ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A£½H++HA-£»HA-H++A2-¡£ÏÖÓÐÏÂÁÐËÄÖÖÈÜÒº¢Ù0£®0lmol/LµÄH2AÈÜÒº¢Ú0£®0lmol/LµÄNaHAÈÜÒº ¢Û0£®02mol/LµÄHC1ÈÜÒºÓë0£®04mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ¢Ü0£®02mol/LµÄNaOHÈÜÒºÓë0£®02mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ

ÏÂÁйØÓÚÉÏÊöËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ          £¨     £©

A£®ÈÜÒº¢ÚÖдæÔÚË®½âƽºâ£ºHA-+H2OH2A+OH-

B£®ÈÜÒº¢ÛÖÐÓУºc£¨HA-£©+c£¨A2Ò»£©=c£¨Na+£©

C£®ÈÜÒº¢ÜÖÐÓУºc£¨OHÒ»£©=c£¨H+£© +c£¨HA-£© +2c£¨H2A£©

D£®ËÄÖÖÈÜÒºÖÐc£¨HA-£©Å¨¶È´óС£º¢Û>¢Ú>¢Ù>¢Ü

 

¡¾´ð°¸¡¿

B

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A=H++HA-£»HA-?H++A2-£®ÏÖÓÐÏÂÁÐËÄÖÖÈÜÒº£º
¢Ù0.01mol?L-1µÄH2AÈÜÒº
¢Ú0.01mol?L-1µÄNaHAÈÜÒº
¢Û0.02mol?L-1µÄHClÈÜÒºÓë0.04mol?L-1µÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
¢Ü0.02mol?L-1µÄNaOHÈÜÒºÓë0.02mol?L-1µÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
ÏÂÁйØÓÚÉÏÊöËÄÖÖÈÜÒºµÄ˵·¨²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêºÓ±±Ê¡¸ßÈý3ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A£½H++HA£­£»HA£­H++A2£­¡£ÏÖÓÐÏÂÁÐËÄÖÖÈÜÒº£º

¢Ù 0.01mol?L1µÄH2AÈÜÒº

¢Ú 0.01mol?L1µÄNaHAÈÜÒº

¢Û 0.02mol?L1µÄHClÈÜÒºÓë0.04mol?L1µÄNaHAÈÜÒºµÈÌå»ý»ìºÏ

¢Ü 0.02mol?L1µÄNaOHÈÜÒºÓë0.02mol?L1µÄNaHAÈÜÒºµÈÌå»ý»ìºÏ

ÏÂÁйØÓÚÉÏÊöËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ£¨   £©

A£®ÈÜÒº¢ÚÖдæÔÚË®½âƽºâ£ºHA¨D+H2O H2A+OH¨D

B£®ÈÜÒº¢ÛÖÐÓУºc(HA£­)+2c(A2£­)=c(Na+)

C£®ÈÜÒº¢ÜÖÐÓУºc(OH£­)=c(H+)+c(HA£­)

D£®ËÄÖÖÈÜÒºÖÐc (HA£­)Ũ¶È´óС£º¢Û£¾¢Ù£¾¢Ú£¾¢Ü

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄêºþÄÏÊ¡¸ßÈýÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÑ¡ÔñÌâ

ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A=H++HA£­£»HA£­H++A2£­¡£¹ØÓÚÏÂÁÐËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ

¢Ù0.01mol/LµÄH2AÈÜÒº£»¢Ú0.01mol/LµÄNaHAÈÜÒº£»¢Û0.02mol/LµÄHClÈÜÒºÓë0.04mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ£»¢Ü0.02mol/LµÄNaOHÈÜÒºÓë0.02mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ£»

A£®ËÄÖÖÈÜÒºÖÐc(HA£­)Ũ¶È´óС£º¢Û£¾¢Ú£¾¢Ù£¾¢Ü

B£®ÈÜÒº¢ÙÖÐÒ»¶¨²»´æÔÚOH£­

C£®ÈÜÒº¢ÚÖдæÔÚË®½âƽºâ£ºHA£­+H2OH2A+OH£­

D£®ÈÜÒº¢ÛÖÐÓйØÀë×ÓŨ¶È¹Øϵ£ºc(HA£­)+c(A2£­)=c(Na+)

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÕã½­Ê¡Õ㶫±±ÈýУ¸ß¶þµÚ¶þѧÆÚÆÚÖÐÁª¿¼»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÑ¡ÔñÌâ

ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A £½ H++HA£­£»HA£­H++A2£­¡£¹ØÓÚÏÂÁÐËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ                                           (     )

¢Ù0.01mol/LµÄH2AÈÜÒº              ¢Ú0.01mol/LµÄNaHAÈÜÒº

¢Û0.02mol/LµÄHClÈÜÒºÓë0.04mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ

¢Ü0.02mol/LµÄNaOHÈÜÒºÓë0.02mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ

A£®ÈÜÒº¢ÙÖÐÁ£×ÓŨ¶È´óС˳ÐòÊÇ£ºc(H2A)£¾c(H£«)£¾c(HA¡ª)£¾c(A2¡ª)£¾c(OH£­)

B£®ÈÜÒº¢ÚÖÐÓйØÀë×ÓŨ¶È¹Øϵ£ºc(HA¡ª)£«2c(A2£­)£«c(H2A)£½c(Na+)

C£®ËÄÖÖÈÜÒºÖÐc(HA£­)Ũ¶È´óС£º¢Û£¾¢Ù£¾¢Ú£¾¢Ü

D£®ÈÜÒº¢ÛÖÐÓйØÀë×ÓŨ¶È¹Øϵ£ºc(HA£­)£«c(A2£­)£«c(OH£­)=c(Na+)£«c(H£«)

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸