(10·Ö)ͨ³£ÈËÃǰѲð¿ª1mol ij»¯Ñ§¼üËùÎüÊÕµÄÄÜÁ¿¿´³É¸Ã»¯Ñ§¼üµÄ¼üÄÜ¡£¼üÄܵĴóС¿ÉÓÃÓÚ¹ÀË㻯ѧ·´Ó¦µÄ·´Ó¦ÈÈ£¨¡÷H£©¡£
»¯Ñ§¼ü
Cl£­Cl
H¡ªH
H¡ªCl
N¡ÔN
¼üÄÜ/kJ¡¤mol
243
436
431
946
£¨1£©°´ÒªÇóÍê³ÉÌî¿Õ
a  2HCl(g) £½ H2(g)£«Cl2(g)£»¡÷H=                      
b N2 (g)+3H2(g)= 2NH3(g)  ¦¤H="-92" kJ/mol£¬ÔòN¡ªH¼üµÄ¼üÄÜÊÇ          kJ¡¤mol
£¨2£©1 mol NO2ºÍ1mol CO·´Ó¦Éú³ÉCO2ºÍNO¹ý³ÌÖÐÄÜÁ¿±ä»¯Ê¾Òâͼ£¬Çëд³öNO2ºÍCO·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ                                    

£¨3£© ÒÑÖªÔÚ³£Î³£Ñ¹Ï£º
¢Ù 2CH3OH(l) £« 3O2(g) £½ 2CO2(g) £« 4H2O(g) ¦¤H1
¢Ú 2CO (g)+ O2(g) £½ 2CO2(g) ¦¤H2
¢Û H2O(g) £½ H2O(l)  ¦¤H3
ÔòCH3OH(l)£«O2(g)=" CO(g)" + 2H2O(l)¦¤H =          £¨Óú¬¦¤H1¡¢¦¤H2¡¢¦¤H3µÄʽ×Ó±íʾ£©
(4)ÒÑÖª£º2Al (s)+ 3/2O2£¨g£©==Al2O3(s)  ¡÷H=" -1" 644.3 kJ? mol-1
2Fe (s) +3/2O2£¨g£©==Fe2O3(s)  ¡÷H=" -815.88" kJ? mol-1
ÊÔд³öÂÁ·ÛÓëÑõ»¯Ìú·ÛÄ©·¢ÉúÂÁÈÈ·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ_______________________¡£
£¨1£©¡÷H ="+183" kJ/mol £¨2·Ö£©    391£¨2·Ö£©
£¨2£©NO2(g) + CO(g) = CO2(g) + NO(g) ¡÷H =" -" 234kJ¡¤mol-1£¨2·Ö£©
£¨3£©1/2¦¤H1-1/2/¦¤H2+2¦¤H3£¨2·Ö£©
£¨4£©2Al (s) + Fe2O3(s) === Al2O3(s) +2Fe (s) ¡÷H=" -828.42" kJ mol-1£¨2·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨4·Ö£©
ÒÑÖªÏÂÁÐÁ½¸öÈÈ»¯Ñ§·½³Ìʽ£º
H2£¨g£©£«O2£¨g£©====H2O£¨l£©¡÷H£½£­285kJ¡¤mol£­1
C3H8£¨g£©£«5O2£¨g£©====3CO2£¨g£©£«4H2O£¨l£©¡÷H£½£­2220.0kJ¡¤mol£­1
£¨1£©ÊµÑé²âµÃH2ºÍC3 H8µÄ»ìºÏÆøÌå¹²5 mol£¬ÍêȫȼÉÕÉú³ÉҺ̬ˮʱ·ÅÈÈ6262.5kJ£¬Ôò»ìºÏÆøÌåÖÐH2ºÍC3 H8µÄÌå»ý±ÈÊÇ_______£»
£¨2£©ÒÑÖª£ºH2O£¨l£©====H2O£¨g£© ¡÷H£½£«44.0kJ¡¤mol£­1£¬Ð´³ö±ûÍéȼÉÕÉú³ÉCO2ºÍÆø̬ˮµÄÈÈ»¯Ñ§·½³Ìʽ_________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁз´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º£¨1£©C(s)£«O2(g)£½CO2(g) £»¦¤H 1£½£­393.5kJ/mol 
£¨2£©CH3COOH£¨l£©£«2O2£¨g£©£½2CO2(g)£«2H2O(l) £»¦¤H 2£½£­870.3kJ/mol
£¨3£©H2(g)£«O2(g)£½H2O(l) £»¦¤H 3£½£­285.8kJ/mol 
Ôò·´Ó¦2C(s)£«2H2(g)£«O2(g)£½CH3COOH(l) µÄ¦¤HΪ£¨  £©
A£®488.3 kJ/molB£®£­488.3 kJ/molC£®£­244.15 kJ/molD£®244.15 kJ/mol

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

10 gÁò»ÇÔÚ O2ÖÐÍêȫȼÉÕÉú³ÉÆø̬SO2£¬·Å³öµÄÈÈÁ¿ÄÜʹ 500 g H2OζÈÓÉ18¡æÉýÖÁ62.4¡æ£¬ÔòÁò»ÇµÄȼÉÕÈÈΪ                                  £¬ÈÈ»¯Ñ§·½³ÌʽΪ                                            ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º
¢ÙCaCO3(s)===CaO£«CO2(g)¡¡¦¤H£½177.7 kJ
¢ÚC(s)£«H2O(s)===CO(g)£«H2(g)    ¦¤H£½£­131.3 kJ/mol
¢ÛH2SO4(l)£«NaOH(l)===Na2SO4(l)£«H2O(l)  ¦¤H£½£­57.3 kJ/mol
¢ÜC(s)£«O2(g)===CO2(g)¡¡¦¤H£½£­393.5 kJ/mol
¢ÝCO(g)£«O2(g)===CO2(g)¡¡¦¤H£½£­283 kJ/mol
¢ÞHNO3(aq)£«NaOH(aq)===NaNO3(aq)£«H2O(l)   ¦¤H£½£­57.3 kJ/mol
¢ß2H2(g)£«O2(g)===2H2O(l)¡¡¦¤H£½£­517.6 kJ/mol
(1)ÉÏÊöÈÈ»¯Ñ§·½³ÌʽÖУ¬²»ÕýÈ·µÄÓÐ______________£¬²»ÕýÈ·µÄÀíÓÉ·Ö±ðÊÇ________
(2)¸ù¾ÝÉÏÊöÐÅÏ¢£¬Ð´³öCת»¯ÎªCOµÄÈÈ»¯Ñ§·½³Ìʽ£º      ¡£
(3)ÉÏÊö·´Ó¦ÖУ¬±íʾȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽÓР         £»
±íʾÖкÍÈȵÄÈÈ»¯Ñ§·½³ÌʽÓÐ______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨2·Ö£©°×Á×£¨P4£©ÊÇÕýËÄÃæÌå¹¹Ð͵ķÖ×Ó£¬µ±ÓëÑõÆø×÷ÓÃÐγÉP4O10ʱ£¬Ã¿Á½¸öÁ×Ô­×ÓÖ®¼ä²åÈëÒ»¸öÑõÔ­×Ó£¬´ËÍ⣬ÿ¸öÁ×Ô­×ÓÓÖÒÔË«¼üÔÙ½áºÏÒ»¸öÑõÔ­×Ó¡£»¯Ñ§·´Ó¦¿ÉÊÓΪ¾É¼ü¶ÏÁѺÍмüÐγɵĹý³Ì¡£ÏÖÌṩÒÔÏ»¯Ñ§¼üµÄ¼üÄÜ£¨kJ/mol£©¡£P-P¼ü£º198 kJ /mol £»P-O¼ü£º360 kJ /mol £»O=O¼ü£º498 kJ /mol £»P=O¼ü£º585 kJ /mol¡£ÊÔ¸ù¾ÝÕâЩÊý¾Ý£¬¼ÆËã³öÒÔÏ·´Ó¦µÄ·´Ó¦ÈÈ£ºP4£¨S£¬°×Á×£©+ 5O2£¨g£©= P4O10£¨s£©£»
¦¤H=                                                                     ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨4·Ö£©ÒÑÖªÏÂÁз´Ó¦µÄ·´Ó¦ÈÈ:
¢ÙCH3COOH(l)£«2O2(g)£½2CO2(g)£«2H2O(l)   ¡÷H£½£­870.3kJ¨Mmol
¢ÚC(S)£«O2(g)£½CO2(g)                    ¡÷H£½£­393.5kJ¨Mmol
¢Û2C(S)£«2H2(g)£«O2(g)£½CH3COOH(l)       ¡÷H£½£­488.3kJ¨Mmol
Çëд³öH2ȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ                                        ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

½º×´ÒºÇ⣨Ö÷Òª³É·ÖÊÇH2ºÍCH4£©ÓÐÍûÓÃÓÚδÀ´µÄÔËÔØ»ð¼ýºÍ¿Õ¼äÔËÊäϵͳ¡£ÊµÑé²âµÃ101 kPaʱ£¬lmol H2ÍêȫȼÉÕÉú³ÉҺ̬ˮ£¬·Å³ö285£®8kJµÄÈÈÁ¿£»1 mol CH4ÍêȫȼÉÕÉú³ÉҺ̬ˮºÍCO2ÆøÌ壬·Å³ö890£®3kJµÄÈÈÁ¿¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ                           £¨   £©
A£®2H2£¨g£©+ O2£¨g£©=2H2O£¨1£©£»¡÷H=-285£®8kJ£¯mol
B£®CH4£¨g£©+2 O2£¨g£©=CO2£¨g£©+2H2O£¨1£©£»¡÷H=-890£®3kJ£¯mol
C£®CH4£¨g£©+2 O2£¨g£©=CO2£¨g£©+2H2O£¨g£©£»¡÷H=-890£®3kJ£¯mol
D£®CH4£¨g£©+2O2£¨g£©=CO2£¨g£©+2H2O£¨1£©£»¡÷H=+890£®3kJ£¯mol

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

¸ù¾Ý¸Ç˹¶¨ÂÉÅжÏÏÂͼËùʾµÄÎïÖÊת±ä¹ý³ÌÖУ¬ÕýÈ·µÄµÈʽÊÇ
A£®¡÷H1=¡÷H2=¡÷H3=¡÷H4B£®¡÷H1+¡÷H2=¡÷H3+¡÷H4
C£®¡÷H1+¡÷H2+¡÷H3=¡÷H4D£®¡÷H1=¡÷H2+¡÷H3+¡÷H4

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸