¼×¡¢ÒÒ¡¢±ûÊÇÈýÖÖ²»º¬ÏàͬÀë×ӵĿÉÈÜÐÔÇ¿µç½âÖÊ¡£ËüÃÇËùº¬µÄÀë×ÓÈçϱíËùʾ£º

ÑôÀë×Ó
NH4+¡¢Na£«¡¢Mg2£«
ÒõÀë×Ó
OH£­¡¢NO3¡ª¡¢SO42¡ª
 
È¡µÈÖÊÁ¿µÄÈýÖÖ»¯ºÏÎïÅäÖƳÉÏàͬÌå»ýµÄÈÜÒº£¬ÆäÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶È£ºc(¼×)£¾c(ÒÒ)£¾c(±û)¡£
(1)¼×ÊÇ________£¬ÏòAlCl3ÈÜÒºÖÐÖðµÎ¼ÓÈë¼×ÈÜÒº£¬¹Û²ìµ½µÄÏÖÏóÊÇ________£¬¶ÔÓ¦µÄÀë×Ó·½³ÌʽΪ________¡£
(2)ÒÒÊÇ______£¬Éè¼ÆʵÑéÈ·¶¨ÒÒµÄÎïÖÊ×é³É________(ÈôÒÒÒÑÈ·¶¨£¬Ôò²»Ìî¸Ã¿Õ)¡£

(1)NaOH¡¡ÏÈÉú³É°×É«³Áµí£¬¼ÌÐøµÎ¼Ó£¬°×É«³ÁµíÏûʧ¡¡Al3£«£«3OH£­=Al(OH)3¡ý¡¢Al(OH)3£«OH£­=AlO2¡ª£«2H2O
(2)(NH4)2SO4»òNH4NO3¡¡È¡ÒÒÈÜÒºÓÚСÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿BaCl2ÈÜÒº£¬ÈôÓа×É«³ÁµíÎö³ö£¬ÔòÒÒÊÇ(NH4)2SO4£¬ÈôÎÞÃ÷ÏÔÏÖÏó£¬ÔòÒÒÊÇNH4NO3

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£¨13·Ö£©Ä³Ç¿ËáÐÔÈÜÒºX¿ÉÄܺ¬ÓÐBa2+¡¢A13+¡¢NH4+¡¢Fe2+¡¢Fe3+¡¢CO32-¡¢SO32-¡¢SO42-¡¢C1-¡¢NO3-ÖеÄÒ»ÖÖ»ò¼¸ÖÖ£¬È¡¸ÃÈÜÒº½øÐÐÁ¬ÐøʵÑ飬ʵÑé¹ý³ÌÈçÏ£º¸ù¾ÝÒÔÉÏÐÅÏ¢£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÆøÌåFΪ____________¡£
£¨2£©ÉÏÊöÀë×ÓÖУ¬ÈÜÒºXÖгýH+Í⻹¿Ï¶¨º¬ÓеÄÀë×ÓÊÇ_______£¬²»ÄÜÈ·¶¨ÊÇ·ñº¬ÓеÄÀë×ÓÊÇ____¡£
£¨3£©Ð´³öÉú³ÉAµÄÀë×Ó·½³Ìʽ£º_________________¡£
£¨4£©Í¨³£¿ÉÒÔÀûÓÃKClOÔÚ¼îÐÔÌõ¼þÏÂÑõ»¯GÀ´ÖƱ¸Ò»ÖÖÐÂÐÍ¡¢¸ßЧ¡¢¶à¹¦ÄÜË®´¦Àí¼ÁK2FeO4£®Çëд³öÖƱ¸¹ý³ÌÖеÄÀë×Ó·½³Ìʽ__________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ



Ìáʾ£ºÔÚ±¾ÊµÁ³Ìõ¼þÏ£¬Ni(¢ò)²»Äܱ»Ñõ»¯£º¸ßÃÌËá¼ØµÄ»¹Ô­²úÎïÊÇMnO2
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©·´Ó¦¢ÚÖгýµôµÄÔÓÖÊÀë×ÓÊÇ                     £¬·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                             £»ÔÚ¼Ó¸ßÃÌËá¼ØÈÜҺǰ£¬ÈôpH½ÏµÍ£¬¶Ô³ýÔÓµÄÓ°ÏìÊÇ                                                           ¡£
£¨2£©·´Ó¦¢ÛµÄ·´Ó¦ÀàÐÍΪ     £¬¹ýÂ˵õ½µÄÂËÔüÖУ¬³ýÁ˹ýÁ¿µÄпÍ⻹ÓР                                           ¡£
£¨3£©·´Ó¦¢ÜÐγɵijÁµíÒªÓÃˮϴ£¬¼ìÑé³ÁµíÊÇ·ñÏ´µÓ¸É¾»µÄ·½·¨ÊÇ                                                ¡£
£¨4£©·´Ó¦¢ÜÖвúÎïµÄ³É·Ö¿ÉÄÜÊÇZnCO3¡¤xZn(OH)2È¡¸É²ÙºóµÄÂ˱ý11.2g£¬ìÑÉÕºó¿ÉµÃµ½²úÆ·8.1g£¬ÔòxµÈÓÚ                    ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©½«Ò»¶¨Á¿µÄFe·Û¡¢Cu·Û¡¢FeCl3ÈÜÒº¡¢CuCl2ÈÜÒº»ìºÏÓÚijÈÝÆ÷Öгä·Ö·´Ó¦(¼Ù¶¨ÈÝÆ÷²»²ÎÓë·´Ó¦)£¬ÅжÏÏÂÁÐÇé¿öÏÂÈÝÆ÷ÖнðÊôÀë×ÓÓë½ðÊôµ¥ÖʵĴæÔÚÇé¿ö£º£¨Ó÷ûºÅ±íʾ£©
¢ÙÈôFe·ÛÓÐÊ£Ó࣬ÔòÈÝÆ÷Öв»¿ÉÄÜÓÐ____________£»
¢ÚÈôFeCl3ÓÐÊ£Ó࣬ÔòÈÝÆ÷Öв»¿ÉÄÜÓÐ___________£»
¢ÛÈôCuCl2ÓÐÊ£Ó࣬ÔòÈÝÆ÷Öл¹¿ÉÄÜÓÐ____________¡£
£¨2£©ÓÐһƿÎÞÉ«³ÎÇåÈÜÒº,¿ÉÄܺ¬NH4£«¡¢K£«¡¢Na £«¡¢Mg2£«¡¢Ba2£«¡¢ Al3£«¡¢ Fe3£«¡¢SO42£­¡¢CO32£­¡¢Cl£­¡¢I£­ÖеÄÒ»ÖÖ»ò¼¸ÖÖ£¬È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺
¢ÙÓÃpHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜÒº³ÊËáÐÔ£»
¢ÚÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÉÙÁ¿CCl4¼°ÊýµÎÐÂÖƵÄÂÈË®£¬¾­Õñµ´ºó¾²Öã¬CCl4²ã³Ê×ϺìÉ«£»
¢ÛÈ¡²¿·ÖÈÜÒº£¬ÖðµÎ¼ÓÈëÏ¡NaOHÈÜÒº£¬Ê¹ÈÜÒº´ÓËáÐÔÖð½¥×ª±äΪ¼îÐÔ£¬Ôڵμӹý³ÌÖм°µÎ¼ÓÍê±Ïºó£¬ÈÜÒºÖоùÎÞ³ÁµíÉú³É£»
¢ÜÈ¡²¿·ÖÉÏÊö³Ê¼îÐÔµÄÈÜÒº£¬¼ÓNa2CO3ÈÜÒº£¬Óа×É«³ÁµíÉú³É£»
¢Ý½«¢ÛµÃµ½µÄ¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶¡£
¸ù¾ÝÉÏÊöʵÑéÊÂʵȷ¶¨²¢»Ø´ð£ºÔÚÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÓС¡¡¡¡¡               £¬¿Ï¶¨²»´æÔÚµÄÀë×ÓÓС¡     ¡¡           £¬ÒªÈ·¶¨ÊÇ·ñ´æÔÚµÄÒõÀë×ÓµÄʵÑé·½·¨ÊÇ____________               ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÓйØFeSO4µÄת»¯¹ØϵÈçͼËùʾ(²¿·ÖÎïÖÊÒÑÂÔÈ¥)¡£

ÒÑÖª£º¢ÙXÓÉÁ½ÖÖ»¯ºÏÎï×é³É£¬½«XͨÈëÆ·ºìÈÜÒº£¬ÈÜÒºÍÊÉ«£»Í¨ÈëBaCl2ÈÜÒº£¬²úÉú°×É«³Áµí¡£
¢ÚYÊǺì×ØÉ«µÄ»¯ºÏÎï¡£
(1)ÆøÌåXµÄ³É·ÖÊÇ(Ìѧʽ)       ¡£
(2)·´Ó¦¢ñµÄ·´Ó¦ÀàÐÍÊôÓÚ(ÌîÐòºÅ)       ¡£
a£®·Ö½â·´Ó¦  b£®¸´·Ö½â·´Ó¦
c£®Öû»·´Ó¦  d£®»¯ºÏ·´Ó¦
e£®Ñõ»¯»¹Ô­·´Ó¦
(3)ÈÜÒº2ÖнðÊôÑôÀë×ӵļìÑé·½·¨ÊÇ                               ¡£
(4)Èô¾­·´Ó¦¢ñµÃµ½16 g¹ÌÌåY£¬²úÉúµÄÆøÌåXÇ¡ºÃ±»0.4 L 1 mol¡¤L£­1 NaOHÈÜÒºÍêÈ«ÎüÊÕ£¬Ôò·´Ó¦¢ôÖÐÉú³ÉFeSO4µÄÀë×Ó·½³ÌʽÊÇ                                               ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ij´ý²âÈÜÒºÖпÉÄܺ¬ÓÐSO42-¡¢SO32-¡¢CO32-¡¢HCO3-¡¢NO3-¡¢Cl£­¡¢Br£­ÖеÄÈô¸ÉÖÖ¼°Ò»ÖÖ³£¼û½ðÊôÑôÀë×Ó(Mn£«)£¬ÏÖ½øÐÐÈçÏÂʵÑé(ÿ´ÎʵÑéËùÓÃÊÔ¼Á¾ùÊÇ×ãÁ¿µÄ£¬¼ø¶¨ÖÐijЩ³É·Ö¿ÉÄÜûÓиø³ö)¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)¸ù¾ÝÉÏÊö¿òͼÐÅÏ¢Ìîдϱí(²»ÄÜÈ·¶¨µÄ²»Ìî)¡£

 
¿Ï¶¨´æÔÚµÄÀë×Ó
¿Ï¶¨Ã»ÓеÄÀë×Ó
³ÁµíD
»¯Ñ§Ê½»òÀë×Ó·ûºÅ
 
 
 
 
(2)´ý²âÈÜÒºÖÐÊÇ·ñÓÐSO32-¡¢SO42-             ¡£ÈôÆøÌåDÓö¿ÕÆø±äºìÉ«£¬ÔòÉú³É³ÁµíDʱ¿Ï¶¨·¢ÉúµÄ·´Ó¦µÄÀë×Ó·½³ÌʽΪ             £¬ÐγɳÁµíBʱ·´Ó¦µÄÀë×Ó·½³ÌʽΪ             ¡£
(3)ÈôMn£«Îª³£¼û½ðÊôÑôÀë×ÓÇÒÔ­×ÓÐòÊý²»´óÓÚ20£¬ÔòҪȷ¶¨Ëü¾ßÌåÊǺÎÖÖÀë×ӵķ½·¨ÊÇ                                                     ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ


¢ñ.¸ßÌúËá¼Ø(K2FeO4)ÊǼ«ºÃµÄÑõ»¯¼Á£¬¾ßÓиßЧµÄÏû¶¾×÷Óã¬ÎªÒ»ÖÖÐÂÐÍ·ÇÂȸßЧÏû¶¾¼Á¡£ÆäÉú²ú¹¤ÒÕÁ÷³ÌÈçÏ£º
 
Çëͬ´ðÏÂÁÐÎÊÌâ¡£
£¨1£©Ð´³öÏòKOHÈÜÒºÖÐͨÈë×ãÁ¿Cl2·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ                  ¡£
£¨2£©ÔÚÈÜÒºIÖмÓÈëKOH¹ÌÌåµÄÄ¿µÄÊÇ     (Ñ¡ÌîÐòºÅ)¡£

A£®ÎªÏÂÒ»²½·´Ó¦Ìṩ¼îÐԵĻ·¾³
B£®Ê¹KClO3ת»¯ÎªKClO
C£®ÓëÈÜÒºIÖйýÁ¿µÄCl2¼ÌÐø·´Ó¦£¬Éú³É¸ü¶àµÄKClO
D£®KOH¹ÌÌåÈܽâ»á·Å³ö½Ï¶àµÄÈÈÁ¿£¬ÓÐÀûÓÚÌá¸ß·´Ó¦ËÙÂʺÍKClOµÄ´¿¶È
£¨3£©´ÓÈÜÒº¢òÖзÖÀë³öK2FeO4ºó£¬»¹»áÓи±²úÆ·KNO3¡¢KCl£¬Ôò·´Ó¦¢ÛÖз¢ÉúµÄÀë×Ó·´Ó¦·½³ÌʽΪ                            ¡£ÒªÖƵÃ69.3¿ËK2FeO4£¬ÀíÂÛÉÏÏûºÄÑõ»¯¼ÁµÄÎïÖʵÄÁ¿Îª      mol¡£
£¨4£©¸ßÌúµç³ØÊÇÒ»ÖÖÐÂÐͶþ´Îµç³Ø£¬µç½âҺΪ¼îÈÜÒº£¬Æ䷴ӦʽΪ£º
3Zn(OH)2+2Fe(OH)3+4KOH3Zn+2K2FeO4+8H2O£¬
·Åµçʱµç³ØµÄ¸º¼«·´Ó¦Ê½Îª                          ¡£
¢ò.ëÂ(N2H4)ÓÖ³ÆÁª°±£¬ÊÇÒ»ÖÖ¿ÉȼÐÔµÄÒºÌ壬ÓÃ×÷»ð¼ýȼÁÏ¡£
£¨5£©Ð´³öë·Ö×ӵĵç×Óʽ                  ¡£
£¨6£©ëÂÄÜÓëN2O4·´Ó¦£º2N2H4(g)£«N2O4(g)=3N2(g)£«4H2O(g)  ¦¤H£½£­1076.7 kJ/mol¡£
ÒÑÖª£ºN2(g)£«2O2(g)=N2O4(g)¡¡¦¤H£½£«8.7 kJ/mol£¬ д³öëÂÓëO2·´Ó¦Éú³ÉN2ºÍH2O(g)µÄÈÈ»¯Ñ§·½³Ìʽ                                                  ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

¹¤Òµ·ÏË®Öг£º¬ÓÐÒ»¶¨Á¿µÄCr2O72¡ªºÍCrO42¡ª£¬ËüÃÇ»á¶ÔÈËÀ༰Éú̬ϵͳ²úÉúºÜ´óµÄÉ˺¦£¬±ØÐë½øÐд¦Àí¡£¸Ã·¨µÄ¹¤ÒÕÁ÷³ÌΪ

ÆäÖеڢٲ½´æÔÚƽºâ£º2CrO42¡ª£¨»ÆÉ«£©+2H+Cr2O72¡ª£¨³ÈÉ«£©+H2O
£¨1£©ÈôƽºâÌåϵµÄpH=2£¬ÔòÈÜÒºÏÔ           É«¡£
£¨2£©ÄÜ˵Ã÷µÚ¢Ù²½·´Ó¦´ïƽºâ״̬µÄÊÇ     ¡££¨Ñ¡Ìî±àºÅ£©

A£®Cr2O72¡ªºÍCrO42¡ªµÄŨ¶ÈÏàͬB£®vÕý(Cr2O72¡ª) ="2v" Äæ(CrO42¡ª)
C£®ÈÜÒºµÄÑÕÉ«²»±äD£®ÈÜÒºµÄpHÖµ²»±ä
£¨3£©Ð´³öµÚ¢Ú²½ÖÐCr2O72£­×ª±äΪCr3£«µÄÀë×Ó·½³Ìʽ£º                           ¡£
£¨4£©ÏòCr2(SO4)3ÈÜÒºÖУ¬µÎ¼ÓNaOH£¬µ±pH£½4.6ʱ£¬¿ªÊ¼³öÏÖCr(OH)3³Áµí£¬Ëæ×ÅpHµÄÉý¸ß£¬³ÁµíÔö¶à£¬µ«µ±pH¡Ý13ʱ£¬³ÁµíÏûʧ£¬³öÏÖÁÁÂÌÉ«µÄ[Cr(OH)4]£­Àë×Ó¡£Æäƽºâ¹ØϵÈçÏ£º

ÏÖÏò0.05mol¡¤L£­1µÄCr2(SO4)3ÈÜÒº50mLÖУ¬¼ÓÈëµÈÌå»ý0.6 mol¡¤L£­1µÄNaOHÈÜÒº£¬³ä·Ö·´Ó¦ºó£¬ÈÜÒºÖпɹ۲쵽µÄÏÖÏóΪ      £¬ÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ       ¡£
£¨5£©ÔÚNa[Cr(OH)4]ºÍNa2Cr2O7»ìºÏºóµÄÈÜÒºÖмÓÈëH2SO4Ëữ£¬¸õÔªËØÒÔ             ÐÎʽ´æÔÚ£¨ÌîдÀë×Ó·ûºÅ£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

¶þÑõ»¯ÂÈ£¨ClO2£©ÊÇÄ¿Ç°¹ú¼ÊÉϹ«ÈϵĵÚËÄ´ú¸ßЧ¡¢ÎÞ¶¾µÄÏû¶¾¼Á£¬ÊÇÒ»ÖÖ»ÆÂÌÉ«µÄÆøÌ壬Ò×ÈÜÓÚË®¡£
¢ñ.£¨1£©ClO2¿ÉÓÉKClO3ÔÚH2SO4´æÔÚµÄÌõ¼þÏÂÓëNa2SO3·´Ó¦ÖƵá£Ôò¸Ã·´Ó¦µÄÑõ»¯²úÎïÓ뻹ԭ²úÎïµÄÎïÖʵÄÁ¿Ö®±ÈÊÇ________¡£
¢ò.ʵÑéÊÒÒ²¿ÉÓÃNH4Cl¡¢ÑÎËá¡¢NaClO2£¨ÑÇÂÈËáÄÆ£©ÎªÔ­ÁÏÖƱ¸ClO2£¬ÆäÁ÷³ÌÈçÏ£º

£¨2£©Ð´³öµç½âʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________________________________¡£
£¨3£©³ýÈ¥ClO2ÖеÄNH3¿ÉÑ¡ÓõÄÊÔ¼ÁÊÇ________¡££¨ÌîÐòºÅ£©

A£®±¥ºÍʳÑÎË®B£®¼îʯ»Ò
C£®Å¨ÁòËáD£®Ë®
£¨4£©²â¶¨ClO2£¨Èçͼ£©µÄ¹ý³ÌÈçÏ£ºÔÚ׶ÐÎÆ¿ÖмÓÈë×ãÁ¿µÄµâ»¯¼Ø£¬ÓÃ100 mLË®Èܽâºó£¬ÔÙ¼Ó3 mLÁòËáÈÜÒº£»ÔÚ²£Á§Òº·â¹ÜÖмÓÈëË®£»½«Éú³ÉµÄClO2ÆøÌåͨ¹ýµ¼¹ÜÔÚ׶ÐÎÆ¿Öб»ÎüÊÕ£»½«²£Á§·â¹ÜÖеÄË®·âÒºµ¹Èë׶ÐÎÆ¿ÖУ¬¼ÓÈ뼸µÎµí·ÛÈÜÒº£¬ÓÃc mol¡¤L£­1Áò´úÁòËáÄƱê×¼ÈÜÒºµÎ¶¨£¨I2£«2S2O32-=2I£­£«S4O62-£©£¬¹²ÓÃÈ¥V mLÁò´úÁòËáÄÆÈÜÒº¡£

¢Ù×°ÖÃÖв£Á§Òº·â¹ÜµÄ×÷ÓÃÊÇ______________________________________¡£
¢ÚÇëд³öÉÏÊö¶þÑõ»¯ÂÈÆøÌåÓëµâ»¯¼ØÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ__________________________¡£
¢ÛµÎ¶¨ÖÕµãµÄÏÖÏóÊÇ_______________________________________________¡£
¢Ü²âµÃͨÈëClO2µÄÖÊÁ¿m£¨ClO2£©£½________¡££¨Óú¬c¡¢VµÄ´úÊýʽ±íʾ£©
£¨5£©ÓÃClO2´¦Àí¹ýµÄÒûÓÃË®£¨pHΪ5.5¡«6.5£©³£º¬ÓÐÒ»¶¨Á¿¶ÔÈËÌå²»ÀûµÄÑÇÂÈËá¸ùÀë×ÓClO2-¡£2001ÄêÎÒ¹úÎÀÉú²¿¹æ¶¨£¬ÒûÓÃË®µÄClO2-º¬Á¿Ó¦²»³¬¹ý0.2 mg¡¤L£­1¡£ÈôÒûÓÃË®ÖÐClO2-µÄº¬Á¿³¬±ê£¬¿ÉÏòÆäÖмÓÈëÊÊÁ¿µÄij»¹Ô­¼Á£¬¸Ã·´Ó¦µÄÑõ»¯²úÎïÊÇ________£¨Ìѧʽ£©£¬Æä·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸