Question

20£®Æ¯·Û¾«ÊÇÒ»ÖÖ³£ÓõÄÏû¶¾¼Á£¬¹¤ÒµÉϽ«ÂÈÆøͨÈëʯ»ÒÈé[Ca£¨OH£©₂]ÖÆȡƯ·Û¾«£®
£¨1£©Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º2Cl₂+2Ca£¨OH£©₂=CaCl₂+Ca£¨ClO£©₂+2H₂O£®
£¨2£©Æ¯·Û¾«ÈÜÓÚË®ºó£¬ÊÜ¿ÕÆøÖеÄCO₂×÷Ó㬼´²úÉúÓÐƯ°×¡¢É±¾ú×÷ÓõÄijÖÖÎïÖÊ£¬¸Ã»¯Ñ§·´Ó¦·½³ÌʽΪCa£¨ClO£©₂+CO₂+H₂O=CaCO₃¡ý+2HClO£®
£¨3£©Å¨ÑÎËáºÍ´ÎÂÈËá¸ÆÄÜ·¢ÉúÈçÏ·´Ó¦£ºCa£¨ClO£©₂+4HCl£¨Å¨£©=CaCl₂+2Cl₂¡ü+2H₂O£®ÓþÃÖõÄƯ·Û¾«ºÍŨÑÎËá·´Ó¦ÖƵÃÆøÌåÖпÉÄܺ¬Óл¯ºÏÎд³ö¸Ã¸Ã½áºÏÎïµç×ÓʽÓë½á¹¹Ê½¡¢O=C=O£®

Answer 1

·ÖÎö £¨1£©ÂÈÆøͨÈëʯ»ÒÈé[Ca£¨OH£©₂]ÖÆȡƯ·Û¾«µÄ·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢´ÎÂÈËá¸Æ¡¢Ë®£»
£¨2£©Æ¯·Û¾«ÈÜÓÚË®ºó£¬ÊÜ¿ÕÆøÖеÄCO₂×÷Ó㬼´²úÉúÓÐƯ°×¡¢É±¾ú×÷ÓõĴÎÂÈË᣻
£¨3£©Öü´æºÜ¾ÃµÄƯ°×·Û¿ÉÄܺ¬Ì¼Ëá¸Æ£¬ºÍŨÑÎËá·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌ壬CO₂Êǹ²¼Û»¯ºÏÎ̼ԭ×ÓºÍÑõÔ­×ÓÖ®¼äÓÐ2¶Ô¹²Óõç×Ó¶Ô£®

½â´ð ½â£º£¨1£©¹¤ÒµÉϽ«ÂÈÆøͨÈëʯ»ÒÈé[Ca£¨OH£©₂]ÖÆȡƯ·Û¾«£¬»¯Ñ§·´Ó¦·½³ÌʽΪ£º2Cl₂+2Ca£¨OH£©₂=CaCl₂+Ca£¨ClO£©₂+2H₂O£¬
¹Ê´ð°¸Îª£º2Cl₂+2Ca£¨OH£©₂=CaCl₂+Ca£¨ClO£©₂+2H₂O£»
£¨2£©Æ¯·Û¾«ÈÜÓÚË®ºó£¬ÊÜ¿ÕÆøÖеÄCO₂×÷Ó㬼´²úÉúÓÐƯ°×¡¢É±¾ú×÷ÓõÄijÖÖÎïÖÊΪ´ÎÂÈËᣬ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCa£¨ClO£©₂+CO₂+H₂O=CaCO₃¡ý+2HClO£»
¹Ê´ð°¸Îª£ºCa£¨ClO£©₂+CO₂+H₂O=CaCO₃¡ý+2HClO£»
£¨3£©¾ÃÖõÄƯ·Û¾«ÊÇ´ÎÂÈËá¸ÆºÍ¿ÕÆøÖжþÑõ»¯Ì¼¡¢Ë®ÕôÆø·´Ó¦Éú³ÉÁË̼Ëá¸Æ£¬ÓþÃÖõÄƯ·Û¾«ºÍŨÑÎËá·´Ó¦ÖƵÃÆøÌåÖпÉÄܺ¬Óл¯ºÏÎïCO₂£¬CO₂Êǹ²¼Û»¯ºÏÎ̼ԭ×ÓºÍÑõÔ­×ÓÖ®¼äÓÐ2¶Ô¹²Óõç×Ó¶Ô£¬Æäµç×ÓʽΪ£¬½á¹¹Ê½Îª£ºO=C=O£¬
¹Ê´ð°¸Îª£º£»O=C=O£»

µãÆÀ ±¾Ì⿼²éÁËÂÈÆø¼°Æ仯ºÏÎïµÄÐÔÖÊÓ¦Óã¬Ö÷Òª¿¼²é»¯Ñ§·½³ÌʽµÄÊéдºÍ·´Ó¦Ô­ÀíµÄÀí½â£¬ÌâÄ¿ÄѶÈÖеȣ®