£¨2010?Æô¶«ÊÐÄ£Ä⣩¹ý̼ËáÄÆÊÇÒ»ÖÖÓжàÓÃ;µÄÐÂÐÍÑõϵƯ°×¼Á£¬»¯Ñ§Ê½¿É±íʾΪaNa2CO3?bH2O2£®ÏÖ½«Ò»¶¨ÖÊÁ¿µÄ¹ý̼ËáÄÆ·ÛÄ©ÈÜÓÚË®Åä³ÉÏ¡ÈÜÒº£¬ÔÙÏòÆäÖмÓÈëÊÊÁ¿MnO2·ÛÄ©£¬³ä·Ö·´Ó¦ºóÉú³É672mLÆøÌ壨±ê×¼×´¿ö£©£®·´Ó¦ºóµÄ»ìºÏÎï¾­¹ýÂË¡¢Ï´µÓºó£¬½«ÂËÒººÍÏ´µÓÒº»ìºÏ²¢¼ÓË®Åä³É100mLÈÜÒºA£®ÏÖÏòÈý·ÝÌå»ýΪ10mL¡¢Å¨¶ÈΪcmol/LµÄÏ¡ÁòËáÖзֱðÖðµÎµÎÈëÈÜÒºA£¬±ßµÎ±ßÕñµ´£¬³ä·Ö·´Ó¦ºó£¬²âµÃʵÑéÊý¾ÝÈçϱíËùʾ£º
ʵÑéÐòºÅ ¢ñ ¢ò ¢ó
µÎ¼ÓÈÜÒºAµÄÌå»ý/mL 10.0 20.0 30.0
Éú³ÉÆøÌåµÄÌå»ý/mL£¨±ê×¼×´¿ö£© 89.6 179.2 224
£¨1£©¼ÆËãÏ¡ÁòËáµÄÎïÖʵÄÁ¿Å¨¶È£®
£¨2£©Í¨¹ý¼ÆËãÈ·¶¨¹ý̼ËáÄƵĻ¯Ñ§Ê½£®
£¨3£©¹¤ÒµÉϳ£ÒÔËùº¬»îÐÔÑõµÄÖÊÁ¿·ÖÊý[w£¨»îÐÔÑõ£©=
16n(H2O2)
m(ÑùÆ·)
¡Á100%]À´ºâÁ¿¹ý̼ËáÄƲúÆ·µÄÓÅÁÓ£¬13%ÒÔÉÏÕßΪÓŵÈÆ·£®ÏÖ½«0.2gij³§¼ÒÉú²úµÄ¹ý̼ËáÄÆÑùÆ·£¨Ëùº¬ÔÓÖʲ»²ÎÓëºóÃæµÄÑõ»¯»¹Ô­·´Ó¦£©ÈÜÓÚË®Åä³ÉÈÜÒº£¬¼ÓÈë15.0mL 1mol/LÁòËᣬÔÙ¼ÓÈë×ãÁ¿KI£¬Ò¡ÔȺóÖÃÓÚ°µ´¦£¬³ä·Ö·´Ó¦ºó£¬¼ÓÈëÉÙÁ¿µí·ÛÊÔÒº£¬ÓÃ0.1mol/L Na2S2O3ÈÜÒºµÎ¶¨µ½À¶É«Ç¡ºÃÏûʧʱ£¬¹²ÏûºÄ30.00mL£¬ÊÔ¼ÆËãÅжϸÃÑùÆ·ÊÇ·ñΪÓŵÈÆ·£®£¨ÒÑÖª£º2Na2S2O3+I2¡úNa2S4O6+2NaI£©
·ÖÎö£º£¨1£©ÓÉͼ±í¿ÉÖª£¬µÚÈý·ÝÏ¡ÁòËáÍêÈ«·´Ó¦£¬¸ù¾Ý̼ËáÄƺÍÏ¡ÁòËá·´Ó¦µÄ»¯Ñ§·½³ÌʽÒÔ¼°Éú³ÉµÄÆøÌåµÄÌå»ý¼´¿É¼ÆËã³öÏ¡ÁòËáµÄÎïÖʵÄÁ¿£¬È»ºóÇó³öÏ¡ÁòËáµÄÎïÖʵÄÁ¿Å¨¶È£»
£¨2£©·Ö±ðÇó³ö̼ËáÄƺÍË«ÑõË®µÄÎïÖʵÄÁ¿¼´¿É£»
£¨3£©¸ù¾Ý2I-+H2O2+2H+=I2+2H2O£¬2Na2S2O3+I2¡úNa2S4O6+2NaI¿ÉÖªn£¨H2O2£©=
n(Na2S2O3)
2
£®
½â´ð£º½â£º£¨1£©ÉèÏ¡ÁòËáµÄÎïÖʵÄÁ¿Îªx£¬
Na2CO3+H2SO4=Na2SO4+H2O+CO2¡ü
        1               22.4L/mol
        x              0.224L
1
=
22.4L/mol
0.224L

½âÖ®µÃ£ºx=0.01mol£¬
Ï¡ÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ£ºC=
n
V
=
0.01mol
0.01L
=1 mol/L£¬
´ð£ºÏ¡ÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ1mol/L£»
£¨2£©n£¨O2£©=
0.672L
22.4L/mol
=0.03mol£¬n£¨H2O2£©=0.06mol£¬ÓÉʵÑé¢ñÖÐÊý¾Ý¿ÉÖª£¬10mLAÈÜÒºÖУºn£¨Na2CO3£©=n£¨CO2£©=0.004 mol£¬ËùÒÔ100mLAÖк¬ÓÐ0.04molNa2CO3£¬n£¨Na2CO3£©£ºn£¨H2O2£©=0.04£º0.06=2£º3
ËùÒÔ»¯Ñ§Ê½Îª2Na2CO3?3H2O2£¨ÓÃʵÑé¢ñÖÐÊý¾ÝÒ²µÃ·Ö£©£¬
´ð£º¹ý̼ËáÄƵĻ¯Ñ§Ê½Îª2Na2CO3?3H2O2£»
£¨3£©¸ù¾Ý2I-+H2O2+2H+=I2+2H2O£¬2Na2S2O3+I2¡úNa2S4O6+2NaI¿ÉÖª£ºn£¨H2O2£©=
n(Na2S2O3)
2
=
0.1mol/L¡Á0.030L
2
=1.5¡Á10-3mol£¬
¸Ã¹ý̼ËáÄƵĻîÐÔÑõµÄÖÊÁ¿·ÖÊýΪ£º
1.5¡Á10 -3¡Á16
0.2
=12%£¼13%£¬ËùÒÔ¸ÃÑùÆ·²»ÊÇÓŵÈÆ·£¬
´ð£º¸ÃÑùÆ·²»ÊÇÓŵÈÆ·£®
µãÆÀ£º±¾Ì⿼²é¸ù¾Ý»¯Ñ§·½³ÌʽµÄ¼ÆË㣬ÄѶȽϴó£¬×¢ÒâŪÇå³þ·½³ÌʽÖи÷ÎïÖʵÄÁ¿µÄ¹ØϵÊǽâÌâµÄ¹Ø¼ü£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2010?Æô¶«ÊÐÄ£Ä⣩ijÖÖ·¼Ïã×廯ºÏÎïA£¬ÆäÕôÆøÃܶÈÊÇÏàͬÌõ¼þÏÂH2ÃܶȵÄ82±¶£®AÓÉ̼¡¢Çâ¡¢ÑõÈýÖÖÔªËØ×é³É£¬¾­²â¶¨Ì¼¡¢ÇâµÄÖÊÁ¿·ÖÊý·Ö±ðΪ
73.2%ºÍ7.32%£®
£¨1£©AµÄ·Ö×ÓʽÊÇ
C10H12O2
C10H12O2
£®
£¨2£©ÒÑÖª£º
¢¡£®£¨R1¡¢R2¡¢R3´ú±íÌþ»ù£©
¢¢£®
ÓÖÖª£¬AÔÚÒ»¶¨Ìõ¼þÏÂÄÜ·¢ÉúÈçÏÂת»¯£¬Ä³Ð©Éú³ÉÎÈçH2OµÈ£©ÒÑÂÔÈ¥£®

Çë»Ø´ð£º
¢Ù²½Öè¢ñµÄÄ¿µÄÊÇ
±£»¤·ÓôÇ»ù
±£»¤·ÓôÇ»ù
£»
¢ÚÈôGΪ̼ËᣬÔòEµÄ½á¹¹¼òʽÊÇ
HCOOH
HCOOH
¢ÛF¡úHµÄ·´Ó¦ÀàÐÍÊÇ
Ëõ¾Û·´Ó¦
Ëõ¾Û·´Ó¦
£»
¢ÜFÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢Éúõ¥»¯·´Ó¦£¬Éú³ÉM£¨MÓëFeCl3·´Ó¦£¬ÈÜÒº³Ê×ÏÉ«£»ÇÒ·Ö×ӽṹÖк¬Óб½»·ºÍÒ»¸öÆßÔª»·£©Çëд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ
£»
¢ÝAµÄ½á¹¹¼òʽÊÇ
£»ÉÏÊöת»¯ÖÐB¡úDµÄ»¯Ñ§·½³ÌʽÊÇ
£®
£¨3£©ÒÑÖªAµÄijÖÖͬ·ÖÒì¹¹ÌåN¾ßÓÐÈçÏÂÐÔÖÊ£º
¢ÙNÓëFeCl3·´Ó¦£¬ÈÜÒº³Ê×ÏÉ«£»
¢ÚNÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢ÉúÒø¾µ·´Ó¦£¬NÓëH2ÔÚ±½»·²àÁ´ÉÏ°´ÕÕÎïÖʵÄÁ¿Ö®±È1£º1×÷ÓúóµÄÉú³ÉÎï²»ÄÜ·¢ÉúÏûÈ¥·´Ó¦£»
¢ÛÔÚͨ³£Çé¿öÏ£¬1mol NÄÜÓ뺬1mol Br2µÄŨäåË®·¢ÉúÈ¡´ú·´Ó¦£»
¢ÜN·Ö×ÓÖб½»·ÉϵÄÈ¡´ú»ùÉÏÎÞÖ§Á´£®
Çëд³ö£ºN¿ÉÄܵĽṹ¼òʽ
£¨Ð´Ò»ÖÖ¼´¿É£©£®
£¨4£©ÇëÉè¼ÆºÏÀí·½°¸£¬Íê³É´Óµ½µÄºÏ³É·Ïߣ¨ÓúϳÉ·ÏßÁ÷³Ìͼ±íʾ£¬²¢×¢Ã÷·´Ó¦Ìõ¼þ£©£®
Ìáʾ£º¢Ù£»ºÏ³É¹ý³ÌÖÐÎÞ»úÊÔ¼ÁÈÎÑ¡£»¢ÚºÏ³É·ÏßÁ÷³ÌͼʾÀýÈçÏ£º
CH3CH2OH
ŨH2SO4
170¡æ
CH2=CH2
¸ßΡ¢¸ßѹ
´ß»¯¼Á

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2010?Æô¶«ÊÐÄ£Ä⣩ÔÚÏÂÁÐÈÜÒºÖУ¬¸÷×éÀë×ÓÒ»¶¨Äܹ»´óÁ¿¹²´æµÄÊÇѧ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2010?Æô¶«ÊÐÄ£Ä⣩£¨1£©CH3+£®CH3-£®CH3-¶¼ÊÇÖØÒªµÄÓлú·´Ó¦ÖмäÌ壬ÓйØËüÃǵÄ˵·¨ÕýÈ·µÄÊÇ
CDE
CDE
£®
A£®ËüÃǾùÓɼ×ÍéÈ¥µôÒ»¸öÇâÔ­×ÓËùµÃ
B£®ËüÃÇ»¥ÎªµÈµç×ÓÌ壬̼ԭ×Ó¾ù²ÉÈ¡sp2ÔÓ»¯
C£®CH3-ÓëNH3£®H3O+»¥ÎªµÈµç×ÓÌ壬¼¸ºÎ¹¹Ð;ùΪÈý½Ç׶ÐÎ
D£®CH3+ÖеÄ̼ԭ×Ó²ÉÈ¡sp2ÔÓ»¯£¬ËùÓÐÔ­×Ó¾ù¹²Ãæ
E£®Á½¸öCH3-»òÒ»¸öCH3+ºÍCH3-½áºÏ¾ù¿ÉµÃµ½CH3CH3
£¨2£©Ð¿ÊÇÒ»ÖÖÖØÒªµÄ½ðÊô£¬Ð¿¼°Æ仯ºÏÎïÓÐ׏㷺µÄÓ¦Óã®
¢ÙÖ¸³öпÔÚÖÜÆÚ±íÖеÄλÖãº
ËÄ
ËÄ
ÖÜÆÚ£¬
¢òB
¢òB
×壬
ds
ds
Çø£®
¢ÚÆÏÌÑÌÇËáп[CH2OH£¨CHOH£©4COO]2ZnÊÇÄ¿Ç°Êг¡ÉÏÁ÷ÐеIJ¹Ð¿¼Á£®Ð´³öZn2+»ù̬µç×ÓÅŲ¼Ê½
1s22s22p63s23p63d10»ò[Ar]3d10
1s22s22p63s23p63d10»ò[Ar]3d10
£»ÆÏÌÑÌÇ·Ö×ÓÖÐ̼ԭ×ÓÔÓ»¯·½Ê½ÓÐ
sp2¡¢sp3
sp2¡¢sp3
£®
¢ÛZn2+ÄÜÓëNH3ÐγÉÅäÀë×Ó[Zn£¨NH3£©4]2+£®ÅäλÌåNH3·Ö×ÓÊôÓÚ
¼«ÐÔ·Ö×Ó
¼«ÐÔ·Ö×Ó
£¨Ìî¡°¼«ÐÔ·Ö×Ó¡±»ò¡°·Ç¼«ÐÔ·Ö×Ó¡±£©£»ÔÚ[Zn£¨NH3£©4]2+ÖУ¬Zn2+λÓÚÕýËÄÃæÌåÖÐÐÄ£¬NλÓÚÕýËÄÃæÌåµÄ¶¥µã£¬ÊÔÔÚ×óÏÂͼÖбíʾ[Zn£¨NH3£©4]2+ÖÐZn2+ÓëNÖ®¼äµÄ»¯Ñ§¼ü£®
¢ÜÈçͼ±íʾпÓëij·Ç½ðÊôÔªËØXÐγɵĻ¯ºÏÎᄃ°û£¬ÆäÖÐZnºÍXͨ¹ý¹²¼Û¼ü½áºÏ£¬¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½Îª
ZnX
ZnX
£»¸Ã»¯ºÏÎïµÄ¾§ÌåÈÛµã±È¸É±ù¸ßµÃ¶à£¬Ô­ÒòÊÇ
¸ß£¬¸Ã»¯ºÏÎïÊÇÔ­×Ó¾§Ì壬¶ø¸É±ùÊÇ·Ö×Ó¾§Ìå
¸ß£¬¸Ã»¯ºÏÎïÊÇÔ­×Ó¾§Ì壬¶ø¸É±ùÊÇ·Ö×Ó¾§Ìå
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2010?Æô¶«ÊÐÄ£Ä⣩ֱ½ÓNaBH4/H2O2ȼÁϵç³Ø£¨DBFC£©µÄ½á¹¹Èçͼ£¬¡°¸º¼«²ÄÁϲÉÓÃPt/C£¬Õý¼«²ÄÁϲÉÓÃMnO2¡±£¬Óйظõç³ØµÄ˵·¨ÕýÈ·µÄÊÇ
£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸