐ賤ʱ¼ä½Á°è£¬²¢ÔڽϸßζÈ(80¡«85 ¡æ)ϽøÐУ¬ÆäÄ¿µÄÊÇ_______________________________________¡£
Ca(HS)2ÓëCaCN2ÔÚË®ÈÜÒºÖкϳÉÁòëåµÄ»¯Ñ§·½³ÌʽΪ________________________________¡£
(4)»¯ºÏÎïXÓëÁòë廥Ϊͬ·ÖÒì¹¹Ì壬X¼ÓÈëFeCl3ÈÜÒºÖУ¬ÈÜÒºÏÔºìÉ«£¬XµÄ»¯Ñ§Ê½Îª________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÓÐÈýÆ¿ÎÞÉ«ÈÜÒºµÄ±êÇ©Ëð»µÁË£¬Ö»ÖªµÀËüÃÇ·Ö±ðÊÇÑÎËá¡¢BaCl2ÈÜÒººÍNa2CO3ÈÜÒº¡£¼×¡¢ÒÒÁ½Î»Í¬Ñ§¸÷ÓÃÒ»ÖÖÊÔ¼Á£¬Ò»´ÎÐÔ¼ø±ð¶¼È¡µÃÁ˳ɹ¦¡£¼×ÓõÄÒ»ÖÖָʾ¼ÁÊÇ_________£»ÒÒÓõÄÒ»ÖÖËáÈÜÒºÊÇ__________¡£±ûͬѧûÓÃÈκÎÊÔ¼ÁÒ²¼ø±ð³É¹¦ÁË£¬ËûµÄ¼ø±ð¹ý³ÌÊÇ£ºÈ¡ÑùÓÚÊÔ¹ÜÖУ¬±àºÅΪa¡¢b¡¢c£¬È»ºó½«ÈýÖÖÈÜÒºÁ½Á½»ìºÏ£¬·¢ÏÖa¼ÓÈëbÖÐÓÐÆøÅݲúÉú£¬a¼ÓÈëcÖÐÓа×É«³Áµí²úÉú£¬Ôòa¡¢b¡¢c·Ö±ðÊÇ________¡¢________¡¢__________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

¸õÌú¿óµÄÖ÷Òª³É·Ö¿É±íʾΪFeO¡¤Cr2O3£¬»¹º¬ÓÐMgO¡¢Al2O3¡¢Fe2O3µÈÔÓÖÊ£¬ÒÔÏÂÊÇÒÔ¸õÌú¿óΪԭÁÏÖƱ¸ÖظõËá¼Ø£¨K2Cr2O7£©µÄÁ÷³Ìͼ£º

ÒÑÖª£º¢Ù4FeO¡¤Cr2O3+ 8Na2CO3+ 7O28Na2CrO4 + 2 Fe2O3 + 8CO2¡ü£»
¢ÚNa2CO3 + Al2O32NaAlO2 + CO2¡ü£»¢Û Cr2O72£­+ H2O2CrO42£­ + 2H+
¸ù¾ÝÌâÒâ»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¹ÌÌåXÖÐÖ÷Òªº¬ÓÐ_________£¨Ìîд»¯Ñ§Ê½£©£»Òª¼ì²âËữ²Ù×÷ÖÐÈÜÒºµÄpHÊÇ·ñµÈÓÚ4.5£¬Ó¦¸ÃʹÓÃ__________£¨ÌîдÒÇÆ÷»òÊÔ¼ÁÃû³Æ£©¡£
£¨2£©Ëữ²½ÖèÓô×Ëáµ÷½ÚÈÜÒºpH<5£¬ÆäÄ¿µÄÊÇ_________________________________¡£
£¨3£©²Ù×÷¢óÓжಽ×é³É£¬»ñµÃK2Cr2O7¾§ÌåµÄ²Ù×÷ÒÀ´ÎÊÇ£º¼ÓÈëKCl¹ÌÌå¡¢Õô·¢Å¨Ëõ¡¢      ¡¢¹ýÂË¡¢_______¡¢¸ÉÔï¡£
£¨4£©Ï±íÊÇÏà¹ØÎïÖʵÄÈܽâ¶ÈÊý¾Ý£¬²Ù×÷¢ó·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ£ºNa2Cr2O7+2KCl ¡úK2Cr2O7¡ý+2NaCl¡£¸Ã·´Ó¦ÔÚÈÜÒºÖÐÄÜ·¢ÉúµÄÀíÓÉÊÇ_______________¡£

ÎïÖÊ
Èܽâ¶È/(g/100gË®)
0¡ãC
40¡ãC
80¡ãC
KCl
28
40.1
51.3
NaCl
35.7
36.4
38
K2Cr2O7
4.7
26.3
73
Na2Cr2O7
163
215
376
 
£¨5£©¸±²úÆ·YÖ÷Òªº¬ÇâÑõ»¯ÂÁ£¬»¹º¬ÉÙÁ¿Ã¾¡¢ÌúµÄÄÑÈÜ»¯ºÏÎï¼°¿ÉÈÜÐÔÔÓÖÊ£¬¾«È··ÖÎöYÖÐÇâÑõ»¯ÂÁº¬Á¿ÊdzÆÈ¡n gÑùÆ·£¬¼ÓÈë¹ýÁ¿______£¨ÌîдÊÔ¼Á£©¡¢Èܽ⡢¹ýÂË¡¢ÔÙ______£¨ÌîдÊÔ¼Á£©¡¢¡­¡­×ÆÉÕ¡¢ÀäÈ´¡¢³ÆÁ¿£¬µÃ¸ÉÔï¹ÌÌåm g ¡£¼ÆËãÑùÆ·ÖÐÇâÑõ»¯ÂÁµÄÖÊÁ¿·ÖÊýΪ_______£¨Óú¬m¡¢nµÄ´úÊýʽ±íʾ£©¡£
£¨6£©Áù¼Û¸õÓж¾£¬¶øCr3+Ïà¶Ô°²È«¡£¹¤Òµº¬¸õ£¨CrO3£©·ÏÔüÎÞº¦»¯´¦ÀíµÄ·½·¨Ö®Ò»ÊǸɷ¨½â¶¾£¬ÓÃú²»ÍêȫȼÉÕÉú³ÉµÄCO»¹Ô­CrO3¡£ÔÚʵÑéÊÒÖÐÄ£ÄâÕâÒ»¹ý³ÌµÄ×°ÖÃÈçÏ£º

COÓɼ×ËáÍÑË®ÖƵã»ÊµÑé½áÊøʱϨÃð¾Æ¾«µÆµÄ˳ÐòÊÇ_________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸