Óмס¢ÒÒÁ½¸öÈÝ»ýÏàµÈµÄºãÈÝÃܱÕÈÝÆ÷£¬Ïò¼×ÈÝÆ÷ÖÐͨÈë6molAºÍ2molB£¬ÏòÒÒÈÝÆ÷ÖÐͨÈë1.5molA¡¢
0.5molBºÍ3molC£¬±£³ÖÁ½ÈÝÆ÷µÄζȺ㶨£¬Ê¹·´Ó¦3A£¨g£©+B£¨g£©xC£¨g£©´ïµ½Æ½ºâ£¬´Ëʱ²âµÃ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐCµÄÌå»ý·ÖÊý¾ùΪ0.2¡£
£¨1£©Èôx=2£¬Ôòƽºâʱ¼×¡¢ÒÒÁ½ÈÝÆ÷AµÄÎïÖʵÄÁ¿_________£¨Ìî¡°ÏàµÈ¡±»ò¡°²»ÏàµÈ£©£¬´Ëʱ¼×ÖÐAµÄÌå»ý·ÖÊýΪ___________£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖеÄѹǿ֮±ÈΪ___________¡£
£¨2£©Èôx=4£¬Æ½ºâʱ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖеÄѹǿ֮±ÈΪ__________¡£
£¨3£©Èôx=4£¬Æ½ºâºóÏò¼×ÈÝÆ÷ÖÐÔÙ¼Ó3molAºÍ1molB£¬CµÄÌå»ý·ÖÊý___________£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©0.2¡£
£¨1£©ÏàµÈ£»0.6£»1:1
£¨2£©8:5
£¨3£©µÈÓÚ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨15·Ö£©»¯Ñ§Ñ§¿ÆÖеÄƽºâÀíÂÛÖ÷Òª°üÀ¨£º»¯Ñ§Æ½ºâ¡¢µçÀëƽºâ¡¢Ë®½âƽºâºÍÈܽâƽºâËÄÖÖ£¬ÇÒ¾ù·ûºÏÀÕÏÄÌØÁÐÔ­Àí¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

       ¢ñ£®Óмס¢ÒÒÁ½¸öÈÝ»ýÏàµÈµÄºãÈÝÃܱÕÈÝÆ÷£¬

        ·¢Éú·´Ó¦3A(g)+B(g)  xC(g)    ¡÷H = QKJ/mol

       »Ø´ðÏÂÁÐÎÊÌ⣺

   £¨1£©ÏÂÁи÷ÏîÄÜ×÷ΪÅжϸ÷´Ó¦´ïµ½»¯Ñ§Æ½ºâ״̬µÄÒÀ¾ÝÊÇ             £¨ÌîÐòºÅ£©

              ¢Ù »¯Ñ§·´Ó¦ËÙÂÊ£ºv(A)=3v(B)                  ¢Ú »ìºÏÆøÌåµÄÃܶȱ£³Ö²»±ä

              ¢Û ÓÐ3molAÏûºÄµÄͬʱÓÐ1molBÉú³É        ¢Ü CµÄŨ¶È±£³Ö²»±ä

   £¨2£©¸ù¾ÝÊÔÑé²âµÃµÄÊý¾Ý¿ÉÖª£¬Î¶ÈÔ½¸ß¸Ã·´Ó¦µÄ»¯Ñ§Æ½ºâ³£ÊýÔ½´ó£¬ÔòQ     0£¨Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©

   £¨3£©Ïò¼×ÖÐͨÈë6molAºÍ2molB£¬ÏòÒÒÖÐͨÈë1.5molA¡¢0.5molBºÍ3molC£¬½«Á½ÈÝÆ÷µÄζȺ㶨ÔÚ770K£¬Ê¹·´Ó¦3A(g)+B(g) xc(g)´ïµ½Æ½ºâ£¬´Ëʱ²âµÃ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐCµÄÌå»ý·ÖÊý¾ùΪ0.2 ¡£

        ¢Ù Èôƽºâʱ£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿ÏàµÈ£¬Ôòx=         £»

        ¢Ú ƽºâʱ¼×ÖÐAµÄÌå»ý·ÖÊýΪ              £»

        ¢Û ÈôƽºâʱÁ½ÈÝÆ÷µÄѹǿ²»ÏàµÈ£¬ÔòÁ½ÈÝÆ÷ÖÐѹǿ֮±ÈΪ          

  ¢ò£®£¨1£©pH£½3µÄÑÎËáa L£¬·Ö±ðÓëÏÂÁÐ3ÖÖÈÜÒº»ìºÏ£¬³ä·Ö·´Ó¦ºóÈÜÒº³ÊÖÐÐÔ£º

¢ÙpH£½11µÄ°±Ë®b L£» ¢ÚÎïÖʵÄÁ¿Å¨¶ÈΪ1¡Á10-3mol/L °±Ë®c L£»

¢Ûc(OH-)£½1¡Á10-3 mol/LµÄBa(OH)2ÈÜÒºd L£»

ÊÔÅжÏa¡¢b¡¢c¡¢dµÄ´óС¹ØϵÕýÈ·µÄÊÇ              

A£®a£½b£¾c£¾d     B£®b£¾a£½d£¾c    C£®c£¾a£¾d£¾b   D£®c£¾a£½d£¾b

£¨2£©ÒÑÖªÊÒεÄÌõ¼þÏ£¬pH¾ùΪ5µÄH2SO4ÈÜÒººÍNH4ClÈÜÒº£¬ Á½ÈÜÒºÖÐc£¨H+£© • c£¨OH-£©=___________£»¸÷È¡5mLÉÏÊöÈÜÒº£¬·Ö±ð¼ÓˮϡÊÍÖÁ50mL£¬pH½Ï´óµÄÊÇ________ÈÜÒº£»¸÷È¡5mLÉÏÊöÈÜÒº£¬·Ö±ð¼ÓÈȵ½90¡æ£¬pH½ÏСµÄÊÇ________ÈÜÒº¡£

£¨3£©Í¬Å¨¶ÈµÄÏÂÁÐÈÜÒº£º¢ÙNH4Al(SO4)2£»¢ÚNH4Cl£»¢ÛNH3¡¤H2O£»¢ÜCH3COONH4£¬ÆäÖÐc(NH4+)ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£º                (Ìî±àºÅ)¡£

¢ó£®Ò»¶¨Î¶ÈϵÄÄÑÈܵç½âÖÊAmBnÔÚË®ÈÜÒºÖдﵽ³ÁµíÈܽâƽºâʱ£¬Æäƽºâ³£ÊýKsp=cm£¨An+£©¡Ácn£¨Bm¡ª£©£¬³ÆΪÄÑÈܵç½âÖʵÄÈܶȻý¡£

£¨1£©ÔÚ25¡æ£¬AgClµÄ°×É«Ðü×ÇÒºÖУ¬ÒÀ´Î¼ÓÈëµÈŨ¶ÈµÄKIÈÜÒººÍNa2SÈÜÒº£¬¹Û²ìµ½µÄÏÖÏóÊÇ                        £»

£¨2£©ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ        £¨Ìî×Öĸ£©

  A£®ÈܶȻýСµÄ³Áµí¿ÉÒÔת»¯ÎªÈܶȻý¸üСµÄ³Áµí

  B£®25¡æʱ£¬AgCl¹ÌÌåÔÚµÈÎïÖʵÄÁ¿Å¨¶ÈNaCl¡¢CaCl2ÈÜÒºÖеÄÈܶȻýÏàͬ¡£

  C£®25¡æʱ£¬±¥ºÍAgCl¡¢AgI¡¢Ag2SÈÜÒºÖÐËùº¬Ag+µÄŨ¶ÈÏàͬ

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(10·Ö)Óмס¢ÒÒÁ½¸öÈÝ»ýÏàµÈµÄºãÈÝÃܱÕÈÝÆ÷£¬Ïò¼×ÖÐͨÈë6mol AºÍ2mol B£¬ÏòÒÒÖÐͨÈë1.5mol A¡¢0.5mol BºÍ3mol C£¬½«Á½ÈÝÆ÷µÄζȺ㶨ÔÚ770K£¬Ê¹·´Ó¦3A(g)+B(g)xC(g)´ïµ½Æ½ºâ£¬´Ëʱ²âµÃ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐCµÄÌå»ý·ÖÊý¶¼Îª0.2£¬ÊԻشðÏÂÁÐÓйØÎÊÌ⣺

(1)Èôƽºâʱ£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿ÏàµÈ£¬Ôòx=_________£»

Èôƽºâʱ£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿²»ÏàµÈ£¬Ôòx=_________¡£

(2)ÈôƽºâʱÁ½ÈÝÆ÷ÖеÄѹǿ²»ÏàµÈ£¬ÔòÁ½ÈÝÆ÷ÖÐѹǿ֮±ÈΪ         ¡£

(3)ƽºâʱ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐA¡¢BµÄÎïÖʵÄÁ¿Ö®±ÈÊÇ·ñÏàµÈ____________£¨Ìî¡°ÏàµÈ¡±»ò¡°²»ÏàµÈ¡±£©£¬Æ½ºâʱ¼×ÖÐAµÄÌå»ý·ÖÊýΪ____________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ìºÚÁú½­Ê¡Äµµ¤½­Ò»ÖиßÈýÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨15·Ö£©»¯Ñ§Ñ§¿ÆÖеÄƽºâÀíÂÛÖ÷Òª°üÀ¨£º»¯Ñ§Æ½ºâ¡¢µçÀëƽºâ¡¢Ë®½âƽºâºÍÈܽâƽºâËÄÖÖ£¬ÇÒ¾ù·ûºÏÀÕÏÄÌØÁÐÔ­Àí¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ñ£®Óмס¢ÒÒÁ½¸öÈÝ»ýÏàµÈµÄºãÈÝÃܱÕÈÝÆ÷£¬
·¢Éú·´Ó¦3A(g)+B(g)  xC(g)    ¡÷H = QKJ/mol
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÏÂÁи÷ÏîÄÜ×÷ΪÅжϸ÷´Ó¦´ïµ½»¯Ñ§Æ½ºâ״̬µÄÒÀ¾ÝÊÇ             £¨ÌîÐòºÅ£©
¢Ù»¯Ñ§·´Ó¦ËÙÂÊ£ºv(A)="3v(B)                 " ¢Ú»ìºÏÆøÌåµÄÃܶȱ£³Ö²»±ä
¢ÛÓÐ3molAÏûºÄµÄͬʱÓÐ1molBÉú³É       ¢Ü CµÄŨ¶È±£³Ö²»±ä
£¨2£©¸ù¾ÝÊÔÑé²âµÃµÄÊý¾Ý¿ÉÖª£¬Î¶ÈÔ½¸ß¸Ã·´Ó¦µÄ»¯Ñ§Æ½ºâ³£ÊýÔ½´ó£¬ÔòQ    0£¨Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©
£¨3£©Ïò¼×ÖÐͨÈë6molAºÍ2molB£¬ÏòÒÒÖÐͨÈë1.5molA¡¢0.5molBºÍ3molC£¬½«Á½ÈÝÆ÷µÄζȺ㶨ÔÚ770K£¬Ê¹·´Ó¦3A(g)+B(g) xc(g)´ïµ½Æ½ºâ£¬´Ëʱ²âµÃ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐCµÄÌå»ý·ÖÊý¾ùΪ0.2 ¡£
¢ÙÈôƽºâʱ£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿ÏàµÈ£¬Ôòx=         £»
¢Úƽºâʱ¼×ÖÐAµÄÌå»ý·ÖÊýΪ              £»
¢ÛÈôƽºâʱÁ½ÈÝÆ÷µÄѹǿ²»ÏàµÈ£¬ÔòÁ½ÈÝÆ÷ÖÐѹǿ֮±ÈΪ          
¢ò£®£¨1£©pH£½3µÄÑÎËáa L£¬·Ö±ðÓëÏÂÁÐ3ÖÖÈÜÒº»ìºÏ£¬³ä·Ö·´Ó¦ºóÈÜÒº³ÊÖÐÐÔ£º
¢ÙpH£½11µÄ°±Ë®b L£»¢ÚÎïÖʵÄÁ¿Å¨¶ÈΪ1¡Á10-3 mol/L °±Ë®c L£»
¢Ûc(OH-)£½1¡Á10-3 mol/LµÄBa(OH)2ÈÜÒºd L£»
ÊÔÅжÏa¡¢b¡¢c¡¢dµÄ´óС¹ØϵÕýÈ·µÄÊÇ              
A£®a£½b£¾c£¾d     B£®b£¾a£½d£¾c    C£®c£¾a£¾d£¾b   D£®c£¾a£½d£¾b
£¨2£©ÒÑÖªÊÒεÄÌõ¼þÏ£¬pH¾ùΪ5µÄH2SO4ÈÜÒººÍNH4ClÈÜÒº£¬Á½ÈÜÒºÖÐc£¨H+£© ? c£¨OH-£©=___________£»¸÷È¡5mLÉÏÊöÈÜÒº£¬·Ö±ð¼ÓˮϡÊÍÖÁ50mL£¬pH½Ï´óµÄÊÇ________ÈÜÒº£»¸÷È¡5mLÉÏÊöÈÜÒº£¬·Ö±ð¼ÓÈȵ½90¡æ£¬pH½ÏСµÄÊÇ________ÈÜÒº¡£
£¨3£©Í¬Å¨¶ÈµÄÏÂÁÐÈÜÒº£º¢ÙNH4Al(SO4)2£»¢ÚNH4Cl£»¢ÛNH3¡¤H2O£»¢ÜCH3COONH4£¬ÆäÖÐc(NH4+) ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£º                (Ìî±àºÅ)¡£
¢ó£®Ò»¶¨Î¶ÈϵÄÄÑÈܵç½âÖÊAmBnÔÚË®ÈÜÒºÖдﵽ³ÁµíÈܽâƽºâʱ£¬Æäƽºâ³£ÊýKsp=cm£¨An+£©¡Ácn£¨Bm¡ª£©£¬³ÆΪÄÑÈܵç½âÖʵÄÈܶȻý¡£
£¨1£©ÔÚ25¡æ£¬AgClµÄ°×É«Ðü×ÇÒºÖУ¬ÒÀ´Î¼ÓÈëµÈŨ¶ÈµÄKIÈÜÒººÍNa2SÈÜÒº£¬¹Û²ìµ½µÄÏÖÏóÊÇ                        £»
£¨2£©ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ       £¨Ìî×Öĸ£©
A£®ÈܶȻýСµÄ³Áµí¿ÉÒÔת»¯ÎªÈܶȻý¸üСµÄ³Áµí
B£®25¡æʱ£¬AgCl¹ÌÌåÔÚµÈÎïÖʵÄÁ¿Å¨¶ÈNaCl¡¢CaCl2ÈÜÒºÖеÄÈܶȻýÏàͬ¡£
C£®25¡æʱ£¬±¥ºÍAgCl¡¢AgI¡¢Ag2SÈÜÒºÖÐËùº¬Ag+µÄŨ¶ÈÏàͬ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê½­Î÷Ê¡Äϲý¶þÖи߶þµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

(10·Ö)Óмס¢ÒÒÁ½¸öÈÝ»ýÏàµÈµÄºãÈÝÃܱÕÈÝÆ÷£¬Ïò¼×ÖÐͨÈë6mol AºÍ2mol B£¬ÏòÒÒÖÐͨÈë1.5mol A¡¢0.5mol BºÍ3mol C£¬½«Á½ÈÝÆ÷µÄζȺ㶨ÔÚ770K£¬Ê¹·´Ó¦3A(g)+B(g)xC(g)´ïµ½Æ½ºâ£¬´Ëʱ²âµÃ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐCµÄÌå»ý·ÖÊý¶¼Îª0.2£¬ÊԻشðÏÂÁÐÓйØÎÊÌ⣺
(1)Èôƽºâʱ£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿ÏàµÈ£¬Ôòx=        £»Èôƽºâʱ£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿²»ÏàµÈ£¬Ôòx=        ¡£
(2)ƽºâʱ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐA¡¢BµÄÎïÖʵÄÁ¿Ö®±ÈÊÇ·ñÏàµÈ        £¨Ìî¡°ÏàµÈ¡±»ò¡°²»ÏàµÈ¡±£©£¬Æ½ºâʱ¼×ÖÐAµÄÌå»ý·ÖÊýΪ                 ¡£
(3)ÈôƽºâʱÁ½ÈÝÆ÷ÖеÄѹǿ²»ÏàµÈ£¬ÔòÁ½ÈÝÆ÷ÖÐѹǿ֮±ÈΪ                ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì½­Î÷Ê¡¸ß¶þµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

(10·Ö)Óмס¢ÒÒÁ½¸öÈÝ»ýÏàµÈµÄºãÈÝÃܱÕÈÝÆ÷£¬Ïò¼×ÖÐͨÈë6mol AºÍ2mol B£¬ÏòÒÒÖÐͨÈë1.5mol A¡¢0.5mol BºÍ3mol C£¬½«Á½ÈÝÆ÷µÄζȺ㶨ÔÚ770K£¬Ê¹·´Ó¦3A(g)+B(g)xC(g)´ïµ½Æ½ºâ£¬´Ëʱ²âµÃ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐCµÄÌå»ý·ÖÊý¶¼Îª0.2£¬ÊԻشðÏÂÁÐÓйØÎÊÌ⣺

(1)Èôƽºâʱ£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿ÏàµÈ£¬Ôòx=         £»Èôƽºâʱ£¬¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿²»ÏàµÈ£¬Ôòx=         ¡£

(2)ƽºâʱ¼×¡¢ÒÒÁ½ÈÝÆ÷ÖÐA¡¢BµÄÎïÖʵÄÁ¿Ö®±ÈÊÇ·ñÏàµÈ         £¨Ìî¡°ÏàµÈ¡±»ò¡°²»ÏàµÈ¡±£©£¬Æ½ºâʱ¼×ÖÐAµÄÌå»ý·ÖÊýΪ                  ¡£

(3)ÈôƽºâʱÁ½ÈÝÆ÷ÖеÄѹǿ²»ÏàµÈ£¬ÔòÁ½ÈÝÆ÷ÖÐѹǿ֮±ÈΪ                 ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸