¡¾»¯Ñ§¡ª¡ªÑ¡ÐÞ2£º»¯Ñ§Óë¼¼Êõ¡¿£¨15·Ö£©
ͨ¹ýº£Ë®ÄÜ»ñµÃµ­Ë®¡¢Ê³ÑΡ¢Ã¾µÈ£¬Ê³ÑοɽøÒ»²½ÓÃÓÚÂȼҵ¡£Çë»Ø´ðÏÂÁÐÎÊÌâ¡£
£¨1£©ÁоÙÁ½ÖÖº£Ë®µ­»¯µÄ·½·¨£º_________¡¢_________¡£
£¨2£©Âȼҵͨ¹ýµç½â±¥ºÍʳÑÎË®ÄÜ»ñµÃÉÕ¼îºÍÂÈÆøµÈÎïÖÊ£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________£¬ÈçͼÊÇÓÃÀë×Ó½»»»Ä¤·¨µç½â±¥ºÍʳÑÎË®µÄÔ­ÀíʾÒâͼ¡£ÆäÖÐʯī½ÓµçÔ´_________¼«£¬µç½âʱÌúµç¼«µÄµç¼«·´Ó¦Ê½Îª_________¡£µç½â¹ý³ÌÖÐͨ¹ýÀë×Ó½»»»Ä¤µÄÖ÷ÒªÀë×ÓÊÇ__________¡£

£¨3£©ºîÊÏÖƼÖУ¬Ê×ÏÈÏò±¥ºÍʳÑÎË®ÖÐͨÈëCO2ºÍNH3ÖƱ¸NaHCO3£¬Æ仯ѧ·½³ÌʽΪ____________£»ÏÈͨÈëµÄÊÇ__________£¨Ìѧʽ£©£¬ÆäÀíÓÉÊÇ__________________ £»ÔÙÀûÓÃNaHCO3ÊÜÈÈ·Ö½â¿ÉÖƱ¸´¿¼î¡£
£¨4£©Ä¿Ç°ÊÀ½çÉÏ60%ÒÔÉϵÄþ¶¼ÊÇ´Óº£Ë®ÖÐÌáÈ¡µÄ£¬ÒÑÖª£ºMgOºÍMgCl2µÄÈÛµã·Ö±ðΪ2852¡æºÍ714¡æ¡£·ÖÎö˵Ã÷¹¤ÒµÉϲÉÓõç½âÈÛÈÚMgCl2¶ø²»Êǵç½âÈÛÈÚMgOµÄÀíÓÉ__________    ______________________________________________________________________ ¡£


£¨1£©ÕôÁ󷨡¢Àë×Ó½»»»·¨¡¢µçÉøÎö·¨£¨ÈÎÑ¡Á½¸ö£©£¨2·Ö£©
£¨2£©2NaCl+2H2Oµç½â2NaOH+H2¡ü+Cl2¡ü£¨2·Ö£©    Õý£¨1·Ö£©     2H++2e-H2¡ü£¨2·Ö£©  
Na+ºÍH+£¨1·Ö£©
£¨3£©NaCl+NH3+CO2+H2ONaHCO3+NH4Cl£¨2·Ö£©   NH3£¨1·Ö£©    NH3¼«Ò×ÈÜÓÚNaClÈÜÒº£¬¶øCO2ÔÚNaClÈÜÒºÖÐÈܽâ¶ÈºÜС£¨2·Ö£©
£¨4£©ÓÉÓÚÈÛµãMgO£¾MgCl2£¬µç½âMgOºÄ·Ñµç¶à£¬¶øµç½âMgCl2ºÄµç½ÏÉÙ£¨2·Ö£©

½âÎöÊÔÌâ·ÖÎö£º
£¨1£©ÕôÁ󷨡¢Àë×Ó½»»»·¨¡¢µçÉøÎö·¨£¨ÈÎÑ¡Á½¸ö£©
£¨2£©2NaCl+2H2Oµç½â2NaOH+H2¡ü+Cl2¡ü    Õý    2H++2e-H2¡ü  
Na+ºÍH+
£¨3£©NaCl+NH3+CO2+H2ONaHCO3+NH4Cl   NH3    NH3¼«Ò×ÈÜÓÚNaClÈÜÒº£¬¶øCO2ÔÚNaClÈÜÒºÖÐÈܽâ¶ÈºÜС
£¨4£©ÓÉÓÚÈÛµãMgO£¾MgCl2£¬µç½âMgOºÄ·Ñµç¶à£¬¶øµç½âMgCl2ºÄµç½ÏÉÙ
¿¼µã£º¿¼²é»¯Ñ§ÔÚÉú»îÖеÄÓ¦Óá£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÓйؽðÊôµÄ¹¤ÒµÖÆ·¨ÖУ¬ÕýÈ·µÄÊÇ£¨  £©

A£®Á¶Í­£ºÓûÆÍ­¿ó£¨Ö÷Òª³É·ÖΪCuFeS2£©Ö±½Óµç½â¾«Á¶µÃµ½´¿¶ÈΪ99.9%µÄÍ­
B£®ÖÆÂÁ£º¹¤ÒµÉϵç½âÂÈ»¯ÂÁÀ´ÖƱ¸ÂÁ
C£®ÖÆÄÆ£ºµç½â±¥ºÍNaClÈÜÒº
D£®Á¶Ìú£ºÓÃCOÔÚ¸ßÎÂÏ»¹Ô­Ìú¿óʯÖеÄÌú

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁнðÊôͨ³£²ÉÓüÓÈÈ·Ö½âµÄ·½·¨À´Ò±Á¶µÄÊÇ (     )

A£®Na B£®Al C£®Fe D£®Ag

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐ˵·¨ÖУ¬²»ÕýÈ·µÄÊÇ

A£®ÓÃÕôÁó·¨ÄÜ´Óº£Ë®ÖÐÌáÈ¡µ­Ë®
B£®´Óº£Ë®ÖпÉÒԵõ½ÂÈ»¯Ã¾£¬ÔÙ¼ÓÈÈ·Ö½â¿ÉÖƽðÊôþ
C£®ÓÃÂÈÆø´Óº£Ë®ÖÐÌáäåµÄ¹Ø¼ü·´Ó¦ÊÇCl2+2Br£­= 2Cl£­+Br2
D£®ÃºµÄÆø»¯Ö÷Òª·´Ó¦ÊÇ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£¨12·Ö£©Ä¿Ç°ÊÀ½çÉÏ60%µÄþÊÇ´Óº£Ë®ÌáÈ¡µÄ¡£º£Ë®ÌáþµÄÖ÷ÒªÁ÷³ÌÈçÏ£º

Ìáʾ£º ¢ÙMgCl2¾§ÌåµÄ»¯Ñ§Ê½ÎªMgCl2?6H2O£»
¢ÚMgOµÄÈÛµãΪ2852¡æ£¬ÎÞË®MgCl2µÄÈÛµãΪ714¡æ¡£
£¨1£©²Ù×÷¢ÙµÄÃû³ÆÊÇ         £¬ ²Ù×÷¢ÚµÄÃû³Æ          ¡¢        ¡¢¹ýÂË¡£
£¨2£©ÊÔ¼ÁaµÄÃû³ÆÊÇ            ¡£
£¨3£©ÓÃÂÈ»¯Ã¾µç½âÉú²ú½ðÊôþµÄ»¯Ñ§·½³ÌʽΪ£º                    ¡£
£¨4£©¹¤ÒµÉÏÊǽ«ÇâÑõ»¯Ã¾×ª±äΪÂÈ»¯Ã¾£¬ÔÙµç½âÂÈ»¯Ã¾À´ÖÆȡþµ¥ÖÊ£»¶ø²»²ÉÓ㺼ÓÈÈMg(OH)2µÃµ½MgO£¬ÔÙµç½âÈÛÈÚMgOµÄ·½·¨ÖƽðÊôþ£¬ÆäÔ­ÒòÊÇ      ¡¡¡¡                                ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

Ä¿Ç°ÊÀ½çÉÏ60%µÄþÊÇ´Óº£Ë®ÖÐÌáÈ¡µÄ¡£º£Ë®ÌáþµÄÖ÷ÒªÁ÷³ÌÈçÏÂ:

Çë»Ø´ðÏÂÁÐÎÊÌâ:
(1)´ÓÀë×Ó·´Ó¦µÄ½Ç¶È˼¿¼,ÔÚº£Ë®ÖмÓÈëʯ»ÒÈéµÄ×÷ÓÃÊÇ¡¡¡¡¡¡¡¡,д³öÔÚ³Áµí³ØÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 
(2)ʯ»ÒÈéÊÇÉúʯ»ÒÓëË®ÐγɵĻ¯ºÏÎï,´Ó³ä·ÖÀûÓú£Ñó»¯Ñ§×ÊÔ´,Ìá¸ß¾­¼ÃЧÒæµÄ½Ç¶È,Éú²úÉúʯ»ÒµÄÖ÷ÒªÔ­ÁÏÀ´Ô´ÓÚº£ÑóÖеġ¡¡¡¡¡¡¡¡£ 
(3)²Ù×÷AÊÇ¡¡¡¡¡¡¡¡,²Ù×÷BÊÇ¡¡¡¡¡¡¡¡¡£ 
(4)¼ÓÈëµÄ×ãÁ¿ÊÔ¼ÁaÊÇ¡¡¡¡¡¡¡¡(Ìѧʽ)¡£ 
(5)ÎÞË®MgCl2ÔÚÈÛÈÚ״̬ÏÂ,ͨµçºó»á²úÉúMgºÍCl2,¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡£´Ó¿¼Âdzɱ¾ºÍ·ÏÎïÑ­»·ÀûÓõĽǶÈ,¸±²úÎïÂÈÆø¿ÉÒÔÓÃÓÚ¡¡¡¡¡¡¡¡¡£ 
(6)º£Ë®ÌáþµÄ¹ý³Ì,ΪʲôҪ½«º£Ë®ÖеÄÂÈ»¯Ã¾×ª±äΪÇâÑõ»¯Ã¾,ÔÙת±äΪÂÈ»¯Ã¾?
_____________________________________________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÔĶÁÒÔÏÂÄÚÈÝ£¬»Ø´ðÎÊÌâ¡£
Ò±Á¶½ðÊôÒ»°ãÓÐÏÂÁÐËÄÖÖ·½·¨£º¢Ù½¹Ì¿·¨£»¢ÚˮúÆø(»òH2£¬»òCO)·¨£»¢Û»îÆýðÊôÖû»·¨£»¢Üµç½â·¨¡£ËÄÖÖ·½·¨¸÷ÓÐÓÅȱµã£¬ÔÚ¹¤ÒµÉϾùÓÐÓ¦Óá£
(1)Ò»ÖÖÎÞÉ«ÆøÌåAÓëºìÈȵÄÌ¿·´Ó¦£¬µÃµ½ÁíÒ»ÖÖÎÞÉ«ÆøÌåB£¬BÓë×ÆÈȵÄÑõ»¯Í­·´Ó¦£¬Óֵõ½A£¬ÔòA¡¢B·Ö±ðΪ_______(ÌîÐòºÅ)¡£
A.O2¡¢CO2         B.O2¡¢CO         C.CO2¡¢CO         D.CO¡¢CO2
(2)ÏÂÁÐ˵·¨´íÎóµÄÊÇ_______(ÌîÐòºÅ)¡£
A.¶Ô·Ï¾É½ðÊôµÄ×îºÃ´¦Àí·½·¨ÊÇ»ØÊÕÔÙÀûÓÃ
B.ÌáÁ¶½ðÊôÒª¾­¹ý¿óʯµÄ¸»¼¯¡¢Ò±Á¶¡¢¾«Á¶Èý²½
C.»îÆýðÊôµÄÒ±Á¶¶¼ÊÇͨ¹ýµç½âÆäÑÎÈÜÒºÖƵÃ
D.ÈÈ»¹Ô­·¨Öл¹Ô­¼ÁÓн¹Ì¿¡¢Ò»Ñõ»¯Ì¼¡¢ÇâÆø»ò»îÆýðÊôµÈ
(3)îÑ(Ti)ÓС°Î´À´¸ÖÌú¡±Ö®³Æ¡£¹¤ÒµÉϳ£ÒÔ£ºTiCl4+2MgTi+2MgCl2»ñµÃº£Ãà×´îÑ¡£¸Ã·´Ó¦ÔÚÏÂÁÐÄÄÖÖ»·¾³ÖнøÐÐ_______ (ÌîÐòºÅ)¡£
A.Ï¡ÓÐÆøÌåÖР      B.¿ÕÆøÖР       C.µªÆøÖР       D.CO2ÆøÌåÖÐ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

¹¤ÒµÉÏÒÔ»ÆÌú¿óΪԭÁÏÉú²úÁòËáÖ÷Òª·ÖΪÈý¸ö½×¶Î½øÐУ¬¼´ìÑÉÕ¡¢´ß»¯Ñõ»¯¡¢ÎüÊÕ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ìÑÉÕ»ÆÌú¿óÐγɵįÆø±ØÐë¾­³ý³¾¡¢Ï´µÓ¡¢¸ÉÔïºó½øÈë           (ÌîÉ豸Ãû³Æ)£¬ÆäÖ÷ҪĿµÄÊÇ                ¡£
(2)´ß»¯Ñõ»¯ËùʹÓõĴ߻¯¼Á·°´¥Ã½(V2O5)Äܼӿì¶þÑõ»¯ÁòÑõ»¯ËÙÂÊ£¬´Ë¹ý³ÌÖвúÉúÁËÒ»Á¬´®µÄÖмäÌå(Èçͼ1)

ÆäÖÐa¡¢c¶þ²½·´Ó¦µÄ»¯Ñ§·½³Ìʽ¿É±íʾΪ£º           ¡¢         ¡£
(3)550¡æʱ£¬SO2ת»¯ÎªSO3µÄƽºâת»¯ÂÊ(¦Á)ÓëÌåϵ×Üѹǿ(P)µÄ¹ØϵÈçͼ2Ëùʾ£¬

Ôò£º½«2.0mol SO2ºÍ1.0mol O2ÖÃÓÚ5LÃܱÕÈÝÆ÷ÖУ¬·´Ó¦´ïƽºâºó£¬Ìåϵ×ÜѹǿΪ0.10M Pa£¬AÓëB±íʾ²»Í¬Ñ¹Ç¿ÏµÄSO2ת»¯ÂÊ£¬Í¨³£Çé¿öϹ¤ÒµÉú²úÖвÉÓó£Ñ¹µÄÔ­ÒòÊÇ£º       ¡£
(4)Ϊѭ»·ÀûÓô߻¯¼Á£¬¿ÆÑÐÈËÔ±×îÐÂÑÐÖÆÁËÒ»ÖÖÀë×Ó½»»»·¨»ØÊÕ·°µÄй¤ÒÕ£¬»ØÊÕÂÊ´ï91.7%ÒÔÉÏ¡£ÒÑÖª·Ï·°´ß»¯¼ÁÖк¬ÓÐV2O5¡¢VOSO4¼°²»ÈÜÐÔ²ÐÔü£¬²éÔÄ×ÊÁÏÖª£ºVOSO4¿ÉÈÜÓÚË®£¬V2O5ÄÑÈÜÓÚË®£¬NH4VO3ÄÑÈÜÓÚË®¡£¸Ã¹¤ÒÕµÄÁ÷³ÌÈçͼÈçÏ£º

Ôò·´Ó¦¢Ù¢Ú¢Û¢ÜÖÐÊôÓÚÑõ»¯»¹Ô­·´Ó¦µÄÊÇ           (ÌîÊý×ÖÐòºÅ)£¬·´Ó¦¢ÙµÄÀë×Ó·½³ÌʽΪ                                       £¬¸Ã¹¤ÒÕÖз´Ó¦¢ÛµÄ³ÁµíÂÊ(ÓֳƳÁ·°ÂÊ)ÊÇ»ØÊÕ·°µÄ¹Ø¼üÖ®Ò»£¬³Á·°ÂʵĸߵͳýÊÜÈÜÒºpHÓ°ÏìÍ⣬»¹ÐèÒª¿ØÖÆÂÈ»¯ï§ÏµÊý(NH4Cl¼ÓÈëÖÊÁ¿ÓëÁÏÒºÖÐV2O5µÄÖÊÁ¿±È)ºÍζȡ£¸ù¾ÝÏÂͼÊÔ½¨Òé¿ØÖÆÂÈ»¯ï§ÏµÊýºÍζȣº           ¡¢           ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºµ¥Ñ¡Ìâ

ϱíÖнðÊôµÄÒ±Á¶Ô­ÀíÓë·½·¨²»ÍêÈ«ÕýÈ·µÄÊÇ£¨ £©

 
Ò±Á¶Ô­Àí
·½·¨
A
2HgO2Hg£«O2¡ü
Èȷֽⷨ
B
2Al2O3£¨ÈÛÈÚ£©4Al£«3O2¡ü
µç½â·¨
C
Cu2S£«O22Cu£«SO2
Èȷֽⷨ
D
Fe2O3£«2Al2Fe£«Al2O3
ÈÈ»¹Ô­·¨
 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸