ijÐËȤС×é̽¾¿SO2ÆøÌ廹ÔFe3£«¡¢I2£¬ËûÃÇʹÓõÄÒ©Æ·ºÍ×°ÖÃÈçͼËùʾ£º
(1)SO2ÆøÌ廹ÔFe3£«µÄ²úÎïÊÇ________(ÌîÀë×Ó·ûºÅ)£¬²Î¼Ó·´Ó¦µÄSO2ºÍFe3£«µÄÎïÖʵÄÁ¿Ö®±ÈÊÇ________¡£
(2)ÏÂÁÐʵÑé·½°¸ÊÊÓÃÓÚÔÚʵÑéÊÒÖÆÈ¡ËùÐèSO2µÄÊÇ________¡£
A£®Na2SO3ÈÜÒºÓëHNO3 B£®Na2SO3¹ÌÌåÓëŨÁòËá
C£®¹ÌÌåÁòÔÚ´¿ÑõÖÐȼÉÕ D£®ÍÓëÈÈŨH2SO4
(3)×°ÖÃCµÄ×÷ÓÃÊÇ____________________________________¡£
(4)ÈôÒª´ÓAÖÐËùµÃÈÜÒºÌáÈ¡¾§Ì壬±ØÐë½øÐеÄʵÑé²Ù×÷²½Ö裺Õô·¢¡¢ÀäÈ´½á¾§¡¢¹ýÂË¡¢×ÔÈ»¸ÉÔÔÚÕâһϵÁвÙ×÷ÖÐûÓÐÓõ½µÄÒÇÆ÷ÓÐ________(ÌîÐòºÅ)¡£
A£®Õô·¢Ãó¡¡¡¡¡¡ B£®Ê¯ÃÞÍø
C£®Â©¶· D£®ÉÕ± E£®²£Á§°ô F£®ÛáÛö
(5)ÔÚÉÏÊö×°ÖÃÖÐͨÈë¹ýÁ¿µÄSO2£¬ÎªÁËÑéÖ¤AÖÐSO2ÓëFe3£«·¢ÉúÁËÑõ»¯»¹Ô·´Ó¦£¬ËûÃÇÈ¡AÖеÄÈÜÒº£¬·Ö³ÉÈý·Ý£¬²¢Éè¼ÆÁËÈçÏÂʵÑ飺
·½°¸¢Ù£ºÍùµÚÒ»·ÝÊÔÒºÖмÓÈëËáÐÔKMnO4ÈÜÒº£¬×ϺìÉ«ÍÊÈ¥¡£
·½°¸¢Ú£ºÍùµÚ¶þ·ÝÊÔÒºÖмÓÈëKSCNÈÜÒº£¬²»±äºì£¬ÔÙ¼ÓÈëÐÂÖƵÄÂÈË®£¬ÈÜÒº±äºì¡£
·½°¸¢Û£ºÍùµÚÈý·ÝÊÔÒºÖмÓÈëÓÃÏ¡ÑÎËáËữµÄBaCl2£¬²úÉú°×É«³Áµí¡£
ÉÏÊö·½°¸²»ºÏÀíµÄÊÇ________£¬ÔÒòÊÇ__________________________
______________________________________________¡£
(6)ÄܱíÃ÷I£»¹ÔÐÔÈõÓÚSO2µÄÏÖÏóÊÇ_____________________________
___________________________________________¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
þ¼°ÆäºÏ½ðÊÇÒ»ÖÖÓÃ;ºÜ¹ãµÄ½ðÊô²ÄÁÏ£¬Ä¿Ç°ÊÀ½çÉÏ60%µÄþÊÇ´Óº£Ë®ÖÐÌáÈ¡µÄ¡£Ö÷Òª²½ÖèÈçÏ£º
(1)ΪÁËʹMgSO4ת»¯ÎªMg(OH)2£¬ÊÔ¼Á¢Ù¿ÉÒÔÑ¡ÓÃ________£¬ÒªÊ¹MgSO4Íêȫת»¯Îª³Áµí£¬¼ÓÈëÊÔ¼ÁµÄÁ¿Ó¦Îª________________¡£
(2)¼ÓÈëÊÔ¼Á¢Ùºó£¬Äܹ»·ÖÀëµÃµ½Mg(OH)2³ÁµíµÄ·½·¨ÊÇ_____________¡£
(3)ÊÔ¼Á¢ÚÑ¡ÓÃ________£»Ð´³öÆä·´Ó¦µÄÀë×Ó·½³Ìʽ_______¡£
(4)ÎÞË®MgCl2ÔÚÈÛÈÚ״̬Ï£¬Í¨µçºó²úÉúþºÍÂÈÆø£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
ij»¯Ñ§Ð¡×éÒÔ±½¼×ËáΪÔÁÏÖÆÈ¡±½¼×Ëá¼×õ¥¡£ÓйØÎïÖʵķеãºÍÏà¶Ô·Ö×ÓÖÊÁ¿Èç±í£º
ÎïÖÊ | ¼×´¼ | ±½¼×Ëá | ±½¼×Ëá¼×õ¥ |
·Ðµã£¯¡æ | 64.7 | 249 | 199.6 |
Ïà¶Ô·Ö×ÓÖÊÁ¿ | 32 | 122 | 136 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
ÁòËáÑÇÌúï§[(NH4)2SO4¡¤FeSO4¡¤6H2O]ΪdzÂÌÉ«¾§Ì壬Ò×ÈÜÓÚË®£¬²»ÈÜÓھƾ«£¬ÔÚË®ÖеÄÈܽâ¶È±ÈFeSO4»ò(NH4)2SO4¶¼ÒªÐ¡¡£ÊµÑéÊÒÖг£ÒÔ·ÏÌúмΪÔÁÏÀ´ÖƱ¸£¬Æä²½ÖèÈçÏ£º
ͼ1
²½Öè1£ºÌúмµÄ´¦Àí¡£½«·ÏÌúм·ÅÈëÈȵÄ̼ËáÄÆÈÜÒºÖнþÅݼ¸·ÖÖÓºó£¬ÓÃͼ1Ëùʾ·½·¨·ÖÀë³ö¹ÌÌ岢ϴµÓ¡¢¸ÉÔï¡£
²½Öè2£ºFeSO4ÈÜÒºµÄÖƱ¸¡£½«´¦ÀíºÃµÄÌúм·ÅÈë׶ÐÎÆ¿£¬¼ÓÈë¹ýÁ¿µÄ3 mol¡¤
L£1H2SO4ÈÜÒº£¬¼ÓÈÈÖÁ³ä·Ö·´Ó¦ÎªÖ¹¡£³ÃÈȹýÂË(Èçͼ2Ëùʾ)£¬ÊÕ¼¯ÂËÒººÍÏ´µÓÒº¡£
ͼ2
²½Öè3£ºÁòËáÑÇÌú淋ÄÖƱ¸¡£ÏòËùµÃFeSO4ÈÜÒºÖмÓÈë±¥ºÍ(NH4)2SO4ÈÜÒº£¬¾¹ý¼ÓÈÈŨËõ¡¢ÀäÈ´½á¾§¡¢¹ýÂË¡¢ÒÒ´¼Ï´µÓºóµÃµ½ÁòËáÑÇÌú茶§Ìå¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)²½Öè1ÖÐͼ1·ÖÀë·½·¨³ÆΪ________·¨¡£
(2)²½Öè2ÖÐÓÐÒ»´¦Ã÷ÏÔ²»ºÏÀíµÄÊÇ___________________________________¡£
³ÃÈȹýÂ˵ÄÀíÓÉÊÇ________________________________________________¡£
(3)²½Öè3¼ÓÈÈŨËõ¹ý³ÌÖУ¬µ±________ʱֹͣ¼ÓÈÈ¡£ÓÃÎÞË®ÒÒ´¼Ï´µÓ¾§ÌåµÄÔÒòÊÇ______________________________________________________________¡£
(4)FeSO4¡¤7H2OÔÚ³±ÊªµÄ¿ÕÆøÖÐÒ×±»Ñõ»¯³ÉFe(OH)SO4¡¤3H2O£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
ÓÉ߻ૼ×ËáÍÑôȵõ½ß»à«Óë±ûͪÔÚËáÐÔÌõ¼þÏÂËõºÏ£¬¿ÉµÃµ½°Ë¼×»ùËÄÑõÔÓ¿äÌØÏ©¡£ÓйØʵÑéÔÀí¼°Á÷³ÌÈçÏ£»
²½Öè1£ºß»à«µÄÖƱ¸
ÔÚÔ²µ×ÉÕÆ¿ÖзÅÖÃ4.5 g߻ૼ×Ëᣨ100 ¡æÉý»ª£¬ß»à«¼×ËáÔÚ133 ¡æÈÛÈÚ£¬230¡«232 ¡æ·ÐÌÚ£¬²¢ÔÚ´ËζÈÏÂÍÑôÈ£©£¬°´Í¼°²×°ºÃÒÇÆ÷¡£ÏÈ´ó»ð¼ÓÈÈʹ߻ૼ×Ëá¿ìËÙÈÛ»¯£¬È»ºóµ÷½Ú¼ÓÈÈÇ¿¶È£¬²¢±£³Ö΢·Ð£¬µ±ß»à«¼×ËáÍÑôÈ·´Ó¦Íê±Ï£¬Í£Ö¹¼ÓÈÈ¡£µÃÎÞÉ«ÒºÌå߻ૣ¨·Ðµã£º31¡«32 ¡æ£¬Ò×ÈÜÓÚË®£©¡£
²½Öè2£º´ó»·»¯ºÏÎï°Ë¼×»ùËÄÑõÔÓ¿äÌØÏ©µÄºÏ³É
ÔÚ25 mL׶ÐÎÆ¿ÖмÓÈë2.7 mL 95%ÒÒ´¼ºÍ1.35 mLŨÑÎËᣬ»ìÔÈ£¬ÔÚ±ùÔ¡ÖÐÀäÖÁ5 ¡æÒÔÏ£¬È»ºó½«3.3 mL±ûͪºÍ1.35 mL߻૵ĻìºÏҺѸËÙµ¹Èë׶ÐÎÆ¿ÖУ¬³ä·Ö»ìÔÈ£¬±ùÔ¡ÀäÈ´£¬¾²ÖõÃÒ»»ÆÉ«À¯×´¹ÌÌå¡£¹ýÂË£¬²¢ÓÃ3 mLÎÞË®ÒÒ´¼Ï´µÓ£¬Óñ½Öؽᾧ£¬µÃ°×É«½á¾§°Ë¼×»ùËÄÑõÔÓ¿äÌØÏ©¡£
£¨1£©²½Öè1ÖÐÓôó»ð¼±ËÙ¼ÓÈÈ£¬ÆäÖ÷ҪĿµÄÊÇ____________________________¡£
£¨2£©×°ÖÃͼÖмîʯ»ÒµÄ×÷ÓÃÊÇ__________________________________________£»
ÎÞË®ÂÈ»¯¸ÆµÄ×÷ÓÃÊÇ________________________________________________¡£
£¨3£©ÍÑôÈ×°ÖÃÖÐÓñùÑÎÔ¡µÄÄ¿µÄÊÇ_____________________________________¡£
£¨4£©ºÏ³É°Ë¼×»ùËÄÑõÔÓ¿äÌØÏ©¼ÓÈëÑÎËáµÄÄ¿µÄÊÇ_________________________¡£
£¨5£©È·ÂÛ²úƷΪ°Ë¼×»ùËÄÑõÔÓ¿äÌØÏ©£¬¿Éͨ¹ý²â¶¨·Ðµã£¬»¹¿É²ÉÓõļì²â·½·¨ÓÐ__________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
°¢Ë¾Æ¥ÁÖ¿ÉÓÉË®ÑîËáÓëÒÒËáôû×÷ÓÃÖƵá£ÆäÖƱ¸ÔÀíÈçÏ£º
°¢Ë¾Æ¥ÁÖ(ÒÒõ£Ë®ÑîËá)µÄÄÆÑÎÒ×ÈÜÓÚË®¡£°¢Ë¾Æ¥ÁÖ¿É°´Èçϲ½ÖèÖÆÈ¡ºÍ´¿»¯£º
²½Öè1£ºÔÚ¸ÉÔïµÄ50 mLÔ²µ×ÉÕÆ¿ÖмÓÈë2 gË®ÑîËá¡¢5 mLÒÒËáôûºÍ5µÎŨÁòËᣬÕñµ´Ê¹Ë®ÑîËáÈ«²¿Èܽ⡣
²½Öè2£º°´Í¼ËùʾװÖÃ×°ÅäºÃÒÇÆ÷£¬Í¨Ë®£¬ÔÚˮԡÉϼÓÈÈ»ØÁ÷5¡«10 min£¬¿ØÖÆˮԡζÈÔÚ85¡«90 ¡æ¡£
²½Öè3£º·´Ó¦½áÊøºó£¬È¡Ï·´Ó¦Æ¿£¬ÀäÈ´£¬ÔÙ·ÅÈë±ùË®ÖÐÀäÈ´¡¢½á¾§¡¢³éÂË¡¢ÀäˮϴµÓ2¡«3´Î£¬¼ÌÐø³éÂ˵ôֲúÎï¡£
²½Öè4£º½«´Ö²úÎïתÒÆÖÁ150 mLÉÕ±ÖУ¬ÔÚ½Á°èϼÓÈë25 mL±¥ºÍ̼ËáÇâÄÆÈÜÒº£¬³ä·Ö½Á°è£¬È»ºó¹ýÂË¡£
²½Öè5£º½«ÂËÒºµ¹Èë10 mL 4 mol¡¤L£1ÑÎËᣬ½Á°è£¬½«ÉÕ±ÖÃÓÚ±ùÔ¡ÖÐÀäÈ´£¬Ê¹½á¾§ÍêÈ«¡£³éÂË£¬ÔÙÓÃÀäˮϴµÓ2¡«3´Î¡£
(1)²½Öè1ŨÁòËáµÄ×÷ÓÿÉÄÜÊÇ________¡£
(2)²½Öè2ÖУ¬ÀäÄý¹Üͨˮ£¬Ë®Ó¦´Ó________¿Ú½ø(Ìî¡°a¡±»ò¡°b¡±)¡£
(3)²½Öè3³éÂËʱ£¬ÓÐʱÂËÖ½»á´©¿×£¬±ÜÃâÂËÖ½´©¿×µÄ´ëÊ©ÊÇ______________________________________________________________¡£
(4)²½Öè4·¢ÉúÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________________£»¹ýÂ˵õ½µÄ¹ÌÌåΪ________¡£
(5)È¡¼¸Á£²½Öè5»ñµÃµÄ¾§Ìå¼ÓÈëÊ¢ÓÐ5 mLË®µÄÊÔ¹ÜÖУ¬¼ÓÈë1¡«2µÎ1%ÈýÂÈ»¯ÌúÈÜÒº£¬·¢ÏÖÈÜÒº±ä×ÏÉ«£¬¿É²ÉÓÃ________·½·¨£¬½øÒ»²½´¿»¯¾§Ìå¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
SiO2¡¢SO2ºÍCO2¶¼ÊÇËáÐÔÑõ»¯ÎËüÃǵĻ¯Ñ§ÐÔÖʾßÓÐÒ»¶¨µÄÏàËÆÐÔ£»MgºÍNaµÄ»¯Ñ§ÐÔÖÊÒ²¾ßÓÐÒ»¶¨ÏàËÆÐÔ¡£
ijÐËȤС×éÓÃÈçͼËùʾװÖýøÐÐMgÓëSO2·´Ó¦µÄʵÑé¡£
(1)Ñ¡ÔñÖÆÈ¡SO2µÄºÏÊÊÊÔ¼Á________(Ìî±àºÅ)¡£
¢ÙŨHCl¡¡¢ÚŨH2SO4¡¡¢ÛNa2SO3¹ÌÌå¡¡¢ÜCaSO3¹ÌÌå
(2)ÉÏÊö×°Öû¹¿ÉÓÅ»¯£¬ÓÅ»¯µÄ·½·¨ÊÇ________________________________________£¬×°ÖÃCÖÐNaOHÈÜÒºµÄ×÷ÓÃÊÇ___________________________________________________________
(3)¼×ͬѧÍƲâMgÓëSO2µÄ·´Ó¦ºÍMgÓëCO2µÄ·´Ó¦ÏàËÆ£¬Ôò¸Ã·´Ó¦·½³ÌʽΪ_________________________________________£»
ÒÒͬѧµÄÍƲâÊÇ£º2Mg£«3SO22MgSO3£«S£»±ûͬѧµÄÍƲâÊÇ£º3Mg£«SO22MgO£«MgS£¬ÒªÑéÖ¤¼×¡¢ÒÒ¡¢±ûÈýλͬѧµÄÍƲâÊÇ·ñÕýÈ·£¬¶¡Í¬Ñ§×÷ÈçÏÂʵÑé̽¾¿£º
ÒÑÖª£ºMgSO3ºÍMgS¶¼Î¢ÈÜÓÚË®£¬ÄÜÓëÑÎËá·¢Éú¸´·Ö½â·´Ó¦·Å³öÆøÌ壻H2SÆøÌåͨÈëCuSO4ÈÜÒºÖгöÏÖºÚÉ«³Áµí¡£
ÏÞÑ¡ÊÔ¼Á£º2 mol¡¤L£1ÑÎËá¡¢2 mol¡¤L£1ÏõËá¡¢ÕôÁóË®¡¢2 mol¡¤L£1 NaOHÈÜÒº¡¢Æ·ºìÈÜÒº¡¢³ÎÇåʯ»ÒË®¡¢2 mol¡¤L£1 CuSO4ÈÜÒº£»ÒÇÆ÷ºÍÓÃÆ·×ÔÑ¡¡£
ÐòºÅ | ʵÑé²½Öè | Ô¤ÆÚÏÖÏóºÍ½áÂÛ |
¢Ù | È¡ÉÙÁ¿·´Ó¦ºóËùµÃ¹ÌÌåÓÚÊÔ¹ÜÖÐ | |
¢Ú | ÏòÊÔ¹ÜÖеĹÌÌåÂýÂýµÎ¼Ó____________£¬ÊԹܿÚÈûÉÏ´øµ¼¹ÜµÄµ¥¿×Èû£¬²¢½«µ¼¹ÜͨÈëÊ¢ÓÐ________µÄÊÔ¹ÜÖÐ | ÈôÊÔ¹ÜÖеÄ________£¬Ôò±ûͬѧÍƲâÕýÈ·£¬ÈôÊÔ¹ÜÖеĹÌÌåδÍêÈ«Èܽ⣬ÇÒ________£¬ÔòÒÒͬѧÍƲâÕýÈ· |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
ÑÇÂÈËáÄÆ£¨NaClO2£©ÊÇÒ»ÖÖ¸ßЧÑõ»¯¼Á¡¢Æ¯°×¼Á¡£ÒÑÖª£ºNaClO2±¥ºÍÈÜÒºÔÚζȵÍÓÚ38¡æʱÎö³öµÄ¾§ÌåÊÇNaClO2¡¤3H2O£¬¸ßÓÚ38¡æʱÎö³ö¾§ÌåÊÇNaClO2£¬¸ßÓÚ60¡æʱNaClO2·Ö½â³ÉNaClO3ºÍNaCl¡£ÀûÓÃÏÂͼËùʾװÖÃÖƱ¸ÑÇÂÈËáÄÆ¡£
Íê³ÉÏÂÁÐÌî¿Õ£º
£¨1£©×°ÖâÚÖвúÉúClO2µÄ»¯Ñ§·½³ÌʽΪ ¡£×°Öâ۵Ä×÷ÓÃÊÇ ¡£
£¨2£©´Ó×°Öâܷ´Ó¦ºóµÄÈÜÒº»ñµÃNaClO2¾§ÌåµÄ²Ù×÷²½ÖèΪ£º
¢Ù¼õѹ£¬55¡æÕô·¢½á¾§£»¢Ú £»¢Û £»¢ÜµÍÓÚ60¡æ¸ÉÔµÃµ½³ÉÆ·¡£
£¨3£©×¼È·³ÆÈ¡ËùµÃÑÇÂÈËáÄÆÑùÆ·10gÓÚÉÕ±ÖУ¬¼ÓÈëÊÊÁ¿ÕôÁóË®ºÍ¹ýÁ¿µÄµâ»¯¼Ø¾§Ì壬ÔÙµÎÈëÊÊÁ¿µÄÏ¡ÁòËᣬ³ä·Ö·´Ó¦£¨ClO2£+ 4I£+4H+ ¡ú2H2O+2I2+Cl££©¡£½«ËùµÃ»ìºÏÒºÅä³É250mL´ý²âÈÜÒº¡£ÅäÖÆ´ý²âÒºÐèÓõ½µÄ¶¨Á¿²£Á§ÒÇÆ÷ÊÇ £»
£¨4£©È¡25.00mL´ý²âÒº£¬ÓÃ2.0 mol/L Na2S2O3±ê×¼ÒºµÎ¶¨£¨I2 +2S2O32£¡ú2I£+S4O62££©£¬ÒÔµí·ÛÈÜÒº×öָʾ¼Á£¬´ïµ½µÎ¶¨ÖÕµãʱµÄÏÖÏóΪ ¡£Öظ´µÎ¶¨2´Î£¬²âµÃNa2S2O3ÈÜҺƽ¾ùֵΪ20.00 mL¡£¸ÃÑùÆ·ÖÐNaClO2µÄÖÊÁ¿·ÖÊýΪ ¡£
£¨5£©Í¨¹ý·ÖÎö˵Ã÷×°ÖâÙÔÚ±¾ÊµÑéÖеÄ×÷Óà ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
º£ÑóÖ²ÎïÈ纣´ø¡¢º£ÔåÖк¬ÓзḻµÄµâÔªËØ£¬µâÔªËØÒÔµâÀë×ÓµÄÐÎʽ´æÔÚ¡£ÊµÑéÊÒÀï´Óº£ÔåÖÐÌáÈ¡µâµÄÁ÷³ÌÈçÏ£º
£¨1£©Ö¸³ö²Ù×÷¢ÛµÄÃû³Æ£º £»²Ù×÷¢ÚÖгäÈëÊÊÁ¿Cl2µÄÄ¿µÄÊÇ ¡£
£¨2£©ÌáÈ¡µâµÄ¹ý³ÌÖУ¬¿É¹©Ñ¡ÔñµÄÊÔ¼ÁÊÇ ( )
A£®¾Æ¾« | B£®ËÄÂÈ»¯Ì¼ | C£®ÆûÓÍ | D£®´×Ëá |
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com