ÎåÖÖ¶ÌÖÜÆÚÔªËØA¡¢B¡¢C¡¢D¡¢EµÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£AºÍCͬ×壬BºÍDͬ×壬CÀë×ÓºÍBÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹¡£AºÍB¡¢D¡¢E¾ùÄÜÐγɹ²¼Û»¯ºÏÎï¡£AºÍBÐγɵĻ¯ºÏÎïÔÚË®ÖгʼîÐÔ£¬CºÍEÐγɵĻ¯ºÏÎïÔÚË®ÖгÊÖÐÐÔ¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÎåÖÖÔªËØÖУ¬Ô­×Ӱ뾶×î´óµÄÊÇ         £¬·Ç½ðÊôÐÔ×îÇ¿µÄÊÇ        (ÌîÔªËØ·ûºÅ)¡£
£¨2£©ÓÉAºÍB¡¢D¡¢EËùÐγɵĹ²¼ÛÐÍ»¯ºÏÎïÖУ¬ÈÈÎȶ¨ÐÔ×î²îµÄÊÇ         £¨Óû¯Ñ§Ê½±íʾ£©¡£
£¨3£©AºÍEÐγɵĻ¯ºÏÎïÓëAºÍBÐγɵĻ¯ºÏÎï·´Ó¦£¬²úÎïµÄ»¯Ñ§Ê½Îª        ,ÆäÖдæÔڵĻ¯Ñ§¼üÀàÐÍΪ            ¡£
£¨4£©µ¥ÖÊDÔÚ³ä×ãµÄµ¥ÖÊEÖÐȼÉÕ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                    £»
£¨5£©µ¥ÖÊEÓëË®·´Ó¦µÄÀë×Ó·½³Ìʽ                                         ¡£

£¨1£©Na    Cl
£¨2£©PH3
£¨3£©NH4Cl    Àë×Ó¼ü¡¢¹²¼Û¼ü
£¨4£©2P+5Cl22PCl5
£¨5£©Cl2+H2O=H++ Cl-+HClO

½âÎöÊÔÌâ·ÖÎö£ºAºÍBÐγɵĻ¯ºÏÎïÔÚË®ÖгʼîÐÔ£¬ÅжÏAÊÇHÔªËØ£¬BÊÇNÔªËØ£»AºÍCͬ×壬BºÍDͬ×壬ÔòCÊÇNaÔªËØ£¬DÊÇPÔªËØ£»CºÍEÐγɵĻ¯ºÏÎïÔÚË®ÖгÊÖÐÐÔ£¬ÔòEÊÇClÔªËØ£¬ÂÈ»¯ÄƵÄÈÜÒº³ÊÖÐÐÔ¡£
£¨1£©¸ù¾ÝÔªËØÖÜÆÚÂÉÅжϣ¬ÎåÖÖÔªËØÖУ¬Ô­×Ӱ뾶×î´óµÄÊÇNa£¬·Ç½ðÊôÐÔ×îÇ¿µÄÊÇCl£»
£¨2£©B¡¢D¡¢EÖзǽðÊôÐÔ×îÈõµÄÊÇP£¬ÓëHÐγÉPH3µÄÈÈÎȶ¨ÐÔ×î²î£»
£¨3£©AºÍEÐγɵĻ¯ºÏÎïÊÇHCl£¬AºÍBÐγɵĻ¯ºÏÎïÊÇ°±Æø£¬¶þÕß·´Ó¦Éú³ÉÂÈ»¯ï§»¯Ñ§Ê½ÎªNH4Cl£¬´æÔÚÀë×Ó¼ü¡¢¹²¼Û¼ü£»
£¨4£©PÔÚÂÈÆøÖÐȼÉÕÉú³ÉÎåÂÈ»¯Á×£¬»¯Ñ§·½³ÌʽΪ2P+5Cl22PCl5
£¨5£©ÂÈÆøÓëË®·´Ó¦Éú³ÉÂÈ»¯ÇâºÍ´ÎÂÈËᣬÀë×Ó·½³ÌʽΪCl2+H2O=H++ Cl-+HClO
¿¼µã£º¿¼²éÔªËØÍƶϣ¬ÔªËØÖÜÆÚÂɵÄÓ¦Ó㬻¯Ñ§¼üµÄÅжϣ¬»¯Ñ§·½³Ìʽ¡¢Àë×Ó·½³ÌʽµÄÊéд

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£¨13·Ö£©¢ñ£®Í¨³£×´¿öÏ£¬X¡¢YºÍZÊÇÈýÖÖÆø̬µ¥ÖÊ¡£XµÄ×é³ÉÔªËØÊǵÚÈýÖÜÆÚÔ­×Ӱ뾶×îСµÄÔªËØ(Ï¡ÓÐÆøÌåÔªËسýÍâ)£»YºÍZ¾ùÓÉÔªËØR×é³É£¬·´Ó¦Y+2I-+2H+====I2+Z+H2O³£×÷ΪYµÄ¼ø¶¨·´Ó¦¡£WÊǶÌÖÜÆÚÔªËØ£¬×îÍâ²ãµç×ÓÊýÊÇ×îÄÚ²ãµç×ÓÊýµÄÈý±¶£¬ÎüÒýµç×Ó¶ÔµÄÄÜÁ¦±ÈXµ¥ÖʵÄ×é³ÉÔªËØÒªÈõ¡£
£¨1£© ZµÄ»¯Ñ§Ê½__________________
£¨2£©½«YºÍ¶þÑõ»¯Áò·Ö±ðͨÈëÆ·ºìÈÜÒº£¬¶¼ÄÜʹƷºìÍÊÉ«¡£¼òÊöÓÃÍÊÉ«µÄÈÜÒºÇø±ðYºÍ¶þÑõ»¯ÁòµÄʵÑé·½·¨:________________________________________________________¡£
£¨3£©¾Ù³öʵÀý˵Ã÷XµÄÑõ»¯ÐÔ±ÈWµ¥ÖÊÑõ»¯ÐÔÇ¿(½öÓÃÒ»¸ö»¯Ñ§·½³Ìʽ±íʾ):_____________¡£
¢ò£®ÈçͼÊÇ0.1 mol¡¤L£­1ËÄÖÖµç½âÖÊÈÜÒºµÄpHËæζȱ仯µÄͼÏñ¡£

£¨1£©ÆäÖзûºÏ0.1 mol¡¤L£­1NH4Al(SO4)2µÄpHËæζȱ仯µÄÇúÏßÊÇ________(ÌîдÐòºÅ)£¬
£¨2£©20 ¡æʱ£¬0.1 mol¡¤L£­1NH4Al(SO4)2ÖÐ2c(SO42-)£­c(NH4+)£­3c(Al3£«)£½________¡££¨¼ÆË㾫ȷֵ£©
£¨3£©ÊÒÎÂʱ£¬Ïò100 mL 0.1 mol¡¤L£­1 NH4HSO4ÈÜÒºÖеμÓ0.1 mol¡¤L£­1 NaOHÈÜÒº£¬µÃµ½ÈÜÒºpHÓëNaOHÈÜÒºÌå»ýµÄ¹ØϵÇúÏßÈçͼËùʾ£º

ÊÔ·ÖÎöͼÖÐa¡¢b¡¢c¡¢dËĸöµã£¬Ë®µÄµçÀë³Ì¶È×î´óÊÇ________µã£»ÔÚbµã£¬ÈÜÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄÅÅÁÐ˳ÐòÊÇ______________________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

Ô­×ÓÐòÊýÓÉСµ½´óÅÅÁеÄËÄÖÖ¶ÌÖÜÆÚÔªËØX¡¢Y¡¢Z¡¢W£¬ËÄÖÖÔªËصÄÔ­×ÓÐòÊýÖ®ºÍΪ32£¬ÔÚÖÜÆÚ±íÖÐXÊÇÔ­×Ӱ뾶×îСµÄÔªËØ£¬Y¡¢Z×óÓÒÏàÁÚ£¬Z¡¢WλÓÚͬÖ÷×å¡£
£¨1£©XÔªËØÊÇ        £¨ÌîÃû³Æ£© ,WÔÚÖÜÆÚ±íÖеÄλÖà                          ¡£
£¨2£©XÓëY Ðγɻ¯ºÏÎïµÄµç×ÓʽΪ        £¬XÓëW×é³ÉµÄ»¯ºÏÎïÖдæÔÚ       ¼ü£¨Ìî¡°Àë×Ó¡±¡°¹²¼Û¡±£©¡£
£¨3£©¢Ùд³öʵÑéÊÒÖƱ¸YX3µÄ»¯Ñ§·½³Ìʽ£º                                        ¡£
¢Ú¹¤ÒµÉÏÒ²¿ÉÒÔÑ¡ÔñºÏÊʵÄÌõ¼þ½øÐÐYX3µÄºÏ³É£¬ÈôÒÑÖªÔÚ¸ÃÌõ¼þÏÂÿÉú³É2molYX3ÆøÌåʱ·Å³ö
92.4kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ                                           ¡£
£¨4£©ÓÉX¡¢Y¡¢Z¡¢WËÄÖÖÔªËØ×é³ÉµÄÒ»ÖÖÀë×Ó»¯ºÏÎïA¡£ÒÑÖª1mol AÄÜÓë×ãÁ¿NaOHŨÈÜÒº·´Ó¦Éú³É±ê×¼×´¿öÏÂ44.8LÆøÌå¡£ÔòAµÄÃû³ÆÊÇ          ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

A¡¢B¡¢C¡¢DËÄÖÖ¶ÌÖÜÆÚÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó£¬AÔ­×ÓµÄ×îÍâ²ãÉÏÓÐ4¸öµç×Ó£»BµÄÒõÀë×ÓºÍCµÄÑôÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹£¬Á½ÔªËصĵ¥ÖÊ·´Ó¦£¬ÄÜÉú³ÉÒ»ÖÖµ­»ÆÉ«µÄ¹ÌÌåE£»DµÄL²ãµç×ÓÊýµÈÓÚK¡¢MÁ½¸öµç×Ó²ãÉϵĵç×ÓÊýÖ®ºÍ¡£
£¨1£©AΪ     £¬BΪ     £¬CΪ     £¬DΪ     ¡££¨ÌîÔªËØ·ûºÅ£©
£¨2£©DµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄ»¯Ñ§Ê½ÊÇ       £¬EµÄµç×ÓʽÊÇ       ¡£
£¨3£©Ð´³öÓÉA¡¢B×é³ÉµÄ»¯ºÏÎïÓëE·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º         ¡£
£¨4£©ÇëÓõç×Óʽ±íʾ³öCºÍDÐγɵĻ¯ºÏÎïFµÄÐγɹý³Ì£º            ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

X¡¢Y¡¢Z¡¢M¡¢GÎåÖÖÔªËØ·ÖÊôÈý¸ö¶ÌÖÜÆÚ£¬ÇÒÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£XÊÇÔªËØÖÜÆÚ±íÖÐÔ­×Ӱ뾶×îСµÄÔªËØ£¬X¡¢ZͬÖ÷×壬¿ÉÐγÉÀë×Ó»¯ºÏÎïZX£»Y¡¢MͬÖ÷×壬¿ÉÐγÉMY2¡¢MY3Á½ÖÖ·Ö×Ó¡£ Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©YÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ               £¬ZXµÄµç×ÓʽΪ          ¡£
£¨2£©ÉÏÊöÔªËصÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïËáÐÔ×îÇ¿µÄÊÇ              £¨Ð´»¯Ñ§Ê½£©£¬·Ç½ðÊôÆø̬Ç⻯ÎﻹԭÐÔ×îÇ¿µÄÊÇ                 £¨Ð´»¯Ñ§Ê½£©¡£
£¨3£©Y¡¢GµÄµ¥ÖÊ»òÁ½ÔªËØÖ®¼äÐγɵĻ¯ºÏÎï¿É×÷Ïû¶¾¼ÁµÄÓР      ¡¢       £¨Ð´³öÆäÖÐÁ½ÖÖÎïÖʵĻ¯Ñ§Ê½£©¡£
£¨4£©X2MµÄ±ê׼ȼÉÕÈȦ¤H£½£­a kJ¡¤mol£­1£¬Ð´³ö±íʾX2M±ê׼ȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ£º               ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÒÑÖªXÔªËØÔ­×ÓµÄK¡¢L²ãµÄµç×ÓÊýÖ®ºÍ±ÈL¡¢M²ãµÄµç×ÓÊýÖ®ºÍ¶à1¸öµç×Ó¡£YÔª
ËصÄÔ­×Ó×îÍâ²ãµç×ÓÊý±ÈÄÚ²ãµç×ÓÊýÉÙ3¸ö¡£ZÔªËغËÍâÓÐ3¸öµç×Ӳ㣬×îÍâ²ãÓÐ3¸öµç×Ó¡£WÔªËØ×î¸ß»¯ºÏ¼ÛÊÇ×îµÍ»¯ºÏ¼Û¾ø¶ÔÖµµÄ3±¶£¬ËüÔÚ×î¸ß¼ÛÑõ»¯ÎïÖеÄÖÊÁ¿·ÖÊýΪ40%¡£
(1)YºÍWµÄÆø̬Ç⻯ÎïµÄÎȶ¨ÐÔΪ(Óû¯Ñ§Ê½±íʾ)       £¾       ¡£
(2)Xµ¥ÖÊÔÚ¿ÕÆøÖмÓÈÈÉú³ÉµÄ»¯ºÏÎïÊÇ       »¯ºÏÎï(Ìî¡°Àë×Ó¡±»ò¡°¹²¼Û¡±)¡£
(3)XºÍZµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯Îï·´Ó¦µÄÀë×Ó·½³Ìʽ                        ¡£
(4)WµÄµÍ¼ÛÑõ»¯ÎïÓëYµ¥ÖʵÄË®ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ                       ¡£
(5)YÓëZÐγɻ¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ       ¡£ÊµÑé²âµÃµ±´Ë»¯ºÏÎï´¦ÓÚ¹Ì̬ºÍҺ̬ʱ²»µ¼µç£¬ÈÜÓÚË®Äܵ¼µç¡£ÓÉ´ËÅжϸû¯ºÏÎï¾ßÓР      ¼ü(Ìî¡°Àë×Ó¡±»ò¡°¹²¼Û¡±)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ϱíΪԪËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬Çë»Ø´ðÓйØÎÊÌ⣺

 
¢ñA
¢òA
¢óA
¢ôA
¢õA
¢öA
¢÷A
0
2
 
 
 
 
¢Ù
¢Ú
¢Û
 
3
¢Ü
¢Ý
¢Þ
¢ß
¢à
¢á
¢â
 
 
£¨1£©±íÖÐ×î»îÆõĽðÊôÊÇ          £¬·Ç½ðÊôÐÔ×îÇ¿µÄÔªËØÊÇ         £¨ÌîдԪËØ·ûºÅ£©¡£
£¨2£©±íÖÐÄÜÐγÉÁ½ÐÔÇâÑõ»¯ÎïµÄÔªËØÃû³ÆÊÇ         £¬Ð´³ö¸ÃÔªËصÄÇâÑõ»¯ÎïÓë¢ÜµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯Îï·´Ó¦µÄÀë×Ó·½³Ìʽ£º                  ¡£
£¨3£©ÔªËØ¢áºÍÔªËØ¢âµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖÐËáÐÔ½ÏÇ¿ÊÇ              £¨Óû¯Ñ§Ê½±íʾ£©¡£
£¨4£©ÔªËØ¢âÓëÔªËØ¢ÝÐγɵĻ¯ºÏÎïÊôÓÚ                (Ìî ¡°¹²¼Û¡±»ò¡°Àë×Ó¡±)»¯ºÏÎï¡£
£¨5£©Çë»­³öÔªËØ¢ÚµÄÔ­×ӽṹʾÒâͼΪ                £¬ÔªËآٵĵ¥ÖÊÔÚ³£ÎÂÏ»¯Ñ§ÐÔÖÊÎȶ¨£¬Í¨³£¿ÉÒÔ×ö±£»¤Æø£¬ÇëÓõç×Óʽ±íʾÆä·Ö×Ó          ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

A¡¢B¡¢C¡¢DÊÇËÄÖÖ¶ÌÖÜÆÚÔªËØ£¬ËüÃǵÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÆäÖУ¬A¡¢C¼°B¡¢D·Ö±ðÊÇͬÖ÷×åÔªËØ£»AÔªËصÄÔ­×Ӱ뾶ÊÇËùÓÐÖ÷×åÔªËØÖÐÔ­×Ӱ뾶×îСµÄ£»B¡¢DÁ½ÔªËصÄÔ­×ÓºËÖÐÖÊ×ÓÊýÖ®ºÍÊÇA¡¢CÁ½ÔªËØÔ­×ÓºËÖÐÖÊ×ÓÊýÖ®ºÍµÄ2±¶£»ËÄÖÖÔªËØËùÐγɵĵ¥ÖÊÖÐA¡¢Bµ¥ÖÊÊÇÆøÌ壬C¡¢Dµ¥ÖÊÊǹÌÌå¡£
£¨1£©Ð´³öÒÔÏÂÔªËصÄÃû³Æ£º B           £»C          ¡£
£¨2£©Óû¯Ñ§·½³Ìʽ±íʾC2DµÄÐγɹý³Ì£º                                         ¡£
£¨3£©ÊµÑéÊÒ³£ÓÃA¡¢BÁ½ÔªËØËùÐγɵÄÔ­×Ó¸öÊýΪ1£º1µÄ»¯ºÏÎïÀ´ÖƱ¸Ò»ÖÖ³£¼ûÆøÌ壬Æ仯ѧ·½³ÌʽΪ                                                        ¡£´ËʵÑéÖг£¼ÓÈëÒ»ÖÖºÚÉ«·ÛδÎïÖÊ£¬Æä×÷ÓÃÊÇ                      ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©Ð´³ö±íʾº¬ÓÐ8¸öÖÊ×Ó£¬10¸öÖÐ×ÓµÄÔ­×ӵĻ¯Ñ§·ûºÅ________£»
£¨2£©ÒÑÖªÒõÀë×ÓaX2£­ºÍÑôÀë×ÓbYn£«¾ßÓÐÏàͬµÄºËÍâµç×ÓÅŲ¼£¬Ôòa¡¢b¡¢nÖ®¼äµÄ¹ØϵΪa£½________£»
£¨3£©±È½ÏÏÂÁдóС£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©
A£®Ô­×Ӱ뾶£ºCl______Na
B£®ËáÐÔ£ºH2CO3______H2SiO3
£¨4£©Ä³ÔªËØRÆø̬Ç⻯ÎïµÄ»¯Ñ§Ê½ÎªRH3£¬Æä×î¸ß¼ÛÑõ»¯ÎïÖк¬ÑõÁ¿Îª£¬ÒÑÖª¸ÃÔªËصÄÔ­×ÓºËÖÐÖÐ×ÓÊýºÍÖÊ×ÓÊýÏàµÈ£¬Ôò¸ÃÔªËصÄÃû³ÆÊÇ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸