ÔÚÈçͼÓÃʯī×÷µç¼«µÄµç½â³ØÖУ¬·ÅÈë500mLº¬Ò»ÖÖÈÜÖʵÄijÀ¶É«ÁòËáÑÎÈÜÒº½øÐеç½â£¬¹Û²ìµ½Aµç¼«±íÃæÓкìÉ«µÄ¹Ì̬ÎïÖÊÉú³É£¬Bµç¼«ÓÐÎÞÉ«ÆøÌåÉú³É¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Çëд³öB¼«°åµÄÃû³Æ£º            µç¼«·´Ó¦Ê½           
д³öµç½âʱ·´Ó¦µÄ×ÜÀë×Ó·½³Ìʽ                          
£¨2£©Èôµ±ÈÜÒºÖеÄÔ­ÓÐÈÜÖÊÍêÈ«µç½âºó£¬Í£Ö¹µç½â£¬È¡³öAµç¼«£¬Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿¡¢µç¼«ÔöÖØ1.6g¡£µç½âºóÈÜÒºµÄpHΪ          £»ÒªÊ¹µç½âºóÈÜÒº»Ö¸´µ½µç½âÇ°µÄ״̬£¬ÔòÐè¼ÓÈë       £¬ÆäÖÊÁ¿Îª         g¡££¨¼ÙÉèµç½âÇ°ºóÈÜÒºµÄÌå»ý²»±ä£©
£¨3£©ÈôÔ­ÈÜҺΪ1L  K2SO4¡¢CuSO4µÄ»ìºÏÈÜÒº£¬ÇÒc£¨SO42-£©=" 2.0mol/L" £»ÈçͼװÖõç½â£¬µ±Á½¼«¶¼ÊÕ¼¯µ½22.4LÆøÌ壨±ê×¼×´¿ö£©Ê±£¬Í£Ö¹µç½â¡£
ÔòÔ­ÈÜÒºÖеÄc(K+)£½                              
£¨1£©Ñô¼«£¨2·Ö£©4OH-- 4e-=2H2O+O2 ¡ü£¨2·Ö£©¡¢

µç½â

 
 


2Cu2+ +2H2O  =" " 2Cu +O2 ¡ü+ 4H+£¨2·Ö£©
£¨2£©PH=1£¨2·Ö£©  CuO £¨2·Ö£©; 2¿Ë£¨2·Ö£©  £¨»òCuCO3  3.1 £©
£¨3£© c£¨K+£©="2mol/L    " £¨3·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÓÃʯī×÷µç¼«µç½âÈÜҺʱ£¬Í¼12-5ËùʾµÄµç½â±ä»¯ÇúÏߺÏÀíµÄÊÇ
A£®¢Ù¢ÜB£®¢Ú¢ÜC£®¢Ú¢ÛD£®¢Ù¢Û

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁйØÓÚµç½â²ÛµÄÐðÊöÖÐÕýÈ·µÄÊÇ£¨   £©
A£®ÓëµçÔ´Õý¼«ÏàÁ¬µÄÊǵç½â²ÛµÄÒõ¼«¡£B£®ÓëµçÔ´¸º¼«ÏàÁ¬µÄÊǵç½â²ÛµÄ¸º¼«¡£
C£®µç½â²ÛµÄÑô¼«·¢Éú»¹Ô­·´Ó¦¡£D£®µç×Ó´ÓµçÔ´µÄ¸º¼«Ñص¼ÏßÁ÷Èëµç½â²ÛµÄÒõ¼«¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨12·Ö£©±±¾©2008Äê°ÂÔË»á½ðÅÆÖ±¾¶Îª70 mm£¬ºñ6 mm¡£½±ÅÆÕýÃæΪ²åÉϳá°òÕ¾Á¢µÄÏ£À°Ê¤ÀûÅ®ÉñºÍÏ£À°ÅËÄÉÐÁÄɿƾº¼¼³¡¡£½±ÅƱ³ÃæÏâǶ×ÅÈ¡×ÔÖйú¹Å´úÁúÎÆÓñèµÔìÐ͵ÄÓñ赡£
£¨1£©»·ÐÎÓñèµÓÉ°×ÓñÖƳɡ£°×ÓñµÄ»¯Ñ§³É·Ö¿É¼òµ¥¿´×÷ÊÇCa2Mg5Si8O22£¨OH£©2£¬½«Æä¸Äд³ÉÑõ»¯ÎïµÄÐÎʽΪ________________¡£
£¨2£©Îª²â¶¨½ðÅƵÄ×é³É£¬½«Ä³È¥µô°×ÓñµÄ½ðÅÆÑùÆ·£¬Í¶Èëµ½¹ýÁ¿Ï¡ÏõËáÖУ¬ÓÐÎÞÉ«ÆøÌå²úÉú£¬µ±²»ÔÙÉú³ÉÆøÌåʱ£¬½ðÅƲÐÁôÒ»½ð»ÆÉ«Íâ¿Ç£»½«Éú³ÉµÄÆøÌåÓë11.2 L O2£¨±ê×¼×´¿ö£©»ìºÏ¼´³Êºì×ØÉ«£¬×îºó½«ÆäͨÈëË®ÖУ¬ËùÓÐÆøÌåÍêÈ«±»Ë®ÎüÊÕÉú³ÉÏõË᣻ÔÙÏò½ðÅÆÈܽâËùµÃµÄÈÜÒºÖеμÓÂÈ»¯ÄÆ£¬Á¢¼´²úÉú°×É«³Áµí£»×îºó½«²Ð¿ÇͶÈëµ½ÍõË®ÖУ¬Ëæ¼´Èܽ⣬Éú³ÉÆøÌåµÄÌå»ýΪ1.344 L£¨±ê×¼×´¿ö£©¡£ÒÑÖª£ºAu£«HNO3£«4HCl===H[AuCl4]£«NO¡ü£«2H2O¡£
¢Ù¸Ã½ðÅÆËùº¬»Æ½ðÖÊÁ¿Îª________¡£
¢Ú¸Ã½ðÅƳýº¬»Æ½ðÍ⻹º¬ÓÐÁíÒ»½ðÊôÊÇ________£¨ÌîÔªËØ·ûºÅ£©£¬ÆäÖÊÁ¿Îª________¡£
£¨3£©»Æ½ð³ýÄÜÈÜÓÚÍõË®Í⻹ÄÜÈÜÓÚÇ軯¼Ø£¬·´Ó¦·½³ÌʽÈçÏ£º

¢ÙÅäƽ¸Ã·´Ó¦£¬²¢½«¼ÆÁ¿ÊýÌîÈë·½¿òÄÚ¡£
¢ÚK[Au£¨CN£©2]¿É×÷Ϊµç¶Æ½ðµÄµç¶ÆÒº£¬½ðÅƱíÃæµÄ»Æ½ð¾ÍÊÇͨ¹ýµç¶Æ¶ÆÉϵġ£ÔÚµç¶Æ½ðÅÆʱ£¬Òõ¼«·´Ó¦Ê½Îª________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©(1998ÄêÉϺ£)Âȼµç½â±¥ºÍʳÑÎË®ÖÆÈ¡NaOHµÄ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏÂ

ÒÀ¾ÝÉÏͼ£¬Íê³ÉÏÂÁÐÌî¿Õ£º
(1)ÔÚµç½â¹ý³ÌÖУ¬ÓëµçÔ´Õý¼«ÏàÁ¬µÄµç¼«ÉÏËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ              £¬ÓëµçÔ´¸º¼«ÏàÁ¬µÄµç¼«¸½½ü£¬ÈÜÒºpH             (Ñ¡Ìî¡°²»±ä¡±¡°Éý¸ß¡±»ò¡°Ï½µ¡±)¡£
(2)¹¤ÒµÊ³Ñκ¬Ca2+¡¢Mg2+µÈÔÓÖÊ¡£¾«Öƹý³Ì·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ
                                ¡¢                                    ¡£
(3)Èç¹û´ÖÑÎÖÐSO42-º¬Á¿½Ï¸ß£¬±ØÐëÌí¼Ó±µÊÔ¼Á³ýÈ¥SO42-£¬¸Ã±µÊÔ¼Á¿ÉÒÔ
ÊÇ          (Ñ¡Ìîa£¬b£¬c¶àÑ¡¿Û·Ö)¡£
a£®Ba(OH)2        b£®Ba(NO3)2        c£®BaCl2
(4)ΪÓÐЧ³ýÈ¥Ca2+¡¢Mg2+¡¢SO42¡ª£¬¼ÓÈëÊÔ¼ÁµÄºÏÀí˳ÐòΪ      (Ñ¡Ìîa¡¢b¡¢c¶àÑ¡¿Û·Ö)
a£®ÏȼÓNaOH,ºó¼ÓNa2CO3£¬ÔÙ¼Ó±µÊÔ¼Á
b£®ÏȼÓNaOH£¬ºó¼Ó±µÊÔ¼Á£¬ÔÙ¼ÓNa2CO3
c£®ÏȼӱµÊÔ¼Á£¬ºó¼ÓNaOH£¬ÔÙ¼ÓNa2CO3
(5)ÍÑÑι¤ÐòÖÐÀûÓÃNaOHºÍNaClÔÚÈܽâ¶ÈÉϵIJîÒ죬ͨ¹ý      ¡¢ÀäÈ´¡¢              (Ìîд²Ù×÷Ãû³Æ)³ýÈ¥NaCl
(6)ÔÚ¸ôĤ·¨µç½âʳÑÎˮʱ£¬µç½â²Û·Ö¸ôΪÑô¼«ÇøºÍÒõ¼«Çø£¬·ÀÖ¹Cl2ÓëNaOH·´Ó¦£»²ÉÓÃÎÞ¸ôĤµç½âÀäµÄʳÑÎˮʱ£¬Cl2ÓëNaOH³ä·Ö½Ó´¥£¬²úÎï½öÊÇNaClOºÍH2£¬ÏàÓ¦µÄ»¯Ñ§·½³ÌʽΪ                                                           ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨¹²6·Ö,ÿ¿Õ2·Ö£©£®´ÓH+¡¢Cu2+¡¢Na+¡¢SO42£­¡¢Cl£­µÈÎåÖÖÀë×ÓÖÐÑ¡ÔñÊʵ±µÄÀë×Ó×é³Éµç½âÖÊ£¬Ê¹Ö®·ûºÏÏÂÁÐÒªÇó¡£
£¨1£©ÒÔ̼°ôΪµç¼«£¬µç½âʱµç½âÖÊÖÊÁ¿¼õС£¬Ë®Á¿²»±ä£¬Ó¦Ñ¡Óõĵç½âÖÊÊÇ________________________________£»
£¨2£©ÒÔ̼°ôΪµç¼«£¬µç½âʱµç½âÖÊÖÊÁ¿²»±ä£¬Ë®Á¿¼õÉÙ£¬Ó¦Ñ¡Óõĵç½âÖÊÊÇ________________________________£»
£¨3£©ÒÔ̼°ôΪÑô¼«£¬Ìú°ôΪÒõ¼«£¬µç½âʱµç½âÖÊÖÊÁ¿ºÍË®Á¿¶¼¼õÉÙ£¬ÔòӦѡÓõĵç½âÖÊÊÇ_________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁи÷ÏîÖеÄÎïÖÊÄܵ¼µçÇÒÊôÓÚÇ¿µç½âÖʵÄÊÇ                      £¨   £©
A£®¹Ì̬ÂÈ»¯ÄÆB£®ÈÛÈÚ״̬µÄÂÈ»¯Ã¾
C£®°±Ë®D£®±ù´×Ëá

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÓöèÐԵ缫µç½âÂÈ»¯Í­ÈÜÒº£¬·´Ó¦¿ªÊ¼Ê±Òõ¼«ºÍÑô¼«ÉÏ·Ö±ðÎö³öµÄÎïÖÊÊÇ£¨ £©
A£®H2ºÍCl2B£®CuºÍO2
C£®CuºÍCl2D£®H2ºÍO2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÓйػ¯Ñ§·´Ó¦Ô­ÀíµÄÓ¦ÓÃÐðÊöÕýÈ·µÄÊÇ                                           £¨   £©
A£®ÓÃÃ÷·¯¾»Ë®ÊÇÒòΪAl2+Ë®½âÉú³ÉµÄAl£¨OH£©3½ºÁ£¾ßÓкÜÇ¿µÄÎü¸½ÐÔ
B£®ºÏ³É°±Éú³É¹ý³ÌÖУ¬²ÉÓøßθßѹ¶¼ÊÇΪÁËÌá¸ßN2¡¢H2ת»¯ÂÊ
C£®ÍùÌú¶¤¶Æͭʱ£¬ÓÃÍ­×öÒõ¼«
D£®µç½â±¥ºÍʳÑÎË®ÖÆÉռNaOHÔÚÑô¼«ÇøÓò²úÉú

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸