(1)¾ßÓÐÖ§Á´µÄ»¯ºÏÎïAµÄ·Ö×ÓʽΪ£ºC4H6O2£¬A¿ÉÒÔʹBr2µÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«£®1 mol¡¡AºÍ1 mol¡¡NaHCO3ÄÜÍêÈ«·´Ó¦£¬ÔòAµÄ½á¹¹¼òʽÊÇ_________£®Ð´³öÓëA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º________£®

(2)»¯ºÏÎïBº¬ÓÐC¡¢H¡¢OÈýÖÖÔªËØ£®Ïà¶Ô·Ö×ÓÖÊÁ¿Îª60£¬ÆäÖÐ̼µÄÖÊÁ¿·ÖÊýΪ60.0£¥£¬ÇâµÄÖÊÁ¿·ÖÊýΪ13.3£¥£®BÔÚ´ß»¯¼ÁCuµÄ×÷ÓÃϱ»ÑõÆøÑõ»¯³ÉC£¬CÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÔòBµÄ½á¹¹¼òʽÊÇ________£®

(3)DÔÚÇâÑõ»¯ÄÆ(NaOH)Ë®ÈÜÒºÖмÓÈÈ·´Ó¦£¬¿ÉÉú³ÉAµÄÄÆÑκÍB£¬ÏàÓ¦·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_________£®

´ð°¸£º
½âÎö£º

¡¡¡¡´ð°¸£º(1)£»

¡¡¡¡CH2CH£­CH2£­COOH£¬

¡¡¡¡CH3£­CHCH£­COOH£»

¡¡¡¡(2)CH3CH2CH2OH£»

¡¡¡¡(3)

¡¡¡¡£®

¡¡¡¡Ë¼Â·½âÎö£º¸ÃÌâÐèҪ׼ȷÀí½âÌâÄ¿¸ø³öµÄ½á¹¹ÐÅÏ¢²¢½«ÕâЩÐÅÏ¢½øÐÐ×ۺϷÖÎö£®

¡¡¡¡(1)¸ù¾ÝÌâÒ⣬AÊÇÒ»¸ö4̼»¯ºÏÎÇÒÓÐÖ§Á´£¬ËùÒÔA±ØÐë¾ßÓÐÏÂÁÐ̼¼Ü£º£®ÓÖÒòΪAÄÜʹäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«£¬±íÃ÷AÓÐ̼̼˫¼ü£®1 mol¡¡AºÍ1 mol¡¡NaHCO3ÄÜÍêÈ«·´Ó¦£¬±íÃ÷AÖк¬ÓÐÒ»¸öôÈ»ù£®½«ÉÏÊöÐÅÏ¢×ÛºÏÆðÀ´£¬AµÄ½á¹¹¼òʽֻÄÜÊÇ£º

¡¡¡¡ÉÏÃæµÄ·ÖÎö±íÃ÷£ºÓëAÓÐÏàͬ¹ÙÄÜÍŵÄAµÄͬ·ÖÒì¹¹ÌåÖ»ÄÜÊÇÎÞÖ§Á´µÄ»¯ºÏÎÓÖÓÉÓÚôÈ»ùÖ»ÄÜ´¦ÓÚÁ´¶Ë£¬ËùÒÔÖ»ÓÐË«¼üµÄλÖÿÉÒԸı䣮×ÛÉÏËùÊö£¬Âú×ãÒªÇóµÄAµÄͬ·ÖÒì¹¹ÌåÖ»ÓÐÁ½ÖÖ£¬ËüÃÇÊÇ£ºCHCH£­CH2£­COOH

¡¡¡¡CH3£­CHCH£­COOH

¡¡¡¡(2)Ê×Ïȸù¾ÝBµÄÏà¶Ô·Ö×ÓÖÊÁ¿ºÍ×é³ÉÔªËØµÄÖÊÁ¿·ÖÊýÇó³öBµÄ·Ö×Óʽ£®

¡¡¡¡

¡¡¡¡BµÄ·Ö×Óʽ£ºC2H8O

¡¡¡¡ÔÙÒÀ¾ÝBC£¬CÓÖÄÜ·¢ÉúÒø¾µ·´Ó¦£¬¿ÉÒÔÍÆ¶ÏCÊÇÈ©£¬BÊÇ´¼£¬¶øÇÒ´¼ôÇ»ùÒ»¶¨Á¬ÔÚ¶Ë»ùµÄ̼ԭ×ÓÉÏ£®×ÛÉÏËùÊö£¬¿ÉÍÆ¶ÏBµÄ½á¹¹¼òʽΪ£ºCH3CH2CH2OH£®

¡¡¡¡(3)BÊDZû´¼£¬AµÄÄÆÑÎÊÇ£®DÔÚNaOHµÄË®ÈÜÒºÖмÓÈȲúÉúBºÍAµÄÄÆÑΣ®ÔòDÒ»¶¨ÊÇBºÍAÐγɵÄõ¥£¬¹ÊDµÄ½á¹¹¼òʽÊÇ£º

¡¡¡¡£®

¡¡¡¡ÏàÓ¦µÄ·´Ó¦·½³ÌʽΪ£º

¡¡¡¡


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(1)¾ßÓÐÖ§Á´µÄ»¯ºÏÎïAµÄ·Ö×ÓʽΪ£ºC4H6O2£¬A¿ÉÒÔʹBr2µÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«¡£1 mol AºÍ1 mol NaHCO3ÄÜÍêÈ«·´Ó¦£¬ÔòAµÄ½á¹¹¼òʽÊÇ____________¡£Ð´³öÓëA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º_______________________________¡£

(2)»¯ºÏÎïBº¬ÓÐC¡¢H¡¢OÈýÖÖÔªËØ¡£Ïà¶Ô·Ö×ÓÖÊÁ¿Îª60£¬ÆäÖÐ̼µÄÖÊÁ¿·ÖÊýΪ60.0%£¬ÇâµÄÖÊÁ¿·ÖÊýΪ13.3%¡£BÔÚ´ß»¯¼ÁCuµÄ×÷ÓÃϱ»ÑõÆøÑõ»¯³ÉC£¬CÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÔòBµÄ½á¹¹¼òʽÊÇ_______________________________________________¡£

(3)DÔÚÇâÑõ»¯ÄÆ(NaOH)Ë®ÈÜÒºÖмÓÈÈ·´Ó¦£¬¿ÉÉú³ÉAµÄÄÆÑκÍB£¬ÏàÓ¦·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(1)¾ßÓÐÖ§Á´µÄ»¯ºÏÎïAµÄ·Ö×ÓʽΪC4H6O2£¬A¿ÉÒÔʹBr2µÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«¡£1 mol AºÍ1 mol NaHCO3ÄÜÍêÈ«·´Ó¦£¬ÔòAµÄ½á¹¹¼òʽÊÇ_______________¡£Ð´³öÓëA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄAµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ_______________¡£

(2)»¯ºÏÎïBº¬ÓÐC¡¢H¡¢OÈýÖÖÔªËØ£¬Ïà¶Ô·Ö×ÓÖÊÁ¿Îª60£¬ÆäÖÐ̼µÄÖÊÁ¿·ÖÊýΪ60%£¬ÇâµÄÖÊÁ¿·ÖÊýΪ13.3%£¬BÔÚ´ß»¯¼ÁCuµÄ×÷ÓÃϱ»Ñõ»¯³ÉC£¬CÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÔòBµÄ½á¹¹¼òʽÊÇ____________¡£

(3)DÔÚNaOHË®ÈÜÒºÖмÓÈÈ·´Ó¦£¬¿ÉÉú³ÉAµÄÄÆÑκÍB£¬ÏàÓ¦·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(14·Ö)

1.¾ßÓÐÖ§Á´µÄ»¯ºÏÎïAµÄ·Ö×ÓʽΪC4H6O2£¬A¿ÉÒÔʹäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÍËÉ«¡£1 mol AºÍ1 mol NaHCO3ÄÜÍêÈ«·´Ó¦£¬ÔòAµÄ½á¹¹¼òÊÇ                          ¡£

д³öÓëA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄAµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ                        ¡¢

                          ¡£

2.»¯ºÏÎïBº¬ÓÐC¡¢H¡¢OÈýÖÖÔªËØ£¬Ïà¶Ô·Ö×ÓÖÊÁ¿Îª60£¬ÆäÖÐ̼µÄÖÊÁ¿·ÖÊýΪ60%£¬ÇâµÄÖÊÁ¿·ÖÊýΪ13.3%¡£BÔÚCuµÄ´ß»¯×÷ÓÃϱ»ÑõÆøÑõ»¯³ÉC£¬CÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÔòBµÄ½á¹¹¼òʽÊÇ                    ¡£ÎïÖÊBµÄºË´Å¹²ÕñÇâÆ×£¨NMR£©»á²úÉú        ¸öÎüÊշ壬·åÖµ±ÈÀýΪ            ¡£

3.DÊÇÓÉAºÍB·´Ó¦Éú³ÉµÄõ¥£¬ÏàÓ¦·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ________________________

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê¸ÊËàÊ¡À¼ÖÝÒ»ÖиßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£© (1)¾ßÓÐÖ§Á´µÄ»¯ºÏÎïAµÄ·Ö×ÓʽΪC4H6O2£¬A¿ÉÒÔʹBr2µÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«¡£1molAºÍ1mol NaHCO3ÄÜÍêÈ«·´Ó¦£¬ÔòAµÄ½á¹¹¼òʽÊÇ         £¬Ð´³öÓëA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄAµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ                         
(2)»¯ºÏÎïBº¬ÓÐC¡¢H¡¢OÈýÖÖÔªËØ£¬·Ö×ÓÁ¿Îª60£¬ÆäÖÐ̼µÄÖÊÁ¿·ÖÊýΪ60%£¬ÇâµÄÖÊÁ¿·ÖÊýΪ13.33%¡£BÔÚ´ß»¯¼ÁCuµÄ×÷ÓÃϱ»Ñõ»¯³ÉC£¬CÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÔòBµÄ½á¹¹¼òʽÊÇ    
¢ÇijÓлúÎïÍêȫȼÉÕ£¬Éú³É±ê×¼×´¿öÏÂCO2µÄÌå»ýΪ4.48 L£¬H2OµÄÖÊÁ¿Îª5.4g¡£
¢ÙÈôÓлúÎïµÄÖÊÁ¿Îª4.6g£¬´ËÓлúÎïµÄ·Ö×ÓʽΪ                         
¢ÚÈôÓлúÎïµÄÖÊÁ¿Îª6.2g£¬ÇÒ´ËÓлúÎïlmolÄܺÍ×ãÁ¿µÄ½ðÊôÄÆ·´Ó¦Éú³ÉlmolH2£¬´ËÓлúÎïµÄ½á¹¹¼òʽΪ                                            (Á½¸öôÇ»ù²»ÄÜÁ¬ÔÚͬһ¸ö̼ԭ×ÓÉÏ)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì¸ÊËàÊ¡¸ßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£© (1)¾ßÓÐÖ§Á´µÄ»¯ºÏÎïAµÄ·Ö×ÓʽΪC4H6O2£¬A¿ÉÒÔʹBr2µÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«¡£1molAºÍ1mol NaHCO3ÄÜÍêÈ«·´Ó¦£¬ÔòAµÄ½á¹¹¼òʽÊÇ          £¬Ð´³öÓëA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄAµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ                          

(2)»¯ºÏÎïBº¬ÓÐC¡¢H¡¢OÈýÖÖÔªËØ£¬·Ö×ÓÁ¿Îª60£¬ÆäÖÐ̼µÄÖÊÁ¿·ÖÊýΪ60%£¬ÇâµÄÖÊÁ¿·ÖÊýΪ13.33%¡£BÔÚ´ß»¯¼ÁCuµÄ×÷ÓÃϱ»Ñõ»¯³ÉC£¬CÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÔòBµÄ½á¹¹¼òʽÊÇ    

¢ÇijÓлúÎïÍêȫȼÉÕ£¬Éú³É±ê×¼×´¿öÏÂCO2µÄÌå»ýΪ4.48 L£¬H2OµÄÖÊÁ¿Îª5.4g¡£

¢ÙÈôÓлúÎïµÄÖÊÁ¿Îª4.6g£¬´ËÓлúÎïµÄ·Ö×ÓʽΪ                         

¢ÚÈôÓлúÎïµÄÖÊÁ¿Îª6.2g£¬ÇÒ´ËÓлúÎïlmolÄܺÍ×ãÁ¿µÄ½ðÊôÄÆ·´Ó¦Éú³ÉlmolH2£¬´ËÓлúÎïµÄ½á¹¹¼òʽΪ                                             (Á½¸öôÇ»ù²»ÄÜÁ¬ÔÚͬһ¸ö̼ԭ×ÓÉÏ)

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸