·çÃÒÈ«ÇòµÄÒûÁϹû´×Öк¬ÓÐÆ»¹ûËᣨMLA)£¬Æä·Ö×ÓʽΪC4H6O5¡£0.1 molÆ»¹ûËáÓë×ãÁ¿NaHCO3ÈÜÒº·´Ó¦ÄܲúÉú4.48 L CO2£¨±ê×¼×´¿ö£©£¬Æ»¹ûËáÍÑË®ÄÜÉú³ÉʹäåË®ÍÊÉ«µÄ²úÎƻ¹ûËá¾­¾ÛºÏÉú³É¾ÛÆ»¹ûËᣨPMLA£©¡£

 


£¨1£©Ð´³öÏÂÁÐÎïÖʵĽṹ¼òʽ£ºA               £¬D              ¡£

£¨2£©Ö¸³ö·´Ó¦ÀàÐÍ£º¢Ù             ¢Ú              ¡£

£¨3£©Ð´³öËùÓÐÓëMLA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º                     ¡£

£¨4£©Ð´³öE¡úFת»¯µÄ»¯Ñ§·½³Ìʽ                                                ¡£

£¨5£©ÉÏÊöת»¯¹ØϵÖв½Öè¢ÛºÍ¢ÜµÄ˳ÐòÄÜ·ñµßµ¹£¿      £¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©ËµÃ÷ÀíÓÉ£º        ¡£

£¨6£©PMLA¾ßÓÐÁ¼ºÃµÄÉúÎïÏàÈÝÐÔ£¬¿ÉÍû×÷ΪÊÖÊõ·ìºÏÏߵȲÄÁÏÓ¦ÓÃÓÚÉúÎïÒ½Ò©ºÍÉúÎï²ÄÁÏÁìÓò¡£ÆäÔÚÉúÎïÌåÄÚË®½âµÄ»¯Ñ§·½³ÌʽΪ                                     ¡£

£¨1£©CH2BrCH=CHCH2Br£¬OHCCH2CHBrCHO

£¨2£©¼Ó³É£¬È¡´ú

£¨3£©                                                   

£¨4£©HOOCCH2CHBrCOOH + 3NaOH ¡ú NaOOCCH2CH(OH)COONa + NaBr + 2H2O

£¨5£©²»ÄÜ£¬ÈôÏÈÑõ»¯ÔòBÖÐ̼̼˫¼üÒ²±»Ñõ»¯¡£

£¨6£©»ò


½âÎö:

Ê×ÏȼÆËãMLAµÄ²»±¥ºÍ¶ÈΪ2£¬¸ù¾Ý0.1molMLA²úÉú0.2mol¶þÑõ»¯Ì¼£¬ËµÃ÷ÊǶþÔªôÈËáÕýºÃÂú×ã²»±¥ºÍ¶È¡£ÓÖÆäÄÜÍÑË®£¬ËµÃ÷ʣϵÄÒ»¸öÑõÔ­×ÓÊÇôÇ»ù¡£ÔÙ½áºÏÆäÖƱ¸Ô­ÁÏ1£¬3-¶¡¶þÏ©µÄ̼¼Ü½á¹¹£¬¿ÉÖªÆä½á¹¹ÎªHOOCCH2CH(OH)COOH¡£¶Ô±ÈMLAºÍ1£¬3-¶¡¶þÏ©µÄ½á¹¹£¬ÍÆÖªÆäËûÎïÖʽṹ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

·çÃÒÈ«ÇòµÄÒûÁϹû´×Öк¬ÓÐÆ»¹ûËᣨMLA£©£¬Æ»¹ûËá¾­¾ÛºÏÉú³É¾ÛÆ»¹ûËᣨPMLA£©£®
ÒÑÖª£º
£¨1£©0.1molÆ»¹ûËáÓë×ãÁ¿NaHCO3ÈÜÒº·´Ó¦ÄܲúÉú4.48L CO2£¨±ê×¼×´¿ö£©£»
£¨2£©Æ»¹ûËáÍÑË®Éú³ÉÄÜʹäåË®ÍÊÉ«µÄ²úÎ
£¨3£©R-CH2-COOH
Cl2
´ß»¯¼Á
 
RCH2Br
¢ÙNaCN
¢ÚH2O£¬H+
 RCH2COOH£®

Çë»Ø´ð£º
£¨1£©Ð´³öʵÑéÊÒÖÆÒÒÏ©µÄ»¯Ñ§·½³Ìʽ
CH3CH2OH
ŨÁòËá
170¡æ
H2C=CH2¡ü+H2O
CH3CH2OH
ŨÁòËá
170¡æ
H2C=CH2¡ü+H2O
£®
£¨2£©EµÄºË´Å¹²ÕñÇâÆ×ÓÐÈý×é·å£¬Æä·åÃæ»ý±ÈΪ1£º2£º2£¬EµÄ½á¹¹¼òʽΪ
HOCH2CH2CH2CH2OH
HOCH2CH2CH2CH2OH
£®
£¨3£©Ð´³öMLAËùº¬¹ÙÄÜÍŵÄÃû³Æ
ôÈ»ù¡¢ôÇ»ù
ôÈ»ù¡¢ôÇ»ù
£¬Fת»¯³ÉMLA¿ÉÄÜ·¢ÉúµÄ·´Ó¦ÀàÐÍ
Ñõ»¯·´Ó¦¡¢È¡´ú·´Ó¦
Ñõ»¯·´Ó¦¡¢È¡´ú·´Ó¦
£®
£¨4£©Ð´³öÒ»ÖÖÓëMLA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ
£®
£¨5£©¼ìÑéDÖÐÊÇ·ñº¬ÓÐÂÈÔªËصķ½·¨ÊÇ£ºÈ¡ÉÙÁ¿DÓÚÊÔ¹ÜÖУ¬
ÏòÊÔ¹ÜÖмÓÈëÊÊÁ¿ÇâÑõ»¯ÄÆÈÜÒº£¬¼ÓÈÈ£¬Ê¹Æä³ä·Ö·´Ó¦£®ÀäÈ´ºóÈ¡¼¸µÎË®²ãÇåÒº£¬¼ÓÈëµ½¹ýÁ¿µÄÏõËáÓëÏõËáÒøµÄ»ìºÏÈÜÒºÖУ¬³öÏÖ°×É«³Áµí
ÏòÊÔ¹ÜÖмÓÈëÊÊÁ¿ÇâÑõ»¯ÄÆÈÜÒº£¬¼ÓÈÈ£¬Ê¹Æä³ä·Ö·´Ó¦£®ÀäÈ´ºóÈ¡¼¸µÎË®²ãÇåÒº£¬¼ÓÈëµ½¹ýÁ¿µÄÏõËáÓëÏõËáÒøµÄ»ìºÏÈÜÒºÖУ¬³öÏÖ°×É«³Áµí
£¬ÔòÖ¤Ã÷DÖк¬ÓÐÂÈÔªËØ£®
£¨6£©Ð´³öCÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ
HOOCCH2CH£¨Cl£©COOH+3NaOH¡úNaOOCCH2CH£¨OH£©COONa+NaCl+2H2O
HOOCCH2CH£¨Cl£©COOH+3NaOH¡úNaOOCCH2CH£¨OH£©COONa+NaCl+2H2O
£®
£¨7£©PMLA¾ßÓÐÁ¼ºÃµÄÉúÎïÏàÈÝÐÔ£¬¿É×÷ΪÊÖÊõ·ìºÏÏߵȲÄÁÏÓ¦ÓÃÓÚÉúÎïÒ½Ò©ºÍÉúÎï²ÄÁÏÁìÓò£®ÆäÔÚÉúÎïÌåÄÚË®½âµÄ»¯Ñ§·½³Ìʽ
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

·çÃÒÈ«ÇòµÄÒûÁϹû´×Öк¬ÓÐÆ»¹ûËá(MLA)£¬Æä·Ö×ÓʽΪC4H6O5¡£0.1 molÆ»¹ûËáÓë×ãÁ¿NaHCO3ÈÜÒº·´Ó¦ÄܲúÉú4.48 L CO2(±ê×¼×´¿ö)£¬Æ»¹ûËáÍÑË®ÄÜÉú³ÉʹäåË®ÍÊÉ«µÄ²úÎƻ¹ûËá¾­¾ÛºÏÉú³É¾ÛÆ»¹ûËá(PMLA)¡£

(1)д³öÏÂÁÐÎïÖʵĽṹ¼òʽ£ºA____________£¬D____________¡£

(2)Ö¸³ö·´Ó¦ÀàÐÍ£º¢Ù____________£¬¢Ú____________¡£

(3)д³öËùÓÐÓëMLA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º____________________¡£

(4)д³öE¡úFת»¯µÄ»¯Ñ§·½³Ìʽ£º______________________________________________¡£

(5)ÉÏÊöת»¯¹ØϵÖв½Öè¢ÛºÍ¢ÜµÄ˳ÐòÄÜ·ñµßµ¹£¿____________(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)£¬ËµÃ÷ÀíÓÉ£º_____________________________________________________________________¡£

(6)PMLA¾ßÓÐÁ¼ºÃµÄÉúÎïÏàÈÝÐÔ£¬¿ÉÍû×÷ΪÊÖÊõ·ìºÏÏߵȲÄÁÏÓ¦ÓÃÓÚÉúÎïÒ½Ò©ºÍÉúÎï²ÄÁÏÁìÓò¡£ÆäÔÚÉúÎïÌåÄÚË®½âµÄ»¯Ñ§·½³ÌʽΪ________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê±±¾©Êзą́Çø¸ßÈý£¨ÉÏ£©ÆÚÄ©»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

·çÃÒÈ«ÇòµÄÒûÁϹû´×Öк¬ÓÐÆ»¹ûËᣨMLA£©£¬Æ»¹ûËá¾­¾ÛºÏÉú³É¾ÛÆ»¹ûËᣨPMLA£©£®
ÒÑÖª£º
£¨1£©0.1molÆ»¹ûËáÓë×ãÁ¿NaHCO3ÈÜÒº·´Ó¦ÄܲúÉú4.48L CO2£¨±ê×¼×´¿ö£©£»
£¨2£©Æ»¹ûËáÍÑË®Éú³ÉÄÜʹäåË®ÍÊÉ«µÄ²úÎ
£¨3£©R-CH2-COOH 
RCH2Br RCH2COOH£®

Çë»Ø´ð£º
£¨1£©Ð´³öʵÑéÊÒÖÆÒÒÏ©µÄ»¯Ñ§·½³Ìʽ______

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸