(9·Ö)°´ÒªÇóдÈÈ»¯Ñ§·½³Ìʽ£º

(1)ÒÑ֪ϡÈÜÒºÖУ¬1 mol H2SO4ÓëNaOHÈÜҺǡºÃÍêÈ«·´Ó¦Ê±£¬·Å³ö114.6 kJÈÈÁ¿£¬Ð´³ö±íʾH2SO4ÓëNaOH·´Ó¦µÄÖкÍÈÈ»¯Ñ§·½³Ìʽ______________________________________.

(2)25¡æ¡¢101 kPaÌõ¼þϳä·ÖȼÉÕÒ»¶¨Á¿µÄ¶¡ÍéÆøÌå·Å³öÈÈÁ¿ÎªQ kJ£¬¾­²â¶¨£¬½«Éú³ÉµÄCO2ͨÈë×ãÁ¿³ÎÇåʯ»ÒË®ÖвúÉú25 g°×É«³Áµí£¬Ð´³ö±íʾ¶¡ÍéȼÉÕÈÈ»¯Ñ§·½³Ìʽ___________________£®

(3)ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º

¢ÙCH3COOH(l)£«2O2(g)===2CO2(g)£«2H2O(l)    ¦¤H1£½£­870.3kJ/mol

¢ÚC(s)£«O2(g)===CO2(g)              ¡¡      ¦¤H2£½£­393.5kJ/mol

¢ÛH2(g)£«O2(g)===H2O(l)                    ¦¤H3£½£­285.8kJ/mol

д³öÓÉC(s)¡¢H2(g)ºÍO2(g)»¯ºÏÉú³ÉCH3COOH(l)µÄÈÈ»¯Ñ§·½³Ìʽ_______________________£®

 

(9·Ö)   (1)H2SO4(aq)£«NaOH(aq)===Na2SO4(aq)£«H2O(l)¡¡  ¦¤H£½£­57.3 kJ/mol

(2)C4H10(g)£«O2(g)===4CO2(g)£«5H2O(l)   ¦¤H£½£­16Q kJ/mol

(3)2C(s)£«2H2(g)£«O2(g)===CH3COOH(l)    ¦¤H£½£­488.3 kJ/mol

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêɽ¶«Ê¡¼ÃÄþÊÐÁºÉ½Ò»ÖиßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í £¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

(6·Ö)°´ÒªÇóдÈÈ»¯Ñ§·½³Ìʽ£º
(1)ÒÑ֪ϡÈÜÒºÖУ¬1 mol H2SO4ÓëNaOHÈÜҺǡºÃÍêÈ«·´Ó¦Éú³ÉÕýÑÎʱ£¬·Å³ö114.6 kJÈÈÁ¿£¬Ð´³ö±íʾH2SO4ÓëNaOH·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ_____________________¡£
(2)25¡æ¡¢101 kPaÌõ¼þϳä·ÖȼÉÕÒ»¶¨Á¿µÄ¶¡ÍéÆøÌå·Å³öÈÈÁ¿ÎªQ kJ£¬¾­²â¶¨£¬½«Éú³ÉµÄCO2ͨÈë×ãÁ¿³ÎÇåʯ»ÒË®ÖвúÉú25 g°×É«³Áµí£¬Ð´³ö±íʾ¶¡ÍéȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ                                                 ¡£
(3)ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º
¢ÙCH3COOH(l)£«2O2(g)===2CO2(g)£«2H2O(l)     ¦¤H1£½£­870.3 kJ/mol
¢ÚC(s)£«O2(g)===CO2(g)              ¡¡       ¦¤H2£½£­393.5 kJ/mol
¢ÛH2(g)£«O2(g)===H2O(l )                    ¦¤H3£½£­285.8 kJ/mol
д³öÓÉC(s)¡¢H2(g)ºÍO2(g)»¯ºÏÉú³ÉCH3COOH(l)µÄÈÈ»¯Ñ§·½³Ìʽ                 ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012Äêн®ÎÚ³ľÆëÊеڰËÖÐѧ¸ßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§¾í ÌâÐÍ£ºÌî¿ÕÌâ

(9·Ö)°´ÒªÇóдÈÈ»¯Ñ§·½³Ìʽ£º
(1)ÒÑ֪ϡÈÜÒºÖУ¬1 mol H2SO4ÓëNaOHÈÜҺǡºÃÍêÈ«·´Ó¦Ê±£¬·Å³ö114.6 kJÈÈÁ¿£¬Ð´³ö±íʾH2SO4ÓëNaOH·´Ó¦µÄÖкÍÈÈ»¯Ñ§·½³Ìʽ______________________________________.
(2)25¡æ¡¢101 kPaÌõ¼þϳä·ÖȼÉÕÒ»¶¨Á¿µÄ¶¡ÍéÆøÌå·Å³öÈÈÁ¿ÎªQ kJ£¬¾­²â¶¨£¬½«Éú³ÉµÄCO2ͨÈë×ãÁ¿³ÎÇåʯ»ÒË®ÖвúÉú25 g°×É«³Áµí£¬Ð´³ö±íʾ¶¡ÍéȼÉÕÈÈ»¯Ñ§·½³Ìʽ___________________£®
(3)ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º
¢ÙCH3COOH(l)£«2O2(g)===2CO2(g)£«2H2O(l)     ¦¤H1£½£­870.3 kJ/mol
¢ÚC(s)£«O2(g)===CO2(g)              ¡¡       ¦¤H2£½£­393.5 kJ/mol
¢ÛH2(g)£«O2(g)===H2O(l )                     ¦¤H3£½£­285.8 kJ/mol
д³öÓÉC(s)¡¢H2(g)ºÍO2(g)»¯ºÏÉú³ÉCH3COOH(l)µÄÈÈ»¯Ñ§·½³Ìʽ_______________________£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìɽ¶«Ê¡¼ÃÄþÊиßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

(6·Ö)°´ÒªÇóдÈÈ»¯Ñ§·½³Ìʽ£º

(1)ÒÑ֪ϡÈÜÒºÖУ¬1 mol H2SO4ÓëNaOHÈÜҺǡºÃÍêÈ«·´Ó¦Éú³ÉÕýÑÎʱ£¬·Å³ö114.6 kJÈÈÁ¿£¬Ð´³ö±íʾH2SO4ÓëNaOH·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ_____________________¡£

(2)25¡æ¡¢101 kPaÌõ¼þϳä·ÖȼÉÕÒ»¶¨Á¿µÄ¶¡ÍéÆøÌå·Å³öÈÈÁ¿ÎªQ kJ£¬¾­²â¶¨£¬½«Éú³ÉµÄCO2ͨÈë×ãÁ¿³ÎÇåʯ»ÒË®ÖвúÉú25 g°×É«³Áµí£¬Ð´³ö±íʾ¶¡ÍéȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ                                                  ¡£

(3)ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º

¢ÙCH3COOH(l)£«2O2(g)===2CO2(g)£«2H2O(l)     ¦¤H1£½£­870.3 kJ/mol

¢ÚC(s)£«O2(g)===CO2(g)               ¡¡       ¦¤H2£½£­393.5 kJ/mol

¢ÛH2(g)£«O2(g)===H2O(l )                     ¦¤H3£½£­285.8 kJ/mol

д³öÓÉC(s)¡¢H2(g)ºÍO2(g)»¯ºÏÉú³ÉCH3COOH(l)µÄÈÈ»¯Ñ§·½³Ìʽ                  ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012Äêн®ÎÚ³ľÆëÊиßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§¾í ÌâÐÍ£ºÌî¿ÕÌâ

(9·Ö)°´ÒªÇóдÈÈ»¯Ñ§·½³Ìʽ£º

(1)ÒÑ֪ϡÈÜÒºÖУ¬1 mol H2SO4ÓëNaOHÈÜҺǡºÃÍêÈ«·´Ó¦Ê±£¬·Å³ö114.6 kJÈÈÁ¿£¬Ð´³ö±íʾH2SO4ÓëNaOH·´Ó¦µÄÖкÍÈÈ»¯Ñ§·½³Ìʽ______________________________________.

(2)25¡æ¡¢101 kPaÌõ¼þϳä·ÖȼÉÕÒ»¶¨Á¿µÄ¶¡ÍéÆøÌå·Å³öÈÈÁ¿ÎªQ kJ£¬¾­²â¶¨£¬½«Éú³ÉµÄCO2ͨÈë×ãÁ¿³ÎÇåʯ»ÒË®ÖвúÉú25 g°×É«³Áµí£¬Ð´³ö±íʾ¶¡ÍéȼÉÕÈÈ»¯Ñ§·½³Ìʽ___________________£®

(3)ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º

¢ÙCH3COOH(l)£«2O2(g)===2CO2(g)£«2H2O(l)     ¦¤H1£½£­870.3 kJ/mol

¢ÚC(s)£«O2(g)===CO2(g)               ¡¡       ¦¤H2£½£­393.5 kJ/mol

¢ÛH2(g)£«O2(g)===H2O(l )                     ¦¤H3£½£­285.8 kJ/mol

д³öÓÉC(s)¡¢H2(g)ºÍO2(g)»¯ºÏÉú³ÉCH3COOH(l)µÄÈÈ»¯Ñ§·½³Ìʽ_______________________£®

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸