µ±Î¶ȸßÓÚ40¡æʱ£¬Í­µÄƽ¾ùÈܽâËÙÂÊËæ×Å·´Ó¦Î¶ÈÉý¸ß¶øϽµ£¬ÆäÖ÷ÒªÔ­ÒòÊÇ                  ¡£

¢ÈÔÚÌá´¿ºóµÄCuSO4ÈÜÒºÖмÓÈëÒ»¶¨Á¿µÄNa2SO3ºÍNaClÈÜÒº£¬¼ÓÈÈ£¬Éú³ÉCuCl³Áµí¡£ÖƱ¸CuClµÄÀë×Ó·½³ÌʽÊÇ                                             ¡£

28. (9·Ö)ÏÂÁÐÒ»¾ä»°ÖÐÐðÊöÁËÁ½¸öÖµ£¬Ç°Õß¼ÇΪM£¬ºóÕß¼ÇΪN£¬MºÍNµÄ¹Øϵ´ÓA¡¢B¡¢C¡¢DÖÐÑ¡Ôñ

A. M>N                   B.M<N                C.M=N         D. ÎÞ·¨±È½Ï

¢ÅÏàͬζÈÏ£¬1L 1mol/L µÄNH4ClÈÜÒºÖеÄNH4£«¸öÊýºÍ2 L 0.5mol¡¤L£­1NH4ClÈÜÒºÖÐNH4£«µÄ¸öÊý£º     £»

¢ÆÏàͬζÈÏ£¬pHֵΪ12µÄÉÕ¼îÈÜÒºÖÐË®µÄµçÀë¶ÈºÍpHֵΪ12µÄCH3COONaÈÜÒºÖÐË®µÄµçÀë¶È£º     £»

¢ÇÁ½·ÝÊÒÎÂʱµÄ±¥ºÍʯ»ÒË®£¬Ò»·ÝÉýε½50¡æ£»ÁíÒ»·Ý¼ÓÈëÉÙÁ¿CaO£¬»Ö¸´ÖÁÊÒΣ¬Á½ÈÜÒºÖеÄc(Ca2+)£º    £»

¢È³£ÎÂÏÂÁ½·ÝµÈŨ¶ÈµÄ´¿¼îÈÜÒº£¬½«µÚ¶þ·ÝÉý¸ßζȣ¬Á½ÈÜÒºÖÐc(HCO3£­)£º      £»

¢É½«pHֵΪ2µÄ´×ËáºÍÑÎËᶼϡÊÍÏàͬ±¶ÊýËùµÃÏ¡ÈÜÒºµÄpHÖµ£º        £»

¢Ê³£ÎÂÏÂ0.1mol/LµÄCH3COOHÓë0.1mol/LCH3COONaµÈÌå»ý»ìºÏºóÈÜÒºÖÐc(Na+)ºÍc(CH3COO£­)£º     £»

¢ËͬζÈÏ£¬0.1mol/LFeCl3ÈÜÒºÖÐFe3+Ë®½â°Ù·ÖÂÊÓë0.01mol¡¤L£­1FeCl3ÈÜÒºÖÐFe3+ µÄË®½â°Ù·ÖÂÊ£º        £»

¢ÌÊÒÎÂÏÂijǿËáºÍijǿ¼îÈÜÒºµÈÌå»ý»ìºÏºó£¬ÈÜÒºµÄpHֵΪ7£¬Ô­ËáÈÜÒººÍÔ­¼îÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È£º  £»

¢ÍPHÖµÏàͬµÄ´×ËáºÍÑÎËᣬ·Ö±ðÓÃÕôÁóˮϡÊÍÖÁÔ­À´µÄM±¶ºÍN±¶£¬Ï¡ÊͺóÁ½ÈÜÒºµÄPHÖµÈÔÈ»Ïàͬ£¬ ÔòMºÍNµÄ¹ØϵÊÇ£º       ¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

¢ñ£®ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ
£®
A£®¡°½Ó´¥·¨¡±ÖÆH2SO4ʱ£¬´ß»¯Ñõ»¯½×¶ÎµÄ·´Ó¦Ô­ÀíΪ2SO2£¨g£©+O2£¨g£©
´ß»¯¼Á
¡÷
2SO3£¨g£©¡÷H£¼0
B£®º£Ë®ÌáþµÄÖ÷Òª²½ÖèΪ£º

C£®ÆÕͨˮÄàµÄÖ÷Òª³É·ÖÊǹèËá¸Æ
D£®ð¤ÍÁµÄÖ÷Òª³É·ÖÊÇÈýÑõ»¯¶þÂÁ
¢ò£®¹¤ÒµÉÏ¿ÉÓÃʳÑκÍʯ»ÒʯΪÖ÷ÒªÔ­ÁÏ£¬¾­²»Í¬µÄ·½·¨Éú²ú´¿¼î£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Â·²¼À¼·¨ÊÇÒÔʳÑΡ¢Ê¯»Òʯ¡¢Å¨ÁòËá¡¢½¹Ì¿ÎªÔ­ÁÏ£¬ÔÚ¸ßÎÂϽøÐÐìÑÉÕ£¬ÔÙ½þÈ¡¡¢½á¾§¶øÖƵô¿¼î£®
¢ÙʳÑκÍŨÁòËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
2NaCl+H2SO4£¨Å¨£©
  ¡÷  
.
 
Na2SO4+2HCl¡ü
2NaCl+H2SO4£¨Å¨£©
  ¡÷  
.
 
Na2SO4+2HCl¡ü
£»
¢ÚÁòËáÄƺͽ¹Ì¿¡¢Ê¯»Òʯ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Na2SO4+2C+CaCO3
 ¸ßΠ
.
 
CaS+Na2CO3+CO2¡ü
Na2SO4+2C+CaCO3
 ¸ßΠ
.
 
CaS+Na2CO3+CO2¡ü
£¨ÒÑÖª²úÎï֮һΪCaS£©£»
£¨2£©°±¼î·¨µÄ¹¤ÒÕÈçͼ1Ëùʾ£¬µÃµ½µÄ̼ËáÇâÄƾ­ìÑÉÕÉú³É´¿¼î£®
¢ÙͼÖеÄÖмä²úÎïCÊÇ
Ca£¨OH£©2
Ca£¨OH£©2
£¬DÊÇ
NH3
NH3
£¨Ð´»¯Ñ§Ê½£©£»
¢Ú×°ÖÃÒÒÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
CO2+H2O+NH3=NaHCO3¡ý+NH4Cl
CO2+H2O+NH3=NaHCO3¡ý+NH4Cl
£»
£¨3£©ÁªºÏÖƼÊǶ԰±¼î·¨µÄ¸Ä½ø£¬ÆäÓŵãÊÇ
ÄÜÌá¸ßÔ­ÁϵÄÀûÓÃÂÊ£¬¼õÉÙ·ÏÔü£¨CaCl2£©µÄÅÅ·Å£¬±£ÁôÁË°±¼î·¨µÄÓŵ㣬Ïû³ýÁËËüµÄȱµã£¬Ê¹Ê³ÑεÄÀûÓÃÂÊÌá¸ß£»
NH4Cl ¿É×öµª·Ê£»
¿ÉÓëºÏ³É°±³§ÁªºÏ£¬Ê¹ºÏ³É°±µÄÔ­ÁÏÆø CO ת»¯³É CO2£¬¸ï³ýÁË CaCO3 ÖÆ CO2 ÕâÒ»¹¤Ðò
ÄÜÌá¸ßÔ­ÁϵÄÀûÓÃÂÊ£¬¼õÉÙ·ÏÔü£¨CaCl2£©µÄÅÅ·Å£¬±£ÁôÁË°±¼î·¨µÄÓŵ㣬Ïû³ýÁËËüµÄȱµã£¬Ê¹Ê³ÑεÄÀûÓÃÂÊÌá¸ß£»
NH4Cl ¿É×öµª·Ê£»
¿ÉÓëºÏ³É°±³§ÁªºÏ£¬Ê¹ºÏ³É°±µÄÔ­ÁÏÆø CO ת»¯³É CO2£¬¸ï³ýÁË CaCO3 ÖÆ CO2 ÕâÒ»¹¤Ðò
£»
£¨4£©ÓÐÈËÈÏΪ̼ËáÇâ¼ØÓë̼ËáÇâÄƵĻ¯Ñ§ÐÔÖÊÏàËÆ£¬¹ÊÒ²¿ÉÓð±¼î·¨ÒÔÂÈ»¯¼ØºÍʯ»ÒʯµÈΪԭÁÏÖÆ̼Ëá¼Ø£®Çë½áºÏͼ1µÄÈܽâ¶È£¨S£©Ëæζȱ仯ÇúÏߣ¬·ÖÎö˵Ã÷ÊÇ·ñ¿ÉÐУ¿
²»¿ÉÐУ®ÒòΪKHCO3ºÍNH4ClµÄÈܽâ¶ÈÏà²î²»´ó£¬µ±Î¶ȸßÓÚ40¡æʱ£¬KHCO3µÄÈܽâ¶È´óÓÚNH4Cl£¬½µÎ½ᾧʱ»áÎö³ö½Ï¶àµÄKCl
²»¿ÉÐУ®ÒòΪKHCO3ºÍNH4ClµÄÈܽâ¶ÈÏà²î²»´ó£¬µ±Î¶ȸßÓÚ40¡æʱ£¬KHCO3µÄÈܽâ¶È´óÓÚNH4Cl£¬½µÎ½ᾧʱ»áÎö³ö½Ï¶àµÄKCl
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2009?½­ËÕ£©·Ï¾ÉÓ¡Ë¢µç·°åµÄ»ØÊÕÀûÓÿÉʵÏÖ×ÊÔ´ÔÙÉú£¬²¢¼õÉÙÎÛȾ£®·Ï¾ÉÓ¡Ë¢µç·°å¾­·ÛËé·ÖÀ룬Äܵõ½·Ç½ðÊô·ÛÄ©ºÍ½ðÊô·ÛÄ©£®
£¨1£©ÏÂÁд¦ÀíÓ¡Ë¢µç·°å·Ç½ðÊô·ÛÄ©µÄ·½·¨ÖУ¬²»·ûºÏ»·¾³±£»¤ÀíÄîµÄÊÇ
BD
BD
£¨Ìî×Öĸ£©£®
A£®ÈÈÁѽâÐγÉȼÓÍ                       B£®Â¶Ìì·ÙÉÕ
C£®×÷ΪÓлú¸´ºÏ½¨Öþ²ÄÁϵÄÔ­ÁÏ           D£®Ö±½ÓÌîÂñ
£¨2£©ÓÃH2O2ºÍH2SO4µÄ»ìºÏÈÜÒº¿ÉÈܳöÓ¡Ë¢µç·°å½ðÊô·ÛÄ©ÖеÄÍ­£®ÒÑÖª£ºCu£¨s£©+2H+£¨aq£©¨TCu2+£¨aq£©+H2£¨g£©H=64.39KJ?mol-12H2O2£¨l£©¨T2H2O£¨l£©+O2£¨g£©H=-196.46KJ?mol-1H2(g)+
1
2
O2(g)
¨TH2O£¨l£©H=-285.84KJ?mol-1
ÔÚH2SO4ÈÜÒºÖÐCuÓëH2O2·´Ó¦Éú³ÉCu2+ºÍH2OµÄÈÈ»¯Ñ§·½³ÌʽΪ
Cu£¨s£©+H2O2£¨l£©+2H+£¨aq£©=Cu2+£¨aq£©+2H2O£¨l£©¡÷H=-319.68KJ£®mol-1
Cu£¨s£©+H2O2£¨l£©+2H+£¨aq£©=Cu2+£¨aq£©+2H2O£¨l£©¡÷H=-319.68KJ£®mol-1
£®
£¨3£©¿ØÖÆÆäËûÌõ¼þÏàͬ£¬Ó¡Ë¢µç·°åµÄ½ðÊô·ÛÄ©ÓÃ10%H2O2ºÍ3.0mol?L-1H2SO4µÄ»ìºÏÈÜÒº´¦Àí£¬²âµÃ²»Í¬Î¶ÈÏÂÍ­µÄƽ¾ùÈܽâËÙÂÊ£¨¼ûÏÂ±í£©£®
ζȣ¨¡æ£© 20 30 40 50 60 70 80
ͭƽ¾ùÈܽâËÙÂÊ
£¨¡Á10-3mol?L-1?min-1£©
7.34 8.01 9.25 7.98 7.24 6.73 5.76
µ±Î¶ȸßÓÚ40¡æʱ£¬Í­µÄƽ¾ùÈܽâËÙÂÊËæ×Å·´Ó¦Î¶ÈÉý¸ß¶øϽµ£¬ÆäÖ÷ÒªÔ­ÒòÊÇ
H2O2·Ö½âËÙÂʼӿì
H2O2·Ö½âËÙÂʼӿì
£®
£¨4£©ÔÚÌá´¿ºóµÄCuSO4ÈÜÒºÖмÓÈëÒ»¶¨Á¿µÄNa2SO3ºÍNaClÈÜÒº£¬¼ÓÈÈ£¬Éú³ÉCuCl³Áµí£®ÖƱ¸CuClµÄÀë×Ó·½³ÌʽÊÇ
2Cu2++SO32-+2Cl-+H2O¨T2CuCl¡ý+SO42-+2H+
2Cu2++SO32-+2Cl-+H2O¨T2CuCl¡ý+SO42-+2H+
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

·Ï¾ÉÓ¡Ë¢µç·°åµÄ»ØÊÕÀûÓÿÉʵÏÖ×ÊÔ´ÔÙÉú£¬²¢¼õÉÙÎÛȾ£®·Ï¾ÉÓ¡Ë¢µç·°å¾­·ÛËé·ÖÀ룬Äܵõ½·Ç½ðÊô·ÛÄ©ºÍ½ðÊô·ÛÄ©£®
£¨1£©Ð´³ö¹¤ÒµÉÏÖƱ¸Ó¡Ë¢µç·°åÔ­ÀíµÄÀë×Ó·½³Ìʽ£º
Cu+2Fe3+=Cu2++2Fe2+
Cu+2Fe3+=Cu2++2Fe2+

£¨2£©ÏÂÁд¦ÀíÓ¡Ë¢µç·°å·Ç½ðÊô·ÛÄ©µÄ·½·¨ÖУ¬²»·ûºÏ»·¾³±£»¤ÀíÄîµÄÊÇ
BD
BD
£¨Ìî×Öĸ£©£®
A£®ÈÈÁѽâÐγÉȼÓÍ                    B£®Â¶Ìì·ÙÉÕ
C£®×÷ΪÓлú¸´ºÏ½¨Öþ²ÄÁϵÄÔ­ÁÏ        D£®Ö±½ÓÌîÂñ
£¨3£©ÓÃH2O2ºÍH2SO4µÄ»ìºÏÈÜÒº¿ÉÈܳöÓ¡Ë¢µç·°å½ðÊô·ÛÄ©ÖеÄÍ­£®
д³öÔÚH2SO4ÈÜÒºÖÐCuÓëH2O2 ·´Ó¦Éú³ÉCu2+ ºÍH2OµÄÀë×Ó·½³Ìʽ
Cu+H2O2+2H+=Cu2++2H2O
Cu+H2O2+2H+=Cu2++2H2O
£®
£¨4£©¿ØÖÆÆäËûÌõ¼þÏàͬ£¬Ó¡Ë¢µç·°åµÄ½ðÊô·ÛÄ©ÓÃ10% H2O2ºÍ3.0mol?L-1 H2SO4µÄ»ìºÏÈÜÒº´¦Àí£¬²âµÃ²»Í¬Î¶ÈÏÂÍ­µÄƽ¾ùÈܽâËÙÂÊ£¨¼ûÏÂ±í£©£®
ζȣ¨¡æ£© 20 30 40 50 60 70 80
ͭƽ¾ùÈܽâËÙÂÊ     £¨¡Á10-3 mol?L-1?min-1£© 7.34 8.01 9.25 7.98 7.24 6.73 5.76
µ±Î¶ȸßÓÚ40¡æʱ£¬Í­µÄƽ¾ùÈܽâËÙÂÊËæ×Å·´Ó¦Î¶ÈÉý¸ß¶øϽµ£¬ÆäÖ÷ÒªÔ­ÒòÊÇ
H2O2·Ö½âËÙÂʼӿì
H2O2·Ö½âËÙÂʼӿì
£®
£¨5£©ÔÚÌá´¿ºóµÄCuSO4ÈÜÒºÖмÓÈëÒ»¶¨Á¿µÄNa2SO3ºÍNaClÈÜÒº£¬¼ÓÈÈ£¬Éú³ÉCuCl³Áµí£®ÖƱ¸CuClµÄÀë×Ó·½³ÌʽÊÇ
2Cu2++SO32-+2Cl-+H2O
  ¡÷  
.
 
2CuCl¡ý+SO42-+2H+
2Cu2++SO32-+2Cl-+H2O
  ¡÷  
.
 
2CuCl¡ý+SO42-+2H+
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2010?³±ÖݶþÄ££©¹ýÑõ»¯ÇâÊÇÖØÒªµÄÑõ»¯¼Á¡¢»¹Ô­¼Á£¬ÆäË®ÈÜÒºÓÖ³ÆË«ÑõË®£¬³£ÓÃ×÷Ïû¶¾¡¢É±¾ú¡¢Æ¯°×µÈ£®Ä³»¯Ñ§ÐËȤС×éÈ¡Ò»¶¨Á¿µÄ¹ýÑõ»¯ÇâÈÜÒº£¬×¼È·²â¶¨¹ýÑõ»¯ÇâµÄº¬Á¿£¬²¢Ì½¾¿¹ýÑõ»¯ÇâµÄÐÔÖÊ¡¢ÓÃ;£®
¢ñ£®²â¶¨¹ýÑõ»¯ÇâµÄº¬Á¿
£¨1£©ÒÆÈ¡10.00mLÃܶÈΪ¦Ñ g/mLµÄ¹ýÑõ»¯ÇâÈÜÒºÖÁ250mL ÈÝÁ¿Æ¿ÖУ¬¼ÓˮϡÊÍÖÁ¿Ì¶È£¬Ò¡ÔÈ£®ÒÆÈ¡Ï¡ÊͺóµÄ¹ýÑõ»¯ÇâÈÜÒº25.00mLÖÁ׶ÐÎÆ¿ÖУ¬¼ÓÈëÏ¡ÁòËáËữ£¬ÓÃÕôÁóˮϡÊÍ£¬×÷±»²âÊÔÑù£®
£¨2£©ÓøßÃÌËá¼Ø±ê×¼ÈÜÒºµÎ¶¨±»²âÊÔÑù£¬Æä·´Ó¦µÄÀë×Ó·½³ÌʽÈçÏ£º2MnO4-+5H2O2+6H+=2Mn2++8H2O+5O2¡ü£¬Öظ´µÎ¶¨Èý´Î£¬Æ½¾ùºÄÓÃc mol/L KMnO4±ê×¼ÈÜÒºV mL£¬ÔòÔ­¹ýÑõ»¯ÇâÈÜÒºÖйýÑõ»¯ÇâµÄÖÊÁ¿·ÖÊýΪ
17Cv
200¦Ñ
17Cv
200¦Ñ
£®
£¨3£©ÈôµÎ¶¨Ç°µÎ¶¨¹Ü¼â×ìÖÐÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ£¬Ôò²â¶¨½á¹û
Æ«¸ß
Æ«¸ß
£¨Ìî¡°Æ«¸ß¡±»ò¡°Æ«µÍ¡±»ò¡°²»±ä¡±£©£®
¢ò£®Ì½¾¿¹ýÑõ»¯ÇâµÄÐÔÖÊ
£¨4£©¸Ã»¯Ñ§ÐËȤС×é¸ù¾ÝËùÌṩµÄʵÑéÌõ¼þÉè¼ÆÁËÁ½¸öʵÑ飬·Ö±ðÑéÖ¤¹ýÑõ»¯ÇâµÄÑõ»¯ÐԺͲ»Îȶ¨ÐÔ£®£¨ÊµÑéÊÔ¼ÁÖ»ÓУº¹ýÑõ»¯ÇâÈÜÒº¡¢Ï¡ÁòËá¡¢µâ»¯¼Øµí·ÛÈÜÒº¡¢±¥ºÍÁò»¯ÇâÈÜÒº£¬ÊµÑéÒÇÆ÷¼°ÓÃÆ·¿É×ÔÑ¡£®£©ÇëÌîдËûÃǵÄʵÑé·½·¨ºÍʵÑéÏÖÏóµÄ±íÖпհףº
ʵÑéÄÚÈÝ ÊµÑé·½·¨ ʵÑéÏÖÏó
ÑéÖ¤Ñõ»¯ÐÔ È¡ÊÊÁ¿µâ»¯¼Øµí·ÛÈÜÒº¡¢Ï¡ÁòËáÓÚÊÔ¹ÜÖУ¬µÎÈë¹ýÑõ»¯ÇâÈÜÒº£®£¨»ò£ºÈ¡ÊÊÁ¿±¥ºÍÁò»¯ÇâÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎÈë¹ýÑõ»¯ÇâÈÜÒº£®£©
ÈÜÒº±äÀ¶É«
ÈÜÒº±äÀ¶É«
£®
£¨»ò£º
²úÉúµ­»ÆÉ«³Áµí»òÈÜÒº±ä»ë×Ç
²úÉúµ­»ÆÉ«³Áµí»òÈÜÒº±ä»ë×Ç
 £©
ÑéÖ¤ÈȲ»Îȶ¨ÐÔ È¡ÊÊÁ¿¹ýÑõ»¯ÇâÈÜÒºÓÚÊÔ¹ÜÖУ¬
ÉÔ΢¼ÓÈÈ
ÉÔ΢¼ÓÈÈ

Óôø»ðÐǵÄľÌõ¼ìÑé
Óôø»ðÐǵÄľÌõ¼ìÑé
£®
²úÉúÆøÅÝ£¬´ø»ðÐǵÄľÌõ¸´È¼£®
¢ó£®ÓÃH2O2ºÍH2SO4µÄ»ìºÏÈÜÒº¿ÉÈܳöÓ¡Ë¢µç·°å½ðÊô·ÛÄ©ÖеÄÍ­
£¨5£©Ó¡Ë¢µç·°å½ðÊô·ÛÄ©ÖеÄCuÔÚH2SO4ÓëH2O2ÈÜÒºÖз´Ó¦Éú³ÉCu2+ºÍH2OµÄÀë×Ó·½³ÌʽΪ
Cu+H2O2+2H+=Cu2++2H2O
Cu+H2O2+2H+=Cu2++2H2O
£®
£¨6£©¿ØÖÆÆäËûÌõ¼þÏàͬ£¬Ó¡Ë¢µç·°åµÄCuÓÃ10%H2O2ºÍ3.0mol/L H2SO4µÄ»ìºÏÈÜÒº´¦Àí£¬²âµÃ²»Í¬Î¶ÈÏÂÍ­µÄƽ¾ùÈܽâËÙÂÊÈçÏÂ±í£º
ζȣ¨¡æ£© 20 30 40 50 60 70 80
     Í­Æ½¾ùÈܽâËÙÂÊ
£¨¡Á10-3mol?L-1?min-1£©
7.34 8.01 9.25 7.98 7.24 6.73 5.76
µ±Î¶ȸßÓÚ40¡æʱ£¬Í­µÄƽ¾ùÈܽâËÙÂÊËæ×Å·´Ó¦Î¶ÈÉý¸ß¶øϽµ£¬ÆäÖ÷ÒªÔ­ÒòÊÇ
ζÈÉý¸ß£¬H2O2·Ö½âËÙÂʼӿì
ζÈÉý¸ß£¬H2O2·Ö½âËÙÂʼӿì
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

X¡¢Y¡¢ZÈýÖÖ¶ÌÖÜÆÚÔªËØ£¬Æäµ¥ÖÊÔÚ³£ÎÂϾùΪÎÞÉ«ÆøÌ壬ËüÃǵÄÔ­×ÓÐòÊýÖ®ºÍΪ16£®ÔÚÊʵ±Ìõ¼þÏÂÈýÖÖµ¥ÖÊÁ½Á½»¯ºÏ£¬¿É·¢ÉúÈçͼ1Ëùʾ±ä»¯£®¼ºÖª1¸öB·Ö×ÓÖк¬ÓÐZÔªËصÄÔ­×Ó¸öÊý±ÈC·Ö×ÓÖк¬ÓÐZÔªËصÄÔ­×Ó¸öÊýÉÙ1¸ö£®
¾«Ó¢¼Ò½ÌÍø
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÓÉ X¡¢Y¡¢ZÈýÖÖÔªËع²Í¬×é³ÉµÄÈýÖÖ²»Í¬ÖÖÀ໯ºÏÎïµÄ»¯Ñ§Ê½Îª
 
£¬ÏàͬŨ¶ÈÉÏÊöË®ÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
 
£¨Ìîд»¯Ñ§Ê½£©£®
£¨2£©Allis-ChalmersÖÆÔ칫˾·¢ÏÖ¿ÉÒÔÓÃC×÷ΪȼÁϵç³ØµÄȼÁÏ£¬ÒÔÇâÑõ»¯¼ØÈÜҺΪ½éÖÊ£¬·¢ÉúÈçÏ·´Ó¦£º4NH3+3O2=2N2+6H2O£¬ÊÔд³ö¸Ãµç³Ø¸º¼«µÄµç¼«·´Ó¦Ê½
 
£¬ÈÜÒºÖÐOH-Ïò
 
¼«Òƶ¯£¨Ìî¡°Õý¡°»ò¡°¸º¡°£©£®
£¨3£©Z·Ö±ðÓëX¡¢YÁ½ÔªËØ¿ÉÒÔ¹¹³É18¸öµç×Ó·Ö×Ӽ׺ÍÒÒ£¬Æä·Ö×ÓÖÐÖ»´æÔÚ¹²¼Ûµ¥¼ü£¬³£ÎÂϼס¢ÒÒ¾ùΪÎÞÉ«ÒºÌ壬¼×Ëæ×ÅζÈÉý¸ß·Ö½âËÙÂʼӿ죮
¢ÙÒÒÄܹ»½«CuO»¹Ô­ÎªCu2O£¬ÒÑ֪ÿ1molÒҲμӷ´Ó¦ÓÐ4molµç×ÓתÒÆ£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
 
£®
¢Ú½«Í­·ÛÄ©ÓÃ10%¼×ºÍ3.0mol?L-1H2SO4»ìºÏÈÜÒº´¦Âñ£¬²âµÃ²»Í¬Î¶ÈÏÂÍ­µÄƽ¾ùÈܽâËÙÂÊÈçÏÂ±í£º
ζȣ¨¡æ£© 20 30 40 50 60 70 80
Í­µÄƽ¾ùÈܽâËÙÂÊ
£¨¡Á10-3mol-L-1?min-1£©
7.34 8.01 9.25 7.98 7.24 6.73 5.76
ÓɱíÖÐÊý¾Ý¿ÉÖª£¬µ±Î¶ȸßÓÚ40¡æʱ£¬Í­µÄƽ¾ùÈܽâËÙÂÊËæ×ÅζȵÄÉý¸ß¶øϽµ£¬ÆäÖ÷ÒªÔ­ÒòÊÇ
 
£®
¢ÛʵÑéÊÒ¿ÉÓü××÷ÊÔ¼ÁÈ¡XµÄµ¥ÖÊ£¬·¢Éú×°ÖÿÉÑ¡ÓÃÈçͼ2ËùʾµÄ
 
£¨Ìî×°ÖôúºÅ£©£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸