£¨2013?½­Î÷¶þÄ££©ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
·ÖÎö£ºA£®pHÏàͬʱ£¬ÈÜÒºµÄc£¨H+£©£¬´×ËáΪÈõËᣬÈÜҺŨ¶È×î´ó£»
B£®¸ù¾ÝÈÜÒºµÄµçºÉÊغãÅжϣ»
C£®´ÓÈõµç½âÖʵĵçÀëºÍÓ°ÏìÑÎÀàË®½âµÄÒòËØ·ÖÎö£»
D£®Al3+Ë®½â£¬´Ù½øË®µÄµçÀ룮
½â´ð£º½â£ºA£®pHÏàͬʱ£¬ÈÜÒºµÄc£¨H+£©£¬´×ËáΪÈõËᣬÈÜҺŨ¶È×î´ó£¬ÖкÍNaOHÈÜҺʱÏûºÄNaOHµÄÎïÖʵÄÁ¿ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ¢Ù£¾¢Û=¢Ú£¬¹ÊA´íÎó£»
B£®NaHCO3ÈÜÒºÖдæÔÚµçºÉÊغ㣬ӦΪc£¨Na+£©+c£¨H+£©=c£¨HCO3-£©+2c£¨CO32-£©+c£¨OH-£©£¬¹ÊB´íÎó£»
C£®CH3COOHΪÈõËᣬµçÀë³Ì¶È½ÏС£¬ÔòÈÜÒºÖÐc£¨CH3COO-£©×îС£¬ÓÉÓÚCH3COO-ºÍNH4+·¢Éú»¥´ÙË®½â£¬ÔòCH3COONH4ÈÜÒºÖÐCH3COO-Ũ¶ÈСÓÚCH3COONa£¬¹ÊCÕýÈ·£»
D£®Al3+Ë®½â£¬´Ù½øË®µÄµçÀ룬ÈÜÒºÖÐH+ÍêÈ«ÓÉË®µçÀ룬ÔòË®µçÀë³öµÄH+µÄÎïÖʵÄÁ¿Å¨¶ÈΪ10-4mol?L-1£¬¹ÊD´íÎó£®
¹ÊÑ¡C£®
µãÆÀ£º±¾Ì⿼²é½ÏΪ×ۺϣ¬Éæ¼°Èõµç½âÖʵĵçÀë¡¢ÑÎÀàµÄË®½â£¬×¢Òâ°ÑÎÕÓ°ÏìÑÎÀàË®½âµÄÒòËØ£¬Ò×´íµãΪD£¬×¢ÒâÑÎÀàË®½âµÄÔ­Àí¼°Ó¦Óã®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?½­Î÷¶þÄ££©·Ö×ÓʽΪC8H16O2µÄÓлúÎïA£¬ËüÄÜÔÚËáÐÔÌõ¼þÏÂË®½âÉú³ÉBºÍC£¬ÇÒBÔÚÒ»¶¨Ìõ¼þÏÂÄÜת»¯³ÉC£®ÔòÓлúÎïAµÄ¿ÉÄܽṹÓУ¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?½­Î÷¶þÄ££©£¨»¯Ñ§-Ñ¡ÐÞÎïÖʽṹÓëÐÔÖÊ£©
A¡¢B¡¢C¡¢DΪǰËÄÖÜÆÚÔªËØ£®AÔªËصÄÔ­×Ó¼Ûµç×ÓÅŲ¼Îªns2 np2£¬BÔªËØÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ3±¶£¬CÔªËØÔ­×ÓµÄMÄܲãµÄpÄܼ¶ÓÐ3¸öδ³É¶Ôµç×Ó£¬DÔªËØÔ­×ÓºËÍâµÄMÄܲãÖÐÖ»ÓÐ2¶Ô³É¶Ôµç×Ó£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©µ±n=2ʱ£¬AB2ÊôÓÚ
·Ç¼«ÐÔ
·Ç¼«ÐÔ
 ·Ö×Ó£¨Ìî¡°¼«ÐÔ¡±»ò¡°·Ç¼«ÐÔ¡±£©£¬·Ö×ÓÖÐÓÐ
2
2
¸ö¦Ä¼ü¡¢
2
2
 ¸ö¦Ð¼ü£® A6H6·Ö×ÓÖÐAÔ­×ÓµÄÔÓ»¯¹ìµÀÀàÐÍÊÇ
sp2
sp2
 ÔÓ»¯£®
£¨2£©µ±n=3ʱ£¬AÓëBÐγɵľ§ÌåÊôÓÚ
Ô­×Ó
Ô­×Ó
 ¾§Ì壮
£¨3£©ÈôAÔªËصÄÔ­×Ó¼Ûµç×ÓÅŲ¼Îª3s23p2£¬A¡¢C¡¢DÈýÖÖÔ­×ӵĵ縺ÐÔÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
S£¾P£¾Si
S£¾P£¾Si
£¨ÓÃÔªËØ·ûºÅ±íʾ£©£»A¡¢C¡¢DÈýÖÖÔªËصĵÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
P£¾S£¾Si
P£¾S£¾Si
£¨ÓÃÔªËØ·ûºÅ±íʾ£©£®
£¨4£©ÒÑ֪ijºì×ÏÉ«ÅäºÏÎïµÄ×é³ÉΪCoCl3?5NH3?H2O£¬¸ÃÅäºÏÎïÖеÄÖÐÐÄÀë×ÓîÜÀë×ÓÔÚ»ù̬ʱµÄºËÍâµç×ÓÅŲ¼Ê½Îª
1s22s22p63s23p63d6»ò[Ar]3d6
1s22s22p63s23p63d6»ò[Ar]3d6
£¬×÷ΪÅäλÌåÖ®Ò»µÄNH3·Ö×ӵĿռ乹ÐÍΪ
Èý½Ç׶ÐΣ¨»òËÄÃæÌåÐΣ©
Èý½Ç׶ÐΣ¨»òËÄÃæÌåÐΣ©
£®
£¨5£©½ðÊôÌúµÄ¾§ÌåÔÚ²»Í¬Î¶ÈÏÂÓÐÁ½Öֶѻý·½Ê½£¬¾§°û·Ö±ðÈçͼËùʾ£¬ÌåÐÄÁ¢·½¾§°ûºÍÃæÐÄÁ¢·½¾§°ûÖÐʵ¼Êº¬ÓеÄFeÔ­×Ó¸öÊýÖ®±ÈΪ
1£º2
1£º2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2013?½­Î÷¶þÄ££©ÒÔʳÑÎΪԭÁϽøÐÐÉú²ú²¢×ÛºÏÀûÓõÄijЩ¹ý³ÌÈçͼËùʾ£®

£¨1£©³ýÈ¥´ÖÑÎÖеÄCa2+¡¢Mg2+ºÍSO4-2Àë×Ó£¬¼ÓÈëÏÂÁгÁµí¼ÁµÄ˳ÐòÊÇ£¨ÌîÐòºÅ£©
cab»òcba»òbca
cab»òcba»òbca
£®
a£®Na2CO3         b£®NaOH        c£®BaCl2
£¨2£©½«ÂËÒºµÄpHµ÷ÖÁËáÐÔ³ýÈ¥µÄÀë×ÓÊÇ
CO32-ºÍOH-
CO32-ºÍOH-
£®
£¨3£©µç½âÂÈ»¯ÄÆÏ¡ÈÜÒº¿ÉÖƱ¸¡°84Ïû¶¾Òº¡±£¬Í¨µçʱÂÈÆø±»ÈÜÒºÍêÈ«ÎüÊÕ£¬ÈôËùµÃÏû¶¾Òº½öº¬Ò»ÖÖÈÜÖÊ£¬Ð´³öÏàÓ¦µÄ»¯Ñ§·½³Ìʽ£º
NaCl+H2O
 Í¨µç 
.
 
NaClO+H2¡ü
NaCl+H2O
 Í¨µç 
.
 
NaClO+H2¡ü
£®
£¨4£©ÈôÏò·ÖÀë³öNaHCO3¾§ÌåºóµÄĸҺÖмÓÈë¹ýÁ¿Éúʯ»Ò£¬Ôò¿É»ñµÃÒ»ÖÖ¿ÉÒÔÑ­»·Ê¹ÓõÄÎïÖÊ£¬Æ仯ѧʽÊÇ
NH3
NH3
£®
£¨5£©Ä³Ì½¾¿»î¶¯Ð¡×齫¶þÑõ»¯Ì¼ÆøÌåͨÈ뺬°±µÄ±¥ºÍʳÑÎË®ÖÐÖƱ¸Ì¼ËáÇâÄÆ£¬ÊµÑé×°ÖÃÈçͼËùʾ£¨Í¼Öмг֡¢¹Ì¶¨ÓõÄÒÇÆ÷δ»­³ö£©£®

ÊԻشðÏÂÁÐÓйØÎÊÌ⣺
¢ÙÒÒ×°ÖÃÖеÄÊÔ¼ÁÊÇ
±¥ºÍ̼ËáÇâÄÆÈÜÒº
±¥ºÍ̼ËáÇâÄÆÈÜÒº
£»
¢Ú¶¡×°ÖÃÖÐÏ¡ÁòËáµÄ×÷ÓÃÊÇ
ÎüÊÕδ·´Ó¦µÄ°±Æø
ÎüÊÕδ·´Ó¦µÄ°±Æø
£»
¢ÛʵÑé½áÊøºó£¬·ÖÀë³öNaHCO3 ¾§ÌåµÄ²Ù×÷ÊÇ
¹ýÂË
¹ýÂË
£¨Ìî·ÖÀë²Ù×÷µÄÃû³Æ£©£®
£¨6£©´¿¼îÔÚÉú²úÉú»îÖÐÓй㷺µÄÓ¦Óã®
¢Ù´¿¼î¿ÉÓÃÓÚ³ýÔį̂ÓÍÎÛ£®ÆäÔ­ÒòÊÇ£¨½áºÏÀë×Ó·½³Ìʽ±íÊö£©
̼Ëá¸ùÀë×ÓË®½âÏÔ¼îÐÔ£¬CO32-+H2O?HCO3-+OH-£¬ÓÍÎÛÔÚ¼îÐÔÌõ¼þÏÂË®½â¶ø±»³ýÈ¥
̼Ëá¸ùÀë×ÓË®½âÏÔ¼îÐÔ£¬CO32-+H2O?HCO3-+OH-£¬ÓÍÎÛÔÚ¼îÐÔÌõ¼þÏÂË®½â¶ø±»³ýÈ¥
£®
¢Ú¹¤ÒµÉÏ£¬¿ÉÒÔÓô¿¼î´úÌæÉÕ¼îÉú²úijЩ»¯¹¤²úÆ·£®ÈçÓñ¥ºÍ´¿¼îÈÜÒºÓëCl2·´Ó¦ÖÆÈ¡ÓÐЧ³É·ÖΪNaClOµÄÏû¶¾Òº£¬Æä·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
2CO32-+Cl2+H2O=2HCO3-+Cl-+ClO-
2CO32-+Cl2+H2O=2HCO3-+Cl-+ClO-
£®£¨ÒÑ֪̼ËáµÄËáÐÔÇ¿ÓÚ´ÎÂÈËᣩ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?½­Î÷¶þÄ££©Ä³Ï¡ÁòËáºÍÏ¡ÏõËáµÄ»ìºÏÈÜÒº200mL£¬Æ½¾ù·Ö³ÉÁ½·Ý£®ÏòÆäÖÐÒ»·ÝÖÐÖð½¥¼ÓÈëÍ­·Û£¬×î¶àÄÜÈܽâ9.6g£®ÏòÁíÒ»·ÝÖÐÖð½¥¼ÓÈëÌú·Û£¬²úÉúÆøÌåµÄÁ¿ËæÌú·ÛÖÊÁ¿Ôö¼ÓµÄ±ä»¯ÈçÏÂͼËùʾ£¨ÒÑÖªÏõËáÖ»±»»¹Ô­ÎªNOÆøÌ壩£®ÏÂÁзÖÎö»ò½á¹û´íÎóµÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸