ʵÑéÊÒÀï³£ÓõĸÉÔï¼ÁÓУº¢ÙŨÁòËᣨ98%£©£¬¢ÚÎÞË®ÂÈ»¯¸Æ£¬¢Û±äÉ«¹è½º£Û¹è½ºµÄÖ÷Òª³É·ÖÊǶþÑõ»¯¹è£¬ÔÚÆäÖвôÈëÉÙÁ¿µÄÎÞË®ÂÈ»¯îÜ£¨CoCl2£©×÷ָʾ¼Á£¬ÎÞË®ÂÈ»¯îܳÊÀ¶É«£¬ÎüË®ºó±äΪCoCl2¡¤6H2O³Ê·ÛºìÉ«£Ý£¬¢ÜÎåÑõ»¯¶þÁ×£¬¢Ý¼îʯ»Ò£¨Ö÷Òª³É·ÖÊÇÇâÑõ»¯ÄÆ¡¢Ñõ»¯¸Æ£¬ÖÆ·¨ÊÇ£º°ÑÉúʯ»Ò¼Óµ½Å¨µÄÉÕ¼îÈÜÒºÖУ¬ÔÙ¼ÓÇ¿ÈÈÕô¸É£©µÈ¡£

£¨1£©Ð´³öÖÆÈ¡¸ÉÔï¼Á¼îʯ»Ò¹ý³ÌÖÐÓйط´Ó¦µÄ»¯Ñ§·½³Ìʽ£º__________________________________¡£

£¨2£©ÉÏÊöÎïÖÊÖУ¬ÊôÓÚ´¿¾»ÎïµÄÊÇ______¡£

A£®¢Ù¢Ú¢Ü B£®¢Ú¢Ü

C£®¢Ù¢Ú¢Ü¢Ý D£®È«²¿

£¨3£©ÉÏÊö¸ÉÔï¼ÁÖУ¬²»ÒËÓÃÓÚ¸ÉÔïÂÈ»¯ÇâÆøÌåµÄÊÇ______¡£

£¨4£©ÉÏÊö¢Ù¡«¢Ü£¬ÆäÖ÷Òª»¯Ñ§³É·ÖÒÀ´ÎÊôÓÚ______¡¢______¡¢______¡¢______ £¨Ìîд¸÷ÎïÖÊËùÊôµÄÀà±ð£©¡£

 

£¨1£©CaO£«H2O=Ca£¨OH£©2¡¢Ca£¨OH£©2CaO£«H2O

£¨2£©B £¨3£©¢Ý £¨4£©Ëá ÑÎ Ñõ»¯Îï Ñõ»¯Îï

¡¾½âÎö¡¿Å¨ÁòËáÊÇH2SO4ÓëË®µÄ»ìºÏÎÔÚÎïÖÊ·ÖÀàÖÐÊôÓÚË᣻ÎÞË®ÂÈ»¯¸ÆÊÇ´¿¾»Î±äÉ«¹è½ºÊÇSiO2ºÍCoCl2µÄ»ìºÏÎP2O5ÊÇ´¿¾»Î¼îʯ»ÒÊÇNaOH¡¢CaOµÄ»ìºÏÎï¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014Ä껯ѧ¸ß¿¼×ܸ´Ï°¿ÎʱÑÝÁ· 4-1ÎÞ»ú·Ç½ðÊô²ÄÁϵÄÖ÷½Ç-¹èÁ·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐÓйØ˵·¨ÕýÈ·µÄÊÇ£¨ £©

A. CO2¡¢CH4¡¢N2µÈ¾ùÊÇÔì³ÉÎÂÊÒЧӦµÄÆøÌå

B. 14C¿ÉÓÃÓÚÎÄÎï¼ø¶¨£¬14CÓë12C»¥ÎªÍ¬ËØÒìÐÎÌå

C.¶þÑõ»¯¹è²»ÓëÈκÎËá·´Ó¦£¬¿ÉÓÃʯӢÖÆÔìÄÍËáÈÝÆ÷

D.¾«Á¶´ÖÂÁʱҪÇå³ýÛáÛö±íÃæµÄʯӢɰ£¬ÂÁÓëʯӢɰ·´Ó¦µÄ·½³ÌʽΪ

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014Ä껯ѧ¸ß¿¼×ܸ´Ï°¿ÎʱÑÝÁ· 3-1ÄƼ°ÆäÖØÒª»¯ºÏÎïÁ·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁи÷·´Ó¦£¬Éú³ÉÎï²»Ëæ·´Ó¦Ìõ¼þ»ò·´Ó¦ÎïµÄÓÃÁ¿±ä»¯¶ø±ä»¯µÄÊÇ£¨ £©

A£®NaºÍO2 B£®NaOHºÍCO2 C£®NaHCO3ºÍNaOH D£®Na2CO3ÓëHCl

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014Ä껯ѧ¸ß¿¼×ܸ´Ï°¿ÎʱÑÝÁ· 2-2Àë×Ó·´Ó¦Á·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

ÓÐÒÔÏÂÎïÖÊ£º¢ÙÒº°±£»¢Ú°±Ë®£»¢ÛÑÎË᣻¢Ü´×Ë᣻¢ÝÁòËá±µ£»¢ÞÒø£»¢ßÂÈ»¯Äƾ§Ì壻¢à¶þÑõ»¯Ì¼£»¢á´×Ëá泥»¢â¾Æ¾«ÈÜÒº¡£

£¨1£©ÊôÓÚµç½âÖʵÄÊÇ_____________________________________________________________£»

£¨2£©Äܵ¼µçµÄÊÇ_________________________________________________________________£»

£¨3£©ÊôÓÚÇ¿µç½âÖʵÄÊÇ___________________________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014Ä껯ѧ¸ß¿¼×ܸ´Ï°¿ÎʱÑÝÁ· 2-2Àë×Ó·´Ó¦Á·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁз´Ó¦µÄÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ£¨ £©

A.ÂÈ»¯ÂÁÈÜÒºÖмÓÈë¹ýÁ¿°±Ë®£ºAl3++4NH3¡¤H2O=

B.Ñõ»¯ÄÆÓëË®·´Ó¦£ºO2-+H2O=2OH-

C.̼Ëá¸ÆÈÜÓÚ´×Ë᣺CaCO3+2H+=Ca2++CO2¡ü+H2O

D.ÂÈ»¯ÑÇÌúÈÜÒºÖÐͨÈëÂÈÆø£º2Fe2++Cl2=2Fe3++2Cl-

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014Ä껯ѧ¸ß¿¼×ܸ´Ï°¿ÎʱÑÝÁ· 2-1ÎïÖʵķÖÀàÁ·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÔÚÒ»¶¨Ìõ¼þÏ£¬¸úËá¡¢¼î¡¢Ñζ¼ÄÜ·¢Éú·´Ó¦µÄÎïÖÊÊÇ£¨ £©

A£®K2O B£®Na2CO3 C£®CaCO3 D£®CO2

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014Ä껯ѧ¸ß¿¼×ܸ´Ï°¿ÎʱÑÝÁ· 11-4»¯Ñ§ÊµÑé·½°¸Éè¼ÆÓëÆÀ¼ÛÁ·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

ʳÑÎÖк¬ÓÐÒ»¶¨Á¿µÄþ¡¢ÌúµÈÔÓÖÊ£¬¼ÓµâÑÎÖеâµÄËðʧÖ÷ÒªÊÇÓÉÓÚÔÓÖÊ¡¢Ë®·Ö¡¢¿ÕÆøÖеÄÑõÆøÒÔ¼°¹âÕÕ¡¢ÊÜÈȶøÒýÆðµÄ¡£ÒÑÖª£º

Ñõ»¯ÐÔ£ºIO3-£¾Fe3£«£¾I2£»»¹Ô­ÐÔ£ºS2O32-£¾I£­

3I2£«6OH£­=IO3-£«5I£­£«3H2O£»KI£«I2KI3

(1)ijѧϰС×é¶Ô¼ÓµâÑνøÐÐÈçÏÂʵÑ飺ȡһ¶¨Á¿Ä³¼ÓµâÑÎ(¿ÉÄܺ¬ÓÐKIO3¡¢KI¡¢Mg2£«¡¢Fe3£«)£¬ÓÃÊÊÁ¿ÕôÁóË®Èܽ⣬²¢¼ÓÏ¡ÑÎËáËữ£¬½«ËùµÃÊÔÒº·ÖΪ3·Ý¡£µÚÒ»·ÝÊÔÒºÖеμÓKSCNÈÜÒººóÏÔºìÉ«£»µÚ¶þ·ÝÊÔÒºÖмÓ×ãÁ¿KI¹ÌÌ壬ÈÜÒºÏÔµ­»ÆÉ«£¬ÓÃCCl4ÝÍÈ¡£¬Ï²ãÈÜÒºÏÔ×ϺìÉ«£»µÚÈý·ÝÊÔÒºÖмÓÈëÊÊÁ¿KIO3¹ÌÌåºó£¬µÎ¼Óµí·ÛÊÔ¼Á£¬ÈÜÒº²»±äÉ«¡£

¢Ù¼ÓKSCNÈÜÒººóÏÔºìÉ«£¬¸ÃºìÉ«ÎïÖÊÊÇ_____________(Óû¯Ñ§Ê½±íʾ)£»CCl4ÖÐÏÔ×ϺìÉ«µÄÎïÖÊÊÇ___________(Óõç×Óʽ±íʾ)¡£

¢ÚµÚ¶þ·ÝÊÔÒºÖмÓÈë×ãÁ¿KI¹ÌÌåºó£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ_______________________________________¡¢__________________________________________________________________¡£

(2)KI×÷Ϊ¼Óµâ¼ÁµÄʳÑÎÔÚ±£´æ¹ý³ÌÖУ¬ÓÉÓÚ¿ÕÆøÖÐÑõÆøµÄ×÷Óã¬ÈÝÒ×ÒýÆðµâµÄËðʧ¡£

д³ö³±Êª»·¾³ÏÂKIÓëÑõÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_____________________¡£

½«I2ÈÜÓÚKIÈÜÒº£¬ÔÚµÍÎÂÌõ¼þÏ£¬¿ÉÖƵÃKI3¡¤H2O¡£¸ÃÎïÖÊ×÷ΪʳÑμӵâ¼ÁÊÇ·ñºÏÊÊ£¿___________ (Ìî¡°ÊÇ¡±»ò¡°·ñ¡±)£¬²¢ËµÃ÷ÀíÓÉ_________________________________________________¡£

(3)ΪÁËÌá¸ß¼ÓµâÑÎ(Ìí¼ÓKI)µÄÎȶ¨ÐÔ£¬¿É¼ÓÎȶ¨¼Á¼õÉÙµâµÄËðʧ¡£ÏÂÁÐÎïÖÊÖÐÓпÉÄÜ×÷ΪÎȶ¨¼ÁµÄÊÇ_______¡£

A£®Na2S2O3¡¡¡¡¡¡¡¡¡¡B£®AlCl3¡¡¡¡¡¡¡¡¡¡C£®Na2CO3¡¡¡¡¡¡¡¡¡¡D£®NaNO2

(4)¶Ôº¬Fe2£«½Ï¶àµÄʳÑÎ(¼ÙÉè²»º¬Fe3£«)£¬¿ÉÑ¡ÓÃKI×÷Ϊ¼Óµâ¼Á¡£ÇëÉè¼ÆʵÑé·½°¸£¬¼ìÑé¸Ã¼ÓµâÑÎÖеÄFe2£«____________________________________________________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014Ä껯ѧ¸ß¿¼×ܸ´Ï°¿ÎʱÑÝÁ· 11-3ÎïÖʵÄÖƱ¸Á·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁйØÓÚ¸÷ʵÑé×°ÖõÄÐðÊöÖУ¬²»ÕýÈ·µÄÊÇ( )

A£®×°ÖâٿÉÓÃÓÚ·ÖÀëC2H5OHºÍH2OµÄ»ìºÏÎï

B£®×°ÖâڿÉÓÃÓÚÊÕ¼¯H2¡¢NH3¡¢CO2¡¢Cl2¡¢HCl¡¢NO2µÈÆøÌå

C£®×°ÖâÛÖÐXÈôΪCCl4£¬¿ÉÓÃÓÚÎüÊÕNH3»òHCl£¬²¢·ÀÖ¹µ¹Îü

D£®×°ÖâܿÉÓÃÓÚ¸ÉÔï¡¢ÊÕ¼¯NH3£¬²¢ÎüÊÕ¶àÓàµÄNH3

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014Ä껯ѧ¸ß¿¼×ܸ´Ï°¿ÎʱÑÝÁ· 1-2ÎïÖʵÄÁ¿ÔÚʵÑéÖеÄÓ¦ÓÃÁ·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÁòËáÍ­Ë®ÈÜÒº³ÊËáÐÔ£¬Êô±£»¤ÐÔÎÞ»úɱ¾ú¼Á£¬¶ÔÈËÐó±È½Ï°²È«£¬Æäͬʯ»ÒÈé»ìºÏ¿ÉµÃ¡°²¨¶û¶à¡±ÈÜÒº¡£ÊµÑéÊÒÀïÐèÓÃ480 mL 0.10 mol/LµÄÁòËáÍ­ÈÜÒº£¬ÔòӦѡÓõÄÈÝÁ¿Æ¿¹æ¸ñºÍ³ÆÈ¡ÈÜÖʵÄÖÊÁ¿·Ö±ðΪ£¨ £©

A.480 mLÈÝÁ¿Æ¿£¬³ÆÈ¡7.68 gÁòËáÍ­

B.480 mLÈÝÁ¿Æ¿£¬³ÆÈ¡12.0 gµ¨·¯

C.500 mLÈÝÁ¿Æ¿£¬³ÆÈ¡8.00 gÁòËáÍ­

D.500 mLÈÝÁ¿Æ¿£¬³ÆÈ¡12.5 gµ¨·¯

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸