£¨08ÁúÑÒÒ»ÖжþÄ££©Ä³ÎÞÉ«»ìºÏÆøÌå¿ÉÄÜÓÉCH4¡¢NH3¡¢H2¡¢CO¡¢CO2ºÍHClÖеÄij¼¸ÖÖÆøÌå×é³É¡£ÔÚºãκãѹÌõ¼þÏ£¬½«´Ë»ìºÏÆøÌåͨ¹ýŨH2SO4ʱ£¬×ÜÌå»ý»ù±¾²»±ä£»Í¨¹ý¹ýÁ¿µÄ³ÎÇåʯ»Òˮʱ£¬Î´¼û±ä»ë×Ç£¬µ«»ìºÏÆøÌåµÄ×ÜÌå»ý¼õС£¬°ÑÊ£ÓàÆøÌåµ¼³öºó£¬ÔÚO2ÖÐÄܹ»µãȼ£¬È¼ÉÕ²úÎï²»ÄÜʹCuSO4·ÛÄ©±äÉ«¡£ÔòÔ­»ìºÏÆøÌåÒ»¶¨º¬ÓеijɷÖÊÇ£¨£©

A£®CH4ºÍNH3         B£®HCl¡¢H2ºÍCO     C£®HClºÍCO        D£®HCl¡¢COºÍCO2

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨08ÁúÑÒÒ»ÖжþÄ££©(13·Ö)A¡¢B¡¢C¡¢D¡¢E¡¢F¾ùΪ¶ÌÖÜÆÚÔªËØ£¬AÄÜÓëEÐγÉÆø̬AE4,ÆäÖÐAµÄÖÊÁ¿·ÖÊýΪ75%,EÓëBÄÜÐγɳ£Î³ÊҺ̬µÄE2BÐÍ»¯ºÏÎï,CµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÊÇËáÐÔ×îÇ¿µÄËá,DÔڵؿÇÖк¬Á¿½ö´ÎÓÚB,E¼ÈÄÜÐγɵ¥Ô­×Ӻ˵ÄÑôÀë×Ó£¬ÓÖÄÜÉú³Éµ¥Ô­×Ӻ˵ÄÒõÀë×Ó,FÊǶÌÖÜÆÚÖÐÔ­×Ӱ뾶×î´óµÄÔ­×Ó(³ýÏ¡ÓÐÆøÌå).

(1)¹¤ÒµÖÆÈ¡Dµ¥ÖʵĻ¯Ñ§·½³ÌʽΪ                            

                                 

£¨2£©Ò»Ð¡Á£Fµ¥ÖÊ·ÅÔÚʯÃÞÍøÉϼÓÈÈ,·´Ó¦µÄÏÖÏóÊÇ             

                                                

£¨3£©AE4ÊǺ¬ÓР      ¼ü£¨Ìѧ¼üÀàÐÍ£©µÄ     ·Ö×Ó£¨Ìî ¼«ÐÔ£¬·Ç¼«ÐÔ£©¡£    

£¨4£©Cµ¥ÖʺÍʯ»ÒÈé·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                       £» 

Ò»ÂúÉÕÆ¿Cµ¥ÖʵÄË®ÈÜÒºÈçͼµ¹ÖÃÓÚË®²ÛÖнϳ¤Ê±¼äÈÕÕÕºó£¬ÔÚÆ¿µ×»ýÐîÒ»¶¨Á¿µÄÆøÌ壬¼ìÑé¸ÃÆøÌåµÄ²Ù×÷ÊÇ                           

                                                                                 ¡£

(5)7.8¿ËF2B2ºÍ¹ýÁ¿µÄE2B·´Ó¦Ê±×ªÒƵĵç×ÓÊýΪ         NA(NAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨08ÁúÑÒÒ»ÖжþÄ££©£¨±¾Ìâ¹²16·Ö£©BÊÇÒ»ÖÖÈËÌå²»¿ÉȱÉÙµÄÎÞÉ«ÎÞζµÄÒºÌ壻CÊÇÒ»ÖÖÓдÅÐԵĻ¯ºÏÎEÊÇÒ»ÖÖÎÞÉ«¡¢ÎÞζµÄÓж¾ÆøÌ壬¸ù¾ÝÏÂÁйØϵͼ£¬Íê³É±¾Ì⣺

 

 

 

 

 

 

 

 (1£©Ð´³öB¡¢CµÄ»¯Ñ§Ê½£ºB                    £¬C                   

£¨2£©EºÍN2½á¹¹ÏàËÆ£¬Çëд³öEµÄµç×Óʽ£ºE               

A£®Éý¸ßζȠ         B£®Ôö´óѹǿ         C£®¼ÓÈë´ß»¯¼Á

£¨4£©ÈôGÊÇÒ»ÖÖµ­»ÆÉ«¹ÌÌåµ¥ÖÊ£¬16¿ËµÄGºÍ×ãÁ¿µÄA·´Ó¦·Å³öµÄÈÈÁ¿ÎªQ kJ£¨Q>0£©£¬Ð´³öÕâ¸ö·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ______

ÈôGÊÇÒ»ÖÖÆø̬µ¥ÖÊ£¬HµÄË®ÈÜÒº¿ÉÒÔºÍÓлúÎïI·´Ó¦Ê¹ÈÜÒº³Ê×ÏÉ«£¬Çëд³öG¡¢IµÄ·Ö×Óʽ£º        £¬       £»HµÄË®ÈÜÒº³ÊËáÐÔ£¬ÇëÓû¯Ñ§·½³Ìʽ±íʾ³ÊËáÐÔµÄÔ­Òò¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨08ÁúÑÒÒ»ÖжþÄ££©£¨18·Ö£©¼×¡¢ÒÒ¡¢±ûÈýλͬѧ·Ö±ð½øÐС°Na2CO3ºÍNaCl»ìºÏÎïÖÐNa2CO3ÖÊÁ¿·ÖÊý²â¶¨¡±µÄʵÑ飺

£¨1£©¼×ͬѧʵÑéµÄÖ÷Òª²½ÖèÓУº¢Ù¹ýÂË  ¢Ú¼ÓÈë×ãÁ¿µÄCaCl2ÈÜÒº  ¢Û½«³ÁµíСÐĺæ¸É¡¢³ÆÁ¿£¬²âµÃ¹ÌÌåÖÊÁ¿Îªng  ¢Ü³ÆÈ¡mgÑùÆ·ÈÜÓÚÊÊÁ¿ÕôÁóË®  ¢ÝÏ´µÓ³Áµí2¨D3´Î¡£¸ÃͬѧÕýÈ·µÄ²Ù×÷²½ÖèΪ                  £¨ÌîÐòºÅ£©£»»ìºÏÎïÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýΪ                           £¨Ö»ÐèÁгö¼ÆËãʽ£©¡£

£¨2£©ÒÒͬѧ°ÑÒ»¶¨Á¿µÄ»ìºÏÎïÓë×ãÁ¿ÑÎËá·´Ó¦£¬È»ºóÓÃÈçͼװÖòⶨ²úÉúµÄCO2ÆøÌåµÄÌå»ý£¬ÊµÑéÊÒÖÐÖ»ÓÐÈçÏÂÊÔ¼Á£ºÑùÆ·¡¢6mol/LÑÎËá¡¢Na2CO3ÈÜÒº¡¢CaCl2ÈÜÒº¡¢±¥ºÍNaHCO3ÈÜÒº¡£

»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù¹ã¿ÚÆ¿ÖÐÊ¢·ÅµÄÈÜÒºÊÇ                          ¡£

¢Ú¸Ã×°ÖòⶨµÄÆøÌåÌå»ýÍùÍù²»×¼È·(²»¿¼Âǵ¼¹ÜÖÐË®µÄÌå»ý)£¬

ÀíÓÉÊÇ       ¡¡¡¡                  ¡¡                                          ¡£

£¨3£©±ûͬѧ׼ȷ³ÆÈ¡w g¹ÌÌå»ìºÏÎï·ÅÈë׶ÐÎÆ¿ÖУ¬¼ÓÈëV1 mL 0.1000mol/LÑÎËᣬ³ä·Ö·´Ó¦£¬ÓÃ0.1000mol/LµÄÇâÑõ»¯ÄÆÈÜÒºµÎ¶¨¹ýÁ¿ÑÎËᣬÏûºÄÇâÑõ»¯ÄÆÈÜÒºV2 mL¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÙʵÑéÊÒÏÖÓÐ1.000mol/LÑÎËáÈÜÒº¡£ÎªÁ˾«È·ÅäÖÆ10mL 0.1000mol/LµÄÑÎËáÈÜÒº£¬ÐèÒªµÄÒÇÆ÷ÓУºÉÕ±­¡¢100mLÈÝÁ¿Æ¿¡¢²£Á§°ô¡¢                    ¡£

¢ÚµÎ¶¨Ê±Ñ¡Ôñ                ×÷ָʾ¼Á£¬µÎ¶¨ÖÕµãÈÜÒºµÄÑÕÉ«±ä»¯Îª            ¡£

¢Û»ìºÏÎïÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýΪ                   £¨Ö»ÐèÁгö¼ÆËãʽ£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨08ÁúÑÒÒ»ÖжþÄ££©Ò»¶¨Ìõ¼þÏ£¬Ìå»ýΪ10LµÄÃܱÕÈÝÆ÷ÖУ¬1molXºÍ1molY½øÐз´Ó¦£º

2X(g)£«Y(g)Z(g)£¬¾­60s´ïµ½Æ½ºâ£¬Éú³É0.3molZ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨£©

A£®ÒÔXŨ¶È±ä»¯±íʾµÄ·´Ó¦ËÙÂÊΪ0.001mol/(L?S)

B£®½«ÈÝÆ÷Ìå»ý±äΪ20L£¬ZµÄƽºâŨ¶È±äΪԭÀ´µÄ1/2

C£®ÈôÔö´óѹǿ£¬ÔòÎïÖÊYµÄת»¯ÂʼõС

D£®ÈôÉý¸ßζȣ¬XµÄÌå»ý·ÖÊýÔö´ó£¬Ôò¸Ã·´Ó¦µÄ¡÷H£¾0

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸